I have created a Tumblr blog that shows photos of my interest. I am looking to have my tumblr photo posts to be displayed in random order such that every-time the page is loaded, the order of posts in my grid theme is randomly shown. This way everyone can see all my posts without scrolling.
Does anyone know a code that I can simply insert to my theme so that posts are shown in random order and be shown in random order every time the page loads.
I am not entirely familiar with Tumbler, but I am willing to bet there is a unique class name for those image blocks. You can insert JavaScript on Tumbler as well. see: http://www.problogtricks.com/2013/12/add-custom-css-javascript-code-to-tumblr-blog.html
That said, randomizing elements with JavaScript is super easy. Here is a demo of how that is done. After identifying a unique classname that applies only to those elements, you can change the parameter inside the JavaScript function below.
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title></title>
<style>
.putauniqueclassnamehere{
}
</style>
<script src="jquery-1.11.2.min.js"></script>
<script>
$(document).ready(function (name) {
return function () {
var max = $(name).length;
$.each($(name), function (p1, p2) {
var randPos = Math.floor(Math.random() * (max - 0 + 1) + 0);
$(p2).insertBefore($(name)[randPos]);
})
return ;
}
}(".putauniqueclassnamehere"))
</script>
</head>
<body>
<div class="mytest">Test 1</div>
<div class="mytest">Test 2</div>
<div class="mytest">Test 3</div>
<div class="mytest">Test 4</div>
<div class="mytest">Test 5</div>
</body>
</html>
Just paste this at the end of your theme:
{block:IndexPage}
<script>
$(document).ready(function (name) {
return function () {
var elts = $(name);
var max = elts.length;
$.each(elts, function (index, elt) {
var randPos = Math.floor(Math.random() * (max - 0 + 1) + 0);
$(elt).insertBefore(elts[randPos]);
})
return ;
}
}(".entry"))
</script>
{/block:IndexPage}
All the credit goes to Joshua Dannemann. I just pasted the relevant part of the code with the class to use with my theme: entry. It could be post or something else. Post a link to your tumblr and I can help you some more.
Edits:
renamed p1 and p2
added {block:IndexPage} and {/block:IndexPage} tags (without them, post pages are broken)
Related
I can't figure out how to get access to the full source of the HTML page including iframes. It should be similar to what we see in DevTools > Elements, but via Electron.
By source I mean either text representation of the DOM (including content of all iframes on the page), or the list of all elements and having a way to get access to their text-representations.
Any help is highly appreciated! Thanks.
If you're just looking to get a string of all the HTML, you can do so via the executeJavaScript API:
const {app, BrowserWindow, dialog} = require('electron')
async function createWindow () {
const mainWindow = new BrowserWindow()
await mainWindow.loadFile('index.html')
const result = await mainWindow.webContents.executeJavaScript("document.documentElement.outerHTML");
dialog.showMessageBox(mainWindow, {
message: result
});
}
app.whenReady().then(() => {
createWindow()
app.on('activate', function () {
if (BrowserWindow.getAllWindows().length === 0) createWindow()
})
})
app.on('window-all-closed', function () {
if (process.platform !== 'darwin') app.quit()
})
For an HTML page like:
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<link href="./styles.css" rel="stylesheet">
<title>Hello World!</title>
</head>
<body>
<h1>Hello World!</h1>
We are using Node.js <span id="node-version"></span>,
Chromium <span id="chrome-version"></span>,
and Electron <span id="electron-version"></span>.
<iframe src="https://google.com/chrome"></iframe>
</body>
</html>
You'll get a dialog like this:
It is not however possible to just grab DOM elements in the main process that you can manipulate.
I want to only hide the P0 paragraph using childNodes[x] . I wonder how it works because it hides the whole div with in this code:
<html>
<body>
<div id="myDiv">
<p>P0</p>
<p>P1</p>
</div>
<button onclick="hideFn();">hide</button>
<script>
function hideFn()
{
document.childNodes[0].childNodes[1].childNodes[1].style.display = "none";
}
</script>
</body>
</html>
</html>
You easily could have found the reason yourself by simply doing the traversal step by step:
document
the document
.childNodes[0]
the documentElement, also known as the root node (<html>)
.childNodes[1]
the <body>
.childNodes[1]
the <div>
I am having lots of problem accessing any objects from a Yahoo Boss YQL Json Response data. I used this YQL Console for Boss Search Tables.
Here is what I have done:
<!DOCTYPE HTML>
<html>
<head>
<script src="http://code.jquery.com/jquery-2.0.3.min.js" type="text/javascript"></script>
<script type="text/javascript">
var url = "https://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20boss.search%20where%20service%20%3D%22images%22%20AND%20count%3D%221%22%20AND%20q%3D%22iphone6%22%20AND%20ck%20%3D%20%22MYCONSUMER_KEY%22%20AND%20secret%3D%22MYCONSUMER_SECRET%22%3B&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys";
(function showPix()
{
$.getJSON(url, function (data)
{
console.log(data);
var myObj = data.results.bossresponse.images.results.result.clickurl;
$.each(myObj, function ()
{
$('#pix').append(this);
});
});
})();
</script>
</head>
<body>
<div id="pix">
</div>
<button onclick="showPix();">run</button>
</body>
</html>
The console.log(); gives me one object that contains the image, but I cannot manage to show the image on the screen. And it tells me that showPix is undefined. Any help would be greatly appreciated. TIA
I figured this out as follows:
<html>
<head><title>YQL and RSS: Yahoo Top News Stories</title>
<style type='text/css'>
#results{ width: 40%; margin-left: 30%; border: 1px solid gray; padding: 5px; height: 200px; overflow: auto; }
</style>
<script type='text/javascript'>
// Parses returned response and extracts
// the title, links, and text of each news story.
function top_stories(o){
var items = o.query.results.item;
var output = '';
var no_items=items.length;
for(var i=0;i<no_items;i++){
var title = items[i].title;
var link = items[i].link;
var desc = items[i].description;
output += "<h3><a href='" + link + "'>"+title+"</a></h3>" + desc + "<hr/>";
}
// Place news stories in div tag
document.getElementById('results').innerHTML = output;
}
</script>
</head>
<body>
<!-- Div tag for stories results -->
<div id='results'></div>
<!-- The YQL statment will be assigned to src. -->
<script src='https://query.yahooapis.com/v1/public/yql?q=select%20title%20from%20rss%20where%20url%3D%22http%3A%2F%2Frss.news.yahoo.com%2Frss%2Ftopstories%22&format=json&callback=top_stories'></script>
</body>
I have multiple images in an html page.I want to use html2canvas to convert the page to image.The images are local and from same source.It always keep on showing the error msg " Unable to get image data from canvas because the canvas has been tainted by cross-origin data."
The same code will work for one image or multiple copy of same image.
<!DOCTYPE HTML>
<html>
<head>
<meta charset="utf-8">
<meta name="language" content="de">
<script type="text/javascript" src="./js/jquery-1.9.1.js"></script>
<script type="text/javascript" src="js/html2canvas.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
var target = $('#mainDiv');
html2canvas(target, {
onrendered: function(canvas) {
var data = canvas.toDataURL();
var img = document.getElementById('img1');
img.src = data;
}
});
});
</script>
</head>
<body>
<div id="mainDiv">
<div id="div1" ><p>paragraph 1 paragraph 1 paragraph 1 paragraph 1 paragraph 1 paragraph 1 paragraph 1 paragraph 1 </p></div>
<div id="div2" ><p>paragraph2 paragraph2 paragraph2 paragraph2 paragraph2 paragraph2 paragraph2 paragraph2 </p></div>
<img src="images/01.jpg" >
<img src="images/02.jpg" >
<img src="images/03.jpg" >
<img src="images/04.jpg" >
</div>
<img id="img1"></img>
</body>
</html>
I am not sure what does the error message mean.Also if somebody can tell me how do i make this work with multiple images, it will be very helpful
just remove what you dont need. ie, i have Div1,Div2 etc
function PrintChartCanvas(divId) {
//div canvas
var divObj = html2canvas($('#div' + divId));
var divQueu = divObj.parse();
var divCanvas = divObj.render(divQueu);
divImg = divCanvas.toDataURL();
return divImg;
}
document.getElementById("img1").src = PrintChartCanvas(3);
This should work
I am new to jquery mobile, and am having problems getting content I have inserted dymically using pageinit to display on the first time of the form response page. It displays on subsequent refreshes of the page. I also don't want the content to cache.
I need to use querystring values like ?blah=1&blah=2 as I use these in my call to an external json file.
How should I be doing this? If I use rel="external", and setting ajax to false, I have problems with issues on android. So using pageinit in the header, how do I make the dynamically loaded content (in the example, the time in seconds) in the 2nd page display first time round?
I have simplified the problem into test pages below.
Expected behaviour. When you click on the submit button of the form you go through to the 2nd page which should display the no of seconds taken from datetime
Actual behaviour. The seconds/time does not display on the 2nd page until the page is refreshed.
Elsewhere, I have come across the suggestion to put the pageinit code into the div itself, however this has caused the content to cache on android (ie the no of seconds remains the same), so I don't want to do this.
Any ideas on how I should approach this would be much appreciated
Sample code
=======
Page 1 - form
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="http://code.jquery.com/mobile/1.0.1/jquery.mobile-1.0.1.min.css" />
<script src="http://code.jquery.com/jquery-1.6.4.min.js"></script>
<script src="http://code.jquery.com/mobile/1.0.1/jquery.mobile-1.0.1.min.js"></script>
<script src="/scripts/myinit.js"></script>
</head>
<body>
<div data-role="page" id="page1" data-add-back-btn="true">
<div data-role="content" data-theme="b">
<form action="page_2.htm" method="GET" id="form1" name="form1">
<input type="hidden" name="seconds" value="">
<div class="ui-block-b"><button type="submit" data-theme="a">Submit</button></div>
</form>
</div>
</div>
</body>
</html>
===
Page 2 form response page
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="http://code.jquery.com/mobile/1.0.1/jquery.mobile-1.0.1.min.css" />
<script src="http://code.jquery.com/jquery-1.6.4.min.js"></script>
<script src="http://code.jquery.com/mobile/1.0.1/jquery.mobile-1.0.1.min.js"></script>
<script src="/scripts/myinit.js"></script>
</head>
<body>
<div data-role="page" id="page2" data-add-back-btn="true">
<div id="job" data-role="content">
</div>
</div>
</body>
</html>
===
custom javascript file called /scripts/myinit.js (included in both pages above)
$('#page1').live('pageinit', function(event) {
var seconds = new Date().getTime();
$('input[name=seconds]').val(seconds);
});
$('#page2').live('pageinit', function(event) {
var querystring = location.search.replace( '?', '' ).split( '&' );
var queryObj = {};
for ( var i=0; i<querystring.length; i++ ) {
var name = querystring[i].split('=')[0];
var value = querystring[i].split('=')[1];
queryObj[name] = value;
}
var seconds = queryObj["seconds"];
$('#job').append("seconds=" + seconds);
});
try changing pageinit by pageshow. i had the same problem and it worked for me
Link to the external file like this:
HTML --
I'm a Link
JS --
$(document).delegate('#external-link', 'click', function () {
$.mobile.changePage('/path/to/file.html', { reloadPage : true });
return false;
});
Setting the reloadPage option for the changePage() function will allow the external page to be refreshed rather than loading the cached version. Since the external page will be refreshed, the pageinit code for it will run when it's initialized and your code should function properly.
Documentation: http://jquerymobile.com/demos/1.1.0-rc.1/docs/api/methods.html