I am writing a gui now which contains a popupmenu. This pop up menu should show different names according to cell array called titles and looks like this:
handles.titles={'time','velocity','angular velocity'};
Next, when i click on the popupmenu, i want it to plot the column which connected to this title.
so if i clicked on the 2nd popupmenu option i would like to get graph of velocity vs time.
handles.Parameter_Menu=hObject;
axes(handles.low_axis);
guidata(hObject,handles)
x_axis=xlim([handles.top_axis]);
set(hObject,'string',handles.titles(1:size(handles.matrix.Data,2)));
channel = get(hObject,'Value');
title_channel=handles.titles{channel}
plot(handles.(handles.titles{1}),handles.(handles.titles{channel}));
text=['graph of ' handles.titles2{channel} ' vs ' handles.titles2{1}];
title(text,'fontsize',12)
set(gca,'fontsize',10)
grid on
The problem occurs when i try to use title{3} because it has a space between the words.
Of course i could write it like this angular_velocity but then when i use it in title of the graph i recieve the letter "v" small because of the _ before it.
Is there any option to make it work with space or option to use it with _ but to avoid its effect in the title?
To make the title in plot displays exactly _, you can insert \ before _ (similar to latex):
handles.titles={'time','velocity','angular\_velocity'};
UPDATE:
since you are not only using the titles{i} for plot, but also use it as a struct's fieldname in other commands, then there is no way to have space, because a struct's fieldname must satisfy some conditions: Valid field names begin with a letter, and can contain letters, digits, and underscores.
So, you must use titles{3} = 'angular_velocity' to make other operations work correctly, and set Interpreter property of the title to be none to make the plot's title display as typed (default is TeX Markup, that's why i used \_ for _ above):
title(handle_of_something, titles{3}, 'Interpreter','none')
Related
I want to add small straight line onto some desired characters/numbers inside a string inside textview. I couldn't find a solution. Maybe using NSMutableAttributedString. Meanwhile, I mean doing this programmatically. There is strikethrough style, but not overstrike style. Or maybe adding the letters "a" and "_" with different .baseline values. But how to add both characters onto each other then?
Is it possible?
EDIT: Due to make a try for the helpful answers below, I think to make the line at a spesific height is needed. "A\u{0305}" makes the up line very close to the character, as if it sticks. Is there a way to make it at specific height? For example, if we assume that all the keyboard-inputted characters are written inside every single boxes, the ceiling side of these boxes could be lined?
So this (note: see edit below) appears to be an "a tilde ogonek" (it's Lithuanian).
You can write it for instance as follows using these two Unicode characters:
let atildeogonek = "\u{0105}\u{0303}"
let title = "How to add a small straight line (I mean like this: \(atildeogonek)) onto a character inside a string?"
The first character is the a with an ogonek, the second one is the tilde.
EDIT: The initial question specifically asked about the character ą̃ ("a tilde ogonek") in the title, and I used this code to demonstrate how to use Unicode characters in a Swift string. After posting this answer, the question was edited to be more general about "a line above a character".
Programmatically, you could use a function like this:
func overline(character: Character) -> Character? {
return "\(character)\u{0305}".first
}
That will take a character as input and return a new character (glyph) that has had the Unicode combining overline character added to it. It will return nil if adding the combining overline character fails.
The code print(overline(character:"A")!), for example, returns "A̅"
Or, if you want to add an overline to every character in a string, you could use a function like this:
func overline(characters: String) -> [Character?] {
return Array(characters).map { return "\($0)\u{0305}".first
}
}
(I'm not sure if there are any characters for which the above will fail, so I'm not sure if force-unwrapping the result is safe. Thus I left the result of both functions to be optional Character/Array of Character.)
You can easily find the unicodes of ā or ą̃ by using the xcode's own Character Viewer. Just follow the following steps :
hit : Control + Command + SpaceBar
If you get a compact one like this, click the upper right corner icon to expand it.
When expanded, Click the settings gear in the corner . Select customize list.
select Enclosed Characters
Go down to the bottom and open Code tables then add Unicode.
Now, just search for your required Character and you can check its unicode value. here i am searching ā
to print unicode's value :
print("\u{0101}")
Is there a way to change the text in a dashboard based on a value?
At its most basic, I want to be able to plug in the word 'increased' or 'decreased' based on a change from year to year for a report.
If you mean the free-floating Text object from the same menu as vertical / horizonal containers, Blanks, etc. then you can only use parameters and a few "special" values like Workbook Name.
However, you can use a worksheet as a textbox instead. Just make sure you clear the default formatting (borders, etc.) and put your calculated field that resolves into "increased" / "decreased" on the Text mark. In the same way you can add up or down arrows using CHR() function and set custom colours (by creating two calculated fields that resolve into "increased" and "" and "decreased" and "")
I need to add .jpg at the end of all he cells in one or more columns
9788895249971 into > 9788895249971.jpg
9788867230129 into > 9788867230129.jpg
9788867230273 into > 9788867230273.jpg
9788867230280 into > 9788867230280.jpg
Detailed step-by-step instructions are much appreciated since I am very new to Calc.
Thanks
Do you need to do this once or is this going to be a repeated task every week/month?
If it is something you need to do just once, here is what you can do:
Next (right) to the column where your numbers are open (insert) a new column.
Assuming the following: Numbers are in column A, New column is column B.
In this new column B in the top cell (B1) write:
=A1&".jpg"
Now copy B1 all the way down to the end. In B1 type [Ctrl]+c then Hold [Shift] and hit [PgDn] until the end then press [Ctrl]+v.
Highlight Column B, [Ctrl]+c, then [Edit] [Paste Special] values only (No formula's) this freezes the calculated data.
This is just another option,
just click the function wizard and select concatenate, in that enter which column you want to enter as text1 as and second column in text2. Then when you click OK you will get an concatenated column like below image
so in the C column you will get as a1.jpg.
For those who continue to find this question (as I did):
This can be quickly done using regular expression option of find and replace. (I don't know what version of Calc introduced regex searches, but 6.2.4 has it.)
If you only want to update some non-blank cells on the sheet, select them.
Choose Find and Replace.
On the dialog, fill in the following:
Enter $ for the Find value. ($ means end of line in regex, or in this context end of cell value.)
Enter the desired suffix (.jpg in the question) for the Replace value.
Check Regular Expressions under Other Options
Check Current Selection Only under Other Options if you want to limit to the cells selected in step 1.
Uncheck All Sheets unless that is what you want.
Choose Replace All
This will update the values in-place and does not require any additional columns or formulas.
There's a much more elegant way to do this that doesn't require sacrificing cells just to hold data types, and can be scaled to work with one cell or a large chart range.
Add both pieces of data into the =CONCAT() function
Make sure to use CONCAT instead of CONCATENATE, as `CONCAT accepts cell ranges and is more dynamic.
Open the Function Wizard on the cell in question, and build the following function:
=CONCAT(<your_data>," <suffix>",...)
# Make sure to add a space before the suffix so it appears in the cell.
# You can use this with as many input variables as required letting
# you add as many strings, formulas, or numbers together.
The result should be something like this. In my example, the cell in question is the final value of Ethereum on a balance sheet:
The above example was an easy one, since it was being used as a test, all my summed values were ints, if I had floating point numbers, they would run away to max decimal places (not very pretty).
The function will drag out and expand intelligently to other cells like any other formula.
Adjusting accuracy of floating point values inside a CONCAT function
Sometimes, adding a cell results in a rounding problem, or an extreme amount of decimal places. You can further nest your function using ROUND(<your_data>,<decimal_places>)
Your function would look like this:
=CONCAT(ROUND(<cell_range>, ".jpg")
In your specific case, you don't need a space in the second argument as you want to append .jpg directly to the end of the string.
`
Using Macros to automate the entire process
This is extremely repeatable, and using the Macros feature, you can automate these to make much more simplified functions that allow you to enter just the variables you need, while the macro does the work in the background.
Based on Emmanuel Angelo R.’s answer, I would advice learning to differentiate between fixed cell references and dynamic ones. The following applies:
Cell A1 contains the suffix you would like to add, e.g. ‘.jpg’
Row 2 contains headings, e.g. B2 = ‘Old Filename’ and ‘New Filename’
Cells A3:A¹ contain your filenames
Cells B3:B contain you concatenation formula
In cell B3, type =concatenate(A3;$a$1).² If your locale requires comma as separator, replace my semicolons with commas. Copy cell B3 by selecting it and pressing Ctrl + C. Move the cursor to cell A3, press Ctrl + ↓ (down arror on your cursor keys); this will move you to the bottom of the list of file names. Move your cursor right, then press Ctrl + Shift + ↑; this will select all cells up to the last cell with contents (the one you just wrote your formula in). Press Ctrl + V to paste your contents.
Adding dollar signs in front of your row/column coordinates, will lock that coordinate when pasted. Say you had a list of file types in cells b1–z1 (e.g. jpg, jpeg, tga, bmp, png et c.). An easy way to create the formula would then be by first typing it in cell B3 as =concatenate(A3;B$1), then paste it to every cell till the end of your file names list (cell z3); these cells would then read …A3;b$1, …A3;C$1 et c. When copying it for all the rows below
You could select the entire range of cells with formulas in row 3 and run a search and replace, replacing all instances of ‘A3;’ by ‘A3;$’, effectively inserting a dollar in front of all the cell references, allowing you to, should the need arise, copy it horizontally as well as vertically (the latter being covered by the $ in front of 1).
¹ This means cells from A3 and however far down your sheet goes
² Strictly speaking, it is only necessary to type it as a$1.
I have a Word document with fields of the reference variety, which occur in the form "[field].[field]"--in other words, there's a period between the two fields. I want to globally replace this with a space.
Word offers the ^d special character to search for fields, but for some reason the query "^d.^d" does not find anything. However, ".^d" does. Now comes the problem, however--what do I specify as the replacement text in order to retain the field code? If using regular expressions, I could use a "Find What Expression" such as \1, but with regexp ("wild card") mode the ^d is not permitted.
I guess I could write a macro...
I would like to add to Bibadia's solution.
An example of an index entry field; we want to change a name we misspelled.
Make sure hidden formatting is displayed (toggle with SHIFT+CTRL+F8).
Make sure wildcards option is not selected. To search for fields, use the opening and closing field braces code (optionally use ^w for spaces, as Bibadia suggested):^19 XE "Deo, John" ^21
Replace won't recognize field braces character, but will allow to insert the clipboard's content. ;). To do that, insert in text the correct entry. CTRL+F9 to insert field and type:XE "Doe, John"
Select the field above and copy
Use ^c in the replace box
Hit Replace All
Ta-da!
It's usually better to go the macro route when finding fields because, as you say, the find algorithm that Word uses doesn't work the way you might hope with fields.
But if you know exactly what the fields contain, you can specify a search pattern that will probably work (however not in wildcard mode).
For example, if you want to look for figure number field pairs such as
{ STYLEREF 1 \s }.{ SEQ Figure \* ARABIC \s 1 }
(which would typically be the same set of fields everywhere in the document)
If you only really need to look for the following:
{ STYLEREF 1 \s }.<any field>
you could ensure that field codes are displayed and search for
^d STYLEREF 1 \s ^21.^d
or
^19 STYLEREF 1 \s ^21.^19
If you need to be more precise, you can spell out the second field as well.
"^d" only works for finding the field beginning, not the field end.
It's a shame that ^w wants to find at least 1 whitespace character because otherwise it would be more robust to look for
^19^wSTYLEREF^w1^w\s^w^21.^19
Perhaps someone else knows how to work around that without using wildcards?
Torzaburo,
I suggest that you do this using a macro. You can start by recording the macro, and later refining your processing steps within the macro.
First turn on the hidden characters by navigating to Home > Paragraph > toggle the show/hide Paragraph symbol. Also, select all and toggle the field codes on (right-click and select "Toggle Field Codes".
Open a new blank Word doc in addition to the one you have open. You will use this later. Start the macro recording and find the field using the "^d" (field code) as you said.
When the field is found, copy only the field text within the brackets, and not the full field reference. While the macro is still recording, ALT + TAB to the new blank document and paste the field code in as plain text.
At this point, do the necessary find & replace processing to the field codes. Highlight the processed field codes, copy, ALT + TAB back to the original document, and paste back between the { } brackets.
Stop the macro recording. Add any further custom processing to the macro VBA.
Select-All and re-toggle the field codes. Update the field codes.
You don't need a macro. Just toggle all field codes on by using Alt+F9. Then do a find and replace for what you want to change. Once the replacement is complete, use Alt+F9 again to toggle the field codes back off.
Disclaimer: I didn't originate this solution, but it's clean and elegant and I thought it should be included here:
(Adapted from Search & Replace Field Codes in Word):
Create or find a single instance of the field you want to convert text to
Toggle Field Codes visible (AltF9)
Copy the code for the field you want to use to the Clipboard (highlight and CtrlC)
Open the Replace dialog box (CtrlH), insert the text you want to replace in the Find What box and then enter ^c in the Replace With box.
This will replace your text with the contents of the Clipboard, turning it into the field code you copied in step 3. It also copies formatting information (font, color, etc.), to control how the field will appear when hidden. (Caveat: I've tested this with Word 2003 under Windows 7 only.)
Coming in late on this, probably way too late for Beth (sorry Beth). And this may not be quite what Beth was looking for. But for anyone interested ...
It sounds like Beth may have created captions throughout the document using INSERT CAPTION (hence the presence of field codes). This means these captions will have been (automatically) created in CAPTION style.
To globally replace the separator "." with " " (space) in such captions, take two steps:
[1] Go to REFERENCES | INSERT CAPTION, then click on NUMBERING and replace the SEPARATOR "." with "EM-DASH". This will replace all separators in captions for the selected label in the CAPTION Window. If you have other labels in use in the document (e.g. FIGURE), select the other labels one by one and repeat this process.
[2] Do a find/replace searching for special character "em-dash" (^+) in style CAPTION, replacing with " ". Click REPLACE ALL.
Voila!
NOTE: This presumes that em-dash does not appear in the caption text anywhere. If it does, then you'll need to do a pre- and post- "fiddle" to ensure these em-dashes are not touched by the global replace above.
The "pre-fiddle" is to do a global find/replace across captions, replacing the em-dash ("^+") with some other string (e.g. "EM-DASH") that doesn't ever occur in any caption's text. Then you do the separator change as described above. Finally, the "post-fiddle" is to restore the em-dashes that were in the captions, by doing a global replace of the string "EM-DASH" with the actual em-dash character "^+".
I have a MATLAB program I am developing in order to do some image processing stuff and need to use a user control into a MATLAB GUI user interface I created ad-hoc.
This user control is a List Box and there I would like to insert some text. Well the problem is not that I cannot put text there, I can do that using this call:
set(handles.mylistbox, 'String', 'MyStringToPrint');
Well the problem is that this call does not let me insert many lines in my list box but just overwrite the previous one.
I wish to find a way to let my code insert the new text in a new line. This should not be so difficult to do and it is also a simple pattern:
texttoprint = 'My text to add'
oldtext = get(handles.MyListBox, 'String') %Holding the previous text here
set(handles.MyListBox, 'String', [oldtext '\n' texttoprint]) %Setting (no line feed printed)
set(handles.MyListBox, 'String', [oldtext char(10) texttoprint]) %Setting (this fails too)
Well it is ok and it does not raise any error BUT, \n DOES NOT WORK.
I do not have any new line... BUT NEED TO!!!!
How should I solve this?
The problem is that I need to print text in this user control, not on the MATLAB commandline (that is very simple just by doing sprintf()).
What to do? Thank you
For a listbox, set the string property to a cell
set(myListboxHandle,'String',{'myFirstLine';'mySecondLine'})
If you want to add another line, call
contents = get(myListboxHandle,'String');
set(myListboxHandle,[contents;{'another line'}])
For multiline text in GUIs otherwise, use char(10) instead of \n, i.e.
set(someUiControlHandle,'String',sprintf('my first line%smy second line',char(10)))
When working with list boxes it's usually easier to deal with the options as a cell array of strings. So, you would initialize your list box as follows:
set(handles.MyListBox,'String',{'Option 1'});
And then you can add options to your list box like so:
newOption = 'Option 2';
oldOptions = get(handles.MyListBox,'String');
set(handles.MyListBox,'String',[oldOptions; {newOption}]);