I want to extract lines that have a particular pattern, in a certain column. For example, in my 'input.txt' file, I have many columns. I want to search the 25th column for 'foobar', and extract only those lines that have 'foobar' in the 25th column. I cannot do:
grep foobar input.txt
because other columns may also have 'foobar', and I don't want those lines. Also:
the 25th column will have 'foobar' as part of a string (i.e. it could be 'foobar ; muller' or 'max ; foobar ; john', or 'tom ; foobar35')
I would NOT want 'tom ; foobar35'
The word in column 25 must be an exact match for 'foobar' (and ; so using awk $25=='foobar' is not an option.
In other words, if column 25 had the following lines:
foobar ; muller
max ; foobar ; john
tom ; foobar35
I would want only lines 1 & 2.
How do I use xargs and sed to extract these lines? I am stuck at:
cut -f25 input.txt | grep -nw foobar | xargs -I linenumbers sed ???
thanks!
Do not use xargs and sed, use the other tool common on so many machines and do this:
awk '{if($25=="foobar"){print NR" "$0}}' input.txt
print NR prints the line number of the current match so the first column of the output will be the line number.
print $0 prints the current line. Change it to print $25 if you only want the matching column. If you only want the output, use this:
awk '{if($25=="foobar"){print $0}}' input.txt
EDIT1 to match extended question:
Use what #shellter and #Jotne suggested but add string delimiters.
awk -vFPAT="([^ ]*)|('[^']*')" -vOFS=' ' '$25~/foobar/' input.txt
[^ ]* matches all characters that are not a space.
'[^']*' matches everything inside single quotes.
EDIT2 to exclude everything but foobar:
awk -vFPAT="([^ ]*)|('[^']*')" -vOFS=' ' "\$25~/[;' ]foobar[;' ]/" input.txt
[;' ] only allows ;, ' and in front and after foobar.
Tested with this file:
1 "1 ; 1" 4
2 'kom foobar' 33
3 "ll;3" 3
4 '1; foobar' asd
7 '5 ;foobar' 2
7 '5;foobar' 0
2 'kom foobar35' 33
2 'kom ; foobar' 33
2 'foobar ; john' 33
2 'foobar;paul' 33
2 'foobar1;paul' 33
2 'foobarli;paul' 33
2 'afoobar;paul' 33
and this command awk -vFPAT="([^ ]*)|('[^']*')" -vOFS=' ' "\$2~/[;' ]foobar[;' ]/" input.txt
To get the line with foobar as part of the 25 field.
awk '$25=="foobar"' input.txt
$25 25th filed
== equal to
"foobar"
Since no action spesified, print the complete line will be done, same as {print $0}
Or
awk '$25~/^foobar$/' input.txt
This might work for you (GNU sed):
sed -En 's/\S+/\n&\n/25;s/\n(.*foobar.*)\n/\1/p' file
Surround the 25th field by newlines and pattern match for foobar between newlines.
If you only want to match the word foobar use:
sed -En 's/\S+/\n&\n/25;s/\n(.*\<foobar\>.*)\n/\1/p' file
I have a file, xx.txt, like this.
1PPYA
2PPYB
1GBND
1CVHA
The first line of this file is "1PPYA". I would like to
Read the last character of "1PPYA." In this example, it's "A/"
Find "1PPY.txt" (the first four characters) from the "yy" directory.
Delete the lines start with "csh" which contain the "A" character.
Given the following "1PPY.txt" in the "yy" directory:
csh 1 A 1 27.704 6.347
csh 2 A 1 28.832 5.553
csh 3 A 1 28.324 4.589
csh 4 B 1 27.506 3.695
csh 5 C 1 29.411 4.842
csh 6 A 1 28.378 4.899
The required output would be:
csh 4 B 1 27.506 3.695
csh 5 C 1 29.411 4.842
Assuming your shell is bash
while read word; do
if [[ $word =~ ^(....)(.)$ ]]; then
filename="yy/${BASH_REMATCH[1]}.txt"
letter=${BASH_REMATCH[2]}
if [[ -f "$filename" ]]; then
sed "/^csh.*$letter/d" "$filename"
fi
fi
done < xx.txt
As you've tagged the question with awk:
awk '{
filename = "yy/" substr($1,1,4) ".txt"
letter = substr($1,5)
while (getline < filename)
if (! match($0, "^csh.*" letter))
print
close(filename)
}' xx.txt
This might work for you:
sed 's|^ *\(.*\)\(.\)$|sed -i.bak "/^ *csh.*\2/d" yy/\1.txt|' xx.txt | sh
N.B. I added a file backup. If this is not needed amend the -i.bak to -i
You can use this bash script:
while read f l
do
[[ -f $f ]] && awk -v l=$l '$3 != l' $f
done < <(awk '{len=length($0);l=substr($0,len);f=substr($0,0,len-1);print "yy/" f ".txt", l;}' xx.txt)
I posted this because you are a new user, however it will be much better to show us what you have tried and where you're stuck.
TXR:
#(next "xx.txt")
#(collect)
#*prefix#{suffix /./}
# (next `yy/#prefix.txt`)
# (collect)
# (all)
#{whole-line}
# (and)
# (none)
#shell #num #suffix #(skip)
# (end)
# (end)
# (do (put-string whole-line) (put-string "\n"))
# (end)
#(end)
Run:
$ txr del.txr
csh 4 B 1 27.506 3.695
csh 5 C 1 29.411 4.842
txr: unhandled exception of type file_error:
txr: (del.txr:5) could not open yy/2PPY.txt (error 2/No such file or directory)
Because of the outer #(collect)/#(end) (easily removed) this processes all of the lines from xx.txt, not just the first line, and so it blows up because I don't have 2PPY.txt.
I have a ~23000 line SQL dump containing several databases worth of data. I need to extract a certain section of this file (i.e. the data for a single database) and place it in a new file. I know both the start and end line numbers of the data that I want.
Does anyone know a Unix command (or series of commands) to extract all lines from a file between say line 16224 and 16482 and then redirect them into a new file?
sed -n '16224,16482p;16483q' filename > newfile
From the sed manual:
p -
Print out the pattern space (to the standard output). This command is usually only used in conjunction with the -n command-line option.
n -
If auto-print is not disabled, print the pattern space, then, regardless, replace the pattern space with the next line of input. If
there is no more input then sed exits without processing any more
commands.
q -
Exit sed without processing any more commands or input.
Note that the current pattern space is printed if auto-print is not disabled with the -n option.
and
Addresses in a sed script can be in any of the following forms:
number
Specifying a line number will match only that line in the input.
An address range can be specified by specifying two addresses
separated by a comma (,). An address range matches lines starting from
where the first address matches, and continues until the second
address matches (inclusively).
sed -n '16224,16482 p' orig-data-file > new-file
Where 16224,16482 are the start line number and end line number, inclusive. This is 1-indexed. -n suppresses echoing the input as output, which you clearly don't want; the numbers indicate the range of lines to make the following command operate on; the command p prints out the relevant lines.
Quite simple using head/tail:
head -16482 in.sql | tail -258 > out.sql
using sed:
sed -n '16224,16482p' in.sql > out.sql
using awk:
awk 'NR>=16224&&NR<=16482' in.sql > out.sql
You could use 'vi' and then the following command:
:16224,16482w!/tmp/some-file
Alternatively:
cat file | head -n 16482 | tail -n 258
EDIT:- Just to add explanation, you use head -n 16482 to display first 16482 lines then use tail -n 258 to get last 258 lines out of the first output.
There is another approach with awk:
awk 'NR==16224, NR==16482' file
If the file is huge, it can be good to exit after reading the last desired line. This way, it won't read the following lines unnecessarily:
awk 'NR==16224, NR==16482-1; NR==16482 {print; exit}' file
awk 'NR==16224, NR==16482; NR==16482 {exit}' file
perl -ne 'print if 16224..16482' file.txt > new_file.txt
People trying to wrap their heads around computing an interval for the head | tail combo are overthinking it.
Here's how you get the "16224 -- 16482" range without computing anything:
cat file | head -n +16482 | tail -n +16224
Explanation:
The + instructs the head/tail command to "go up to / start from" (respectively) the specified line number as counted from the beginning of the file.
Similarly, a - instructs them to "go up to / start from" (respectively) the specified line number as counted from the end of the file
The solution shown above simply uses head first, to 'keep everything up to the top number', and then tail second, to 'keep everything from the bottom number upwards', thus defining our range of interest (with no need to compute an interval).
Standing on the shoulders of boxxar, I like this:
sed -n '<first line>,$p;<last line>q' input
e.g.
sed -n '16224,$p;16482q' input
The $ means "last line", so the first command makes sed print all lines starting with line 16224 and the second command makes sed quit after printing line 16428. (Adding 1 for the q-range in boxxar's solution does not seem to be necessary.)
I like this variant because I don't need to specify the ending line number twice. And I measured that using $ does not have detrimental effects on performance.
# print section of file based on line numbers
sed -n '16224 ,16482p' # method 1
sed '16224,16482!d' # method 2
cat dump.txt | head -16224 | tail -258
should do the trick. The downside of this approach is that you need to do the arithmetic to determine the argument for tail and to account for whether you want the 'between' to include the ending line or not.
sed -n '16224,16482p' < dump.sql
Quick and dirty:
head -16428 < file.in | tail -259 > file.out
Probably not the best way to do it but it should work.
BTW: 259 = 16482-16224+1.
I wrote a Haskell program called splitter that does exactly this: have a read through my release blog post.
You can use the program as follows:
$ cat somefile | splitter 16224-16482
And that is all that there is to it. You will need Haskell to install it. Just:
$ cabal install splitter
And you are done. I hope that you find this program useful.
Even we can do this to check at command line:
cat filename|sed 'n1,n2!d' > abc.txt
For Example:
cat foo.pl|sed '100,200!d' > abc.txt
Using ruby:
ruby -ne 'puts "#{$.}: #{$_}" if $. >= 32613500 && $. <= 32614500' < GND.rdf > GND.extract.rdf
I wanted to do the same thing from a script using a variable and achieved it by putting quotes around the $variable to separate the variable name from the p:
sed -n "$first","$count"p imagelist.txt >"$imageblock"
I wanted to split a list into separate folders and found the initial question and answer a useful step. (split command not an option on the old os I have to port code to).
Just benchmarking 3 solutions given above, that works to me:
awk
sed
"head+tail"
Credits on the 3 solutions goes to:
#boxxar
#avandeursen
#wds
#manveru
#sibaz
#SOFe
#fedorqui 'SO stop harming'
#Robin A. Meade
I'm using a huge file I find in my server:
# wc fo2debug.1.log
10421186 19448208 38795491134 fo2debug.1.log
38 Gb in 10.4 million lines.
And yes, I have a logrotate problem. : ))
Make your bets!
Getting 256 lines from the beginning of the file.
# time sed -n '1001,1256p;1256q' fo2debug.1.log | wc -l
256
real 0m0,003s
user 0m0,000s
sys 0m0,004s
# time head -1256 fo2debug.1.log | tail -n +1001 | wc -l
256
real 0m0,003s
user 0m0,006s
sys 0m0,000s
# time awk 'NR==1001, NR==1256; NR==1256 {exit}' fo2debug.1.log | wc -l
256
real 0m0,002s
user 0m0,004s
sys 0m0,000s
Awk won. Technical tie in second place between sed and "head+tail".
Getting 256 lines at the end of the first third of the file.
# time sed -n '3473001,3473256p;3473256q' fo2debug.1.log | wc -l
256
real 0m0,265s
user 0m0,242s
sys 0m0,024s
# time head -3473256 fo2debug.1.log | tail -n +3473001 | wc -l
256
real 0m0,308s
user 0m0,313s
sys 0m0,145s
# time awk 'NR==3473001, NR==3473256; NR==3473256 {exit}' fo2debug.1.log | wc -l
256
real 0m0,393s
user 0m0,326s
sys 0m0,068s
Sed won. Followed by "head+tail" and, finally, awk.
Getting 256 lines at the end of the second third of the file.
# time sed -n '6947001,6947256p;6947256q' fo2debug.1.log | wc -l
A256
real 0m0,525s
user 0m0,462s
sys 0m0,064s
# time head -6947256 fo2debug.1.log | tail -n +6947001 | wc -l
256
real 0m0,615s
user 0m0,488s
sys 0m0,423s
# time awk 'NR==6947001, NR==6947256; NR==6947256 {exit}' fo2debug.1.log | wc -l
256
real 0m0,779s
user 0m0,650s
sys 0m0,130s
Same results.
Sed won. Followed by "head+tail" and, finally, awk.
Getting 256 lines near the end of the file.
# time sed -n '10420001,10420256p;10420256q' fo2debug.1.log | wc -l
256
real 1m50,017s
user 0m12,735s
sys 0m22,926s
# time head -10420256 fo2debug.1.log | tail -n +10420001 | wc -l
256
real 1m48,269s
user 0m42,404s
sys 0m51,015s
# time awk 'NR==10420001, NR==10420256; NR==10420256 {exit}' fo2debug.1.log | wc -l
256
real 1m49,106s
user 0m12,322s
sys 0m18,576s
And suddenly, a twist!
"Head+tail" won. Followed by awk and, finally, sed.
(some hours later...)
Sorry guys!
My analysis above ends up being an example of a basic flaw in doing an analysis.
The flaw is not knowing in depth the resources used for the analysis.
In this case, I used a log file to analyze the performance of a search for a certain number of lines within it.
Using 3 different techniques, searches were made at different points in the file, comparing the performance of the techniques at each point and checking whether the results varied depending on the point in the file where the search was made.
My mistake was to assume that there was a certain homogeneity of content in the log file.
The reality is that long lines appear more frequently at the end of the file.
Thus, the apparent conclusion that longer searches (closer to the end of the file) are better with a given technique, may be biased. In fact, this technique may be better when dealing with longer lines. What remains to be confirmed.
I was about to post the head/tail trick, but actually I'd probably just fire up emacs. ;-)
esc-x goto-line ret 16224
mark (ctrl-space)
esc-x goto-line ret 16482
esc-w
open the new output file, ctl-y
save
Let's me see what's happening.
I would use:
awk 'FNR >= 16224 && FNR <= 16482' my_file > extracted.txt
FNR contains the record (line) number of the line being read from the file.
Using ed:
ed -s infile <<<'16224,16482p'
-s suppresses diagnostic output; the actual commands are in a here-string. Specifically, 16224,16482p runs the p (print) command on the desired line address range.
I wrote a small bash script that you can run from your command line, so long as you update your PATH to include its directory (or you can place it in a directory that is already contained in the PATH).
Usage: $ pinch filename start-line end-line
#!/bin/bash
# Display line number ranges of a file to the terminal.
# Usage: $ pinch filename start-line end-line
# By Evan J. Coon
FILENAME=$1
START=$2
END=$3
ERROR="[PINCH ERROR]"
# Check that the number of arguments is 3
if [ $# -lt 3 ]; then
echo "$ERROR Need three arguments: Filename Start-line End-line"
exit 1
fi
# Check that the file exists.
if [ ! -f "$FILENAME" ]; then
echo -e "$ERROR File does not exist. \n\t$FILENAME"
exit 1
fi
# Check that start-line is not greater than end-line
if [ "$START" -gt "$END" ]; then
echo -e "$ERROR Start line is greater than End line."
exit 1
fi
# Check that start-line is positive.
if [ "$START" -lt 0 ]; then
echo -e "$ERROR Start line is less than 0."
exit 1
fi
# Check that end-line is positive.
if [ "$END" -lt 0 ]; then
echo -e "$ERROR End line is less than 0."
exit 1
fi
NUMOFLINES=$(wc -l < "$FILENAME")
# Check that end-line is not greater than the number of lines in the file.
if [ "$END" -gt "$NUMOFLINES" ]; then
echo -e "$ERROR End line is greater than number of lines in file."
exit 1
fi
# The distance from the end of the file to end-line
ENDDIFF=$(( NUMOFLINES - END ))
# For larger files, this will run more quickly. If the distance from the
# end of the file to the end-line is less than the distance from the
# start of the file to the start-line, then start pinching from the
# bottom as opposed to the top.
if [ "$START" -lt "$ENDDIFF" ]; then
< "$FILENAME" head -n $END | tail -n +$START
else
< "$FILENAME" tail -n +$START | head -n $(( END-START+1 ))
fi
# Success
exit 0
This might work for you (GNU sed):
sed -ne '16224,16482w newfile' -e '16482q' file
or taking advantage of bash:
sed -n $'16224,16482w newfile\n16482q' file
Since we are talking about extracting lines of text from a text file, I will give an special case where you want to extract all lines that match a certain pattern.
myfile content:
=====================
line1 not needed
line2 also discarded
[Data]
first data line
second data line
=====================
sed -n '/Data/,$p' myfile
Will print the [Data] line and the remaining. If you want the text from line1 to the pattern, you type: sed -n '1,/Data/p' myfile. Furthermore, if you know two pattern (better be unique in your text), both the beginning and end line of the range can be specified with matches.
sed -n '/BEGIN_MARK/,/END_MARK/p' myfile
I've compiled some of the highest rated solutions for sed, perl, head+tail, plus my own code for awk, and focusing on performance via the pipe, while using LC_ALL=C to ensure all candidates at their fastest possible, allocating 2-second sleep gap in between.
The gaps are somewhat noticeable :
abs time awk/app speed ratio
----------------------------------
0.0672 sec : 1.00x mawk-2
0.0839 sec : 1.25x gnu-sed
0.1289 sec : 1.92x perl
0.2151 sec : 3.20x gnu-head+tail
Haven't had chance to test python or BSD variants of those utilities.
(fg && fg && fg && fg) 2>/dev/null;
echo;
( time ( pvE0 < "${m3t}"
| LC_ALL=C mawk2 '
BEGIN {
_=10420001-(\
__=10420256)^(FS="^$")
} _<NR {
print
if(__==NR) { exit }
}' ) | pvE9) | tee >(xxh128sum >&2) | LC_ALL=C gwc -lcm | lgp3 ;
sleep 2;
(fg && fg && fg && fg) 2>/dev/null
echo;
( time ( pvE0 < "${m3t}"
| LC_ALL=C gsed -n '10420001,10420256p;10420256q'
) | pvE9 ) | tee >(xxh128sum >&2) | LC_ALL=C gwc -lcm | lgp3 ;
sleep 2; (fg && fg && fg && fg) 2>/dev/null
echo
( time ( pvE0 < "${m3t}"
| LC_ALL=C perl -ne 'print if 10420001..10420256'
) | pvE9 ) | tee >(xxh128sum >&2) | LC_ALL=C gwc -lcm | lgp3 ;
sleep 2; (fg && fg && fg && fg) 2>/dev/null
echo
( time ( pvE0 < "${m3t}"
| LC_ALL=C ghead -n +10420256
| LC_ALL=C gtail -n +10420001
) | pvE9 ) | tee >(xxh128sum >&2) | LC_ALL=C gwc -lcm | lgp3 ;
in0: 1.51GiB 0:00:00 [2.31GiB/s] [2.31GiB/s] [============> ] 81%
out9: 42.5KiB 0:00:00 [64.9KiB/s] [64.9KiB/s] [ <=> ]
( pvE 0.1 in0 < "${m3t}" | LC_ALL=C mawk2 ; )
0.43s user 0.36s system 117% cpu 0.672 total
256 43487 43487
54313365c2e66a48dc1dc33595716cc8 stdin
out9: 42.5KiB 0:00:00 [51.7KiB/s] [51.7KiB/s] [ <=> ]
in0: 1.51GiB 0:00:00 [1.84GiB/s] [1.84GiB/s] [==========> ] 81%
( pvE 0.1 in0 < "${m3t}" |LC_ALL=C gsed -n '10420001,10420256p;10420256q'; )
0.68s user 0.34s system 121% cpu 0.839 total
256 43487 43487
54313365c2e66a48dc1dc33595716cc8 stdin
in0: 1.85GiB 0:00:01 [1.46GiB/s] [1.46GiB/s] [=============>] 100%
out9: 42.5KiB 0:00:01 [33.5KiB/s] [33.5KiB/s] [ <=> ]
( pvE 0.1 in0 < "${m3t}" | LC_ALL=C perl -ne 'print if 10420001..10420256'; )
1.10s user 0.44s system 119% cpu 1.289 total
256 43487 43487
54313365c2e66a48dc1dc33595716cc8 stdin
in0: 1.51GiB 0:00:02 [ 728MiB/s] [ 728MiB/s] [=============> ] 81%
out9: 42.5KiB 0:00:02 [19.9KiB/s] [19.9KiB/s] [ <=> ]
( pvE 0.1 in0 < "${m3t}"
| LC_ALL=C ghead -n +10420256
| LC_ALL=C gtail -n ; )
1.98s user 1.40s system 157% cpu 2.151 total
256 43487 43487
54313365c2e66a48dc1dc33595716cc8 stdin
The -n in the accept answers work. Here's another way in case you're inclined.
cat $filename | sed "${linenum}p;d";
This does the following:
pipe in the contents of a file (or feed in the text however you want).
sed selects the given line, prints it
d is required to delete lines, otherwise sed will assume all lines will eventually be printed. i.e., without the d, you will get all lines printed by the selected line printed twice because you have the ${linenum}p part asking for it to be printed. I'm pretty sure the -n is basically doing the same thing as the d here.
I was looking for an answer to this but I had to end up writing my own code which worked. None of the answers above were satisfactory.
Consider you have very large file and have certain line numbers that you want to print out but the numbers are not in order. You can do the following:
My relatively large file
for letter in {a..k} ; do echo $letter; done | cat -n > myfile.txt
1 a
2 b
3 c
4 d
5 e
6 f
7 g
8 h
9 i
10 j
11 k
Specific line numbers I want:
shuf -i 1-11 -n 4 > line_numbers_I_want.txt
10
11
4
9
To print these line numbers, do the following.
awk '{system("head myfile.txt -n " $0 " | tail -n 1")}' line_numbers_I_want.txt
What the above does is to head the n line then take the last line using tail
If you want your line numbers in order, sort ( is -n numeric sort) first then get the lines.
cat line_numbers_I_want.txt | sort -n | awk '{system("head myfile.txt -n " $0 " | tail -n 1")}'
4 d
9 i
10 j
11 k
Maybe, you would be so kind to give this humble script a chance ;-)
#!/usr/bin/bash
# Usage:
# body n m|-m
from=$1
to=$2
if [ $to -gt 0 ]; then
# count $from the begin of the file $to selected line
awk "NR >= $from && NR <= $to {print}"
else
# count $from the begin of the file skipping tailing $to lines
awk '
BEGIN {lines=0; from='$from'; to='$to'}
{++lines}
NR >= $from {line[lines]=$0}
END {for (i = from; i < lines + to + 1; i++) {
print line[i]
}
}'
fi
Outputs:
$ seq 20 | ./body.sh 5 15
5
6
7
8
9
10
11
12
13
14
15
$ seq 20 | ./body.sh 5 -5
5
6
7
8
9
10
11
12
13
14
15
You could use sed command in your case and is pretty fast.
As mentioned lets assume the range is: between 16224 and 16482 lines
#get the lines from 16224 to 16482 and prints the values into filename.txt file
sed -n '16224 ,16482p' file.txt > filename.txt
#Additional Info to showcase other possible scenarios:
#get the 16224 th line and writes the value to filename.txt
sed -n '16224p' file.txt > filename.txt
#get the 16224 and 16300 line values only and write to filename.txt.
sed -n '16224p;16300p;' file.txt > filename.txt