I am trying to write a query that reorders date ranges around particular spans. It should do something that looks like this
Member Rank Begin Date End Date
2275 A 9/9/14 11/17/14
2275 B 9/26/14 3/24/15
2275 B 3/25/15 12/31/15
8983 A 9/16/13 3/10/15
8983 B 2/24/15 4/28/15
8983 A 4/28/15 12/31/15
and have it become
Member Rank Begin Date End Date
2275 A 9/9/14 11/17/14
2275 B 11/18/14 3/24/15
2275 B 3/25/15 12/31/15
8983 A 9/16/13 3/10/15
8983 B 3/11/15 4/27/15
8983 A 4/28/15 12/31/15
To explain further, I am looking to update the dates. There isn't much to the ranking except A > B. And there is only A and B. Date ranges with rank A should remain untouched. Overlapping B ranked dates are okay. I am concerned with B ranked dates overlapping with A ranked dates. The table is very large (~700 members) and with several different members IDs. The 2nd line (Rank B) of member 2275 changes the begin date to 11/18/15 to not overlap with the 1st line.
I am using Microsoft SQL Server 2008 R2
Thanks
LATEST EDIT: Here's what I did for pre-2012. I don't think it's the most elegant solution.
WITH a AS (
SELECT
1 AS lgoffset
, NULL AS lgdefval
, ROW_NUMBER() OVER(PARTITION BY [Member] ORDER BY [Begin Date]) AS seq
, [Member]
, [Rank]
, [Begin Date]
, [End Date]
FROM #table
)
SELECT
a.seq
, a.[Member]
, a.[Rank]
, a.[Begin Date]
, CASE
WHEN a.[Rank] = 'B' AND a.[Begin Date] <= ISNULL(aLag.[End Date], a.lgdefval)
THEN ISNULL(aLag.[End Date], a.lgdefval)
ELSE a.[Begin Date]
END AS bdate2
, a.[End Date]
INTO #b
FROM a
LEFT OUTER JOIN a aLag
ON a.seq = aLag.seq + a.lgoffset
AND a.[Member] = aLag.[Member]
ORDER BY [Member], [Begin Date];
UPDATE #table
SET #table.bdate = CASE
WHEN #table.rnk = 'B' AND #table.bdate <= (SELECT #b.bdate2 FROM #b WHERE #b.bdate2 > #b.bdate and #table.mbr = #b.mbr)
THEN dateadd(d, 1,(SELECT bdate2 FROM #b WHERE #b.bdate2 > #b.bdate and #table.mbr = #b.mbr ))
ELSE #table.bdate
END
EDIT PS: Below was my previous answer that only applies to 2012 and later.
You may want to try the following SELECT statement to see if you get the desired results and then convert to an UPDATE:
SELECT
[Member]
, [Rank]
, CASE
WHEN [Rank] = 'B' AND [Begin Date] <= LAG([End Date],1,'12/31/2030') OVER(PARTITION BY [Member] ORDER BY [Begin Date])
THEN DATEADD(d,1,LAG([End Date],1,'12/31/2030')OVER(PARTITION BY [Member] ORDER BY [Begin Date]))
ELSE [Begin Date]
END AS [Begin Date]
, [End Date]
FROM #Table
ORDER BY [Member], [Begin Date]
EDIT: So in order to update the begin date column:
UPDATE #Table
SET [Begin Date] = (SELECT
CASE
WHEN [Rank] = 'B' AND [Begin Date] <= LAG([End Date],1,'12/31/2030') OVER(PARTITION BY [Member] ORDER BY [Begin Date])
THEN DATEADD(d,1,LAG([End Date],1,'12/31/2030')OVER(PARTITION BY [Member] ORDER BY [Begin Date]))
ELSE [Begin Date]
END AS [Begin Date]
FROM #Table)
EDIT 2: Some of my code was incorrect due to not realizing the lag function needed an OVER statement, updated select statement and update statement
Sources:Alternate of lead lag function in sql server 2008
http://blog.sqlauthority.com/2011/11/24/sql-server-solution-to-puzzle-simulate-lead-and-lag-without-using-sql-server-2012-analytic-function/
Related
i need to get the balance for the 1st of each month from a table ordered by date, if the 1st is missing from the dataset for a certain month then for that month i want the next available dates data.
I have tried many things but I tried the following to place a case in the where statement which just gives me the first and the second any ideas, maybe an over statement
select date_
, balance
from mytable
where case when extract(day from date_) = 1 then extract(day from date_) = 1 else (extract (day from date_) = 2 )end
group by date_
order by date_ desc
you can use window function row_number:
select * from
(
select * , row_number() over (partition by date_trunc('month',date_) order by date_ ) rn
) t
where rn = 1
DISTINCT ON should do the trick:
SELECT DISTINCT ON (EXTRACT (day FROM date_))
date_, balance
FROM mytable
ORDER BY EXTRACT (day FROM date_), date_;
That will get the first date for each month.
How do I find the first, second, third and fourth saturday of the month?
Ex.: I want to end up with this format...
Blockquote
YYYY, MM, Week#1
Blockquote
YYYY, MM, Week#2
Blockquote
Thanks,
This solution does not depend on Datefirst setting.
declare #d datetime = getdate();
select
dateadd(dd, n, firstSaturday)
from (
select
firstSaturday = dateadd(day, 7-(##datefirst+datepart(weekday, dateadd(day,-1, convert(char(6),#d,112)+'01')))%7, dateadd(day,-1, convert(char(6),#d,112)+'01'))
) t
cross apply (values (0), (7), (14), (21)) q(n)
Here is one way to do it, using a stacked cte to create an inline tally table, with another cte on top of that to generate the months calendar.
Please note that you can change the GETDATE() in the first row code to any date you want (even if it's in the middle of the month) and the code will produce all the Saturdays in that month.
-- Get the current month's start date
DECLARE #MonthStart datetime = DATEADD(MONTH, (DATEDIFF(MONTH, 0, GETDATE())), 0)
;WITH lv0 AS (SELECT 0 g UNION ALL SELECT 0)
,lv1 AS (SELECT 0 g FROM lv0 a CROSS JOIN lv0 b) -- 4
,lv2 AS (SELECT 0 g FROM lv1 a CROSS JOIN lv1 b) -- 16
,lv3 AS (SELECT 0 g FROM lv2 a CROSS JOIN lv2 b) -- 256
,Tally (n) AS (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM lv3)
-- gets all the dates in the current month
,CurrentMonth AS (SELECT TOP (32) dateadd(day, n-1, #MonthStart) As TheDate
FROM Tally
WHERE MONTH(dateadd(day, n-1, #MonthStart)) = MONTH(#MonthStart)
ORDER BY n)
-- gets all the Saturday dates of the current month
SELECT TheDate, DATENAME(WEEKDAY, TheDate)
FROM CurrentMonth
WHERE DATEPART(WEEKDAY, TheDate) = 7 -- Depending on server settings!
If you already have a numbers table, you can use it instead of the stacked cte. If you don't know what is a numbers table and why you should have one, read The "Numbers" or "Tally" Table: What it is and how it replaces a loop by Jeff Moden
You can try this.
SET DATEFIRST 1
DECLARE #MonthId INT = 5
DECLARE #FirstDayOfTheMonth DATE = CONCAT(YEAR(GETDATE()), RIGHT(CONCAT('00', #MonthId),2), '01')
DECLARE #SaturdayId INT = 6
SELECT
DATEADD(DAY, #SaturdayId + WK.ID - DATEPART(WEEKDAY, #FirstDayOfTheMonth), #FirstDayOfTheMonth)
FROM ( VALUES(0),(7),(14),(21),(28)) AS WK(ID)
WHERE
MONTH(DATEADD(DAY, #SaturdayId + WK.ID- DATEPART(WEEKDAY, #FirstDayOfTheMonth),#FirstDayOfTheMonth)) = #MonthId
Here is my code but its showing null while today is friday. But I would like to get last working day.
-- Insert statements for procedure here
--Below is the param you would pass
DECLARE #dateToEvaluate date=GETDATE();
--Routine
DECLARE #startDate date=CAST('1/1/'+CAST(YEAR(#dateToEvaluate) AS char(4)) AS date); -- let's get the first of the year
WITH
tally(n) AS (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL))-1 FROM sys.all_columns),
dates AS (
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) AS dt_id,
DATEADD(DAY,n,#startDate) AS dt,
DATENAME(WEEKDAY,DATEADD(DAY,n,#startdate)) AS dt_name
FROM tally
WHERE n<366 --arbitrary
AND DATEPART(WEEKDAY,DATEADD(DAY,n,#startDate)) NOT IN (6)
AND DATEADD(DAY,n,#startDate) NOT IN (SELECT CAST(HolidayDate AS date) FROM Holiday)),
curr_id(id) AS (SELECT dt_id FROM dates WHERE dt=#dateToEvaluate)
SELECT d.dt
FROM dates AS d
CROSS JOIN
curr_id c
WHERE d.dt_id+1=c.id
The code below will take any date and "walk backward" to find the previous week day (M-F) which is not in the #holidays table.
declare #currentdate datetime = '2015-03-22'
declare #holidays table (holiday datetime)
insert #holidays values ('2015-03-20')
;with cte as (
select
#currentdate k
union all
select
dateadd(day, -1, k)
from cte
where
k = #currentdate
or ((datepart(dw, k) + ##DATEFIRST - 1 - 1) % 7) + 1 > 5 --determine day of week independent of culture
or k in (select holiday from #holidays)
)
select min(k) from cte
The dates table doesn't have any FRIDAY dates in it. Change the NOT IN (6) to NOT IN (1, 7). This will remove Saturday and Sundays from the dates table.
I am trying to find the total per year
For example
Start date End Date Total Value
1 07/01/14 01/01/15 $10,000
2 08/01/13 12/01/14 $10,000
3 03/01/13 05/01/15 $10,000
As you can see, Some items are over multiple years. Is there a way to find out what the total value is per year.
Solution should be:
item 3
2013- $3600
2014-$4800
2015-1600
Then a summation would be down for all three items to give a yearly total.
What I have so far:
I have a rolling summation code which is shown below.
case when
(
[begin date] >= dateadd(mm,0,DATEADD(mm,DATEDIFF(mm,0,getdate()),0))
and [end date] >= dateadd(mm,0,DATEADD(mm,DATEDIFF(mm,0,getdate()),0))
)
OR
(
[Begin Date] < dateadd(mm,0,DATEADD(mm,DATEDIFF(mm,0,getdate()),0))
and [End Date] >= dateadd(mm,0,DATEADD(mm,DATEDIFF(mm,0,getdate()),0))
)
then [Totalvalue]/nullif(DATEDIFF(mm,[begin date],[end date]),0)
else 0
end [Current Month]
I dono how you got that total values for item 3
but for item 3 i hope it should be
2013 = 3704
2014 = 4444
2015 = 1852
Dono how efficient this code is just have a try
CREATE TABLE #tblName
(
itemid INT,
startdate DATETIME,
endate DATETIME,
value int
)
INSERT INTO #tblName
VALUES (1,'2014/07/01','2015/01/01',10000),
(2,'2013/08/01','2014/12/01',10000),
(3,'2013/03/01','2015/05/01',10000)
DECLARE #mindate DATETIME,
#maxdate DATETIME
SELECT #mindate = Min(startdate),
#maxdate = Max(endate)
FROM #tblName
SELECT *
FROM #tblName;
WITH cte
AS (SELECT #mindate startdate
UNION ALL
SELECT Dateadd(mm, 1, startdate) startdate
FROM cte
WHERE startdate <= Dateadd(mm, -1, #maxdate))
SELECT a.value * ( ( convert(numeric(22,6),a.cnt) / convert(numeric(22,6),c.total) ) * 100 ) / 100,a.itemid,a.startdate
FROM (SELECT Avg(value) value,
Count(1) cnt,
itemid,
Year(a.startdate) startdate
FROM cte a
JOIN #tblName b
ON a.startdate BETWEEN b.startdate AND b.endate
GROUP BY itemid,
Year(a.startdate)) a
JOIN(SELECT Sum(cnt) total,
itemid
FROM (SELECT Avg(value) value,
Count(1) cnt,
itemid,
Year(a.startdate) startdate
FROM cte a
JOIN #tblName b
ON a.startdate BETWEEN b.startdate AND b.endate
GROUP BY itemid,
Year(a.startdate)) B
GROUP BY itemid) C
ON a.itemid = c.itemid
WHERE a.itemid = 3
I'm currently trying to get the first and last day of any year. I have data from 1950 and I want to get the first day of the year in the dataset to the last day of the year in the dataset (note that the last day of the year might not be December 31rst and same with the first day of the year).
Initially I thought I could use a CTE and call DATEPART with the day of the year selection, but this wouldn't partition appropriately. I also tried a CTE self-join, but since the last day or first day of the year might be different, this also yields inaccurate results.
For instance, using the below actually generates some MINs in the MAX and vice versa, though in theory it should only grab the MAX date for the year and the MIN date for the year:
;WITH CT AS(
SELECT Points
, Date
, DATEPART(DY,Date) DA
FROM Table
WHERE DATEPART(DY,Date) BETWEEN 363 AND 366
OR DATEPART(DY,Date) BETWEEN 1 AND 3
)
SELECT MIN(c.Date) MinYear
, MAX(c.Date) MaxYear
FROM CT c
GROUP BY YEAR(c.Date)
You want something like this for the first day of the year:
dateadd(year, datediff(year,0, c.Date), 0)
and this for the last day of the year:
--first day of next year -1
dateadd(day, -1, dateadd(year, datediff(year,0, c.Date) + 1, 0)
try this
for getting first day ,last day of the year && firstofthe next_year
SELECT
DATEADD(yy, DATEDIFF(yy,0,getdate()), 0) AS Start_Of_Year,
dateadd(yy, datediff(yy,-1, getdate()), -1) AS Last_Day_Of_Year,
DATEADD(yy, DATEDIFF(yy,0,getdate()) + 1, 0) AS FirstOf_the_NextYear
so putting this in your query
;WITH CT AS(
SELECT Points
, Date
, DATEPART(DY,Date) DA
FROM Table
WHERE DATEPART(DY,Date) BETWEEN
DATEPART(day,DATEADD(yy, DATEDIFF(yy,0,getdate()), 0)) AND
DATEPART(day,dateadd(yy, datediff(yy,-1, getdate()), -1))
)
SELECT MIN(c.Date) MinYear
, MAX(c.Date) MaxYear
FROM CT c
GROUP BY YEAR(c.Date)
I should refrain from developing in the evenings because I solved it, and it's actually quite simple:
SELECT MIN(Date)
, MAX(Date)
FROM Table
GROUP BY YEAR(Date)
I can put these values into a CTE and then JOIN on the dates and get what I need:
;WITH CT AS(
SELECT MIN(Date) Mi
, MAX(Date) Ma
FROM Table
GROUP BY YEAR(Date)
)
SELECT c.Mi
, m.Points
, c.Ma
, f.Points
FROM CT c
INNER JOIN Table m ON c.Mi = m.Date
INNER JOIN Table f ON c.Ma = f.Date