I see a similar question here, but it's 4-year-old. Is there a better way now to re-use the array obtained from getPart('where')?
getPath('where') returns an array of individual WHERE clause segments like below (example).
[0] => (`e`.`type` = 'bleh')
[1] => (AND `e`.`name` = 'blah')
I can do some string operations to clean it up the second segment and re-add to Zend_Db_Select, but it seems really hacky.
Related
I have been playing with Pony arrays to understand Pony better, and wanted to write the map function for any arrays.
I am talking about something like the standard map function most languages have nowadays for converting elements of collections, as in Clojure:
(map #(+ 1 %) [1 2 3]) ; => [2 3 4]
But I want it to actually modify the given array, not return a new one.
My current attempt so far runs into many errors due to capabilities:
// array is "iso" so I can give it to another actor and change it
let my_array: Array[U64] iso = [1; 2; 3; 4]
// other actor tries to recover arrays as "box" just to call pairs() on it
let a = recover box my_array end // ERROR: can't recover to this capability
for (i, item) in a.pairs() do
// TODO set item at i to some other mapped value
try my_array.update(i, fun(item))? end
end
Anyone knows how this can be done
Alright, took me a while, but I was able to get things working.
Here's my basic understanding of what's going on (please correct me if I'm wrong)!
The first step was to understand that we need to use aliases to change the capabilities of a variable in Pony.
So, in order to make an iso variable useable as a box, one must alias it by basically, consuming it into another variable:
let a: Array[U64] ref = consume array // array is "iso"
for (i, item) in a.pairs() do
try a.update(i, item + n)? end
end
This works!!
One more problem I had was that I couldn't do much with the resulting Array[U64] ref. Can't pass it to anyone, for example.
So I wrapped the whole thing into a recover block in order to end up with the same array, but as a val (immutable reference to the array) which is more useful as I can send it to other actors:
let result = recover val
let a: Array[U64] ref = consume array
for (i, item) in a.pairs() do
try a.update(i, item + n)? end
end
a
end
Now I can send result to anyone!
I have 2 arrays - one has attribute called vcdName and the other has attribute called name. I want to remove from array 1 all entries where I find the value of vcdName in the second array. So:
array one
data...vcdName=a
data...vcdName=b
array two
data...name=a
I want to filter array one and remove the first entry (because vcdName value a is found in array two).
I understand I can use lodash functions and I tried the following. I believeusing is will return me those entries that match and I need to put in filteredArray those entries where no match is found in arraytwo.
filteredArray = _.filter(#arrayone, (vcd) -> vcd.vcdName is #arraytwo)
I hope I have not gotten too confusing. It feels this should be moderately easier than I am making it.
Generically I need to do this
for each entry in arrayone
for each entry in arraytwo
does entry from arrayone.vcdName == arraytwo.name - if yes then I do not want that entry from arrayone
I hope that helps
filter is in js core so I don't see why you'd need to use the lodash function, but anyway you can do it like this:
arraytwo_names = #arraytwo.reduce (dict, entry) ->
dict[entry.name] = true
dict
, {}
results = #arrayone.filter (x) ->
!arraytwo_names[x.vcdName]
The reduce is not strictly speaking necessary, since you could loop through arraytwo each iteration of the filter, but it is an optimization and makes the runtime O(N) and not O(N^2).
I am trying to create an array where each element is an empty array.
I have tried this:
var result = Array.fill[Array[Int]](Array.empty[Int])
After looking here How to create and use a multi-dimensional array in Scala?, I also tried this:
var result = Array.ofDim[Array[Int]](Array.empty[Int])
However, none of these work.
How can I create an array of empty arrays?
You are misunderstanding Array.ofDim here. It creates a multidimensional array given the dimensions and the type of value to hold.
To create an array of 100 arrays, each of which is empty (0 elements) and would hold Ints, you need only to specify those dimensions as parameters to the ofDim function.
val result = Array.ofDim[Int](100, 0)
Array.fill takes two params: The first is the length, the second the value to fill the array with, more precisely the second parameter is an element computation that will be invoked multiple times to obtain the array elements (Thanks to #alexey-romanov for pointing this out). However, in your case it results always in the same value, the empty array.
Array.fill[Array[Int]](length)(Array.empty)
Consider also Array.tabulate as follows,
val result = Array.tabulate(100)(_ => Array[Int]())
where the lambda function is applied 100 times and for each it delivers an empty array.
Although I know about splats, still I can't quite grasp the last line from the following code:
class Borrowable extends Decorator
constructor: (#libraryItem) ->
removeBorrower: (borrower) ->
#borrowers[t..t] = [] if ( t = #borrowers.indexOf(borrower) ) > -1
Btw, this code was copied from https://github.com/aksharp/Design-Patterns/blob/master/CoffeeScript/Decorator.coffee
Im assuming this is Destructuring Assignment, still I can't quite get my head around what's it's happening behind the scenes.
Could you help clarify this?
Let's have a closer look at the last line:
#borrowers[t..t] = [] if ( t = #borrowers.indexOf(borrower) ) > -1
I'm not sure if this form counts as Destructuring Assignment, probably it is.
First, it calls #borrowers.indexOf(borrower) to check that borrower is present inside of the #borrowers array and to get it's index.
It's conventional to use borrower in #borrowers form instead of #borrowers.indexOf(borrower) > -1, but in this case we need index of an element as well.
If borrower is present in #borrowers, it gets the part of the #borrowers array between indexes t and t
#borrowers[t..t]
which is the [borrower], and assigns it to the empty array [], thus removing the borrower from #borrowers array.
Here is js-like equivalent of this assignment:
#borrowers.splice t, 1
I have a cell array of length 3 and I want to make a for loop with another cell array with length of 6 , so how can I add extra 3 cells for the first array in order to make the 2 cell arrays equal and to use my for loop in MATLAB?
For example, with 2 inputs:
type = { '12' '62' '5' };
colour = {'re' 'green' 'yellow' 'brown' 'blue' 'black'};
for i = 1:length(colour)
if isequal(colour(i), type(:))
result(i) = type(i);
else
end
end
I need to make the type cell array with the same size with colour cell array (I think I have to add extra 3 empty cells in side the type cell array).
I have to address several issues in your code first:
If you use a cell array, you must use curly braces ({}) to extract elements from it. Instead of writing colour(i) you should be writing colour{i}.
This is not a problem, but it's a matter of good practice. If you don't need to handle the else part of the if statement, don't write it at all.
Preallocate memory so that arrays don't grow inside the loop (it slows down the program). Specifically, add the line result = cell(size(colour)); before the for loop.
Your isequal logic is flawed. Practically, it would always return false because colour{1} is one element and type{:} is many.
According to your example, types contain numbers and colours letters, although they are both strings. Does it make sense to compare the two?
Now, regarding your question, it's up to you to decide how the for loop runs. Since you don't mention what you want to achieve (you rather ask how you want to achieve something without saying what exactly), I cannot say what your for loop should look like, if necessary at all. Maybe you meant to use ismember instead of isequal? If so, the fixed code can look like this:
result = cell(size(colour));
for i = 1:length(colour)
if ismember(colour{i}, type)
result{i} = type{i};
end
end
or shorter, like this:
result = cell(size(colour));
[found, idx] = ismember(colour, type);
result(found) = type{idx(found)}
If you provide more details, maybe I can refine my answer so that it helps you more.