Is there any way to exclude copying of empty files (0 bytes) using robocopy command?
I have a source with thousands of empty files besides other files and destination also have same file names but not empty. I want to copy everything from source to destination except empty files.
Include command line switch /MIN:1 what instructs Robocopy to ignore all files smaller than 1 byte.
From documentation:
/MIN:n : MINimum file size - exclude files smaller than n bytes.
According to Robocopy documentation you should try to simply add /min: 1to your arguments
Related
I have 300 pdf files in a folder in Windows10. The pdf files are named as "1.pdf","2.pdf","3.pdf"......"300.pdf".
I also have a list of 50 random file names(all file names are between 1 and 300) in txt file such as "2.pdf","13.pdf",....
I want to select the specified files mentioned in txt file from the folder and move it to another folder. Is there a way to do it quickly and at once without selecting each individual file and moving it
In Powershell you could do something like
gc txtfile.txt | %{ move $_ destination }
... which would gc or get the contents of txtfile.txt, then for each line, move linefromtxtfile to destination.
The FOR command with the /F option can be used to read a file. Then you can use the move command to move it to the destination directory.
FOR /F "usebackq delims=" %%G IN ("myfile.txt") DO MOVE "%%~G" "destination"
The USEBACKQ option is needed if your text file name has spaces or special characters in it. The DELIMS option is needed so that it does not tokenize the data inside the text file.
This also assumes that your PDF files exist in the same folder as the batch file or the text file lists the relative or absolute paths to the files.
Destination would be an absolute path or relative path depending on your needs.
I've got this line of code using Robocopy:
Robocopy C:\Autopilot_Export \\Zapp\pc\PLI\Hash_Exports Autopilot_CSV.csv
I will have multiple computers networked into this server running this same script and they'll be copying different CSVs under the same CSV name "Autopilot_CSV".
Is there a way to have Robocopy behave similarly to how Windows 10 does when you copy an identical file to a directory and hit "Keep Both" when prompted? So it would end up naming them Autopilot_CSV.csv, Autopilot_CSV(1).csv, Autopilot_CSV(2).csv, Autopilot_CSV(3).csv, and so on...
I've looked over the Robocopy documentation and found the /XN /XO /XE options, but they appear to all be referencing timestamps, differing sizes, older, and newer files. The timestamps and sizes of these files are going to all be different, however, the file names will be the same.
Is there a way to do this?
Thanks!
I have a script to copy files from local machine to Azure blob, but my new requirement is to copy half of source files into one blob container and another half into another blob container. Let me know if I can do so using parallel or one after the other. I am using azcopy for now to move these files without splitting and from only one source to one destination.
.\AzCopy.exe /Source:$localfilepath /Dest:$Destinationpath /DestKey:$key1 /S
As I known, if there is a pattern for filtering these file names, you can use the parameter Pattern of AzCopy tool to separately upload them in two times, such as the command as below from the section Upload blobs matching a specific pattern of the offical tutorial if they are named with the a prefix.
AzCopy /Source:C:\myfolder /Dest:https://myaccount.blob.core.windows.net/mycontainer /DestKey:key /Pattern:a* /S
Here is the description of the parameter Pattern of AzCopy
/Pattern:"file-pattern"
Specifies a file pattern that indicates which files to copy. The behavior of the /Pattern parameter is determined by the location of the source data, and the presence of the recursive mode option. Recursive mode is specified via option /S.
If the specified source is a directory in the file system, then standard wildcards are in effect, and the file pattern provided is matched against files within the directory. If option /S is specified, then AzCopy also matches the specified pattern against all files in any subfolders beneath the directory.
If the specified source is a blob container or virtual directory, then wildcards are not applied. If option /S is specified, then AzCopy interprets the specified file pattern as a blob prefix. If option /S is not specified, then AzCopy matches the file pattern against exact blob names.
If the specified source is an Azure file share, then you must either specify the exact file name, (e.g. abc.txt) to copy a single file, or specify option /S to copy all files in the share recursively. Attempting to specify both a file pattern and option /S together results in an error.
AzCopy uses case-sensitive matching when the /Source is a blob container or blob virtual directory, and uses case-insensitive matching in all the other cases.
The default file pattern used when no file pattern is specified is . for a file system location or an empty prefix for an Azure Storage location. Specifying multiple file patterns is not supported.
Applicable to: Blobs, Files
If there is a simple pattern for files, you have to manually move them into the directories of their own category or write a simple script to filter them to generate the command strings for uploading. Then you can use Foreach-Parallel in PowerShell to realize the parallel upload workflow to satisfy your needs.
I need to flatten a directory structure. I have a very large directory with 6000+ directories and 40000+ files. Some are 12 levels deep and have files in them. The paths exceed 255 character limits and if you add the file names, some are 400 characters +. copy and xcopy will not work for this task. I tried a For /R loop with copy and xcopy and they fail at going beyond 255 character paths. I receive a file not found error.
I know that robocopy is good for 36000 characters, so it seems to be the only option. is there anyway to script this in powershell or batch, vb? every variation I have tried copies the directory structure along with the files.
any help is appreciated.
Imagine the following structure:
/a/1.txt
/a/2.txt
/a/.keep
/a/b/1.txt
/a/b/2.txt
/a/b/3.txt
/a/b/.keep
/a/b/c/1.txt
/a/b/c/2.txt
/a/b/c/3.txt
/a/b/c/4.txt
/a/b/c/.keep
/d/test.txt
/d/work.txt
I want to ignore all files in a directory except .keep files to obtain the following results:
/a/.keep
/a/b/.keep
/a/b/c/.keep
/d/test.txt
/d/work.txt
My .gitignore file that doesn't work:
/a/*
!.keep
Unfortunatelly, you cannot reinclude files at directories ignored by previous rules, according to the gitignore Documentation:
It is not possible to re-include a file if a parent directory of that file is excluded. Git doesn’t list excluded directories for performance reasons, so any patterns on contained files have no effect, no matter where they are defined.
So this
/a/*
!/a/**/.keep
will only reinclude /a/.keep but not the others.
You'll have to exclude each file pattern under /a explictly.
/a/**/*.txt
/a/**/.ignore
/a/**/.alsoignore
UPDATE: Or a better solution is to create the following .gitgnore at your /a subdirectory:
*.*
!.keep
(the only drawback is that this solution will also keep files with no extension)
In your case, you should use:
/a/*
!**/.keep
From the gitignore documentation:
A leading "**" followed by a slash means match in all directories. For
example, "**/foo" matches file or directory "foo" anywhere, the same
as pattern "foo". "**/foo/bar" matches file or directory "bar"
anywhere that is directly under directory "foo".