How do you convert a String to UInt8 array?
var str = "test"
var ar : [UInt8]
ar = str
Lots of different ways, depending on how you want to handle non-ASCII characters.
But the simplest code would be to use the utf8 view:
let string = "hello"
let array: [UInt8] = Array(string.utf8)
Note, this will result in multi-byte characters being represented as multiple entries in the array, i.e.:
let string = "é"
print(Array(string.utf8))
prints out [195, 169]
There’s also .nulTerminatedUTF8, which does the same thing, but then adds a nul-character to the end if your plan is to pass this somewhere as a C string (though if you’re doing that, you can probably also use .withCString or just use the implicit conversion for bridged C functions.
let str = "test"
let byteArray = [UInt8](str.utf8)
swift 4
func stringToUInt8Array(){
let str:String = "Swift 4"
let strToUInt8:[UInt8] = [UInt8](str.utf8)
print(strToUInt8)
}
I came to this question looking for how to convert to a Int8 array. This is how I'm doing it, but surely there's a less loopy way:
Method on an Extension for String
public func int8Array() -> [Int8] {
var retVal : [Int8] = []
for thing in self.utf16 {
retVal.append(Int8(thing))
}
return retVal
}
Note: storing a UTF-16 encoded character (2 bytes) in an Int8 (1 byte) will lead to information loss.
Related
How can I create a base64 encoded string from 4 UInt64 integers?
I presume there are a few steps to this that i'm not sure how to approach, such as combing integers, converting to binary, or perhaps constructing string using some loop over integers?
I'd appreciate any code example or pointers on how to achieve this.
It this what you want?
func base64String(integers: [UInt64]) throws -> String {
let data = try JSONEncoder().encode(integers)
let string = data.base64EncodedString()
return string
}
// call
let result = try? base64String(integers: [234, 23, 3, 1002, 3])
I'm trying to use a library which was written in C. I've imported .a and .h files at Xcode project, and checked it works properly. I've already made them working on Objective-C, and now for Swift.
A problem I've got is functions' arguments. There's a function requires an argument widechar(defined as typedef Unsigned short int in Library), which was UnsafeMutablePointer<UInt16> in Swift. The function translates it and return the result.
So I should convert a String to UnsafeMutablePointer<UInt16>. I tried to find the right way to converting it, but I've only got converting it to UnsafeMutablePointer<UInt8>. I couldn't find answer/information about converting String to UnsafeMutablePointer<UInt16>.
Here's a source code I've written.
extension String{
var utf8CString: UnsafePointer<Int8> {
return UnsafePointer((self as NSString).utf8String!)
}
}
func translate(toBraille: String, withTable: String) -> [String]? {
let filteredString = toBraille.onlyAlphabet
let table = withTable.utf8CString
var inputLength = CInt(filteredString.count)
var outputLength = CInt(maxBufferSize)
let inputValue = UnsafeMutablePointer<widechar>.allocate(capacity: Int(outputLength))
let outputValue = UnsafeMutablePointer<widechar>.allocate(capacity: Int(outputLength))
lou_translateString(table, inputValue, &inputLength, outputValue, &outputLength, nil, nil, 0)
//This is a function that I should use.
let result:[String] = []
return result
}
You have to create an array with the UTF-16 representation of the Swift
string that you can pass to the function, and on return create
a Swift string from the UTF-16 array result.
Lets assume for simplicity that the C function is imported to Swift as
func translateString(_ source: UnsafeMutablePointer<UInt16>, _ sourceLen: UnsafeMutablePointer<CInt>,
_ dest: UnsafeMutablePointer<UInt16>, _ destLen: UnsafeMutablePointer<CInt>)
Then the following should work (explanations inline):
// Create array with UTF-16 representation of source string:
let sourceString = "Hello world"
var sourceUTF16 = Array(sourceString.utf16)
var sourceLength = CInt(sourceUTF16.count)
// Allocate array for UTF-16 representation of destination string:
let maxBufferSize = 1000
var destUTF16 = Array<UInt16>(repeating: 0, count: maxBufferSize)
var destLength = CInt(destUTF16.count)
// Call translation function:
translateString(&sourceUTF16, &sourceLength, &destUTF16, &destLength)
// Create Swift string from UTF-16 representation in destination buffer:
let destString = String(utf16CodeUnits: destUTF16, count: Int(destLength))
I have assumed that the C function updates destLength to reflect
the actual length of the translated string on return.
I am interfacing with libxml2 in swift, and the C APIs binding (still) produce UnsafePointer<Int8>! for c-strings. Whereas Swift APIs normally result in UnsafePointer<UInt8>!.
So my question is - am I doing the string to null-terminated C-string in a proper way?
let cfilePath = unsafeBitCast(myStringString.nulTerminatedUTF8.withUnsafeBufferPointer { $0.baseAddress }, to: UnsafePointer<Int8>.self)
Should I instead prefer using some other method instead of just bypassing Swift type checking with interpreting UInt8 bytes as Int8 bytes?
I'm not sure this solves your problem exactly but for a project where I am sending strings over bluetooth this did the trick:
extension String {
var nullTerminated: Data? {
if var data = self.data(using: String.Encoding.utf8) {
data.append(0)
return data
}
return nil
}
}
Use like this
let data = "asfasf".nullTerminated
I can't find the function the other answers are referencing: nulTerminatedUTF8. Maybe it already does this.
don't use unsafeBitCast for that!!
let cstr = "alpha".nulTerminatedUTF8
let int8arr = cstr.map{ Int8(bitPattern: $0) }
let uint8arr = Array(cstr)
print(int8arr.dynamicType, uint8arr.dynamicType)
// Array<Int8> Array<UInt8>
update
let uint8: UInt8 = 200
let int8 = Int8(bitPattern: uint8)
print(uint8, int8)
// 200 -56
I have decrypted using AES (CrytoSwift) and am left with an UInt8 array. What's the best approach to covert the UInt8 array into an appripriate string? Casting the array only gives back a string that looks exactly like the array. (When done in Java, a new READABLE string is obtained when casting Byte array to String).
I'm not sure if this is new to Swift 2, but at least the following works for me:
let chars: [UInt8] = [ 49, 50, 51 ]
var str = String(bytes: chars, encoding: NSUTF8StringEncoding)
In addition, if the array is formatted as a C string (trailing 0), these work:
str = String.fromCString(UnsafePointer(chars)) // UTF-8 is implicit
// or:
str = String(CString: UnsafePointer(chars), encoding: NSUTF8StringEncoding)
I don't know anything about CryptoSwift. But I can read the README:
For your convenience CryptoSwift provides two function to easily convert array of bytes to NSData and other way around:
let data = NSData.withBytes([0x01,0x02,0x03])
let bytes:[UInt8] = data.arrayOfBytes()
So my guess would be: call NSData.withBytes to get an NSData. Now you can presumably call NSString(data:encoding:) to get a string.
SWIFT 3.1
Try this:
let decData = NSData(bytes: enc, length: Int(enc.count))
let base64String = decData.base64EncodedString(options: .lineLength64Characters)
This is string output
Extensions allow you to easily modify the framework to fit your needs, essentially building your own version of Swift (my favorite part, I love to customize). Try this one out, put at the end of your view controller and call in viewDidLoad():
func stringToUInt8Extension() {
var cache : [UInt8] = []
for byte : UInt8 in 97..<97+26 {
cache.append(byte)
print(byte)
}
print("The letters of the alphabet are \(String(cache))")
}
extension String {
init(_ bytes: [UInt8]) {
self.init()
for b in bytes {
self.append(UnicodeScalar(b))
}
}
}
That might be the dumbest Rustlang question ever but I promise I tried my best to find the answer in the documentation or any other place on the web.
I can convert a string to a vector of bytes like this:
let bar = bytes!("some string");
Unfortunately I can't do it this way
let foo = "some string";
let bar = bytes!(foo);
Because bytes! expects a string literal.
But then, how do I get my foo converted into a vector of bytes?
(&str).as_bytes gives you a view of a string as a &[u8] byte slice (that can be called on String since that derefs to str, and there's also String.into_bytes will consume a String to give you a Vec<u8>.
Use the .as_bytes version if you don't need ownership of the bytes.
fn main() {
let string = "foo";
println!("{:?}", string.as_bytes()); // prints [102, 111, 111]
}
BTW, The naming conventions for conversion functions are helpful in situations like these, because they allow you to know approximately what name you might be looking for.
To expand the answers above. Here are a few different conversions between types.
&str to &[u8]:
let my_string: &str = "some string";
let my_bytes: &[u8] = my_string.as_bytes();
&str to Vec<u8>:
let my_string: &str = "some string";
let my_bytes: Vec<u8> = my_string.as_bytes().to_vec();
String to &[u8]:
let my_string: String = "some string".to_owned();
let my_bytes: &[u8] = my_string.as_bytes();
String to Vec<u8>:
let my_string: String = "some string".to_owned();
let my_bytes: Vec<u8> = my_string.into_bytes();
Specifying the variable type is optional in all cases. Just added to avoid confusion.
Playground link: https://play.rust-lang.org/?version=stable&mode=debug&edition=2021&gist=5ad228e45a38b4f097bbbba49100ecfc
`let v1: Vec<u8> = string.encode_to_vec();`
`let v2: &[u8] = string.as_bytes();`
two work difference, in some of library use ownership of bytes !! if you use as_bytes() see compiler error: must be static.
for example: tokio_uring::fs::File::write_at()
get a ownership of bytes !!
but if you need borrowing , use as_bytes()