I have two tables. I wrote this query but don't show for table result
how write perfect query show table result?
Taccess
id userid groupid accesstype
1 2 1 1
2 4 1 1
Tgroup
grugroupid groupbname userid
1 group-1 1
2 group-2 2
3 group-3 3
4 group-4 4
I need this result for userid=1
I want show all groupid then show accesstype userid=1
grugroupid groupbname accesstype
1 group-1 1
2 group-2 null
3 group-3 null
4 group-4 null
select grugroupid ,
userid ,groupbname ,
(select AccessType from Access where UserID=2 ) as dd,
from TLab_Info
union
select id userid groupid accesstype
from TLab_Access
SELECT g.grugroupid,g.groupbname,a.accesstype
FROM Tgroup g LEFT JOIN
Taccess a on g.grugroupid=a.groupid
WHERE (a.accesstype IS NULL) OR (a.accesstype=1)
GROUP BY g.grugroupid,g.groupbname,a.accesstype
Result:
grugroupid groupbname accesstype
----------------------------------
1 group-1 1
2 group-2 (null)
3 group-3 (null)
4 group-4 (null)
See result in SQL Fiddle.
additional variant to already posted by Raging Bull
SELECT DISTINCT
g.grugroupid,
g.groupbname,
a.accesstype
FROM Tgroup g LEFT JOIN
Taccess a ON g.grugroupid = a.groupid
WHERE COALESCE(a.accesstype,1) = 1
test is here SQL Fiddle
Related
table_1
id customer_id
---------------
1 1
2 2
3 1
4 1
5 3
6 4
table_2
id id_table1 device_mac
-------------------------------------
1 1 aa:bb:cc:dd:ee:ff
2 1 11:22:33:44:55:66
3 2 1a:2a:3a:4a:5a:6a
4 3 2b:3b:4b:5b:6b:7b
5 4 3c:4c:5c:6c:7c:8c
6 2 4d:5d:6d:7d:8d:9d
table_3
id device_mac device_name
---------------------------------------
1 aa:bb:cc:dd:ee:ff loc1
2 11:22:33:44:55:66 loc2
3 1a:2a:3a:4a:5a:6a loc3
4 2b:3b:4b:5b:6b:7b loc4
5 3c:4c:5c:6c:7c:8c loc5
6 4d:5d:6d:7d:8d:9d loc6
I have a requirement where I need to get the below details by customer_id using python and postgres db.
ex: get details with customer_id = 1
table1_id count(table_2) device_names
1 2 [loc1, loc2]
3 1 [loc4]
4 1 [loc5]
I tried with individual queries using python:
select id from table_1 where customer_id=1;
for t1_id from ids above table_1 data:
select * from table_2 where table_id=t1_id
for t2_data from ids above table2_data:
select * from table_3 where device_mac = t2_data.device_mac
# generate expected rows
Can I just do this in a signle query?
Join the tables and aggregate:
SELECT t1.id,
COUNT(*) count,
STRING_AGG(t3.device_name, ',' ORDER BY t3.device_name) device_names
FROM table_1 t1
INNER JOIN table_2 t2 ON t2.id_table1 = t1.id
INNER JOIN table_3 t3 ON t3.device_mac = t2.device_mac
WHERE t1.customer_id = 1
GROUP BY t1.id
If you are getting duplicate device_names you may use DISTINCT:
STRING_AGG(DISTINCT t3.device_name, ',' ORDER BY t3.device_name) device_names
See the demo.
Results:
id
count
device_names
1
2
loc1,loc2
3
1
loc4
4
1
loc5
I have customer ID and transaction Date(yyyy-mm-dd) as shown below
Cust_id Trans_date
1 2017-01-01
1 2017-01-03
1 2017-01-06
2 2017-01-01
2 2017-01-04
2 2017-01-05
I need to find the difference in no_of_days for each transaction grouped at Cust_id
I tried with date_diff and extract using lag function, but I am getting error
function lag(timestamp without time zone) may only be called as a window function
I looking for the result as below
Cust_id Trans_date difference
1 2017-01-01 0
1 2017-01-03 3
1 2017-01-05 2
2 2017-01-01 0
2 2017-01-04 4
2 2017-01-05 1
How to find the difference in postgreSQL?
This is what you want?
with t(Cust_id,Trans_date) as(
select 1 ,'2017-01-01'::timestamp union all
select 1 ,'2017-01-03'::timestamp union all
select 1 ,'2017-01-06'::timestamp union all
select 2 ,'2017-01-01'::timestamp union all
select 2 ,'2017-01-04'::timestamp union all
select 2 ,'2017-01-05'::timestamp
)
select
Cust_id,
Trans_date,
coalesce(Trans_date::date - lag(Trans_date::date) over(partition by Cust_id order by Trans_date), 0) as difference
from t;
I have two tables and for each ID and Level combination in table1, I need to get a count of times matching ID appears in table2 in between sequential times for levels in table1.
So for example, for ID = 1 and Level=1 in table1, two Time entries from table2 for ID=1 fall between Time of Level=1 and Level=2 in table1, so result will be 2 in the result table.
table1:
ID Level Time
1 1 6/7/13 7:03
1 2 6/9/13 7:05
1 3 6/12/13 12:02
1 4 6/17/13 5:01
2 1 6/18/13 8:38
2 3 6/20/13 9:38
2 4 6/23/13 10:38
2 5 6/28/13 1:38
table2:
ID Time
1 6/7/13 11:51
1 6/7/13 14:15
1 6/9/13 16:39
1 6/9/13 19:03
2 6/20/13 11:02
2 6/20/13 15:50
Result would be
ID Level Count
1 1 2
1 2 2
1 3 0
1 4 0
2 1 0
2 3 2
2 4 0
2 5 0
select transformed_tab1.id, transformed_tab1.level, count(tab2.id)
from
(select tab1.id, tab1.level, tm, lead(tm) over (partition by id order by tm) as next_tm
from
(
select 1 as id, 1 as level, '2013-06-07 07:03'::timestamp as tm union
select 1 as id, 2 as level, '2013-06-09 07:05 '::timestamp as tm union
select 1 as id, 3 as level, '2013-06-12 12:02'::timestamp as tm union
select 1 as id, 4 as level, '2013-06-17 05:01'::timestamp as tm union
select 2 as id, 1 as level, '2013-06-18 08:38'::timestamp as tm union
select 2 as id, 3 as level, '2013-06-20 09:38'::timestamp as tm union
select 2 as id, 4 as level, '2013-06-23 10:38'::timestamp as tm union
select 2 as id, 5 as level, '2013-06-28 01:38'::timestamp as tm) tab1
) transformed_tab1
left join
(select 1 as id, '2013-06-07 11:51'::timestamp as tm union
select 1 as id, '2013-06-07 14:15'::timestamp as tm union
select 1 as id, '2013-06-09 16:39'::timestamp as tm union
select 1 as id, '2013-06-09 19:03'::timestamp as tm union
select 2 as id, '2013-06-20 11:02'::timestamp as tm union
select 2 as id, '2013-06-20 15:50'::timestamp as tm) tab2
on transformed_tab1.id=tab2.id and tab2.tm between transformed_tab1.tm and transformed_tab1.next_tm
group by transformed_tab1.id, transformed_tab1.level
order by transformed_tab1.id, transformed_tab1.level
;
SQL Fiddle
select t1.id, level, count(t2.id)
from
(
select id, level,
tsrange(
"time",
lead("time", 1, 'infinity') over(
partition by id order by level
),
'[)'
) as time_range
from t1
) t1
left join
t2 on t1.id = t2.id and t1.time_range #> t2."time"
group by t1.id, level
order by t1.id, level
The solution starts creating a range of timestamps using the lead window function. Notice the [) parameter to the tsrange constructor. It means to include the lower and exclude the upper bound.
Then it joins the two tables with the #> range operator. It means the range includes the element.
It is necessary to left join t1 to have the zero counts.
My table has a parent/child relationship, along the lines of parent.id,id. There is also a column that contains a quantity, and another ID representing a grand-parent, like so:
id parent.id qty Org
1 1 1 100
2 1 0 100
3 1 4 100
4 4 1 101
5 4 2 101
6 6 1 102
7 6 0 102
8 6 1 102
What this is supposed to show is ID 1 is the parent, and ID 2 and 3 are children which belongs to ID 1, and ID 1, 2, and 3 all belong to the grandparent 100.
I would like to know if any child or parent has QTY = 0, what are all the other id's associated to that parent, and what are all the other parents associated with that grandparent?
For example, I would want to see a report that shows me this:
Org id parent.id qty
100 1 1 1
100 2 1 0
100 3 1 4
102 6 6 1
102 7 6 0
102 8 6 1
Much appreciate any help you can offer to build a MS SQL 2000 (yeah, I know) query to handle this.
Try this
select * from tablename a
where exists (select 1 from tablename x
where x.parent_id = a.parent_id and qty = 0)
Example:
;with cte as
( select 1 id,1 parent_id, 1 qty, 100 org
union all select 2,1,0,100
union all select 3,1,4,100
union all select 4,4,1,101
union all select 5,4,2,101
union all select 6,6,1,102
union all select 7,6,0,102
union all select 8,6,1,102
)
select * from cte a
where exists (select 1 from cte x
where x.parent_id = a.parent_id and qty = 0)
SQL DEMO HERE
I have two tables:
PeriodId Period (Periods Table)
-------- -------
1 Week 1
2 Week 2
3 Week 3
EmpId PeriodId ApprovedDate (Worked Table)
----- -------- ------------
1 1 Null
1 2 2/28/2013
2 2 2/28/2013
I am trying to write a query that results in this:
EmpId Period Worked ApprovedDate
----- -------- --------- ------------
1 Week 1 Yes Null
1 Week 2 Yes 2/28/2013
1 Week 3 No Null
2 Week 1 No Null
2 Week 2 Yes 2/28/2013
2 Week 3 No Null
The idea is that I need each Period from the Periods table for each Emp. If there was no record in the Worked table then the 'No' value is placed Worked field.
What does the TSQL look like to get this result?
(Note: if it helps I also have access to an Employee table that has EmpId and LastName for each employee. For performance reasons I'm hoping not to need this but if I do then so be it.)
You should be able to use the following:
select p.empid,
p.period,
case
when w.PeriodId is not null
then 'Yes'
else 'No' End Worked,
w.ApprovedDate
from
(
select p.periodid, p.period, e.empid
from periods p
cross join (select distinct EmpId from worked) e
) p
left join worked w
on p.periodid = w.periodid
and p.empid = w.empid
order by p.empid
See SQL Fiddle with Demo