I am now writing a program involves class and dictionaries. I wonder how could I access a class's values inside a dictionary. For the code below how do I access the test1 value using the dictionary. I have tried using dict[1].test1but it doesn't work.
class test {
var tes1 = 1
}
var refer = test()
var dict = [1:refer]
There are a few problems with the line dict[1].test1:
Firstly, the subscript on a dictionary returns an optional type because there may not be a value for the key. Therefore you need to check a value exists for that key.
Secondly, in your class Test you've defined a variable tes1, but you're asking for test1 from your Dictionary. This was possibly just a type-o though.
To solve these problems you're code should look something like this:
if let referFromDictionary = dict[1] {
prinln(referFromDictionary.test1)
}
That's because the subscript returns an optional, so you have to unwrap it - and the most straightforward way is by using optional chaining:
dict[1]?.tes1
but you can also use optional binding:
if let test = dict[1] {
let value = test.tes1
}
Related
Let's say I have the following class:
class User: NSObject {
var name = "Fred"
var age = 24
var email = "fred#freddy.com"
var married = false
}
I want to be able to write a generic function that takes in a list of KeyPaths for a known class type, read the values and print to screen. The problem is, the I can't get the following code to compile as the type of the KeyPath's Value is not known, and will be different for each time. What do I have to do to make this work generically?
Consider the following:
struct KeyPathProperties<T> {
var name: String
var relatedKeyPaths: [KeyPath<T, Any>]
}
extension KeyPath where Root == User {
var properties: KeyPathProperties<Root> {
switch self {
case \Root.name:
return KeyPathProperties(name: "name", relatedKeyPaths: [\Root.age, \Root.email])
default:
fatalError("Unknown key path")
}
}
}
This line fails to compile:
return KeyPathProperties(name: "name", relatedKeyPaths: [\Root.age, \Root.email])
with this error:
Cannot convert value of type 'KeyPath<User, Int>' to expected element type 'KeyPath<User, Any>'
This is what I wish to be able to do, for instance:
let myUser = User()
var keyPathProps = KeyPathProperties(name: "name", relatedKeyPaths: [\User.age, \User.email])
for keyPath in props.relatedKeyPaths {
print("Value: \(myUser[keyPath: keyPath])")
}
The above won't compile of course. Essentially I want to store keyPaths in an array at runtime, so I can generically at some point in time get values out of the User. I need to know if I can re-write the above in some way where the compiler can safely and correctly determine the type of the keyPath's value at runtime.
This is a conceptual use case for a much more complex architectural issue I'm trying to solve with hopefully less code.
MORE INFORMATION:
At runtime I wish to keep track of the properties that get modified - these properties are held in a modifiedProps array in each object / instance. At some point at runtime, I wish to be able to enumerate over this array of KeyPaths and print their values like so:
for modifiedKeyPath in self.modifiedProps {
print ("\(self[keyPath: modifiedKeyPath])"
}
In short - I need to be able to capture the generic type of the KeyPath within KeyPathProperties. How do I achieve this?
SIDE NOTE: I can already easily achieve this by using Swift 3 style string based KeyPaths (by adding #objc to the class properties). I can store an array of keyPaths as strings and later do:
let someKeyPath = #keyPath(User.email)
...
myUser.value(forKeyPath: someKeyPath)
I just cannot do this with Swift 4 KeyPaths generically.
The error tells you what your misconception is:
Cannot convert value of type 'KeyPath<User, Int>'
to expected element type 'KeyPath<User, Any>'
You seem to think that you can use a KeyPath<User, Int> where a KeyPath<User, Any> is expected, ostensibly on the grounds that an Int is an Any. But that's not true. These are generic types, and generic types are not covariant — that is, there is no substitution principle for generics based on their parameterized types. The two types are effectively unrelated.
If you need an array of key paths regardless of their parameterized types, you would need an array of PartialKeyPath or AnyKeyPath. It seems that in your use case the root object is the same throughout, so presumably you want PartialKeyPath.
I want to initialize every time a struct with dictionaries. Later, I'm going to use its properties instead a dictionary's keys and values - it seems rather easier. However, when I try the code below, it tells me that "Return from initializer without initializing all stored properties" and "1. 'self.one' not initialized" and "2. 'self.two' not initialized". My question is how to initialize a struct from a dictionary, so that I have basically a struct with the contents of the dictionary? Or how to transform it into struct?
struct Blabla {
var one: String
var two: [Int]
init(three: [String: [Int]]) {
for i in three {
self.one = i.key
self.two = i.value
}
} ERROR! - Return from initializer without initializing all stored properties
}
struct Blabla {
var one: String
var two: [Int]
init(three: [String: [Int]]) {
one = ""
two = []
for i in three {
self.one = i.key
self.two = i.value
}
} ERROR! - Return from initializer without initializing all stored properties
}
for in clause may have zero runs, in which case struct properties will not be initialized. You have to provide default values (or emit fatalError if you really need to).
While I think your example is pure synthetical, there is no need to loop through array, you can set properties to its last entry.
The issues is that if three is an empty Dictionary, the instance properties one and two don't get initialised. Also, you are overwriting the properties in each iteration of the for loop and the compiler cannot guarantee that there will be any iterations of the loop in compile-time, hence the compiler error.
You could make the initialiser failable to account for this by checking that the dictionary actually contains at least one key-value pair and assigning that first key-value pair to your properties.
struct Blabla {
var one: String
var two: [Int]
init?(three: [String: [Int]]) {
guard let key = three.keys.first, let value = three[key] else { return nil }
one = key
two = value
}
}
However, you should rethink what it is that you are actually trying to achieve, since with your current setup you have a mismatch between your init input values and the properties of your struct.
This code should compile, but it feels unsafe to me to initialize a Struct in this way because:
It assume your dictionary has values in it.
Your stored properties will always have the last value you looped through.
In order to pull values out to satisfy the compiler you need to force unwrap them. (With Dávid Pásztor's guard-letting approach, this can be avoided)
struct Blabla {
var one: String
var two: [Int]
init(three: [String: [Int]]) {
self.one = three.keys.first!
self.two = three[three.keys.first!]!
}
}
let input = ["pizza": [1,2]]
let l = Blabla(three: input)
If I were you I would let the memberwise initializer that you get for free do its thing and provide either a specialized initializer to handle your case of taking a Dictionary as input or move that parsing to another function/class/etc....
The compiler error is clear: If the dictionary is empty the struct members are never initialized. But the code makes no sense anyway as each iteration of the dictionary overwrites the values.
Maybe you mean to map the dictionary to an array of the struct
struct Blabla {
let one: String
let two: [Int]
}
let three = ["A":[1,2], "B":[3,4]]
let blabla = three.map{Blabla(one: $0.key, two: $0.value)}
print(blabla) // [Blabla(one: "A", two: [1, 2]), Blabla(one: "B", two: [3, 4])]
struct blabla{
var a : string
var b : [int] = []
init(_ data: [string:[int]]){
// whatever you want to do
}
}
Consider the following example.
struct AStruct{
var i = 0
}
class AClass{
var i = 0
var a: A = A(i: 8)
func aStruct() -> AStruct{
return a
}
}
If I try to mutate the the variable of a instance of class AClass it compiles successfully.
var ca = AClass()
ca.a.i = 7
But If I try to mutate the return value of aStruct method, the compile screams
ca.aStruct().i = 8 //Compile error. Cannot assign to property: function call returns immutable value.
Can someone explain this.
This is compiler's way of telling you that the modification of the struct is useless.
Here is what happens: when you call aStruct(), a copy of A is passed back to you. This copy is temporary. You can examine its fields, or assign it to a variable (in which case you would be able to access your modifications back). If the compiler would let you make modifications to this temporary structure, you would have no way of accessing them back. That is why the compiler is certain that this is a programming error.
Try this.
var aValue = ca.aStruct()
aValue.i = 9
Explanation
aStruct() actually returns a copy of the original struct a. it will implicitly be treated as a constant unless you assign it a var.
Try using a class instead of a struct, as it's passed by reference and holds onto the object, while a struct is passed by value (a copy is created).
I have a dictionary declared like this:
var myDict = [Int : [Int]]()
The array in it is not initialized, so every time I have to check it first:
if (myDict[idx] == nil) {
myDict[idx] = []
}
How to initialize it as an empty array in MyDict declaration?
I think you could be misunderstanding something pretty key - let's make sure:
The way the dictionary works, is not to have one array, but an array for each key.
Each value of 'idx' you request the array for returns a different array.
You can't expect it to return an empty array - a dictionary is meant to return a nil value for a key that hasn't been set. To do what you're trying, the following would probably do the trick:
myDict[idx] = myDict[idx] ?? []
That's what dictionary do if you try to retrieve a key for which no value exists.
You can subclass Dictionary and override the subscript func to get what you want like this. Or simply write an extension, or write a operator defination to use a different symbol.
“You can also use subscript syntax to retrieve a value from the dictionary for a particular key. Because it is possible to request a key for which no value exists, a dictionary’s subscript returns an optional value of the dictionary’s value type. ”
Excerpt From: Apple Inc. “The Swift Programming Language (Swift 2.1).” iBooks. https://itunes.apple.com/cn/book/swift-programming-language/id881256329?l=en&mt=11
You can initialize it this way
myDict.forEach {
(var dictElement) -> () in
dictElement.1 = [Int]()
}
Lets say I want to do this:
class foobar : NSObject {
//method declarations, etc.
}
Then later:
let myDictionary:Dictionary = ["returnMeAnAwesomeClass":foobar]
Does not work.
If I put in foobar.Type, it also doesn't work.
If I put in foobar.class as foobar.Type, it also doesn't work.
The reason I want this is because there's a method in a system API that takes a class as the argument, e.g.:
func enterState(_ stateClass: AnyClass) -> Bool
(in GKStateMachine)
I'd find it acceptable to be able to get a string and turn that into a class.
You can use foobar.self if you need to obtain the class type. And also you should add type safety to your dictionary:
let myDictionary: [String:AnyClass] = ["returnMeAnAwesomeClass": foobar.self]
If you're initializing the dictionary at the same place where you're declaring it, you can skip the type declaration, as the compiler will infer it:
let myDictionary = ["returnMeAnAwesomeClass": foobar.self]