I am getting {item.pubDate} from XML and the value is:
Mon, 02 Mar 2015 14:35:47 +0000
so I did this:
<#assign starting_point = item.pubDate?index_of(",")>
<#assign date="${item.pubDate?substring(starting_point + 1)}" />
${date?datetime("dd MMM yyyy hh:mm:ss z")?date}<br>
and the result is: Mar 2, 2015.
My question is, can we change value from Mar to March and if we can then what is the best way to do it? I could have if/elseif statements in freemarker and assign each three letter months to full month name but it looks not good. Any advice/tips will be greatly appreciated. thanks.
It doesn't mater, MMM will parse both Mar and March. The only important thing is to have at least 3 M-s, as http://docs.oracle.com/javase/8/docs/api/java/text/SimpleDateFormat.html says:
If the number of pattern letters is 3 or more, the month is interpreted as text; otherwise, it is interpreted as a number.
Yes, FreeMarker follows the same datetime formatting rules as Java. Use the ?string built in for dates. You can do:
${date?datetime("dd MMM yyyy hh:mm:ss z")?string("MMMM dd, yyyy")}
Source: http://freemarker.org/docs/ref_builtins_date.html#ref_builtin_string_for_date
Related
I am using intl pakage's DateFormat class to format dates with a format like this:
_standardDateFormat = DateFormat('MMM dd, yyyy');
This produces strings like Feb 01, 2023.
How can I have the date without the prefix of 0 when it's a single-digit date? I would like to show Feb 1, 2023. I have tried d, dd, c but they all render with the prefixed 0.
If it's a double-digit date, I would of course like to show both digits: Mar 13, 2023.
Update: the single d format is indeed working, but I needed to restart flutter build to see the effect (not sure why).
This question already has answers here:
Parsing time-of-day with am/pm using Java DateTimeFormatter class [duplicate]
(3 answers)
Can't parse String to LocalDate (Java 8)
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I am trying to format the String date, time and zone information.
LocalDateTime.parse("Dec 01, 2019 1:00:00 PM +00:00", DateTimeFormatter.ofPattern("MMM dd, YYYY hh:mm:ss a XXX"));
ZonedDateTime.parse("Dec 01, 2019 1:00:00 PM +00:00", DateTimeFormatter.ofPattern("MMM dd, YYYY hh:mm:ss a XXX"));
Please note for project support reasons i cannot use above java 8.
I am unable to get this parse work, I did try a lot of versions before i posted here. any support is appreciated.
Exception:
Exception in thread "main" java.time.format.DateTimeParseException: Text 'Dec 01, 2019 1:00:00 PM +00:00' could not be parsed at index 13
at java.base/java.time.format.DateTimeFormatter.parseResolved0(DateTimeFormatter.java:2052)
at java.base/java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1954)
at java.base/java.time.LocalDateTime.parse(LocalDateTime.java:494)
at com.parse.Test.main(Test.java:10)
Your date-time string, "Dec 01, 2019 1:00:00 PM +00:00" has timezone offset of 00:00 hours. The java.time API provides us with OffsetDateTime to parse this type of date-time string to.
Demo:
import java.time.OffsetDateTime;
import java.time.format.DateTimeFormatter;
import java.util.Locale;
class Main {
public static void main(String[] args) {
DateTimeFormatter parser = DateTimeFormatter.ofPattern("MMM dd, uuuu h:mm:ss a XXX", Locale.ENGLISH);
OffsetDateTime odt = OffsetDateTime.parse("Dec 01, 2019 1:00:00 PM +00:00", parser);
System.out.println(odt);
}
}
Output:
2019-12-01T13:00Z
ONLINE DEMO
Learn more about the modern Date-Time API from Trail: Date Time.
What went wrong with your code?
You have used hh whereas your string has only one digit in the hour.
You have used Y instead of y. Note that Y is used for week-based-year. The right symbol for the intended purpose is y or u. Here, you can use y instead of u but I prefer u to y.
I also recommend you understand the importance of using a Locale while using date-time parsing/formatting API. Check Never use SimpleDateFormat or DateTimeFormatter without a Locale to learn more about it.
This Worked
LocalDateTime.parse("Dec 01, 2019 1:00:00 PM +00:00", DateTimeFormatter.ofPattern("MMM dd, yyyy h:mm:ss a XXX"));
ZonedDateTime.parse("Dec 01, 2019 1:00:00 PM +00:00", DateTimeFormatter.ofPattern("MMM dd, yyyy h:mm:ss a XXX"));
What I changed was:
We use lower case yyyy for the year. Format pattern strings are case sensitive.
We use just one h for the hour of day since it may be just one digit (1 in my example). A single h does accept two digits too, though, so times with 10, 11 or 12 will not pose any problem.
According to the documentation, it seems that it is only possible to manipulate dates with a numeric format, and not letters.
Does a package exist if I want to display date with the format Thur, Aug 23 ?
If not, how could I do this ?
Thank you !
You can create your own DateFormat using it's default constructor.
The format you want is EEEE, MMM d.
For Example print(new DateFormat("EEEE, MMM d").format(new DateTime.now())); should print Wedn, Jun 26 for today.
I am creating an app which is using RSS feed.
in that I have to parse a dateTime string.
string coming in data is : Tue, 17 Sep 2013T04:00:00 GMT
I can not convert it into date because of that T b/w year and hour.
Can anyone please provide me the date format for this?
I am using formate like EEE, dd MMM yyyy HH:mm:ss ZZZ
But it is giving null value
I used : EEE, dd MMM yyyy'T'HH:mm:ss ZZZ
and it worked..
date.parse() method of groovy detects date DD and year yyyy correctly but is unable to detect the month as mmm.. As in
println new Date().parse("DD-MMM-yyyy", '22-MAR-2011')
yields output as
Sat Jan 22 00:00:00 GMT+05:30 2011
Why is the month march as MAR picked up as Jan? What can I do to make it detect the month in mmm format?
The problem is actualy that you are using DD - that means day in year
Correct way:
println new Date().parse("dd-MMM-yyyy", '22-MAR-2011')
Quick tip when formatting dates try using the reverse and see what comes out:
println new Date().format("dd-MMM-yyyy")
Groovy uses SimpleDateFormat under the hood but that's not that important since most date libraries use the same format conventions.