How to send a parameter to a custom action? - scala

Question

I am using action composition of play framework 2.3 and I would like to send parameters to the custom action.
For example, if you have a custom action that adds a cache how the custom action can receive the cache key and the desired cache time. Example code inside a play controller:
def myAction(p1: String) = CachedAction(key="myAction1"+p1, time = 300.seconds) {
implicit request =>
... do an expensive calculation …
Ok(views.html.example.template())
}
I have tested an ActionBuilder combined with a custom request but I haven't found a solution.
I am aware that play offers a cache for actions, unfortunately that cache does not meet all the requirements.

Answer 1

I am not sure about solution with ActionBuilder or ActionRefiner but that may work for you:
def CachedAction(key: String, time: Duration)(f: Request[AnyContent] => Result) = {
Action{ request =>
if(cache.contains(key)){
...
} else{
...
}
f(request)
}
}
and then:
def myAction(p1: String) = CachedAction("hello" + p1, 100 millis){ request =>
Ok("cached action")
}
Edit:
Since you need Action.async you can write something like that:
case class Caching[A](key: String, time: Duration)(action: Action[A]) extends Action[A] {
def apply(request: Request[A]): Future[Result] = {
if(cache.contains(key)){
Logger.info("Found key: " + key)
}
action(request)
}
lazy val parser = action.parser
}
def cached(p1: String) = Caching(key = p1, time = 100 millis){
Action.async { Future(Ok("hello")) }
//or
Action { Ok("hello") }
}
Case class with two parameter lists looks weird but it works.
Docs:https://www.playframework.com/documentation/2.3.x/ScalaActionsComposition#Composing-actions