How to execute multiple query one by one - postgresql

table_1 (id, first_Name, last_Name)
table_2 (id, name, table_1_id)
My work is to copy all values of a column from table_1 to table_2 as individual entry. My query is
Query_1:
insert into table_2 ( name, table_1_id )
select first_Name as name, id as table_1_id from table_1.
My other query is
Query_2:
insert into table_2 ( name, table_1_id )
select last_Name as name, id as table_1_id from table_1.
It run pretty good but save all first_name then save all last_name.
my requirement is to run these two queries together and want the result will be like
first_Name(whatever) table_1_id (1)
last_Name(whatever) table_1_id(1)
first_Name(whatever) table_1_id(2)
last_Name(whatever) table_1_id(2)
Thanks in advance
Note: table_1_id is not a foreign key in table_2

Try by using WITH Queries (Common Table Expressions)
WITH cte AS (
insert into table_2 ( name, table_1_id )
select first_Name as name, id as table_1_id from table_1
)
insert into table_2 ( name, table_1_id )
select last_Name as name, id as table_1_id from table_1
and test values by select * table_2 order by table_1_id

You can achieve this using an union all:
INSERT INTO table_2( name, table1_id)
select name, id from
(
select first_name as name, id from table_1
union all
select last_name as name, id from table_1
) A
order by id

Related

Recursive CTE and multiple inserts in joined table

I'm searching to copy nodes of a hierarchical tree and to apply the changes onto a joined table. I found parts of the answer in other questions like Postgresql copy data within the tree table for the tree copy (in my case I only copy the children and not the root) and PostgreSQL - Insert data into multiple tables simultaneously to insert data in several table simultaneously, but I don't manage to mix them.
I would like to:
Generate the new nodes id from the fields table
Insert the new field ids in the data_versions table
Insert the new nodes in the fields table with the data_id from the data_versions table
Note: there is a circular reference between the fields and the data_versions tables.
See below the schema:
Here is a working query, but without the insert in the data_versions table. It is only a shallow copy (keeping the same data_id) while I would like a deep copy:
WITH created_data AS (
WITH RECURSIVE cte AS (
SELECT *, nextval('fields_id_seq') new_id FROM fields WHERE parent_id = :source_field_id
UNION ALL
SELECT fields.*, nextval('fields_id_seq') new_id FROM cte JOIN fields ON cte.id = fields.parent_id
)
SELECT C1.new_id, C1.name, C1.field_type, C1.data_id, C2.new_id new_parent_id
FROM cte C1 LEFT JOIN cte C2 ON C1.parent_id = C2.id
)
INSERT INTO fields (id, name, parent_id, field_type, data_id)
SELECT new_id, name, COALESCE(new_parent_id, :target_field_id), field_type, data_id FROM created_data
RETURNING id, name, parent_id, field_type, data_id;
And here is the draft query I'm working on for inserting data in the data_versions table resulting with WITH clause containing a data-modifying statement must be at the top level as an error:
WITH created_data AS (
WITH cloned_fields AS (
WITH RECURSIVE cte AS (
SELECT *, nextval('fields_id_seq') new_id FROM fields WHERE parent_id = :source_field_id
UNION ALL
SELECT fields.*, nextval('fields_id_seq') new_id FROM cte JOIN fields ON cte.id = fields.parent_id
)
SELECT C1.new_id, C1.name, C1.field_type, C1.data_id, C2.new_id new_parent_id
FROM cte C1 LEFT JOIN cte C2 ON C1.parent_id = C2.id
),
cloned_data AS (
INSERT INTO data_versions (value, author, field_id)
SELECT d.value, d.author, c.new_id
FROM cloned_fields c
INNER JOIN data_versions d ON c.data_id = d.id
RETURNING id data_id
)
SELECT cloned_fields.new_id, cloned_fields.name, cloned_fields.field_type, cloned_fields.new_parent_id, cloned_data.data_id
FROM cloned_fields
INNER JOIN cloned_data ON cloned_fields.data_id = cloned_data.id
)
INSERT INTO fields (id, name, parent_id, field_type, data_id)
SELECT new_id, name, COALESCE(new_parent_id, :target_field_id), field_type, data_id FROM created_data
RETURNING id, name, parent_id, field_type, data_id, value data;
If other people were encountering the same issue as me, I came up with this solution some months later. The trick was to move the data-modifying CTE at the top level as suggested by the error message. We can always access previously declared CTE's:
WITH new_fields_ids AS (
WITH RECURSIVE cte AS (
SELECT *, nextval('fields_id_seq') new_id FROM fields WHERE parent_id = :source_field_id
UNION ALL
SELECT fields.*, nextval('fields_id_seq') new_id FROM cte JOIN fields ON cte.id = fields.parent_id
)
SELECT C1.new_id, C1.name, C1.field_type, C1.data_id, C2.new_id new_parent_id
FROM cte C1 LEFT JOIN cte C2 ON C1.parent_id = C2.id
),
cloned_data AS (
INSERT INTO data_versions (value, author, field_id)
SELECT d.value, d.author, c.new_id
FROM new_fields_ids c
INNER JOIN data_versions d ON c.data_id = d.id
RETURNING id AS data_id, field_id, value
),
created_data AS (
SELECT new_fields_ids.new_id, new_fields_ids.name, new_fields_ids.field_type, new_fields_ids.new_parent_id, cloned_data.data_id
FROM new_fields_ids
INNER JOIN cloned_data ON new_fields_ids.new_id = cloned_data.field_id
),
cloned_fields AS (
INSERT INTO fields (id, name, parent_id, field_type, data_id)
SELECT new_id, name, COALESCE(new_parent_id, :target_field_id), field_type, data_id FROM created_data
RETURNING id, name, parent_id, field_type, data_id
)
SELECT f.id, f.name, f.parent_id, f.field_type, f.data_id, d.value AS data FROM cloned_fields f
INNER JOIN cloned_data d ON f.id = d.field_id;

postgres how to insert values with 2 selects

I'm trying to do a query on Postgres but it's not working. I'd like to create an insert query with 2 select:
Example :
INSERT INTO table1 (id_1, id_2)
SELECT id from table_2 where code='01',
SELECT id from table_2 where code='02';
I don't find the good syntax for this.
I believe below query will works for your use case
INSERT INTO stats(totalProduct, totalCustomer, totalOrder)
VALUES(
(SELECT COUNT(*) FROM products),
(SELECT COUNT(*) FROM customers),
(SELECT COUNT(*) FROM orders)
);
you can changes query accordingly
You can add one more SELECT to achieve this
INSERT INTO table_1 (id_1, id_2)
SELECT
(SELECT id FROM table_2 WHERE code = '01') AS Id_1,
(SELECT id FROM table_2 WHERE code = '02') AS Id_2;
Or you may try with CASE expression:
INSERT INTO table1 (id_1, id_2)
SELECT MAX(CASE WHEN code = '01' THEN id ELSE 0 END) AS Id_1,
MAX(CASE WHEN code = '02' THEN id ELSE 0 END) AS Id_2
FROM table_2
Please refer to the working fiddle on db<>fiddle

How to define T-SQL variables in Insert statement

I have this example insert statement that used to work for copying matching rows from Table2 to Table1:
INSERT INTO Table1 SELECT * FROM Table2 WHERE ID='555'
When this statement was working, both tables had the same three columns, FirstName, LastName, and EmailAddr1.
I've since added a column, EmailAddr2, to Table1 that doesn't appear in Table2 and I want to make sure that my modified insert statement will work as I expect.
Will this accomplish my goal?
SELECT #EmailAddr2 = 'bill#mail.gov'
INSERT INTO Table1 SELECT FirstName, LastName, EmailAddr1, #EmailAddr2
FROM Table2 WHERE ID='555'
You should do:
declare #emailAddr2 varchar(50)
set #emailAddr2 = 'Bill#mail.gov'
Insert into Table1 ( firstname, lastname, emailaddr1, emailaddr2 )
select firstname, lastname, emailaddr1, #emailAddr2
from table2 where id = '555'

Join two tables with count from first table

I know there is an obvious answer to this question, but I'm like a noob trying to remember how to write queries. I have the following table structure in Postgresql:
CREATE TABLE public.table1 (
accountid BIGINT NOT NULL,
rpt_start DATE NOT NULL,
rpt_end DATE NOT NULL,
CONSTRAINT table1_pkey PRIMARY KEY(accountid, rpt_start, rpt_end)
)
WITH (oids = false);
CREATE TABLE public.table2 (
customer_id BIGINT NOT NULL,
read VARCHAR(255),
CONSTRAINT table2 PRIMARY KEY(customer_id)
)
WITH (oids = false);
The objective of the query is to display a result set of accountid's, count of accountid's in table1 and read from table2. The join is on table1.accountid = table2.customer_id.
The result set should appear as follows:
accountid count read
1234 2 100
1235 9 110
1236 1 91
The count column reflect the number of rows in table1 for each accountid. The read column is a value from table2 associated with the same accountid.
select accountid, "count", read
from
(
select accountid, count(*) "count"
from table1
group by accountid
) t1
inner join
table2 t2 on t1.accountid = t2.customer_id
order by accountid
SELECT table2.customer_id, COUNT(*), table2.read
FROM table2
LEFT JOIN table1 ON (table2.customer_id = table1.accountid)
GROUP BY table2.customer_id, table2.read
SELECT t2.customer_id, t2.read, COUNT(*) AS the_count
FROM table2 t2
JOIN table1 t1 ON t1.accountid = t2.customer_id
GROUP BY t2.customer_id, t2.read
;

display unique row from two tables

I have two tables (one for quarter one, one for quarter two), each of which contains employees who have bonus in that quarter. Every employee has a unique id in the company.
I want to get all employees who has bonus in either q1 or q2. No duplicate employee is needed. Both Id, and Amount are required.
Below is my solution, I want to find out if there is a better solution.
declare #q1 table (
EmployeeID int identity(1,1) primary key not null,
amount int
)
declare #q2 table (
EmployeeID int identity(1,1) primary key not null,
amount int
)
insert into #q1
(amount)
select 1
insert into #q1
(amount)
select 2
select * from #q1
insert into #q2
(amount)
select 1
insert into #q2
(amount)
select 11
insert into #q2
(amount)
select 22
select * from #q2
My Solution:
;with both as
(
select EmployeeID
from #q1
union
select EmployeeID
from #q2
)
select a.EmployeeID, a.amount
from #q1 as a
where a.EmployeeID in (select EmployeeID from both)
union all
select b.EmployeeID, b.amount
from #q2 as b
where b.EmployeeID in (select EmployeeID from both) and b.EmployeeID NOT in (select EmployeeID from #q1)
Result:
EmployeeID, Amount
1 1
2 2
3 22
SELECT EmployeeID, Name, SUM(amount) AS TotalBonus
FROM
(SELECT EmployeeID, Name, amount
from #q1
UNION ALL
SELECT EmployeeID, Name, amount
from #q2) AS all
GROUP BY EmployeeID, Name
The subselect UNIONS both tables together. The GROUP BY gives you one row per employee and the SUM means that if someone got lucky in both qs then you get the total. I'm guessing that's the right thing for you.
try this one:
SELECT EmployeeID
FROM EmployeeList
WHERE EmployeeID IN
(SELECT EmployeeID From QuarterOne
UNION
SELECT EmployeeID From QuarterTwo)
OR by using JOIN
SELECT EmployeeID
FROM EmployeeList a INNER JOIN QuarterTwo b
ON a.EmployeeID = b.EmployeeID
INNER JOIN QuarterTwo c
ON a.EmployeeID = c.EmployeeID
This will return all EmployeeID that has record in either quarter.
Try:
SELECT DISTINCT q1.EmployeeID --- Same as q2.EmployeeID thanks to the join
, q1.EmployeeName -- Not defined in OP source.
FROM #q1 AS q1
CROSS JOIN #q2 AS q2
WHERE q1.amount IS NOT NULL
OR q2.amount IS NOT NULL