We hold a file on a server where we store a version number. Now we update the file extension with that version number (not my choice and not something I can change).
So what I need to be able to do in a batch file is to read that file extension. I know the path to the file and the filename, but need to be able to determine what the extension currently is.
you can search with a wildcard character * to find the file
dir file.txt.* /s /p
Related
I see no way to set destination directory or file here: http://www.cs.cmu.edu/~quake/triangle.switch.html
Actually, the program places result file in the same directory, even if current directory is different.
Why? Is ti possible to change?
The output files for the program are generated from the input file names. You can see this from the source code on line 3586
strcpy(b->outnodefilename, b->innodefilename);
...
strcat(b->outnodefilename, ".node");
strcat(b->outelefilename, ".ele");
...
Because of that I don't think there is a way to set the output directory as an option. It seems you will need to manually copy the output files to a different directory
cp output.node your/output/dir/output.node && rm output.node
example
There is a file "sample.rar".
Folder structure is: "rising\dawn\ and here there are many (folders1, folders2 and file1, file2)" in this archive.
i have used following command
7z.exe x "sample.rar" "rising\dawn\*" -oi:\delete
The result is:
all files and folders in "rising\dawn\" are extracted to "i:\delete" folder but the empty parent folders "rising\dawn\" are also created in destination folder.
e.g. destination looks:
i:\delete\rising\dawn\folder1\file1.bmp
i:\delete\rising\dawn\folder2\subfolder
i:\delete\rising\dawn\file1.txt
i:\delete\rising\dawn\file2.txt
i don't want "rising\dawn\" empty folders to be created but the folder structure there onwards must be as is in the archive.
i want the result:
i:\delete\folder1\file1.bmp
i:\delete\folder2\subfolder
i:\delete\file1.txt
i:\delete\file2.txt
at last i found a way out solution. thanks to the winrar support. i have accepted it as an answer below.
if you find the question useful don't forget to click the up-vote button.
Finally this gave me the result.
Thanks to winrar support.
rar x -ep1 sample.rar rising\dawn\* d:\e\delete\
i have tried other answers given here, this is the only correct answer.
don't forget to upvote.
You can extract the archive normally and
1) move the lower level folder/files to where you would like it, then
2) remove the extra top level archive folders.
Code to do so will depend on the exact task.
Using e command instead of x and add -r option works well.
Like this:
7z.exe e -r "sample.rar" "rising\dawn\*" -oi:\delete
My executable version is "7-Zip [64] 9.20 2010-11-18",
And the platform is Windows 8.1.
This command line eliminates unnecessary parent folders and preserves the hierarchy of folders.
You need to use the e command rather than the x command:
7z.exe e "sample.rar" "scholar\update\*" -oi:\delete
Using e instead of x means 7zip will extract all matching files into the same folder (as specified via the -so switch, or the current directory if this isn't specified) rather than preserving the folder structure from inside the archive.
I'm currently stuck with this problem where my .gz file is "some_name.txt.gz" (the .gz is not visible, but can be recognized with File::Type functions),
and inside the .gz file, there is a FOLDER with the name "some_name.txt", which contains other files and folders.
However, I am not able to extract the archive as you would manually (the folder with the name "some_name.txt" is extracted along with its contents) when calling the extract function from the Archive::Extract because it will just extract the "some_name.txt" folder as a .txt file.
I've been searching the web for answers, but none are correct solutions. Is there a way around this?
From Archive::Extract official doc
"Since .gz files never hold a directory, but only a single file;"
I would recommend using tar on the folder and then gz it.
That way you can use Archive::Tar to easily extract specific file:
Example from official docs:
$tar->extract_file( $file, [$extract_path] )
Write an entry, whose name is equivalent to the file name provided to disk. Optionally takes a second parameter, which is the full native path (including filename) the entry will be written to.
For example:
$tar->extract_file( 'name/in/archive', 'name/i/want/to/give/it' );
$tar->extract_file( $at_file_object, 'name/i/want/to/give/it' );
Returns true on success, false on failure.
Hope this helps.
Maybe you can identify these files with File::Type, rename them with .gz extension instead of .txt, then try Archive::Extract on it?
A gzip file can only contain a single file. If you have an archive file that contains a folder plus multiple other files and folders, then you may have a gzip file that contains a tar file. Alternatively you may have a zip file.
Can you give more details on how the archive file was created and a listing of it contents?
How can I find a folder from a specific location using command prompt.
eg:- I want to search files from desktop and there are around 10 files that contains the name starting from A and i want locations of all such file with file name.
I know it can be done using find commnad but I am unable to write the correct code for it.
Thanks for the help
you can find all files from a directory and sub directories that start with 'a' using this:
dir /b /s a*.*
I am using Windows 7 Enterprise and have approximately 20 files per day for the last 365 days that I need to sort.
All of the files are in the same directory. Each file name also contains the date of the file's creation. The date is in the format MM-DD-YYY and starts at the 29th character of the file name. The files have the .csv extension.
I need to create a batch file to move all of the files with the same date into their own folder and onto another drive on my computer.
#echo off
setlocal EnableDelayedExpansion
for %%a in (*.csv) do (
set fileName=%%~a
set datePart=!fileName:~28,9!
if not exist "D:\!datePart!" md "D:\!datePart!"
move "%%a" "D:\!datePart!"
)
This script extracts the date part of each file name and uses it as the name of the folder to move the file to. If the folder doesn't exist, it is created, then the file is moved to it.
As written, the script iterates over the .csv files in the current directory. This is specified by the mask in the for loop: *.csv. You can change the mask to include a specific path to process, like C:\path\to\*.csv.
The target drive is also hard-coded and assumed to be D:. Change the corresponding entries of the script if you need to use a different drive.
Detail information on every command used in this script can be obtained by calling the command's built-in help from the command prompt, using either of the below syntaxes:
command /?
help command