Related
I have a "mongodb colllenctions" and I'd like to remove the "empty strings"with keys from it.
From this:
{
"_id" : ObjectId("56323d975134a77adac312c5"),
"year" : "15",
"year_comment" : "",
}
{
"_id" : ObjectId("56323d975134a77adac312c5"),
"year" : "",
"year_comment" : "asd",
}
I'd like to gain this result:
{
"_id" : ObjectId("56323d975134a77adac312c5"),
"year" : "15",
}
{
"_id" : ObjectId("56323d975134a77adac312c5"),
"year_comment" : "asd",
}
How could I solve it?
Please try executing following code snippet in Mongo shell which strips fields with empty or null values
var result=new Array();
db.getCollection('test').find({}).forEach(function(data)
{
for(var i in data)
{
if(data[i]==null || data[i]=='')
{
delete data[i]
}
}
result.push(data)
})
print(tojson(result))
Would start with getting a distinct list of all the keys in the collection, use those keys as your query basis and do an ordered bulk update using the Bulk API operations. The update statement uses the $unset operator to remove the fields.
The mechanism to get distinct keys list that you need to assemble the query is possible through Map-Reduce. The following mapreduce operation will populate a separate collection with all the keys as the _id values:
mr = db.runCommand({
"mapreduce": "my_collection",
"map" : function() {
for (var key in this) { emit(key, null); }
},
"reduce" : function(key, stuff) { return null; },
"out": "my_collection" + "_keys"
})
To get a list of all the dynamic keys, run distinct on the resulting collection:
db[mr.result].distinct("_id")
// prints ["_id", "year", "year_comment", ...]
Now given the list above, you can assemble your query by creating an object that will have its properties set within a loop. Normally your query will have this structure:
var keysList = ["_id", "year", "year_comment"];
var query = keysList.reduce(function(obj, k) {
var q = {};
q[k] = "";
obj["$or"].push(q);
return obj;
}, { "$or": [] });
printjson(query); // prints {"$or":[{"_id":""},{"year":""},{"year_comment":""}]}
You can then use the Bulk API (available with MongoDB 2.6 and above) as a way of streamlining your updates for better performance with the query above. Overall, you should be able to have something working as:
var bulk = db.collection.initializeOrderedBulkOp(),
counter = 0,
query = {"$or":[{"_id":""},{"year":""},{"year_comment":""}]},
keysList = ["_id", "year", "year_comment"];
db.collection.find(query).forEach(function(doc){
var emptyKeys = keysList.filter(function(k) { // use filter to return an array of keys which have empty strings
return doc[k]==="";
}),
update = emptyKeys.reduce(function(obj, k) { // set the update object
obj[k] = "";
return obj;
}, { });
bulk.find({ "_id": doc._id }).updateOne({
"$unset": update // use the $unset operator to remove the fields
});
counter++;
if (counter % 1000 == 0) {
// Execute per 1000 operations and re-initialize every 1000 update statements
bulk.execute();
bulk = db.collection.initializeOrderedBulkOp();
}
})
If you need to update a single blank parameter or you prefer to do parameter by parameter, you can use the mongo updateMany functionality:
db.comments.updateMany({year: ""}, { $unset : { year : 1 }})
I have mongodb documents with a field like this:
Image : http://static14.com/p/Inc.5-Black-Sandals-5131-2713231-7-zoom.jpg
How can I replace the zoom part in the string value with some other text in order to get:
Image : http://static14.com/p/Inc.5-Black-Sandals-5131-2713231-7-product2.jpg
You could use mongo's forEach() cursor method to do an atomic update with the $set operator :
db.collection.find({}).snapshot().forEach(function(doc) {
var updated_url = doc.Image.replace('zoom', 'product2');
db.collection.update(
{"_id": doc._id},
{ "$set": { "Image": updated_url } }
);
});
Given a very large collection to update, you could speed up things a little bit with bulkWrite and restructure your update operations to be sent in bulk as:
var ops = [];
db.collection.find({}).snapshot().forEach(function(doc) {
ops.push({
"updateOne": {
"filter": { "_id": doc._id },
"update": { "$set": { "Image": doc.Image.replace('zoom', 'product2') } }
}
});
if ( ops.length === 500 ) {
db.collection.bulkWrite(ops);
ops = [];
}
})
if ( ops.length > 0 )
db.collection.bulkWrite(ops);
db.myCollection.update({image: 'http://static14.com/p/Inc.5-Black-Sandals-5131-2713231-7-zoom.jpg'}, {$set: {image : 'http://static14.com/p/Inc.5-Black-Sandals-5131-2713231-7-product2.jpg'}})
If you need to do this multiple times to multiple documents, you need to iterate them with a function. See here: MongoDB: Updating documents using data from the same document
Nowadays,
starting Mongo 4.2, db.collection.updateMany (alias of db.collection.update) can accept an aggregation pipeline, finally allowing the update of a field based on its own value.
starting Mongo 4.4, the new aggregation operator $replaceOne makes it very easy to replace part of a string.
// { "Image" : "http://static14.com/p/Inc.5-Black-Sandals-5131-2713231-7-zoom.jpg" }
// { "Image" : "http://static14.com/p/Inc.5-Black-Sandals-5131-2713231-7-boom.jpg" }
db.collection.updateMany(
{ "Image": { $regex: /zoom/ } },
[{
$set: { "Image": {
$replaceOne: { input: "$Image", find: "zoom", replacement: "product2" }
}}
}]
)
// { "Image" : "http://static14.com/p/Inc.5-Black-Sandals-5131-2713231-7-product2.jpg" }
// { "Image" : "http://static14.com/p/Inc.5-Black-Sandals-5131-2713231-7-boom.jpg" }
The first part ({ "Image": { $regex: /zoom/ } }) is just there to make the query faster by filtering which documents to update (the ones containing "zoom")
The second part ($set: { "Image": {...) is the update aggregation pipeline (note the squared brackets signifying the use of an aggregation pipeline):
$set is a new aggregation operator (Mongo 4.2) which in this case replaces the value of a field.
The new value is computed with the new $replaceOne operator. Note how Image is modified directly based on the its own value ($Image).
Is there a way to conditionally $addToSet based on a specific key field in a subdocument on an array?
Here's an example of what I mean - given the collection produced by the following sample bootstrap;
cls
db.so.remove();
db.so.insert({
"Name": "fruitBowl",
"pfms" : [
{
"n" : "apples"
}
]
});
n defines a unique document key. I only want one entry with the same n value in the array at any one time. So I want to be able to update the pfms array using n so that I end up with just this;
{
"Name": "fruitBowl",
"pfms" : [
{
"n" : "apples",
"mState": 1111234
}
]
}
Here's where I am at the moment;
db.so.update({
"Name": "fruitBowl",
},{
// not allowed to do this of course
// "$pull": {
// "pfms": { n: "apples" },
// },
"$addToSet": {
"pfms": {
"$each": [
{
"n": "apples",
"mState": 1111234
}
]
}
}
}
)
Unfortunately, this adds another array element;
db.so.find().toArray();
[
{
"Name" : "fruitBowl",
"_id" : ObjectId("53ecfef5baca2b1079b0f97c"),
"pfms" : [
{
"n" : "apples"
},
{
"n" : "apples",
"mState" : 1111234
}
]
}
]
I need to effectively upsert the apples document matching on n as the unique identifier and just set mState whether or not an entry already exists. It's a shame I can't do a $pull and $addToSet in the same document (I tried).
What I really need here is dictionary semantics, but that's not an option right now, nor is breaking out the document - can anyone come up with another way?
FWIW - the existing format is a result of language/driver serialization, I didn't choose it exactly.
further
I've gotten a little further in the case where I know the array element already exists I can do this;
db.so.update({
"Name": "fruitBowl",
"pfms.n": "apples",
},{
$set: {
"pfms.$.mState": 1111234,
},
}
)
But of course that only works;
for a single array element
as long as I know it exists
The first limitation isn't a disaster, but if I can't effectively upsert or combine $addToSet with the previous $set (which of course I can't) then it the only workarounds I can think of for now mean two DB round-trips.
The $addToSet operator of course requires that the "whole" document being "added to the set" is in fact unique, so you cannot change "part" of the document or otherwise consider it to be a "partial match".
You stumbled on to your best approach using $pull to remove any element with the "key" field that would result in "duplicates", but of course you cannot modify the same path in different update operators like that.
So the closest thing you will get is issuing separate operations but also doing that with the "Bulk Operations API" which is introduced with MongoDB 2.6. This allows both to be sent to the server at the same time for the closest thing to a "contiguous" operations list you will get:
var bulk = db.so.initializeOrderedBulkOp();
bulk.find({ "Name": "fruitBowl", "pfms.n": "apples": }).updateOne({
"$pull": { "pfms": { "n": "apples" } }
});
bulk.find({ "Name": "fruitBowl" }).updateOne({
"$push": { "pfms": { "n": "apples", "state": 1111234 } }
})
bulk.execute();
That pretty much is your best approach if it is not possible or practical to move the elements to another collection and rely on "upserts" and $set in order to have the same functionality but on a collection rather than array.
I have faced the exact same scenario. I was inserting and removing likes from a post.
What I did is, using mongoose findOneAndUpdate function (which is similar to update or findAndModify function in mongodb).
The key concept is
Insert when the field is not present
Delete when the field is present
The insert is
findOneAndUpdate({ _id: theId, 'likes.userId': { $ne: theUserId }},
{ $push: { likes: { userId: theUserId, createdAt: new Date() }}},
{ 'new': true }, function(err, post) { // do the needful });
The delete is
findOneAndUpdate({ _id: theId, 'likes.userId': theUserId},
{ $pull: { likes: { userId: theUserId }}},
{ 'new': true }, function(err, post) { // do the needful });
This makes the whole operation atomic and there are no duplicates with respect to the userId field.
I hope this helpes. If you have any query, feel free to ask.
As far as I know MongoDB now (from v 4.2) allows to use aggregation pipelines for updates.
More or less elegant way to make it work (according to the question) looks like the following:
db.runCommand({
update: "your-collection-name",
updates: [
{
q: {},
u: {
$set: {
"pfms.$[elem]": {
"n":"apples",
"mState": NumberInt(1111234)
}
}
},
arrayFilters: [
{
"elem.n": {
$eq: "apples"
}
}
],
multi: true
}
]
})
In my scenario, The data need to be init when not existed, and update the field If existed, and the data will not be deleted. If the datas have these states, you might want to try the following method.
// Mongoose, but mostly same as mongodb
// Update the tag to user, If there existed one.
const user = await UserModel.findOneAndUpdate(
{
user: userId,
'tags.name': tag_name,
},
{
$set: {
'tags.$.description': tag_description,
},
}
)
.lean()
.exec();
// Add a default tag to user
if (user == null) {
await UserModel.findOneAndUpdate(
{
user: userId,
},
{
$push: {
tags: new Tag({
name: tag_name,
description: tag_description,
}),
},
}
);
}
This is the most clean and fast method in the scenario.
As a business analyst , I had the same problem and hopefully I have a solution to this after hours of investigation.
// The customer document:
{
"id" : "1212",
"customerCodes" : [
{
"code" : "I"
},
{
"code" : "YK"
}
]
}
// The problem : I want to insert dateField "01.01.2016" to customer documents where customerCodes subdocument has a document with code "YK" but does not have dateField. The final document must be as follows :
{
"id" : "1212",
"customerCodes" : [
{
"code" : "I"
},
{
"code" : "YK" ,
"dateField" : "01.01.2016"
}
]
}
// The solution : the solution code is in three steps :
// PART 1 - Find the customers with customerCodes "YK" but without dateField
// PART 2 - Find the index of the subdocument with "YK" in customerCodes list.
// PART 3 - Insert the value into the document
// Here is the code
// PART 1
var myCursor = db.customers.find({ customerCodes:{$elemMatch:{code:"YK", dateField:{ $exists:false} }}});
// PART 2
myCursor.forEach(function(customer){
if(customer.customerCodes != null )
{
var size = customer.customerCodes.length;
if( size > 0 )
{
var iFoundTheIndexOfSubDocument= -1;
var index = 0;
customer.customerCodes.forEach( function(clazz)
{
if( clazz.code == "YK" && clazz.changeDate == null )
{
iFoundTheIndexOfSubDocument = index;
}
index++;
})
// PART 3
// What happens here is : If i found the indice of the
// "YK" subdocument, I create "updates" document which
// corresponds to the new data to be inserted`
//
if( iFoundTheIndexOfSubDocument != -1 )
{
var toSet = "customerCodes."+ iFoundTheIndexOfSubDocument +".dateField";
var updates = {};
updates[toSet] = "01.01.2016";
db.customers.update({ "id" : customer.id } , { $set: updates });
// This statement is actually interpreted like this :
// db.customers.update({ "id" : "1212" } ,{ $set: customerCodes.0.dateField : "01.01.2016" });
}
}
}
});
Have a nice day !
How can I remove all fields that are null from all documents of a given collection?
I have a collection of documents such as:
{
'property1': 'value1',
'property2': 'value2',
...
}
but each document may have a null entry instead of a value entry.
I would like to save disk space by removing all null entries. The existence of the null entries does not contain any information in my case because I know the format of the JSON document a priori.
Starting Mongo 4.2, db.collection.update() can accept an aggregation pipeline, finally allowing the removal of a field based on its value:
// { _id: ObjectId("5d0e8...d2"), property1: "value1", property2: "value2" }
// { _id: ObjectId("5d0e8...d3"), property1: "value1", property2: null, property3: "value3" }
db.collection.update(
{},
[{ $replaceWith: {
$arrayToObject: {
$filter: {
input: { $objectToArray: "$$ROOT" },
as: "item",
cond: { $ne: ["$$item.v", null] }
}
}
}}],
{ multi: true }
)
// { _id: ObjectId("5d0e8...d2"), property1: "value1", property2: "value2" }
// { _id: ObjectId("5d0e8...d3"), property1: "value1", property3: "value3" }
In details:
The first part {} is the match query, filtering which documents to update (in our case all documents).
The second part [{ $replaceWith: { ... }] is the update aggregation pipeline (note the squared brackets signifying the use of an aggregation pipeline):
With $objectToArray, we first transform the document to an array of key/values such as [{ k: "property1", v: "value1" }, { k: "property2", v: null }, ...].
With $filter, we filter this array of key/values by removing items for which v is null.
We then transform back the filtered array of key/values to an object using $arrayToObject.
Finally, we replace the whole document by the modified one with $replaceWith.
Don't forget { multi: true }, otherwise only the first matching document will be updated.
// run in mongo shell
var coll = db.getCollection("collectionName");
var cursor = coll.find();
while (cursor.hasNext()) {
var doc = cursor.next();
var keys = {};
var hasNull = false;
for ( var x in doc) {
if (x != "_id" && doc[x] == null) {
keys[x] = 1;
hasNull = true;
}
}
if (hasNull) {
coll.update({_id: doc._id}, {$unset:keys});
}
}
This is an important question since mongodb cannot index null values (i.e. do not query for nulls or you will be waiting for a long time), so it is best to entirely avoid nulls and set default values using setOnInsert.
Here is a recursive solution to removing nulls:
/**
* RETRIEVES A LIST OF ALL THE KEYS IN A DOCUMENT, WHERE THE VALUE IS 'NULL' OR 'UNDEFINED'
*
* #param doc
* #param keyName
* #param nullKeys
*/
function getNullKeysRecursively(doc, keyName, nullKeys)
{
for (var item_property in doc)
{
// SKIP BASE-CLASS STUFF
if (!doc.hasOwnProperty(item_property))
continue;
// SKIP ID FIELD
if (item_property === "_id")
continue;
// FULL KEY NAME (FOR SUB-DOCUMENTS)
var fullKeyName;
if (keyName)
fullKeyName = keyName + "." + item_property;
else
fullKeyName = item_property;
// DEBUGGING
// print("fullKeyName: " + fullKeyName);
// NULL FIELDS - MODIFY THIS BLOCK TO ADD CONSTRAINTS
if (doc[item_property] === null || doc[item_property] === undefined)
nullKeys[fullKeyName] = 1;
// RECURSE OBJECTS / ARRAYS
else if (doc[item_property] instanceof Object || doc[item_property] instanceof Array)
getNullKeysRecursively(doc[item_property], fullKeyName, nullKeys);
}
}
/**
* REMOVES ALL PROPERTIES WITH A VALUE OF 'NULL' OR 'UNDEFINED'.
* TUNE THE 'LIMIT' VARIABLE TO YOUR MEMORY AVAILABILITY.
* ONLY CLEANS DOCUMENTS THAT REQUIRE CLEANING, FOR EFFICIENCY.
* USES bulkWrite FOR EFFICIENCY.
*
* #param collectionName
*/
function removeNulls(collectionName)
{
var coll = db.getCollection(collectionName);
var lastId = ObjectId("000000000000000000000000");
var LIMIT = 10000;
while (true)
{
// GET THE NEXT PAGE OF DOCUMENTS
var page = coll.find({ _id: { $gt: lastId } }).limit(LIMIT);
if (! page.hasNext())
break;
// BUILD BULK OPERATION
var arrBulkOps = [];
page.forEach(function(item_doc)
{
lastId = item_doc._id;
var nullKeys = {};
getNullKeysRecursively(item_doc, null, nullKeys);
// ONLY UPDATE MODIFIED DOCUMENTS
if (Object.keys(nullKeys).length > 0)
// UNSET INDIVIDUAL FIELDS, RATHER THAN REWRITE THE ENTIRE DOC
arrBulkOps.push(
{ updateOne: {
"filter": { _id: item_doc._id },
"update": { $unset: nullKeys }
} }
);
});
coll.bulkWrite(arrBulkOps, { ordered: false } );
}
}
// GO GO GO
removeNulls('my_collection');
document before:
{
"_id": ObjectId("5a53ed8f6f7c4d95579cb87c"),
"first_name": null,
"last_name": "smith",
"features": {
"first": {
"a": 1,
"b": 2,
"c": null
},
"second": null,
"third" : {},
"fourth" : []
},
"other": [
null,
123,
{
"a": 1,
"b": "hey",
"c": null
}
]
}
document after:
{
"_id" : ObjectId("5a53ed8f6f7c4d95579cb87c"),
"last_name" : "smith",
"features" : {
"first" : {
"a" : 1,
"b" : 2
}
},
"other" : [
null,
123,
{
"a" : 1,
"b" : "hey"
}
]
}
As you can see, it removes null, undefined, empty objects and empty arrays. If you need it to be more/less aggressive, it is a matter of modifying the block "NULL FIELDS - MODIFY THIS BLOCK TO ADD CONSTRAINTS".
edits welcome, especially #stennie
You can use the mongo updateMany functionality, but you must do this by specifying the parameter you are going to update, such as the year parameter:
db.collection.updateMany({year: null}, { $unset : { year : 1 }})
Like this question mentioned (mongodb query without field name):
Unfortunately, MongoDB does not support any method of querying all fields with a particular value.
So, you can either iterate the document (like Wizard's example) or do it in non-mongodb way.
If this is a JSON file, remove all the lines with null in sed might works:
sed '/null/d' ./mydata.json
Update for 2022:
If you delete keys with values Null, [], "", {} from the DB, that won't reduce it's size on disk.
You need to do that before you upload data into the collection.
Tested it myself. I had 6.000.000 documents in collection. Ran script of Xavier Guihot. Before script it was 7.8GB, after the script it became 7.9GB.
I confirm, that script do the job and remove keys, it's just that it doesn't reduce the size of the DB space allocation.
Then I deleted completely the collection, and imported .json dumps, that had already been formatted (removed all keys with values Null, [], "", {}). After collection size was 6.1GB That's minus 22% of the original size.
Here is python script I used to remove all empty keys from json dumps:
import fileinput
import json
for line in fileinput.input(inplace=1):
j = {k:v for k, v in json.loads(line).items() if v}
print(line.replace(line, json.dumps(j)))
Just run the script with file name as argument, for example: python3 main.py dump-00001
ps: take into account, that you need to wait ~200 seconds after changes to DB, because WiredTiger keep history backup of data for consistency after you make changes. That's mean, that only after 200 sec you will see real storage allocation of DB. 200 sec is default value for that action.
In the following example, assume the document is in the db.people collection.
How to remove the 3rd element of the interests array by it's index?
{
"_id" : ObjectId("4d1cb5de451600000000497a"),
"name" : "dannie",
"interests" : [
"guitar",
"programming",
"gadgets",
"reading"
]
}
This is my current solution:
var interests = db.people.findOne({"name":"dannie"}).interests;
interests.splice(2,1)
db.people.update({"name":"dannie"}, {"$set" : {"interests" : interests}});
Is there a more direct way?
There is no straight way of pulling/removing by array index. In fact, this is an open issue http://jira.mongodb.org/browse/SERVER-1014 , you may vote for it.
The workaround is using $unset and then $pull:
db.lists.update({}, {$unset : {"interests.3" : 1 }})
db.lists.update({}, {$pull : {"interests" : null}})
Update: as mentioned in some of the comments this approach is not atomic and can cause some race conditions if other clients read and/or write between the two operations. If we need the operation to be atomic, we could:
Read the document from the database
Update the document and remove the item in the array
Replace the document in the database. To ensure the document has not changed since we read it, we can use the update if current pattern described in the mongo docs
You can use $pull modifier of update operation for removing a particular element in an array. In case you provided a query will look like this:
db.people.update({"name":"dannie"}, {'$pull': {"interests": "guitar"}})
Also, you may consider using $pullAll for removing all occurrences. More about this on the official documentation page - http://www.mongodb.org/display/DOCS/Updating#Updating-%24pull
This doesn't use index as a criteria for removing an element, but still might help in cases similar to yours. IMO, using indexes for addressing elements inside an array is not very reliable since mongodb isn't consistent on an elements order as fas as I know.
in Mongodb 4.2 you can do this:
db.example.update({}, [
{$set: {field: {
$concatArrays: [
{$slice: ["$field", P]},
{$slice: ["$field", {$add: [1, P]}, {$size: "$field"}]}
]
}}}
]);
P is the index of element you want to remove from array.
If you want to remove from P till end:
db.example.update({}, [
{ $set: { field: { $slice: ["$field", 1] } } },
]);
Starting in Mongo 4.4, the $function aggregation operator allows applying a custom javascript function to implement behaviour not supported by the MongoDB Query Language.
For instance, in order to update an array by removing an element at a given index:
// { "name": "dannie", "interests": ["guitar", "programming", "gadgets", "reading"] }
db.collection.update(
{ "name": "dannie" },
[{ $set:
{ "interests":
{ $function: {
body: function(interests) { interests.splice(2, 1); return interests; },
args: ["$interests"],
lang: "js"
}}
}
}]
)
// { "name": "dannie", "interests": ["guitar", "programming", "reading"] }
$function takes 3 parameters:
body, which is the function to apply, whose parameter is the array to modify. The function here simply consists in using splice to remove 1 element at index 2.
args, which contains the fields from the record that the body function takes as parameter. In our case "$interests".
lang, which is the language in which the body function is written. Only js is currently available.
Rather than using the unset (as in the accepted answer), I solve this by setting the field to a unique value (i.e. not NULL) and then immediately pulling that value. A little safer from an asynch perspective. Here is the code:
var update = {};
var key = "ToBePulled_"+ new Date().toString();
update['feedback.'+index] = key;
Venues.update(venueId, {$set: update});
return Venues.update(venueId, {$pull: {feedback: key}});
Hopefully mongo will address this, perhaps by extending the $position modifier to support $pull as well as $push.
I would recommend using a GUID (I tend to use ObjectID) field, or an auto-incrementing field for each sub-document in the array.
With this GUID it is easy to issue a $pull and be sure that the correct one will be pulled. Same goes for other array operations.
For people who are searching an answer using mongoose with nodejs. This is how I do it.
exports.deletePregunta = function (req, res) {
let codTest = req.params.tCodigo;
let indexPregunta = req.body.pregunta; // the index that come from frontend
let inPregunta = `tPreguntas.0.pregunta.${indexPregunta}`; // my field in my db
let inOpciones = `tPreguntas.0.opciones.${indexPregunta}`; // my other field in my db
let inTipo = `tPreguntas.0.tipo.${indexPregunta}`; // my other field in my db
Test.findOneAndUpdate({ tCodigo: codTest },
{
'$unset': {
[inPregunta]: 1, // put the field with []
[inOpciones]: 1,
[inTipo]: 1
}
}).then(()=>{
Test.findOneAndUpdate({ tCodigo: codTest }, {
'$pull': {
'tPreguntas.0.pregunta': null,
'tPreguntas.0.opciones': null,
'tPreguntas.0.tipo': null
}
}).then(testModificado => {
if (!testModificado) {
res.status(404).send({ accion: 'deletePregunta', message: 'No se ha podido borrar esa pregunta ' });
} else {
res.status(200).send({ accion: 'deletePregunta', message: 'Pregunta borrada correctamente' });
}
})}).catch(err => { res.status(500).send({ accion: 'deletePregunta', message: 'error en la base de datos ' + err }); });
}
I can rewrite this answer if it dont understand very well, but I think is okay.
Hope this help you, I lost a lot of time facing this issue.
It is little bit late but some may find it useful who are using robo3t-
db.getCollection('people').update(
{"name":"dannie"},
{ $pull:
{
interests: "guitar" // you can change value to
}
},
{ multi: true }
);
If you have values something like -
property: [
{
"key" : "key1",
"value" : "value 1"
},
{
"key" : "key2",
"value" : "value 2"
},
{
"key" : "key3",
"value" : "value 3"
}
]
and you want to delete a record where the key is key3 then you can use something -
db.getCollection('people').update(
{"name":"dannie"},
{ $pull:
{
property: { key: "key3"} // you can change value to
}
},
{ multi: true }
);
The same goes for the nested property.
this can be done using $pop operator,
db.getCollection('collection_name').updateOne( {}, {$pop: {"path_to_array_object":1}})