I would like to calculate the the current time and add 2 minutes to it and print the output in the following format. HH:MM . I searched online and came to know that there are lot of CPAN modules that can be used to implement this. But I'd like to do it without cpan modules.
$current_time = time();
$new_time = $current_time + (2*60); // adding two minutes
print( ' the time is ' . $ new_time ) ;
Output : the time is 1424906904
I searched online and came to know that we need to use POSIX perl interface to print the time in the appropriate format. However i'd like to know if there is a way to do this without using any cpan modules.
You can use localtime:
print scalar localtime($current_time);
Or you can run localtime's return values through POSIX::strftime (which is distributed with Perl as a core module):
use POSIX qw(strftime);
print strftime('%Y-%m-%d %H:%M:%S', localtime $current_time);
That's easy to do with localtime. Hours, minutes, and seconds are the 2nd, 1st, and 0th values returned. For example:
my ($sec, $min, $hours) = localtime(time()+120); # add 120 seconds
printf "%02d:%02d:%02d\n", $hours, $min, $sec;
Time::Piece and Time::Seconds have been included with all Perl installations since 2007.
#!/usr/bin/perl
use strict;
use warnings;
use 5.010;
use Time::Piece;
use Time::Seconds;
my $time = localtime;
$time += 2 * ONE_MINUTE;
say $time->strftime('%H:%M');
Related
I want to compare both date and time check if the timestamp from the file I'm going to open will have equal or greater date and time as if the my timestamp which looks like this:
$Date = "20170608";
$Time = "105006";
My main problem is how to do it efficiently possibly without adding perl libraries and how to check it when there's going to be situation of date switching and the hour will be for example 23:59:44
Time::Piece is core in perl, and supports 'strptime'.
#!/usr/bin/env perl
use strict;
use warnings;
use Time::Piece;
my $Date = "20170608";
my $Time = "10506";
my $ts = Time::Piece->strptime( "$Date $Time", "%Y%m%d %H%M%S" );
print $ts, "\n";
print "Delta:", $ts->epoch - time(), "\n";
Was unclear on what time that $Time represented - strptime converts it to 10:50:06, but I'm guessing it might be intended to be 01:05:06?
If so, then zero pad.
$Time = sprintf ( "%06d", $Time );
To read the timestamp from the file metadata, then you need stat:
my $mtime = (stat $filename)[9];
I have an ISO 8601 time stored in a variable and I have some number of hours stored in another variable like this:
my $current_time = shift; #looks like: 2015-07-01T15:38:08Z
my $hours = shift; # looks like: 12
My goal is to add the hours to the current time, but there doesn't seem to be any built in Perl function to do it. In Powershell, you can do something like this:
$currentTime = $currentTime .AddHours($hours)
Is there an easy way to do this in Perl?
That specific ISO 8601 profile is also known as RFC3339.
use DateTime::Format::RFC3339;
my $dt = DateTime::Format::RFC3339->parse_datetime('2015-07-01T15:38:08Z');
$dt->add( hours => 1 );
print "$dt\n"; # 2015-07-01T16:38:08Z
If you want to accept arbitrary ISO 8601 profiles, you can use DateTime::Format::ISO8601.
use DateTime::Format::ISO8601;
my $dt = DateTime::Format::ISO8601->parse_datetime('2015-07-01T15:38:08Z');
$dt->set_time_zone('UTC'); # Convert to UTC ("Z") if it's not already.
$dt->add( hours => 1 );
print $dt->iso8601().'Z', "\n"; # 2015-07-01T16:38:08Z
I posted these alternatives because these modules are far less error-prone to use than Time::Piece.
You can also use Time::Moment. In the interest of full disclosure, I am the author of Time::Moment.
say Time::Moment->from_string('2015-07-01T15:38:08Z')
->plus_hours(1);
Output:
2015-07-01T16:38:08Z
Rather easy with Time::Piece:
#! /usr/bin/perl
use warnings;
use strict;
use Time::Piece;
use Time::Seconds;
my $current_time = '2015-07-01T15:38:08Z';
my $hours = 12;
my $format = '%Y-%m-%dT%H:%M:%SZ';
my $time = 'Time::Piece'->strptime($current_time, $format);
$time += $hours * ONE_HOUR;
print $time->strftime($format), "\n";
I have searched several hours for a formula to convert dd/mm/yyyy format into epoch time but have not found a solution.
I have two dates, after converting from 2 different formats, that are now like this "08011985" and "09302014". I have to convert them to epoch time to get the difference from earliest and latest date, and do something based on the size of the spread.
I can't install any modules and am on 5.8.8.
The built-in module Time::Local provides the inverse of localtime and gmtime, timelocal and timegm. They take dates and times and return epoch time.
perlfaq4 covers these sorts of questions.
Here's an example using the Time::Local module, which has always been a core component of Perl 5.
use strict;
use warnings;
use Time::Local qw/ timelocal /;
for my $date ( qw/ 08011985 09302014 / ) {
print epoch_for_mmddyyyy($date), "\n";
}
sub epoch_for_mmddyyyy {
my ($m, $d, $y) = unpack 'A2A2A4', shift;
timelocal(0, 0, 0, $d, $m-1, $y);
}
output
491698800
1412031600
I'm working on a Perl program at work and stuck on (what I think is) a trivial problem. I simply need to build a string in the format '06/13/2012' (always 10 characters, so 0's for numbers less than 10).
Here's what I have so far:
use Time::localtime;
$tm=localtime;
my ($day,$month,$year)=($tm->mday,$tm->month,$tm->year);
You can do it fast, only using one POSIX function. If you have bunch of tasks with dates, see the module DateTime.
use POSIX qw(strftime);
my $date = strftime "%m/%d/%Y", localtime;
print $date;
You can use Time::Piece, which shouldn't need installing as it is a core module and has been distributed with Perl 5 since version 10.
use Time::Piece;
my $date = localtime->strftime('%m/%d/%Y');
print $date;
output
06/13/2012
Update
You may prefer to use the dmy method, which takes a single parameter which is the separator to be used between the fields of the result, and avoids having to specify a full date/time format
my $date = localtime->dmy('/');
This produces an identical result to that of my original solution
use DateTime qw();
DateTime->now->strftime('%m/%d/%Y')
expression returns 06/13/2012
If you like doing things the hard way:
my (undef,undef,undef,$mday,$mon,$year) = localtime;
$year = $year+1900;
$mon += 1;
if (length($mon) == 1) {$mon = "0$mon";}
if (length($mday) == 1) {$mday = "0$mday";}
my $today = "$mon/$mday/$year";
use Time::Piece;
...
my $t = localtime;
print $t->mdy("/");# 02/29/2000
Perl Code for Unix systems:
# Capture date from shell
my $current_date = `date +"%m/%d/%Y"`;
# Remove newline character
$current_date = substr($current_date,0,-1);
print $current_date, "\n";
Formating numbers with leading zero is done easily with "sprintf", a built-in function in perl (documentation with: perldoc perlfunc)
use strict;
use warnings;
use Date::Calc qw();
my ($y, $m, $d) = Date::Calc::Today();
my $ddmmyyyy = sprintf '%02d.%02d.%d', $d, $m, $y;
print $ddmmyyyy . "\n";
This gives you:
14.05.2014
Using File::stat we can get the ctime of a given file. My question is how to change the ctime, which means the inode change time in seconds since the epoch, to a normal time representation like "2009-08-26 17:28:28". Is there any build-in or module can solve this task?
The most standard way is to use POSIX module and it's strftime function.
use POSIX qw( strftime );
use File::stat;
my $stat_epoch = stat( 'some_file.name' )->ctime;
print strftime('%Y-%m-%d %H:%M:%S', localtime( $stat_epoch ) );
All these markers like %Y, %m and so on, are defined in standard, and work the same in C, system "date" command (at least on Unix) and so on.
If all you want is a human-readable representation, then
print scalar localtime stat($filename)->ctime;
will do the job. This prints something like "Wed Jun 10 19:25:16 2009".
You can't influence the format, though.
If you want the time in GMT, use "scalar gmtime" instead.
This is a special behaviour of localtime and gmtime in scalar context.
use DateTime;
$dt = DateTime->from_epoch( epoch => $epoch );
The datetime object then contains the representations you require, e.g. $year = $dt->year; etc. In scalar context you get a nice human-readable representation, e.g.
$epoch = 123456789;
$dt = DateTime->from_epoch( epoch => $epoch );
print $dt;
1973-11-29T21:33:09
use File::stat;
use Time::CTime;
$file = "BLAH BLAH BLAH";
$st = stat($file) or die "No $file: $!";
print strftime('%b %o', localtime($st->ctime));
#Feb 11th, for example.
As you can see from the number of answers here, you have lots of options. I like the Date::Format module:
#!/usr/bin/perl
use strict;
use warnings;
use Date::Format;
use File::Stat;
my $fs = File::Stat->new( '.vimrc' );
my $mtime = $fs->ctime();
print time2str( "changed in %Y on %B, %o at %T\n", $mtime );
First, are you really using File::Stat rather than File::stat? If so, and if you have 5.8 or greater, switch to File::stat.
perldoc localtime
localtime EXPR
localtime
Converts a time as returned by the time function to a 9-element list with the time analyzed for the local time zone.
...
In scalar context, localtime() returns the ctime(3) value:
Once you realize thatlocaltime can take an argument, then your mind opens up to all the other possibilities mentioned in this thread.
#!/usr/bin/perl
use strict;
use warnings;
use File::stat;
my $stat = stat 't.pl';
print "$_\n" for $stat->ctime, scalar localtime($stat->ctime);
There's an example in Time::localtime perldoc for using it's ctime() to do this sort of thing.
use File::stat;
use Time::localtime;
my $date_string = ctime(stat($file)->ctime);