I have a string
my $string = $14.275; ## where i need to remove the $
I have tried by using the below code
$y = substr($string , 1, index($string));
The output should be 14.275
First quotes string value and write code like this:
#!/usr/bin/perl
use warnings;
use strict;
my $string = '$14.275';
$string =~ s/^\$//;
print "$string\n";
Output:
14.275
Related
I need to get the subset of a string starting from a specific start word and end before the specified word. Store in the string variable.
Example: pre-wrap">test-for??maths/camp
I need to fetch the subset.
Expected output: test-for??maths
After: pre-wrap"> or may be starting with: test
and before: /camp
I have no clue how to achieve this in Perl.
Here is the code I tried. The output is not coming as expected:
#!/usr/bin/perl
use warnings;
use strict;
my $string = 'pre-wrap">test-for??maths/camp';
my $quoted_substring = quotemeta($string);
my ($quoted_substring1) = split('/camp*', $quoted_substring);
my (undef, $substring2) = split('>\s*', $quoted_substring1);
print $string, "\n";
print $substring2, "\n";
Output:
$ perl test.pl
pre-wrap">test-for??maths/camp
test\-for\?\?maths\ # but why this \ is coming
The following code extracts the part between $before and $after (which may contain regex metacharacters, they are treated as pure characters inside the \Q...\E expressions):
my $string = 'pre-wrap">test-for??maths/camp';
my $before = 'pre-wrap">';
my $after = '/camp';
if ($string =~ /\Q$before\E(.*?)\Q$after\E/) {
print $1; # prints 'test-for??maths'
}
pre-wrap">test-for??maths/camp is in 'd',
perl -ne '/((?<=pre-wrap">)|(?<=>)(?=test))\S+(?=\/camp)/ ; print $&' d
I tried something like this :
use Text::ParseWords;
my $var="Id;Id2;my name 'is Ankit;code";
my #temp = quotewords('\;',1,$var);
my $length = scalar #temp;
print "$length\n";
I can use split() but it does not work in case of - "Id;Id2;"my name is ;Ankit";code". Any suggestions ?
You have to escape the single quote.
use strict;
use warnings;
use Text::ParseWords;
my $var = q{Id;Id2;my name \'is Ankit;code};
my #words = quotewords('\;', 0, $var);
print scalar #words; #prints 4
Here's I want to archive. I want to split a one-liner comma-separated and insert #domain.com then join it back as comma-separated.
The one-liner contains something like:
username1,username2,username3
and I want to be something like:
username1#domain.com,username2#domain.com,username3#domain.com
So my Perl script that I tried which doesn't not work properly:
my $var ='username1,username2,username3';
my #tkens = split /,/, $var;
my #user;
foreach my $tken (#tkens) {
push (#user, "$tken\#domain.com");
}
my $to = join(',',#user);
Is there any shortcut on this in Perl and please post sample please. Thanks
Split, transform, stitch:
my $var ='username1,username2,username3';
print join ",", map { "$_\#domain.com" } split(",", $var);
# ==> username1#domain.com,username2#domain.com,username3#domain.com
You could also use a regular expression substitution:
#!/usr/bin/perl
use strict;
use warnings;
my $var = "username1,username2,username3";
# Replace every comma (and the end of the string) with a comma and #domain.com
$var =~ s/$|,/\#domain.com,/g;
# Remove extra comma after last item
chop $var;
print "$var\n";
You already have good answers. Here I am just telling why your script is not working. I didn't see any print or say line in your code, so not sure how you are trying to print something. No need of last line in your program. You can simply suffix #domain.com with each value, push to an array and print it with join.
#!/usr/bin/perl
use strict;
use warnings;
my $var = 'username1,username2,username3';
my #tkens = split ',', $var;
my #user;
foreach my $tken (#tkens)
{
push #user, $tken."\#domain.com"; # `.` after `$tken` for concatenation
}
print join(',', #user), "\n"
Output:
username1#domain.com,username2#domain.com,username3#domain.com
I'm trying to find the index of the first occurrence of a number from 0-9.
Let's say that:
$myString = "ABDFSASF9fjdkasljfdkl1"
I want to find the position where 9 is.
I've tried this:
print index($myString,[0-9]);
And:
print index($myString,\d);
Use regex Positional Information:
use strict;
use warnings;
my $myString = "ABDFSASF9fjdkasljfdkl1";
if ($myString =~ /\d/) {
print $-[0];
}
Outputs:
8
You can try even below perl code:
use strict;
use warnings;
my $String = "ABDFSASF9fjdkasljfdkl11";
if($String =~ /(\d)/)
{
print "Prematch string of first number $1 is $`\n";
print "Index of first number $1 is " . length($`);
}
You can try this:
perl -e '$string="ABDFSASF9fjdkasljfdkl1";#array=split(//,$string);for $i (0..$#array) {if($array[$i]=~/\d/){print $i;last;}}'
The content of my input file is shown below:
abc\**def\ghi**\abc\!!!!!
abc\**4nfiug\frgrefd\gtefe\wf4fs**\abc\df3gwddw
abc\**eg4/refw**\abc\f3
I need to replace whatever string in between abc \ --------------\abc in my input file with ABC\CBA.
I have tried something like below to get the strings that need to be replaced. But I get stuck when I need to use the search and replace:
my $string1 = qr/abc\W+([^a]+)/;
my $string2 = map{/$string1/ => " "} #input_file; # The string that needs to be replaced
my $string3 = 'ABC\CBA' # String in that. I want it to replace to
s/$string2/$string3/g
How can I fix this?
perl -i -pe 's/this/that/g;' file1
A one-liner to fix a file:
perl -plwe 's/abc\\\K.*(?=\\abc)/ABC\\CBA/' input.txt > output.txt
Or as a script:
use strict;
use warnings;
while (<DATA>) {
s/abc\\\K.*(?=\\abc)/ABC\\CBA/;
print;
}
__DATA__
abc\**def\ghi**\abc\!!!!!
abc\**4nfiug\frgrefd\gtefe\wf4fs**\abc\df3gwddw
abc\**eg4/refw**\abc\f3
The \K (keep) escape sequence means these characters will not be removed. Similarly, the look-ahead assertion (?= ... ) will keep that part of the match. I assumed you only wanted to change the characters in between.
Instead of \K one can use a look-behind assertion: (?<=abc\\). As a personal preference, I used \K instead.
#!/usr/bin/perl
use strict;
use warnings;
open my $fh,"<", "tryit.txt" or die $!;
while (my $line = <$fh>) {
$line =~ s/(abc\\)(.*?)(\\abc)/$1ABC\\CBA$3/;
print $line;
}
gives the following with the input data.
abc\ABC\CBA\abc\!!!!!
abc\ABC\CBA\abc\df3gwddw
abc\ABC\CBA\abc\f3
If you do not want the substitution to operate on the default variable $_, you have to use the =~ operator:
#!/usr/bin/perl
use warnings;
use strict;
my #input_file = split /\n/, <<'__EOF__';
abc\**def\ghi**\abc\!!!!!
abc\**4nfiug\frgrefd\gtefe\wf4fs**\abc\df3gwddw
abc\**eg4/refw**\abc\f3
__EOF__
my $pattern = qr/abc\\.*\\abc/; # pattern to be matched
my $string2 = join "\n", #input_file; # the string that need to be replaced
my $string3 = 'ABC\CBA'; # string i that i want it to replace to
$string2 =~ s/$pattern/$string3/g;
print $string2;
To address your comment about replacing text "inplace" in the file directly, you can use the -i switch for a one-liner. In a script, you can perhaps look at using Tie::File, which allows read-write access to lines of a file as (mutable) elements in an array. To copy Mike/TLP's answer:
#!/usr/bin/perl
use strict;
use warnings;
use Tie::File;
tie my #file, "Tie::File", "tryit.txt" or die $!;
# I think you have to use $_ here (done implicitly)
while (#file) {
s/(abc\\)(.*?)(\\abc)/$1ABC\\CBA$3/;
print;
}