Convert string month to numeric - date

I have a variable period that contains a month as an abbreviated string (i.e. "JAN", "FEB", "MAR", etc). How do I convert period to a numeral (i.e. 1, 2, 3, etc)?
My solution is:
gen fake_date_s = "2000"+period+"1"
gen fake_date = date(fake_date_s, "YMD")
gen month = month(fake_date)

I don't think it's ugly:
clear
input ///
str3 period
JAN
FEB
DEC
end
list
gen monthnum = month(date("2000" + period + "1", "YMD"))
list
This also works:
gen monthnum = month(date(period, "M"))
as it sets the day and the year in the daily date to 01 and 1960, by default.
I'm sure you can find an alternative that doesn't use date functions, but why not use them?

Another approach is:
local i=1
foreach m in `c(Mons)' {
replace month = "`i'" if month == upper("`m'")
local ++i
}
destring month, replace

Related

Assessing which person is the one with the next birthday

In Stata I am trying to assess which of the given birthdays is the next one compared with a given date. My data looks like this:
All dates are in daily format (%dD_m_Y), e.g. 18mar1926
Variable date which is the reference date with which all other dates should be compared
Variables birth1, birth2, birth3, birth4, birth5, birth6 contain the birthday of all possible household members.
For example: A household with two adults A and B. The birthday of A is 20th Nov 1977 and the birthday of person B is 30th March 1978. The reference date is 29.11.2020. I want to know who is the person who has the next birthday, in the example above it is person B, because person A has had its birthday one week before the reference date, so the next birthday in this household will be celebrated on the 30 March 2021.
Example data:
date
birth1
birth2
birth3
birth4
birth5
birth6
02feb2021
15jan1974
27nov1985
30nov2020
31aug1945
27jun1999
07apr1997
19nov2020
27sep1993
30dec1996
29jan2021
29mar1973
05dec2020
21jan1976
02oct1976
21jan1976
25may1995
15feb1997
25nov2020
25nov1943
29nov1946
02feb2021
28apr1979
EDITED to account for Feb 29
*The edit will treat people who have a February 29 birthday as if it were March 1 in cases when the year of date is not a leap year. If that doesn't make sense for your particular use case, it should be easy to alter the code below as you see fit.
Since you want the next birthday in the year rather than the closest birthday, you can use the year of date and the month and day from birth{i} to create a date for each person's next birthday. Then you can sinmply take the earliest value from each household. I reshape long, and generate a person and household id in order to do this.
Make example data
clear
set obs 6
set seed 1996
generate date = floor((mdy(12,31,2020)-mdy(12,1,2015)+1)*runiform() + mdy(12,1,2015))
format date %td
forvalue i = 1/6 {
gen birth`i' = floor((mdy(12,31,1996)-mdy(12,1,1980)+1)*runiform() + mdy(12,1,1980)) if _n < `i' == 0
format birth`i' %td
}
replace birth6 = birth4 in 6 // want a tie
replace birth2 = date("29feb1996","DMY") in 3 // Feb 29
Find Next Birthday
gen household_id = _n
reshape long birth, i(date household_id) j(person)
drop if mi(birth)
gen person_next_birthday = mdy( month(birth), day(birth), year(date))
* TREAT FEB 29 as if they have a march 1 birthday in non-leap years
replace person_next_birthday = mdy(3,1,year(date)) if month(birth) == 2 ///
& day(birth) == 29 & mod(year(date),4)!=0
replace person_next_birthday = mdy( month(birth), day(birth), year(date) + 1) if person_next_birthday < date
replace person_next_birthday = mdy(3,1,year(date)+1) if month(birth) == 2 ///
& day(birth) == 29 & mod(year(date) + 1,4)!=0 & person_next_birthday < date
format person_next_birthday %td
bysort household_id (person_next_birthday): gen next_bday = person_next_birthday[1]
format next_bday %td
drop person_next_birthday
reshape wide birth, i(date household_id next_bday) j(person)
gen next_bday_persons = ""
* Make a string to present household persons who have next bday
foreach v of varlist birth* {
local person = subinstr("`v'","birth","",.)
local condition = "month(`v') == month(next_bday) & day(`v') == day(next_bday)"
local condition_feb29 = "month(next_bday) == 3 & day(next_bday) == 1 & month(`v') == 2 & day(`v') == 29"
replace next_bday_persons = next_bday_persons + "|`person'" if `condition' | `condition_feb29'
}
replace next_bday_persons = regexr(next_bday_persons,"^\|","")
order next_bday_persons, after(next_bday)
The last loop is unnecessary, but illustrates that this is robust to ties.

how can i get the day of the week for a particular given date in Matlab

As today is Wednesday with date June 8, 2016. how can i write a code to get the day of given dates:
like what day is Nov 29
I'm trying to create a struct with
date
day
month
with month and date as input
Use the builtin weekday() function:
>> [num, name] = weekday('08-Jun-2016')
num =
4
name =
Wed
>> [num, name] = weekday('29-Nov-2016')
num =
3
name =
Tue
In addition to the weekday function, you can use the DDD or DDDD formats in the datestr function, like this:
datestr('08-Jun-2016','DDD') %Returns the string 'Wed'
datestr('08-Jun-2016','DDDD') %Returns the string 'Wednesday'
Or, to use a more practical format
datestr('08-Jun-2016','DDDD, mmmm DD, yyyy')
% Returns the string: 'Wednesday, June 08, 2016'

How to change format of date in Meteor/MongoDB [duplicate]

How do I format a Date object to a string?
If you need slightly less control over formatting than the currently accepted answer, Date#toLocaleDateString can be used to create standard locale-specific renderings. The locale and options arguments let applications specify the language whose formatting conventions should be used, and allow some customization of the rendering.
Options key examples:
day:
The representation of the day.
Possible values are "numeric", "2-digit".
weekday:
The representation of the weekday.
Possible values are "narrow", "short", "long".
year:
The representation of the year.
Possible values are "numeric", "2-digit".
month:
The representation of the month.
Possible values are "numeric", "2-digit", "narrow", "short", "long".
hour:
The representation of the hour.
Possible values are "numeric", "2-digit".
minute:
The representation of the minute.
Possible values are "numeric", "2-digit".
second:
The representation of the second.
Possible values are "numeric", 2-digit".
All these keys are optional. You can change the number of options values based on your requirements, and this will also reflect the presence of each date time term.
Note: If you would only like to configure the content options, but still use the current locale, passing null for the first parameter will cause an error. Use undefined instead.
For different languages:
"en-US": For American English
"en-GB": For British English
"hi-IN": For Hindi
"ja-JP": For Japanese
You can use more language options.
For example
var options = { weekday: 'long', year: 'numeric', month: 'long', day: 'numeric' };
var today = new Date();
console.log(today.toLocaleDateString("en-US")); // 9/17/2016
console.log(today.toLocaleDateString("en-US", options)); // Saturday, September 17, 2016
console.log(today.toLocaleDateString("hi-IN", options)); // शनिवार, 17 सितंबर 2016
You can also use the toLocaleString() method for the same purpose. The only difference is this function provides the time when you don't pass any options.
// Example
9/17/2016, 1:21:34 PM
References:
toLocaleString()
toLocaleDateString()
For custom-delimited date formats, you have to pull out the date (or time)
components from a DateTimeFormat object (which is part of the
ECMAScript Internationalization API), and then manually create a string
with the delimiters you want.
To do this, you can use DateTimeFormat#formatToParts. You could
destructure the array, but that is not ideal, as the array output depends on the
locale:
{ // example 1
let f = new Intl.DateTimeFormat('en');
let a = f.formatToParts();
console.log(a);
}
{ // example 2
let f = new Intl.DateTimeFormat('hi');
let a = f.formatToParts();
console.log(a);
}
Better would be to map a format array to resultant strings:
function join(t, a, s) {
function format(m) {
let f = new Intl.DateTimeFormat('en', m);
return f.format(t);
}
return a.map(format).join(s);
}
let a = [{day: 'numeric'}, {month: 'short'}, {year: 'numeric'}];
let s = join(new Date, a, '-');
console.log(s);
You can also pull out the parts of a DateTimeFormat one-by-one using
DateTimeFormat#format, but note that when using this method, as of March
2020, there is a bug in the ECMAScript implementation when it comes to
leading zeros on minutes and seconds (this bug is circumvented by the approach
above).
let d = new Date(2010, 7, 5);
let ye = new Intl.DateTimeFormat('en', { year: 'numeric' }).format(d);
let mo = new Intl.DateTimeFormat('en', { month: 'short' }).format(d);
let da = new Intl.DateTimeFormat('en', { day: '2-digit' }).format(d);
console.log(`${da}-${mo}-${ye}`);
When working with dates and times, it is usually worth using a library (eg. luxon, date-fns, moment.js is not recommended for new projects) because of the many hidden complexities of the field.
Note that the ECMAScript Internationalization API, used in the solutions above
is not supported in IE10 (0.03% global browser market share in Feb
2020).
If you need to quickly format your date using plain JavaScript, use getDate, getMonth + 1, getFullYear, getHours and getMinutes:
var d = new Date();
var datestring = d.getDate() + "-" + (d.getMonth()+1) + "-" + d.getFullYear() + " " +
d.getHours() + ":" + d.getMinutes();
// 16-5-2015 9:50
Or, if you need it to be padded with zeros:
var datestring = ("0" + d.getDate()).slice(-2) + "-" + ("0"+(d.getMonth()+1)).slice(-2) + "-" +
d.getFullYear() + " " + ("0" + d.getHours()).slice(-2) + ":" + ("0" + d.getMinutes()).slice(-2);
// 16-05-2015 09:50
Use the date.format library:
var dateFormat = require('dateformat');
var now = new Date();
dateFormat(now, "dddd, mmmm dS, yyyy, h:MM:ss TT");
returns:
Saturday, June 9th, 2007, 5:46:21 PM
dateformat on npm
http://jsfiddle.net/phZr7/1/
Well, what I wanted was to convert today's date to a MySQL friendly date string like 2012-06-23, and to use that string as a parameter in one of my queries. The simple solution I've found is this:
var today = new Date().toISOString().slice(0, 10);
Keep in mind that the above solution does not take into account your timezone offset.
You might consider using this function instead:
function toJSONLocal (date) {
var local = new Date(date);
local.setMinutes(date.getMinutes() - date.getTimezoneOffset());
return local.toJSON().slice(0, 10);
}
This will give you the correct date in case you are executing this code around the start/end of the day.
var date = new Date();
function toLocal(date) {
var local = new Date(date);
local.setMinutes(date.getMinutes() - date.getTimezoneOffset());
return local.toJSON();
}
function toJSONLocal(date) {
var local = new Date(date);
local.setMinutes(date.getMinutes() - date.getTimezoneOffset());
return local.toJSON().slice(0, 10);
}
// check out your devtools console
console.log(date.toJSON());
console.log(date.toISOString());
console.log(toLocal(date));
console.log(toJSONLocal(date));
Date.toISOString
Date.toJSON
String.slice
External example
Custom formatting function:
For fixed formats, a simple function make the job. The following example generates the international format YYYY-MM-DD:
function dateToYMD(date) {
var d = date.getDate();
var m = date.getMonth() + 1; //Month from 0 to 11
var y = date.getFullYear();
return '' + y + '-' + (m<=9 ? '0' + m : m) + '-' + (d <= 9 ? '0' + d : d);
}
console.log(dateToYMD(new Date(2017,10,5))); // Nov 5
The OP format may be generated like:
function dateToYMD(date) {
var strArray=['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec'];
var d = date.getDate();
var m = strArray[date.getMonth()];
var y = date.getFullYear();
return '' + (d <= 9 ? '0' + d : d) + '-' + m + '-' + y;
}
console.log(dateToYMD(new Date(2017,10,5))); // Nov 5
Note: It is, however, usually not a good idea to extend the JavaScript standard libraries (e.g. by adding this function to the prototype of Date).
A more advanced function could generate configurable output based on a format parameter.
If to write a formatting function is too long, there are plenty of libraries around which does it. Some other answers already enumerate them. But increasing dependencies also has it counter-part.
Standard ECMAScript formatting functions:
Since more recent versions of ECMAScript, the Date class has some specific formatting functions:
toDateString: Implementation dependent, show only the date.
https://262.ecma-international.org/#sec-date.prototype.todatestring
new Date().toDateString(); // e.g. "Fri Nov 11 2016"
toISOString: Show ISO 8601 date and time.
https://262.ecma-international.org/#sec-date.prototype.toisostring
new Date().toISOString(); // e.g. "2016-11-21T08:00:00.000Z"
toJSON: Stringifier for JSON.
https://262.ecma-international.org/#sec-date.prototype.tojson
new Date().toJSON(); // e.g. "2016-11-21T08:00:00.000Z"
toLocaleDateString: Implementation dependent, a date in locale format.
https://262.ecma-international.org/#sec-date.prototype.tolocaledatestring
new Date().toLocaleDateString(); // e.g. "21/11/2016"
toLocaleString: Implementation dependent, a date&time in locale format.
https://262.ecma-international.org/#sec-date.prototype.tolocalestring
new Date().toLocaleString(); // e.g. "21/11/2016, 08:00:00 AM"
toLocaleTimeString: Implementation dependent, a time in locale format.
https://262.ecma-international.org/#sec-date.prototype.tolocaletimestring
new Date().toLocaleTimeString(); // e.g. "08:00:00 AM"
toString: Generic toString for Date.
https://262.ecma-international.org/#sec-date.prototype.tostring
new Date().toString(); // e.g. "Fri Nov 21 2016 08:00:00 GMT+0100 (W. Europe Standard Time)"
Note: it is possible to generate custom output out of those formatting >
new Date().toISOString().slice(0,10); //return YYYY-MM-DD
Examples snippets:
console.log("1) "+ new Date().toDateString());
console.log("2) "+ new Date().toISOString());
console.log("3) "+ new Date().toJSON());
console.log("4) "+ new Date().toLocaleDateString());
console.log("5) "+ new Date().toLocaleString());
console.log("6) "+ new Date().toLocaleTimeString());
console.log("7) "+ new Date().toString());
console.log("8) "+ new Date().toISOString().slice(0,10));
Specifying the locale for standard functions:
Some of the standard functions listed above are dependent on the locale:
toLocaleDateString()
toLocaleTimeString()
toLocalString()
This is because different cultures make uses of different formats, and express their date or time in different ways.
The function by default will return the format configured on the device it runs, but this can be specified by setting the arguments (ECMA-402).
toLocaleDateString([locales[, options]])
toLocaleTimeString([locales[, options]])
toLocaleString([locales[, options]])
//e.g. toLocaleDateString('ko-KR');
The option second parameter, allow for configuring more specific format inside the selected locale. For instance, the month can be show as full-text or abreviation.
toLocaleString('en-GB', { month: 'short' })
toLocaleString('en-GB', { month: 'long' })
Examples snippets:
console.log("1) "+ new Date().toLocaleString('en-US'));
console.log("2) "+ new Date().toLocaleString('ko-KR'));
console.log("3) "+ new Date().toLocaleString('de-CH'));
console.log("4) "+ new Date().toLocaleString('en-GB', { hour12: false }));
console.log("5) "+ new Date().toLocaleString('en-GB', { hour12: true }));
Some good practices regarding locales:
Most people don't like their dates to appear in a foreigner format, consequently, keep the default locale whenever possible (over setting 'en-US' everywhere).
Implementing conversion from/to UTC can be challenging (considering DST, time-zone not multiple of 1 hour, etc.). Use a well-tested library when possible.
Don't assume the locale correlate to a country: several countries have many of them (Canada, India, etc.)
Avoid detecting the locale through non-standard ways. Here you can read about the multiple pitfalls: detecting the keyboard layout, detecting the locale by the geographic location, etc..
If you are already using jQuery UI in your project you could do it this way:
var formatted = $.datepicker.formatDate("M d, yy", new Date("2014-07-08T09:02:21.377"));
// formatted will be 'Jul 8, 2014'
Some datepicker date format options to play with are available here.
Note (2022-10): toLocaleFormat has been deprecated for some time and was removed from Firefox as of version 58. See toLocaleFormat
I think you can just use the non-standard Date method toLocaleFormat(formatString)
formatString: A format string in the same format expected by the strftime() function in C.
var today = new Date();
today.toLocaleFormat('%d-%b-%Y'); // 30-Dec-2011
References:
toLocaleFormat
strftime
Plain JavaScript is the best pick for small onetimers.
On the other hand, if you need more date stuff, MomentJS is a great solution.
For example:
moment().format('YYYY-MM-DD HH:m:s'); // now() -> 2015-03-24 14:32:20
moment("20111031", "YYYYMMDD").fromNow(); // 3 years ago
moment("20120620", "YYYYMMDD").fromNow(); // 3 years ago
moment().startOf('day').fromNow(); // 11 hours ago
moment().endOf('day').fromNow(); // in 13 hours
In modern browsers (*), you can just do this:
var today = new Date().toLocaleDateString('en-GB', {
day : 'numeric',
month : 'short',
year : 'numeric'
}).split(' ').join('-');
Output if executed today (january 24ᵗʰ, 2016):
'24-Jan-2016'
(*) According to MDN, "modern browsers" means Chrome 24+, Firefox 29+, Internet Explorer 11, Edge 12+, Opera 15+ & Safari nightly build.
Requested format in one line - no libraries and no Date methods, just regex:
var d = (new Date()).toString().replace(/\S+\s(\S+)\s(\d+)\s(\d+)\s.*/,'$2-$1-$3');
// date will be formatted as "14-Oct-2015" (pass any date object in place of 'new Date()')
In my testing, this works reliably in the major browsers (Chrome, Safari, Firefox and IE.) As #RobG pointed out, the output of Date.prototype.toString() is implementation-dependent, so for international or non-browser implementations, just test the output to be sure it works right in your JavaScript engine. You can even add some code to test the string output and make sure it's matching what you expect before you do the regex replace.
Packaged Solution: Luxon or date-fns
If you want to use a one solution to fit all, I recommend using date-fns or Luxon.
Luxon is hosted on the Moment.js website and developed by a Moment.js developer because Moment.js has limitations that the developer wanted to address but couldn't.
To install:
npm install luxon or yarn add luxon (visit link for other installation methods)
Example:
luxon.DateTime.fromISO('2010-08-10').toFormat('yyyy-LLL-dd');
Yields:
10-Aug-2010
Manual Solution
Using similar formatting as Moment.js, Class DateTimeFormatter (Java), and Class SimpleDateFormat (Java), I implemented a comprehensive solution formatDate(date, patternStr) where the code is easy to read and modify. You can display date, time, AM/PM, etc. See code for more examples.
Example:
formatDate(new Date(), 'EEEE, MMMM d, yyyy HH:mm:ss:S')
(formatDate is implemented in the code snippet below)
Yields:
Friday, October 12, 2018 18:11:23:445
Try the code out by clicking "Run code snippet."
Date and Time Patterns
yy = 2-digit year; yyyy = full year
M = digit month; MM = 2-digit month; MMM = short month name; MMMM = full month name
EEEE = full weekday name; EEE = short weekday name
d = digit day; dd = 2-digit day
h = hours am/pm; hh = 2-digit hours am/pm; H = hours; HH = 2-digit hours
m = minutes; mm = 2-digit minutes; aaa = AM/PM
s = seconds; ss = 2-digit seconds
S = miliseconds
var monthNames = [
"January", "February", "March", "April", "May", "June", "July",
"August", "September", "October", "November", "December"
];
var dayOfWeekNames = [
"Sunday", "Monday", "Tuesday",
"Wednesday", "Thursday", "Friday", "Saturday"
];
function formatDate(date, patternStr){
if (!patternStr) {
patternStr = 'M/d/yyyy';
}
var day = date.getDate(),
month = date.getMonth(),
year = date.getFullYear(),
hour = date.getHours(),
minute = date.getMinutes(),
second = date.getSeconds(),
miliseconds = date.getMilliseconds(),
h = hour % 12,
hh = twoDigitPad(h),
HH = twoDigitPad(hour),
mm = twoDigitPad(minute),
ss = twoDigitPad(second),
aaa = hour < 12 ? 'AM' : 'PM',
EEEE = dayOfWeekNames[date.getDay()],
EEE = EEEE.substr(0, 3),
dd = twoDigitPad(day),
M = month + 1,
MM = twoDigitPad(M),
MMMM = monthNames[month],
MMM = MMMM.substr(0, 3),
yyyy = year + "",
yy = yyyy.substr(2, 2)
;
// checks to see if month name will be used
patternStr = patternStr
.replace('hh', hh).replace('h', h)
.replace('HH', HH).replace('H', hour)
.replace('mm', mm).replace('m', minute)
.replace('ss', ss).replace('s', second)
.replace('S', miliseconds)
.replace('dd', dd).replace('d', day)
.replace('EEEE', EEEE).replace('EEE', EEE)
.replace('yyyy', yyyy)
.replace('yy', yy)
.replace('aaa', aaa);
if (patternStr.indexOf('MMM') > -1) {
patternStr = patternStr
.replace('MMMM', MMMM)
.replace('MMM', MMM);
}
else {
patternStr = patternStr
.replace('MM', MM)
.replace('M', M);
}
return patternStr;
}
function twoDigitPad(num) {
return num < 10 ? "0" + num : num;
}
console.log(formatDate(new Date()));
console.log(formatDate(new Date(), 'dd-MMM-yyyy')); //OP's request
console.log(formatDate(new Date(), 'EEEE, MMMM d, yyyy HH:mm:ss.S aaa'));
console.log(formatDate(new Date(), 'EEE, MMM d, yyyy HH:mm'));
console.log(formatDate(new Date(), 'yyyy-MM-dd HH:mm:ss.S'));
console.log(formatDate(new Date(), 'M/dd/yyyy h:mmaaa'));
Thank you #Gerry for bringing up Luxon.
#Sébastien -- alternative all browser support
new Date(parseInt(496407600)*1000).toLocaleDateString('de-DE', {
year: 'numeric',
month: '2-digit',
day: '2-digit'
}).replace(/\./g, '/');
Documentation:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date/toLocaleDateString
High-order tagged template literal example based on Date.toLocaleDateString:
const date = new Date(Date.UTC(2020, 4, 2, 3, 23, 16, 738));
const fmt = (dt, lc = "en-US") => (str, ...expr) =>
str.map((str, i) => str + (expr[i]?dt.toLocaleDateString(lc, expr[i]) :'')).join('')
console.log(fmt(date)`${{year: 'numeric'}}-${{month: '2-digit'}}-${{day: '2-digit'}}`);
// expected output: "2020-05-02"
OK, we have got something called Intl which is very useful for formatting a date in JavaScript these days:
Your date as below:
var date = '10/8/2010';
And you change to Date by using new Date() like below:
date = new Date(date);
And now you can format it any way you like using a list of locales like below:
date = new Intl.DateTimeFormat('en-AU').format(date); // Australian date format: "8/10/2010"
date = new Intl.DateTimeFormat('en-US').format(date); // USA date format: "10/8/2010"
date = new Intl.DateTimeFormat('ar-EG').format(date); // Arabic date format: "٨‏/١٠‏/٢٠١٠"
If you exactly want the format you mentioned above, you can do:
date = new Date(Date.UTC(2010, 7, 10, 0, 0, 0));
var options = {year: "numeric", month: "short", day: "numeric"};
date = new Intl.DateTimeFormat("en-AU", options).format(date).replace(/\s/g, '-');
And the result is going to be:
"10-Aug-2010"
For more see the Intl API and Intl.DateTimeFormat documentation.
Using an ECMAScript Edition 6 (ES6/ES2015) string template:
let d = new Date();
let formatted = `${d.getFullYear()}-${d.getMonth() + 1}-${d.getDate()}`;
If you need to change the delimiters:
const delimiter = '/';
let formatted = [d.getFullYear(), d.getMonth() + 1, d.getDate()].join(delimiter);
The Date constructor (and Date.parse()) only accepts one format as a parameter when constructing a date and that is ISO 8601:
// new Date('YYYY-MM-DDTHH:mm:ss.sssZ')
const date = new Date('2017-08-15')
But parsing a from a string is strongly discouraged (MDN recommends against creating date with date strings) due to browser differences and inconsistencies.
The recommended alternative would be building your Date instance directly from the numeric data like this:
new Date(2017, 7, 15) // Month is zero-indexed
That is parsing. Now, to format your date to the string you desire you have several options that are native of the Date object (although I believe none is compliant to the format you require):
date.toString() // 'Wed Jan 23 2019 17:23:42 GMT+0800 (Singapore Standard Time)'
date.toDateString() // 'Wed Jan 23 2019'
date.toLocaleString() // '23/01/2019, 17:23:42'
date.toGMTString() // 'Wed, 23 Jan 2019 09:23:42 GMT'
date.toUTCString() // 'Wed, 23 Jan 2019 09:23:42 GMT'
date.toISOString() // '2019-01-23T09:23:42.079Z'
For other formatting options I'm afraid you'll have to turn to libraries such as Moment.js, day.js and the like.
Credit to Zell Liew from this article for the date formatting tips.
Here's is some code I just wrote to handle the date formatting for a project I'm working on. It mimics the PHP date formatting functionality to suit my needs. Feel free to use it, it's just extending the already existing Date() object. This may not be the most elegant solution but it's working for my needs.
var d = new Date();
d_string = d.format("m/d/Y h:i:s");
/**************************************
* Date class extension
*
*/
// Provide month names
Date.prototype.getMonthName = function(){
var month_names = [
'January',
'February',
'March',
'April',
'May',
'June',
'July',
'August',
'September',
'October',
'November',
'December'
];
return month_names[this.getMonth()];
}
// Provide month abbreviation
Date.prototype.getMonthAbbr = function(){
var month_abbrs = [
'Jan',
'Feb',
'Mar',
'Apr',
'May',
'Jun',
'Jul',
'Aug',
'Sep',
'Oct',
'Nov',
'Dec'
];
return month_abbrs[this.getMonth()];
}
// Provide full day of week name
Date.prototype.getDayFull = function(){
var days_full = [
'Sunday',
'Monday',
'Tuesday',
'Wednesday',
'Thursday',
'Friday',
'Saturday'
];
return days_full[this.getDay()];
};
// Provide full day of week name
Date.prototype.getDayAbbr = function(){
var days_abbr = [
'Sun',
'Mon',
'Tue',
'Wed',
'Thur',
'Fri',
'Sat'
];
return days_abbr[this.getDay()];
};
// Provide the day of year 1-365
Date.prototype.getDayOfYear = function() {
var onejan = new Date(this.getFullYear(),0,1);
return Math.ceil((this - onejan) / 86400000);
};
// Provide the day suffix (st,nd,rd,th)
Date.prototype.getDaySuffix = function() {
var d = this.getDate();
var sfx = ["th","st","nd","rd"];
var val = d%100;
return (sfx[(val-20)%10] || sfx[val] || sfx[0]);
};
// Provide Week of Year
Date.prototype.getWeekOfYear = function() {
var onejan = new Date(this.getFullYear(),0,1);
return Math.ceil((((this - onejan) / 86400000) + onejan.getDay()+1)/7);
}
// Provide if it is a leap year or not
Date.prototype.isLeapYear = function(){
var yr = this.getFullYear();
if ((parseInt(yr)%4) == 0){
if (parseInt(yr)%100 == 0){
if (parseInt(yr)%400 != 0){
return false;
}
if (parseInt(yr)%400 == 0){
return true;
}
}
if (parseInt(yr)%100 != 0){
return true;
}
}
if ((parseInt(yr)%4) != 0){
return false;
}
};
// Provide Number of Days in a given month
Date.prototype.getMonthDayCount = function() {
var month_day_counts = [
31,
this.isLeapYear() ? 29 : 28,
31,
30,
31,
30,
31,
31,
30,
31,
30,
31
];
return month_day_counts[this.getMonth()];
}
// format provided date into this.format format
Date.prototype.format = function(dateFormat){
// break apart format string into array of characters
dateFormat = dateFormat.split("");
var date = this.getDate(),
month = this.getMonth(),
hours = this.getHours(),
minutes = this.getMinutes(),
seconds = this.getSeconds();
// get all date properties ( based on PHP date object functionality )
var date_props = {
d: date < 10 ? '0'+date : date,
D: this.getDayAbbr(),
j: this.getDate(),
l: this.getDayFull(),
S: this.getDaySuffix(),
w: this.getDay(),
z: this.getDayOfYear(),
W: this.getWeekOfYear(),
F: this.getMonthName(),
m: month < 10 ? '0'+(month+1) : month+1,
M: this.getMonthAbbr(),
n: month+1,
t: this.getMonthDayCount(),
L: this.isLeapYear() ? '1' : '0',
Y: this.getFullYear(),
y: this.getFullYear()+''.substring(2,4),
a: hours > 12 ? 'pm' : 'am',
A: hours > 12 ? 'PM' : 'AM',
g: hours % 12 > 0 ? hours % 12 : 12,
G: hours > 0 ? hours : "12",
h: hours % 12 > 0 ? hours % 12 : 12,
H: hours,
i: minutes < 10 ? '0' + minutes : minutes,
s: seconds < 10 ? '0' + seconds : seconds
};
// loop through format array of characters and add matching data else add the format character (:,/, etc.)
var date_string = "";
for(var i=0;i<dateFormat.length;i++){
var f = dateFormat[i];
if(f.match(/[a-zA-Z]/g)){
date_string += date_props[f] ? date_props[f] : '';
} else {
date_string += f;
}
}
return date_string;
};
/*
*
* END - Date class extension
*
************************************/
This may help with the problem:
var d = new Date();
var options = {
day: 'numeric',
month: 'long',
year: 'numeric'
};
console.log(d.toLocaleDateString('en-ZA', options));
A useful and flexible way for formatting the DateTimes in JavaScript is Intl.DateTimeFormat:
var date = new Date();
var options = { year: 'numeric', month: 'short', day: '2-digit'};
var _resultDate = new Intl.DateTimeFormat('en-GB', options).format(date);
// The _resultDate is: "12 Oct 2017"
// Replace all spaces with - and then log it.
console.log(_resultDate.replace(/ /g,'-'));
Result Is: "12-Oct-2017"
The date and time formats can be customized using the options argument.
The Intl.DateTimeFormat object is a constructor for objects that enable language sensitive date and time formatting.
Syntax
new Intl.DateTimeFormat([locales[, options]])
Intl.DateTimeFormat.call(this[, locales[, options]])
Parameters
locales
Optional. A string with a BCP 47 language tag, or an array of such strings. For the general form and interpretation of the locales argument, see the Intl page. The following Unicode extension keys are allowed:
nu
Numbering system. Possible values include: "arab", "arabext", "bali", "beng", "deva", "fullwide", "gujr", "guru", "hanidec", "khmr", "knda", "laoo", "latn", "limb", "mlym", "mong", "mymr", "orya", "tamldec", "telu", "thai", "tibt".
ca
Calendar. Possible values include: "buddhist", "chinese", "coptic", "ethioaa", "ethiopic", "gregory", "hebrew", "indian", "islamic", "islamicc", "iso8601", "japanese", "persian", "roc".
Options
Optional. An object with some or all of the following properties:
localeMatcher
The locale matching algorithm to use. Possible values are "lookup" and "best fit"; the default is "best fit". For information about this option, see the Intl page.
timeZone
The time zone to use. The only value implementations must recognize is "UTC"; the default is the runtime's default time zone. Implementations may also recognize the time zone names of the IANA time zone database, such as "Asia/Shanghai", "Asia/Kolkata", "America/New_York".
hour12
Whether to use 12-hour time (as opposed to 24-hour time). Possible values are true and false; the default is locale dependent.
formatMatcher
The format matching algorithm to use. Possible values are "basic" and "best fit"; the default is "best fit". See the following paragraphs for information about the use of this property.
The following properties describe the date-time components to use in formatted output and their desired representations. Implementations are required to support at least the following subsets:
weekday, year, month, day, hour, minute, second
weekday, year, month, day
year, month, day
year, month
month, day
hour, minute, second
hour, minute
Implementations may support other subsets, and requests will be negotiated against all available subset-representation combinations to find the best match. Two algorithms are available for this negotiation and selected by the formatMatcher property: A fully specified "basic" algorithm and an implementation dependent "best fit" algorithm.
weekday
The representation of the weekday. Possible values are "narrow", "short", "long".
era
The representation of the era. Possible values are "narrow", "short", "long".
year
The representation of the year. Possible values are "numeric", "2-digit".
month
The representation of the month. Possible values are "numeric", "2-digit", "narrow", "short", "long".
day
The representation of the day. Possible values are "numeric", "2-digit".
hour
The representation of the hour. Possible values are "numeric", "2-digit".
minute
The representation of the minute. Possible values are "numeric", "2-digit".
second
The representation of the second. Possible values are "numeric", "2-digit".
timeZoneName
The representation of the time zone name. Possible values are "short", "long".
The default value for each date-time component property is undefined, but if all component properties are undefined, then the year, month and day are assumed to be "numeric".
Check Online
More Details
A JavaScript solution without using any external libraries:
var now = new Date()
months = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec']
var formattedDate = now.getDate() + "-" + months[now.getMonth()] + "-" + now.getFullYear()
alert(formattedDate)
new Date().toLocaleDateString()
// "3/21/2018"
More documentation at developer.mozilla.org
We have lots of solutions for this, but I think the best of them is Moment.js. So I personally suggest to use Moment.js for date and time operations.
console.log(moment().format('DD-MMM-YYYY'));
<script src="//cdnjs.cloudflare.com/ajax/libs/moment.js/2.14.1/moment.min.js"></script>
If you are using jQuery UI in your code, there is an inbuilt function called formatDate(). I am using it this way to format today's date:
var testdate = Date();
testdate = $.datepicker.formatDate( "d-M-yy",new Date(testdate));
alert(testdate);
You can see many other examples of formatting date in the jQuery UI documentation.
This is how I implemented for my npm plugins
var monthNames = [
"January", "February", "March",
"April", "May", "June", "July",
"August", "September", "October",
"November", "December"
];
var Days = [
"Sunday", "Monday", "Tuesday", "Wednesday",
"Thursday", "Friday", "Saturday"
];
var formatDate = function(dt,format){
format = format.replace('ss', pad(dt.getSeconds(),2));
format = format.replace('s', dt.getSeconds());
format = format.replace('dd', pad(dt.getDate(),2));
format = format.replace('d', dt.getDate());
format = format.replace('mm', pad(dt.getMinutes(),2));
format = format.replace('m', dt.getMinutes());
format = format.replace('MMMM', monthNames[dt.getMonth()]);
format = format.replace('MMM', monthNames[dt.getMonth()].substring(0,3));
format = format.replace('MM', pad(dt.getMonth()+1,2));
format = format.replace(/M(?![ao])/, dt.getMonth()+1);
format = format.replace('DD', Days[dt.getDay()]);
format = format.replace(/D(?!e)/, Days[dt.getDay()].substring(0,3));
format = format.replace('yyyy', dt.getFullYear());
format = format.replace('YYYY', dt.getFullYear());
format = format.replace('yy', (dt.getFullYear()+"").substring(2));
format = format.replace('YY', (dt.getFullYear()+"").substring(2));
format = format.replace('HH', pad(dt.getHours(),2));
format = format.replace('H', dt.getHours());
return format;
}
pad = function(n, width, z) {
z = z || '0';
n = n + '';
return n.length >= width ? n : new Array(width - n.length + 1).join(z) + n;
}
You should have a look at DayJs It's a remake of momentJs but modular architecture oriented so lighter.
Fast 2kB alternative to Moment.js with the same modern API
Day.js is a minimalist JavaScript library that parses, validates, manipulates, and displays dates and times for modern browsers with a largely Moment.js-compatible API. If you use Moment.js, you already know how to use Day.js.
var date = Date.now();
const formatedDate = dayjs(date).format("YYYY-MM-DD")
console.log(formatedDate);
<script src="https://cdnjs.cloudflare.com/ajax/libs/dayjs/1.8.16/dayjs.min.js" crossorigin="anonymous"></script>
var today = new Date();
var formattedToday = today.toLocaleDateString() + ' ' + today.toLocaleTimeString();
Inspired by JD Smith's marvellous regular expression solution, I suddenly had this head-splitting idea:
var D = Date().toString().split(" ");
console.log(D[2] + "-" + D[1] + "-" + D[3]);
For any one looking for a really simple ES6 solution to copy, paste and adopt:
const dateToString = d => `${d.getFullYear()}-${('00' + (d.getMonth() + 1)).slice(-2)}-${('00' + d.getDate()).slice(-2)}`
// how to use:
const myDate = new Date(Date.parse('04 Dec 1995 00:12:00 GMT'))
console.log(dateToString(myDate)) // 1995-12-04
As of 2019, it looks like you can get toLocaleDateString to return only certain parts and then you can join them as you wish:
var date = new Date();
console.log(date.toLocaleDateString("en-US", { day: 'numeric' })
+ "-"+ date.toLocaleDateString("en-US", { month: 'short' })
+ "-" + date.toLocaleDateString("en-US", { year: 'numeric' }) );
> 16-Nov-2019
console.log(date.toLocaleDateString("en-US", { month: 'long' })
+ " " + date.toLocaleDateString("en-US", { day: 'numeric' })
+ ", " + date.toLocaleDateString("en-US", { year: 'numeric' }) );
> November 16, 2019
It works same in Internet Explorer 11, Firefox, and Chrome (Chrome 80.x shows 12 hours format when en-UK selected).
const d = new Date('2010/08/05 23:45') // 26.3.2020
const dtfUK = new Intl.DateTimeFormat('UK', { year: 'numeric', month: '2-digit', day: '2-digit',
hour: '2-digit',minute: '2-digit', second: '2-digit' }); //
const dtfUS = new Intl.DateTimeFormat('en', { year: 'numeric', month: '2-digit', day: '2-digit',
hour: '2-digit',minute: '2-digit', second: '2-digit' }); //
console.log(dtfUS.format(d)); // 08/05/2010 11:45:00 PM
console.log(dtfUK.format(d)); // 05.08.2010 23:45:00
/* node.js:
08/05/2010, 11:45:00 PM
2010-08-05 23:45:00
*/
What about something more general?
var d = new Date('2010-08-10T10:34:56.789Z');
var str = d.toDateString() + // Tue Aug 10 2010
' ' + d.toTimeString().split(' ')[0] + // 12:34:56, GMT+0x00 (GMT+0x:00)
' ' + (d.getMonth() + 101) + // 108
' ' + d.getMilliseconds(); // 789
console.log(str); // Tue Aug 10 2010 12:34:56 108 789
console.log(// $1 Tue $2 Aug $3 11 $4 2020 $5 12 $6 34 $7 56 $8 108 $9 789
str.replace(/(\S{3}) (\S{3}) (\d{1,2}) (\d{4}) (\d{2}):(\d{2}):(\d{2}) 1(\d{2}) (\d{1,3})/, '$3-$2-$4 $5:$6.$9 ($1)')
); // 10-Aug-2010 12:34.789 (Tue)
/*
$1: Tue Week Day string
$2: Aug Month short text
$3: 11 Day
$4: 2010 Year
$5: 12 Hour
$6: 34 Minute
$7: 56 Seconds
$8: 08 Month
$9: 789 Milliseconds
*/
Or for example 1-line IIFE "library" ;-)
console.log(
(function (frm, d) { return [d.toDateString(), d.toTimeString().split(' ')[0], (d.getMonth() + 101), d.getMilliseconds()].join(' ').replace(/(\S{3}) (\S{3}) (\d{1,2}) (\d{4}) (\d{2}):(\d{2}):(\d{2}) 1(\d{2}) (\d{1,3})/, frm); })
('$4/$8/$3 $5:$6 ($1)', new Date())
);
You can remove useless parts and / or change indexes if you do not need them.

Get Every Tuesday of the month with Coldfusion

I'm currently working with jquery FullCalendar plugin to create a specific calendar.
One of my tasks I have to work out is how to get any given specific day for the month.
I'm currently using Coldfusion 10 for the server side so I'm wondering is there any specific way of getting every instance of a Tuesday into an array of dates?
Ideally I would like to do this on the server side and populate the calendar plugin.
My issue is primarily trying to source every specific day of a calendar month.
Any advice greatly appreciated.
The firstXDayOfMonth() UDF on CFLlib allows you to find the first of a given day-of-week in a given month. From there you just need to loop from that date adding 7 each iteration until the month is no long the selected month.
theMonth = month(now());
startDate = firstXDayOfMonth(3, theMonth, year(now()));
tuesdays = [];
for (date=startDate; month(date) == theMonth; date +=7){
arrayAppend(tuesdays, dateAdd("s",0, date)); // this just converts date from a number back to a date
}
writeDump(tuesdays);
Update:
Actually the approach for that UDF on CFLib is terrible. Use this variation instead:
function firstXDayOfMonth(dayOfWeek,month,year){
var firstOfMonth = createDate(year, month,1);
var dowOfFirst = dayOfWeek(firstOfMonth);
var daysToAdd = (7 - (dowOfFirst - dayOfWeek)) MOD 7;
var dow = dateAdd("d", daysToAdd, firstOfMonth);
return dow;
}
I'll update the UDF on cflib a bit later: I need to write some decent unit tests for it first, and am a bit busy # the moment.
The Short Version:
At this time, there is not a function in CF that gets all the Tuesdays. But here's an easy way to do it:
// assuming a year and month are defined already
var firstDayOfMonth = createDate( year, month, 1 );
var targetDayOfWeek = 3; // Tuesday is 3 if Sunday is 1
var dayOfWeekArray = []; // This is the outcome.
// loop through each day of the month adding the target days to the array.
for( i = 1; i LTE daysInMonth( firstDayOfMonth ); i++){
var loopingDate = createDate( year, month, i );
if( dayOfWeek( loopingDate ) == targetDayOfWeek ){
ArrayAppend( dayOfWeekArray, loopingDate );
}
}
dayOfWeekArray is an array of every Tuesday of a month.
More Detail:
Your title and post seem to conflict as far as what you're looking for, so I'm going to stick with the title, since that's why I came here...
Here's what you can do to find all the Tuesdays in a month:
Create a date Object
Loop through the days in the target month using the date Object
If the current day is Tuesday, add it to an array
Boom, you got all the Tuesdays of a month in an array
Here's the code I used (cfscript):
// assuming a year and month are defined already
var firstDayOfMonth = createDate( year, month, 1 );
var dayOfWeekArray = [];
var targetDayOfWeek = 3; // Tuesday is 3 if Sunday is 1. Do a quick writeDump in the loop if you're not sure.
for( i = 1; i LTE daysInMonth( firstDayOfMonth ); i++){
var loopingDate = createDate( year, month, i );
if( dayOfWeek( loopingDate ) == targetDayOfWeek ){
ArrayAppend( dayOfWeekArray, datePart( "d", loopingDate );
// ArrayAppend( dayOfWeekArray, loopingDate ); - use this if you'd rather have the whole date object
}
}
This gives you dayOfWeekArray which will be the date of each Tuesday of a particular month. For instance, this month (Jan 2019) will be [1, 8, 15, 22, 29]. You can change this to be the entire date object if you want - that's what I did in the short version at the top.

How to convert year month and min information to day num

I want to convert the given year, month and min information to day of year info.
For eg lets say
year 2004, month 2, day 2 = 33rd day of year
how can I do it in matlab?
Get the datenum for Jan 1 of that year, and subtract it from the given yy/mm/dd. For example, today's day of the year:
jan1 = datenum(datestr(now,'yy'),'yy')
now - jan1 + 1
Check the above against here.
For a specific date,
>> yy = 2004; mm = 2; dd = 2;
>> doty = datenum(yy,mm,dd) - datenum(yy,1,0)
doty =
33