Good day,
I have a nested structure in this format.
Data: [1x1 struct]
a: [1x1 struct]
a1: [10x1 double]
a2: [10x1 double]
a3: [10x1 double]
b: [1x1 struct]
b1: [10x1 double]
b2: [10x1 double]
c: [1x1 struct]
c1: [10x1 double]
c2: [10x1 double]
c3: [10x1 double]
c4: [10x1 double]
Each of sub-fields of a, b & c are duration percentage of an event in buckets. The number of elements in each bucket are number of data-sets. I'd like sum the bucket values of each data set and discard the entire data-set if they don't add up to 100%. How may I access each element of the buckets for a, b & c fields of Data using for loop in a simply format.
EDIT: I figured out how to call the sub-fields & it's elements, sum the percentages & now, if the data-sets not adding up to 100 need to fully removed from each sub-field.
field = fieldnames(Data);
for group = 1:length(field)
for subfield = fieldnames(Data.(field{group}))
fieldSize = structfun(#(field) length(field),Data.(field{group}));
nb_datasets = fieldSize(1,1);
for jj = 1:nb_datasets
for ii = 1:length(subfield)
a_dataset_pcts(jj,ii) = Data.(field{group}).(subfield{ii})(jj,1);
end
a_pct_total(jj,:) = sum(a_dataset_pcts(jj,:));
end
end
end
Matlab like matrices Bensa.... You should drop your approach now.
Fixed size datasets
If all a, b, c arrays are 10x1 sized, you should switch immediately to a cell of arrays, being the index the durations, and the arrays columns the datasets for each duration:
a: [1x1 cell]
a{1}: [10xna double]
a{2}: [10xnb double]
a{3}: [10xnc double]
All statistics go easy. You have two for loops, one for the durations, other for the dataset. Matlab vectorizes the functions inside each dataset (most of the time). In here, i am assuming max(.) is your aggregation array function for obtaining statistics:
n=length(a);
for i=1:n
ni=size(a{i},2);
for j=1:ni
max(a{i})
mean(a{i}')'
if j==j0 && i==i0
a{i}(:,j)=[]; % Cleanup j0th event in i0th dataset
end
end
end
Do you need to compare a.a1 & b.b1 & c.c1? If that is true, then you forcedly should create the auxiliar array x, and then get your stats:
for i=1:n
x(:,i)=a{i};
end
max(x')'
Variable size datasets
If the a, b, c arrays are different each time, then you upgrade the last data and switch to a cell of cells:
a{1}: [1xna cell]
a{1,1}: [la(1)x1 double]
...
a{1,na}: [la(na)x1 double]
a{2}: [1xnb cell]
...
a{3}: [1xnc cell]
...
In here the max(.')' approach is useless, because every dataset could be of different length. If that is the case, you still can reference the data as usually through columns:
n=length(a);
for i=1:n
ni(i)=size(a{i},2);
for j=1:ni(i)
li=length(a{i,j}) % Length of each dataset
max(a{i,j})
% mean(a{i}')' % This do not work anymore
if j==j0 && i==i0
a{i,j}=[]; % Cleanup j0th event in i0th dataset
end
end
end
Do this make sense?. Feel free to comment below...
How should I copy all my cell content in a column to another column in the same cell. e.g.
a{1,1}=[1 2];
a{2,1}=[3 4 5];
a =
[1x2 double] []
[1x3 double] []
then,I'd like to copy all cell contents of this column to another column say column 2 without copying all rows separately using for. I used
a{:,3}= a{:,2}
The right hand side of this assignment has too few values to satisfy the left hand side.
it seems that a{:,2} is not working as it returns different values in different run. So here : doesn't work?
As an output I'd like to have the same elements as copying cells to my new cell homes. i.e.
a{1,2}=[1 2];
a{2,2}=[3 4 5];
So, a will be
a =
[1x2 double] [1x2 double]
[1x3 double] [1x3 double]
You need to use brackets instead if braces in this case.
Try it like this:
a = {[0 1];[2 3];[4 5];};
a(:,2) = a(:,1);
I want to create a structure where in first level will have the variable names for eg:- a
>> a=struct()
a =
struct with no fields.
>> for i=1:30
a.i=rand(3);
end
>> a
a =
i: [3x3 double]
a.i
ans =
0.3477 0.2621 0.2428
0.1500 0.0445 0.4424
0.5861 0.7549 0.6878
But what I want to create is a structure where 'a' is a struct contains 30 fields
where a.1 ; a.2 ;a.3; each give a random matrix which was previously assigned.
I would also like to do this same thing but for 'i' Strings and not just numbers.
For example a video is read and some particular data from every frame is stored in a struct with the variable name of the frame number.
Your code just defines a field called i, 30 times.
You can build a different field name in each iteration using variable field names. Field names must begin with a letter, so you need to use something like f1, f2 etc. as names. To do it, you build the string representing the field name (in this case that string is ['f' num2str(i)]) and put parentheses around it:
for i = 1:30
a.(['f' num2str(i)]) = rand(3);
end
This gives
a =
f1: [3x3 double]
f2: [3x3 double]
f3: [3x3 double]
f4: [3x3 double]
...
I have a double value, A, which is
[1,4,7,6]
I also have B, which is an array that contains many more values. I have a new variable, C, which is essentially a double value of all these numbers (all of them in one cell, vs. five).
[1,4,7,6]
[2,6,9,12]
[3,1,17,13]
[5,7,13,19]
[1,5,9,15]
How do I remove the elements (not the actual values) from C? I want to end up with this.
[2,6,9,12,3,1,17,13,5,7,13,19,1,5,9,15]
How do I get this? I've used these commands:
C(A) = [];
and
C = C(setdiff(1:length(C),A));
The problem is that when I run that command, I get this instead of what I want.
[4,7,2,12,3,1,17,13,5,7,13,19,1,5,9,15]
Clearly that isn't the same as what I have. It's throwing off the rest of my results and I need to fix this specific issue.
Thanks in advance :)
EDIT:
So I figured out that it's spewing the CORRECT numbers out, just in the wrong order. I have to sort it in order for it to work correctly. This is a problem because it causes the next command to be non-functional because the ismember command has issues with the removal (I don't know why, I'm still working on it).
Double array case
If B is a double array, you can use setdiff with 'rows' and 'stable' options, like so -
C = reshape(setdiff(B,A,'rows','stable').',1,[])
With ismember, you can perform the same operation, like so -
C = reshape(B(~ismember(B,A,'rows'),:).',1,[])
You can also use a bsxfun approach as suggested by #Amro -
C = reshape(B(~all(bsxfun(#eq, B, A),2),:).',1,[])
Cell array case
If B is a cell array with number of elements in each cell equal to the number of elements in A, then you can firstly convert it to a double array - B = vertcat(B{:}) and then use either of the above mentioned tools.
Or you can use a cellfun based approach that avoids conversion to a double array, like so -
excl_rows = B(~cellfun(#(x1,x2) isequal(x1,x2), B, repmat({A},size(B,1),1)),:)
C = horzcat(excl_rows{:})
Or another cellfun based approach that avoids repmat -
exclB = B(~cellfun(#(x1) isequal(x1,A), B),:)
C = horzcat(exclB{:})
Example with explanation -
%// Inputs
A = [1,4,7,6]
B = {[1,4,7,6]
[2,6,9,12]
[3,1,17,13]
[5,7,13,19]
[1,5,9,15]}
%// Compare each cell of B with A for equality.
%// The output must be a binary array where one would be for cells that have
%// elements same as A and zero otherwise.
ind = cellfun(#(x1) isequal(x1,A), B)
%// Thus, ~ind would be a binary array where one would reperesent unequal
%// cells that are to be selected in B for the final output.
exclB = B(~ind)
%// exclB is still a cell array with the cells that are different from A.
%// So, concatenate the elements from exclB into a vector as requested.
C = horzcat(exclB{:})
Output -
A =
1 4 7 6
B =
[1x4 double]
[1x4 double]
[1x4 double]
[1x4 double]
[1x4 double]
ind =
1
0
0
0
0
exclB =
[1x4 double]
[1x4 double]
[1x4 double]
[1x4 double]
C =
2 6 9 12 3 1 17 13 5 7 13 19 1 5 9 15
I have an cell including array as below format
a{x,y,z}(i,j)
a is 3 dimensional cell
and
each cell have i*j array
a <79x95x68 cell>
val(:,:,1) =
Columns 1 through 2
[6x6 double] [6x6 double]
[6x6 double] [6x6 double]
[6x6 double] [6x6 double]
i want to rearrange that as below format
a{i,j}(x,y,z)
how to? any good idea? i have to do iteration?
matlab say, a{:,:}(x,y,z) is bad cell referencing.........
here's a suboptimal way to go, it isn't memory efficient, but it is pretty straightforward:
say that x=79,y=95,z=68 are the dimensions of your original cell array, and that each of them gives the same dimensionality ixj matrix (6 by 6). So first you can make a matrix out of the cell array:
b=horzcat(a{:});
then we can reshape it to a 5-d array (this is just for pedagogical purposes) so you already have it ordered as (i,j,x,y,z)...
c=reshape(b,6,6,x,y,z);
then you can either work with c(i,j,x,y,z), or assign c to a cellarray:
d=cell(6,6);
for i=1:6
for j=1:6
d{i,j}=squeeze(c(i,j,:,:,:));
end
end