I need to convert the week field into Date(mm/dd/yyyy).
Week 1 Week 2 Week 3 Week 4 Week 5 Week 6 Week 7 Week 8 Week 9 Week 10 Week 11 Week 12 Week 13 Week 14 Week 15 Week 16 Week 17 Week 18 Week 19 Week 20 Week 21 Week 22
Actually I have dragged the date field into Columns and I selected the week.
I need to convert this into Date (mm/dd/yyyy). How to achieve this?
Directly in your sheet, if you right click on your date field, you'll get a menu with the following options: "Filter", "Show quick filter", etc. You'll also see an option which says "Day.... May 8, 2011". That gives you a full date.
But if you want that date to have the "mm/dd/yyyy" format, you'll need to change it from the left pane. Right clicking on your date dimension provides the following option: "Default Properties/Date Format". You have a few default formats in there, including a custom formatting where you could make it mm/dd/yyyy.
Olivier
I think you want this formula: DATETRUNC('week', [day], 'Monday'), assuming your week starts on Monday. You may also need to change the format to m/d/y in the left-hand pane, per Jim Dehner: https://community.tableau.com/thread/234590
For dates 1/2 - 1/9/2017 this will return (Monday) 1/2/2017. For 1/9 - 1/16, it will return 1/9/2017, etc.
I believe this post could help you out: https://community.tableau.com/s/question/0D54T00000C6Y9TSAV/how-to-convert-week-number-into-a-date-format
Basically you can use this formula:
DATETRUNC('week',DATE(DATEADD('week', WEEK(TODAY())-1, DATE("01/01/"+STR(YEAR(TODAY()))))))
Related
I am trying to get week numbers ( resetting at 1 for each month) as per ISO format for each month in 2019.For example I am interested in getting
All dates in July 2019: week 1 to 4,
All dates in Aug 2019 : week 1 to 4 and so on.
I first created the calculated field (Week_Number_ISO) to get the overall week number in year 2019.I used the following formula;
DATEPART('iso-week',[ Date]) which works as intended.
To get the monthly week number I used the following formula
INT((DATEPART('day',[Created Date])-DATEPART('iso-weekday',[Created Date])+7)/7)+1.
(Idea was to calculate the date of the first day of each week & then divide by 7 and take the integer part)
As per the ISO format, shouldn't July 29 to 31st be a part of week 4 for July?But the formula is showing it as week 5 for July 2019.I feel I am missing something in the formula or am missing something about ISO week number resetting at 1 for each month.
Can someone help me?
Here is an example of the dates in July 2019 and the associated week numbers.
Why would July 28th-July 31st 2019 be considered week 4?
I need help on calculating my start date for my report date parameters.
The end date will always be the last Sunday, here: =DateAdd("d", 1 - WeekDay(Today(), 1), Today())
What I need help with is how to write a formula to go back 6 months from today and pick the 1st Saturday in that range..
Thanks in advance.
Assuming your start day is a Sunday then you can use this...
=DATEADD(
DateInterval.Day,
7 - WEEKEDAY( DATEADD(DateInterval.Month,-6,Today()), FirstDayOfWeek.Sunday),
DATEADD(DateInterval.Month,-6,Today())
)
This works as follows
WEEKEDAY( DATEADD(DateInterval.Month,-6,Today()), FirstDayOfWeek.Sunday)
Takes today's date, subtracts 6 months and then finds out what daynumber that is. Running that today (2018-11-08) gives use (2018-05-10) which is a Thursday, this is day number 5
Saturdays are day number 7 (if your first day of week is a Sunday). As there can be no higher number than 7 we can do a simple subtraction of 7 minus the day number we landed on (from above) which gives us a required adjustment of 2 days.
Finally the outer DATEADD function simply says add our calculated 2 days to the date 6 months ago.
Hope that makes sense!?
If the first day of the week is not a Sunday for you then you may have to do some Mod% calc on the second argument to calculate the correct number of days to adjust by.
Would it be possible to get same day of week last year using Excel? please below example:
Input: Monday 9 Nov 2015 | Output: 10 Nov 2014
Thanks
Simply subtract 52 full weeks with 7 days = 364 days. So if the date is in A1, the formula =A1-364 will get the date exactly 52 weeks before, which is the same day of week in the year before.
To show that it works even for leap years, try the following:
You see the formula date - 364 (=A2-364, =A3-364, ...) always gets the same day of week a year before. That is because it gets the day minus 52 full weeks (52 * 7 days) before. In leap years it gets a different day but the same day of week.
Try this:
=DATE(YEAR(A1)-1,MONTH(A1),DAY(A1))+WEEKDAY(A1)-WEEKDAY(DATE(YEAR(A1)-1,MONTH(A1),DAY(A1)))
It returns the closest date within a week. A1 is the cell with this year's date.
I have an access column which has values like May, May-June, November, January-February etc.
Requirement is that
1) If only one month is there, I should create a transformation with a date column pointing to the last date of that month and the year would be the current year.
Eg May would be 5/30/2015, January would be 1/31/2015
2) If it is having two months, then second month must be taken and the same logic as in Point 1 should be implemented.
Eg May-June would be 6/31/2015, January-February would be 2/28/2015.
My first preference would be without using VBA code.
Please help.
You can use a one-liner in a function:
Public Function GetDateFromMonth(ByVal Months As String) As Date
Dim Ultimo As Date
Ultimo = DateAdd("d", -1, DateAdd("m", 1 + UBound(Split(Months, "-")), CDate(Split(Months, "-")(0) & "/1")))
GetDateFromMonth = Ultimo
End Function
Split the string on the "-", use the second month, add one to that month to get the next month, then take the first day of that month and subtract one from it. For example Jan-Feb : build 3/1/2015 and then subtract 1 day to get the last day of Feb.
Make a table that holds a list of Months:
MonthName MonthNumber
January 1
February 2
March 3
April 4
May 5
June 6
July 7
August 8
September 9
October 10
November 11
December 12
Create this query:
SELECT InputData.Months, DateSerial(Year(Date()),[MonthNumber]+1,0) AS ReqdDate
FROM InputData, Months
WHERE (((IIf(InStr([Months],'-')=0,[Months],Mid([Months],InStr([Months],'-')+1)))=[MonthName]));
That's it. Output looks like this:
Months ReqdDate
May 31/05/2015
May-June 30/06/2015
November 30/11/2015
January-February 28/02/2015
March 31/03/2015
April-September 30/09/2015
Sorry about formatting - noob. I'm in Eu so my dates look odd to you, but you get the idea; you can make them US dates in a moment I'm sure. You can use the bits of this you need in your code in two secs.
If you don't like the lookup table for month number, I'm sure you can use some format function to turn the month name into a month number.
I'm using SAS 9.3
I need to create a way to sum up by week total, and I have no idea how to do it. So basically I have a year list of dates (left column below) with a total from that date (the right column). Our week goes from Friday to the previous Thursday (e.g. Thursday Oct 17 through Friday the Oct 25th).
An issue I also have is as you see the dates on the left are not completely daily and don't always have a Thursday date before the last Friday date. Would any know a way to add these weeks up - Week 1, Week 2, etc etc ...?
Thanks for any help that can be provided
2013-01-01 3
2013-01-02 8
2013-01-03 8
2013-01-04 10
2013-01-06 1
2013-01-07 10
2013-01-08 14
2013-01-09 12
2013-01-10 8
2013-01-11 9
2013-01-12 1
2013-01-14 12
2013-01-15 8
2013-01-16 5
2013-01-17 15
2013-01-18 7
2013-01-20 1
Trivial way:
data want;
set have;
weekno = ceil((date-'03JAN2013'd)/7);
run;
IE, subtract the first thursday and divide by 7, (so 1/1-1/3 is weekno=0).
INTCK function is also adept at calculating this. The basic structure is
weekno=intck('WEEK.5','04JAN2013'd,date); *the second argument is when you want your first week to start;
WEEK means calculate weeks, # on left side of decimal is multiple week groups (2 week periods is WEEK2.), on right side is shift index (from the default sunday-saturday week).
You could also create a format that contained your weeks, and use that.