Find all occurrences of a string in any column with a specific name in postgresql - postgresql

Question

I have a Postgresql database with many tables, some of these tables have a column called 'description'. Some of these descriptions contain the word 'dog'. How can I print the tables names for the tables that have the string 'dog' anywhere in the column 'description', case insensitive?
I tried with a script, but it is failing with the error
$$ LANGUAGE plpgsql
ERROR: syntax error at or near "END"
LINE 16: END LOOP;**
This is the script:
CREATE OR REPLACE FUNCTION findAllDogsInDescription()
RETURNS VOID
AS $$
DECLARE
my_row RECORD;
a int;
i boolean;
BEGIN
FOR my_row IN
SELECT table_name from information_schema.columns where column_name = 'description'
LOOP
execute 'select count(*) from ' || my_row.table_name || ' where description ilike ''%dog%'' ' into i;
if (i > 0) THEN
raise 'Found a dog in the description of the table %', my_row.table_name;
END IF
END LOOP;
END;
$$ LANGUAGE plpgsql;
SELECT findAllDogsInDescription();

Answer 1

It's a simple syntax error. You just need a ; after the END IF. And you need to use a (which is an int) instead of i in the execute ... into statement.
CREATE OR REPLACE FUNCTION findAllDogsInDescription()
RETURNS VOID
AS $$
DECLARE
my_row RECORD;
a int;
i boolean;
BEGIN
FOR my_row IN
SELECT table_name from information_schema.columns where column_name = 'description'
LOOP
execute 'select count(*) from ' || my_row.table_name || ' where description ilike ''%dog%'' ' into a;
if (a > 0) THEN
raise 'Found a dog in the description of the table %', my_row.table_name;
END IF;
END LOOP;
END;
$$ LANGUAGE plpgsql;
SELECT findAllDogsInDescription();