So this is my table in database:
Worker X have this work result BETWEEN '2015-06-01' AND '2015-06-06':
What I want to do is to count the number of work days but my condition is that if (nb_heures + nb_heures_s) > 4 I count it 1 day but if (nb_heures + nb_heures_s) <= 4 I count it 0.5 day.
So the result I must get from this table 5.5 work days and not 6.
I tried this query but it's not working well:
SELECT
count(CASE WHEN (nb_heures + nb_heures_s) > 4 THEN 1 END) as full_day_work,
count(CASE WHEN (nb_heures + nb_heures_s) <= 4 THEN 0.5 END) as half_day_work
FROM pointage_full pf
WHERE date_pointage BETWEEN '2015-06-01' AND '2015-06-06'
AND pf.id_salarie = 5
How can I reach my objectif ?
COUNT(expr) always returns a bigint, as it simply returns the number of rows for which expr is not NULL.
You can use SUM instead :
SELECT SUM(CASE WHEN (nb_heures + nb_heures_s) > 4 THEN 1 ELSE 0.5 END) as number_of_days
FROM pointage_full pf
WHERE date_pointage BETWEEN '2015-06-01' AND '2015-06-06';
Related
Is it possible to Average after every fixed interval and group by one column in MSSQL ?
Suppose I have a table A as under:
NAME Interval Data1 Data2
1 0.01 1 4
1 0.05 4 2
1 0.09 7 6
1 0.11 1 2
1 0.15 7 6
1 0.18 3 1
1 0.19 2 5
2 0.209 9 0
I want the Output to group by Name and run average every 10 counts.
So for expamle
Name - 1
Interval Start - 0
Interval End - 10
Data 1 Avg - 4 [(1 + 4 + 7) / 3]
Data 3 Avg - 4 [(4 + 2 + 6) / 3]
AND
Name - 1
Interval Start - 10
Interval End - 20
Data 1 Avg - 3.25 [(1 + 7 + 3 + 2) / 4]
Data 3 Avg - 3.50 [(2 + 6 + 1 + 5) / 4]
So I want the Ouput as below. The interval per "Name" column is different.
Name Interval-Start Interval-End DataAvg1 DataAvg2
1 0 10 4 4
1 10 20 3.25 3.50
2 0 10 0 0
2 10 20 0 0
2 20 30 9 0
I used the below query, but cant figure out logic per interval.
SELECT Name, Interval, AVG(Data1) AS Data1Avg, AVG(Data2) AS Data2Avg
FROM TableA
GROUP BY Name;
Can someone please help me with it.
using cursor and temp table
--drop table dbo.#result
--drop table dbo.#steps
CREATE TABLE dbo.#result
(
[Name] varchar(50),
[Interval-Start] float,
[Interval-End] float,
[DataAvg1] float,
[DataAvg2] float
)
CREATE TABLE dbo.#steps
(
[IntervalStart] float,
[IntervalEnd] float
)
declare #min int, #max int, #step float
DECLARE #Name varchar(50), #IntervalStart float, #IntervalEnd float;
set #min = 0
set #max = 1
set #step = 0.1
insert into #steps
select #min + Number * #step IntervalStart, #min + Number * #step + #step IntervalEnd
from master..spt_values
where type = 'P' and number between 0 and (#max - #min) / #step
DECLARE _cursor CURSOR FOR
SELECT [Name], [IntervalStart], [IntervalEnd] FROM
(select [Name] from [TableA] Group by [Name]) t
INNER JOIN #steps on 1=1
OPEN _cursor;
FETCH NEXT FROM _cursor
INTO #Name, #IntervalStart, #IntervalEnd;
WHILE ##FETCH_STATUS = 0
BEGIN
insert into dbo.#result
select #Name, #IntervalStart, #IntervalEnd, AVG(CAST(Data1 as FLOAT)), AVG(CAST(Data2 as FLOAT))
FROM [TableA]
where [NAME] = #Name and Interval between #IntervalStart and #IntervalEnd
FETCH NEXT FROM _cursor
INTO #Name, #IntervalStart, #IntervalEnd;
END
CLOSE _cursor;
DEALLOCATE _cursor;
select * from dbo.#result
I want to get a table that constructs a column that tracks how many times an id appears in a given week. If the id appears once it is given a 1, if it appears twice it is given a 2, but if it appears more than two times it is given a 0.
id date
a 2015-11-10
a 2015-11-25
a 2015-11-09
b 2015-11-10
b 2015-11-09
a 2015-11-05
b 2015-11-23
b 2015-11-28
b 2015-12-04
a 2015-11-10
b 2015-12-04
a 2015-12-07
a 2015-12-09
c 2015-11-30
a 2015-12-06
c 2015-10-31
c 2015-11-04
b 2015-12-01
a 2015-10-30
a 2015-12-14
the one week intervals are given as follows
1 - 2015-10-30 to 2015-11-05
2 - 2015-11-06 to 2015-11-12
3 - 2015-11-13 to 2015-11-19
4 - 2015-11-20 to 2015-11-26
5 - 2015-11-27 to 2015-12-03
6 - 2015-12-04 to 2015-12-10
7 - 2015-12-11 to 2015-12-17
The table should look like this.
id interval count
a 1 2
b 1 0
c 1 2
a 2 0
b 2 2
c 2 0
a 3 0
b 3 0
c 3 0
a 4 1
b 4 1
c 4 0
a 5 0
b 5 2
c 5 1
a 6 0
b 6 2
c 6 0
a 7 1
b 7 0
c 7 0
The interval column doesn't have to be there, I simply added it for clarity.
I am new to sql and am unsure how to break the dates into intervals. The only thing I have is grouping by date and counting.
Select id ,date, count (*) as frequency
from data_1
group by id, date having frequency <= 2;
Looking at just the data you provided, this does the trick:
SELECT v.id,
i.interval,
coalesce((CASE WHEN sub.cnt < 3 THEN sub.cnt ELSE 0 END), 0) AS count
FROM (VALUES('a'), ('b'), ('c')) v(id)
CROSS JOIN generate_series(1, 7) i(interval)
LEFT JOIN (
SELECT id, ((date - '2015-10-30')/7 + 1)::int AS interval, count(*) AS cnt
FROM my_table
GROUP BY 1, 2) sub USING (id, interval)
ORDER BY 2, 1;
A few words of explanation:
You have three id values which are here recreated with a VALUES clause. If you have many more or don't know beforehand which id's to enumerate, you can always replace the VALUES clause with a sub-query.
You provide a specific date range over 7 weeks. Since you might have weeks where a certain id is not present you need to generate a series of the interval values and CROSS JOIN that to the id values above. This yields the 21 rows you are looking for.
Then you calculate the occurrences of ids in intervals. You can subtract a date from another date which will give you the number of days in between. So subtract the date of the row from the earliest date, divide that by 7 to get the interval period, add 1 to make the interval 1-based and convert to integer. You can then convert counts of > 2 to 0 and NULL to 0 with a combination of CASE and coalesce().
The query outputs the interval too, otherwise you will have no clue what the data refers to. Optionally, you can turn this into a column which shows the date range of the interval.
More flexible solution
If you have more ids and a larger date range, you can use the below version which first determines the distinct ids and the date range. Note that the interval is now 0-based to make calculations easier. Not that it matters much because instead of the interval number, the corresponding date range is displayed.
WITH mi AS (
SELECT min(date) AS min, ((max(date) - min(date))/7)::int AS intv FROM my_table)
SELECT v.id,
to_char((mi.min + i.intv * 7)::timestamp, 'YYYY-mm-dd') || ' - ' ||
to_char((mi.min + i.intv * 7 + 6)::timestamp, 'YYYY-mm-dd') AS period,
coalesce((CASE WHEN sub.cnt < 3 THEN sub.cnt ELSE 0 END), 0) AS count
FROM mi,
(SELECT DISTINCT id FROM my_table) v
CROSS JOIN LATERAL generate_series(0, mi.intv) i(intv)
LEFT JOIN LATERAL (
SELECT id, ((date - mi.min)/7)::int AS intv, count(*) AS cnt
FROM my_table
GROUP BY 1, 2) sub USING (id, intv)
ORDER BY 2, 1;
SQLFiddle with both solutions.
Assuming you have a table of all users, this will do the trick.
select
users.id,
interval_table.id,
CASE
WHEN count(log_table.user_id)>2 THEN 0
ELSE count(log_table.user_id)
END
from users
cross join interval_table
left outer join log_table
on users.id = log_table.user_id
and log_table.event_date >= interval_table.start_interval
and log_table.event_date < interval_table.stop_interval
group by users.id, interval_table.id
order by interval_table.id, users.id
Check it out: http://sqlfiddle.com/#!15/1a822/21
I am using the following query to get column totals by week for a given date range...
SELECT to_char(week_start - 1, 'dd-MON-yy') week_end, run_qty, acc_qty, CASE WHEN run_qty <> 0 THEN ROUND(acc_qty/run_qty, 4) ELSE 0 END pct
FROM (SELECT week_start, SUM(run_qty) run_qty, SUM(acc_qty) acc_qty
FROM (SELECT TRUNC(NEXT_DAY(TRUNC(created_date), 'Monday')) week_start, NVL(SUM(run_qty), 0) run_qty, NVL(SUM(accepted_qty), 0) acc_qty
FROM shema.table_a
WHERE (some conditions)
AND created_date BETWEEN :FromDate AND :ToDate
GROUP BY TRUNC(NEXT_DAY(TRUNC(created_date), 'Monday'))
UNION
SELECT TRUNC(NEXT_DAY(TRUNC(to_date(zday, 'dd-mon-rrrr')), 'Monday')) week_start, 0run_qty, 0acc_qty
FROM (SELECT :FromDate + (level - 1) zday
FROM dual
CONNECT BY LEVEL <= (:ToDate - :FromDate)))
GROUP BY week_start
ORDER BY week_start desc)
With input paramters of :FromDate = 4/31/2015 and :ToDate = 6/25/2015, this gives me the last day of each week (week defined as Monday - Sunday), the run total for each each week, the accepted total for each week, and the pct of the run total accepted for each week, in a result set that looks like so...
28-JUN-2015 0 0 0
21-JUN-2015 100 50 0.5
14-JUN-2015 50 40 0.8
07-JUN-2015 0 0 0
31-MAY-2015 0 0 0
24-MAY-2015 50 40 0.75
17-MAY-2015 80 50 0.625
10-MAY-2015 60 20 0.3333
03-MAY-2015 0 0 0
Can I use a similar approach in order to calculate a running total of the run and accepted quantities and percentage of quantity accepted over the date range provided? (to give me a result set that would look like)...
28-JUN-2015 340 200 0.5882
21-JUN-2015 340 200 0.5882
14-JUN-2015 240 150 0.625
07-JUN-2015 190 110 0.5789
31-MAY-2015 190 110 0.5789
24-MAY-2015 190 110 0.5789
17-MAY-2015 140 70 0.5
10-MAY-2015 60 20 0.3333
03-MAY-2015 0 0 0
I figured it out... in case anyone runs into this thread by searching for a solution to a similar issue, I wrapped the query above inside...
SELECT week_end, run_qty, acc_qty, pct
FROM (query above)
MODEL
DIMENSION BY(row_number() OVER (ORDER BY to_date(week_end, 'dd-MON-yy') asc) rec)
MEASURES(week_end, run_qty, acc_qty, pct)
RULES(
run_qty[rec > 1] ORDER BY rec = run_qty[cv()] + run_qty[cv() - 1],
acc_qty[rec > 1] ORDER BY rec = acc_qty[cv()] + acc_qty[cv() - 1],
pct[rec >= 0] ORDER BY rec = CASE WHEN run_qty[cv()] <> 0 THEN ROUND(acc_qty[cv()]/run_qty[cv()], 4) ELSE 0 END
)
ORDER BY to_date(week_end, 'dd-MON-yy') desc
...and it runs quickly, giving me the expected results
Good Day Everyone!
well i have this kind of code and it kinda ugly,
a friend of mine told me i can implement Case Statements in here, but i do not know how or how would i implement, the code is long so if you could just help me to optimize my code i would appreciate it greatly!
PS. please be gentle to me, im new in T-sql :)
Thank yoU!
SELECT
SUM(CYJEWELRY) 'CY_Jewelry'
,SUM(CYAPPLICANCE) 'CY_Appliance'
,SUM(CYCELLPHONE) 'CY_Cellphone'
,SUM(PYJEWELRY) 'PY_Jewelry'
,SUM(PYAPPLIANCE) 'PY_Appliance'
,SUM(PYCELLPHONE) 'PY_Cellphone'
FROM
(
---TOTAL NUNG A FORMAT 0,0,0,0,0,0
--------------CURRENT YEAR JEWELRY
SELECT COUNT (*) AS CYJEWELRY,0 AS CYAPPLICANCE,0 AS CYCELLPHONE,0 AS PYJEWELRY,0 AS PYAPPLIANCE,0 AS PYCELLPHONE
FROM #TEMPTABLE1
WHERE (fld_StorageGroupID >= 3 and fld_StorageGroupID <= 14)
UNION
-----------CURRENT YEAR APPLIANCE
SELECT 0,COUNT(*),0,0,0,0
FROM #TEMPTABLE1
WHERE fld_StorageGroupID = 1
UNION
------------CURRENT YEAR CELLPHONE
SELECT 0,0,COUNT(*),0,0,0
FROM #TEMPTABLE1
WHERE fld_StorageGroupID = 2
UNION
---------------LAST YEAR JEWELRY
SELECT 0,0,0,COUNT(*),0,0
FROM #TEMPTABLE2
WHERE (fld_StorageGroupID >= 3 and fld_StorageGroupID <= 14)
UNION
-----------------------LAST YEAR APPLIANCE
SELECT 0,0,0,0,COUNT (*),0
FROM #TEMPTABLE2
WHERE fld_StorageGroupID = 1
UNION
-------------------------LAST YEAR CELLPHONE
SELECT 0,0,0,0,0,COUNT(*)
FROM #TEMPTABLE2
WHERE fld_StorageGroupID = 2
)A
Assuming your data is bit like this Sql Fiddle Example, try this for the sub query using SUM() and CASE.
SELECT SUM(CASE WHEN fld_StorageGroupID >= 3 and fld_StorageGroupID <= 14 ELSE 0 END) Col1And4,
SUM(CASE WHEN fld_StorageGroupID = 1 THEN 1 ELSE 0 END) Col2And5,
SUM(CASE WHEN fld_StorageGroupID = 2 THEN 1 ELSE 0 END) Col3And6
FROM #TEMPTABLE1
GROUP BY fld_StorageGroupID
Since you are applying the same filter for last 3 columns in the subquery, I have done only first 3 columns here.
EDIT:
I think this is better than above (Note: no need to use SUM() in the main query).
Fiddle Example with data
select col1_4 CY_Jewelry,
col2_5 CY_Appliance,
col3_6 CY_Cellphone,
col1_4 PY_Jewelry,
col2_5 PY_Appliance,
col3_6 PY_Cellphone
from (
select sum(case when id>= 3 and id <= 14 then 1 else 0 end) col1_4,
sum(case when id = 2 then 1 else 0 end) col2_5,
sum(case when id = 3 then 1 else 0 end) col3_6
from t
--group by id
) X
I have a table with a list of values. -1 is a blank value:
ID FieldType1A FieldType1B FieldType2A FieldType2B Person
1 15 14 10 -1 1
2 16 -1 12 10 1
3 17 -1 5 6 1
4 6 -1 7 -1 2
...
So the result should be:
Person FieldType1 FieldType2
1 4 5
2 1 1
there is a users table with a list of user IDs, would there be a way of iterating over that list of values to generate the person list in the result set (0 for the field types being perfectly valid as it is merely counts)? I think the answer to T-SQL Column Values Count is a step in the direction I'm attempting to go, but unsure how to combine columns that are the same (the A/Bs allow for a list of answers). That and I'm interested in combining all valid values as not attempting to count the number of each valid response.
You can use a CASE expression to change all non-negative-one values to 1, and -1 values to 0, and then sum them up.
SELECT Person,
SUM(CASE WHEN FieldType1A <> -1 THEN 1 ELSE 0 END) +
SUM(CASE WHEN FieldType1B <> -1 THEN 1 ELSE 0 END) AS FieldType1,
SUM(CASE WHEN FieldType2A <> -1 THEN 1 ELSE 0 END) +
SUM(CASE WHEN FieldType2B <> -1 THEN 1 ELSE 0 END) AS FieldType2
FROM YourTable
GROUP BY Person
SELECT Person,
count(nullif(FieldType1A, -1)) + count(nullif(FieldType1B, -1)) as FieldType1,
count(nullif(FieldType2A, -1)) + count(nullif(FieldType2B, -1)) as FieldType2
FROM yourtable
GROUP BY person