Calculate number of weeks in a given month - Swift - swift

Having looked at a few different suggestions on SO, I've not been able to determine why the function below does not work. It seems to return 6 for some months and 5 for others. When changing weeks for days it works perfectly.
For example, trying
weeksInMonth(8, forYear 2015)
Results in 6.
I believe I have a mis-understanding of what 'firstWeekday' property on calendar does but haven't found an adequate explanation by Apple or online.
Have tried both .WeekOfMonth and .WeekOfYear. Again can't find explanation of exact difference.
Any suggestions would be greatly welcome.
func weeksInMonth(month: Int, forYear year: Int) -> Int?
{
if (month < 1 || month > 12) { return nil }
let dateString = String(format: "%4d/%d/01", year, month)
let dateFormatter = NSDateFormatter()
dateFormatter.dateFormat = "yyyy/MM/dd"
if let date = dateFormatter.dateFromString(dateString),
let calendar = NSCalendar(calendarIdentifier: NSCalendarIdentifierGregorian)
{
calendar.firstWeekday = 2 // Monday
let weekRange = calendar.rangeOfUnit(.WeekOfMonth, inUnit: .Month, forDate: date)
let weeksCount = weekRange.length
return weeksCount
}
else
{
return nil
}
}
Update:
Apologies my question was not clear. I'm trying to work out how many weeks there are in a month that include a Monday in them. For August this should be 5.

Your code computes the number of weeks which occur (complete or partially)
in a month. What you apparently want is the number of Mondays
in the given month. With NSDateComponents and in particular with
the weekdayOrdinal property you can compute the first
(weekdayOrdinal=1) and last (weekdayOrdinal=-1) Monday
in a month. Then compute the difference in weeks (and add one).
A possible implementation in Swift 2:
func numberOfMondaysInMonth(month: Int, forYear year: Int) -> Int?
{
let calendar = NSCalendar(calendarIdentifier: NSCalendarIdentifierGregorian)!
calendar.firstWeekday = 2 // 2 == Monday
// First monday in month:
let comps = NSDateComponents()
comps.month = month
comps.year = year
comps.weekday = calendar.firstWeekday
comps.weekdayOrdinal = 1
guard let first = calendar.dateFromComponents(comps) else {
return nil
}
// Last monday in month:
comps.weekdayOrdinal = -1
guard let last = calendar.dateFromComponents(comps) else {
return nil
}
// Difference in weeks:
let weeks = calendar.components(.WeekOfMonth, fromDate: first, toDate: last, options: [])
return weeks.weekOfMonth + 1
}
Note: That a negative weekdayOrdinal counts backwards from the end of the month is not apparent form the documentation. It was observed in
Determine NSDate for Memorial Day in a given year and confirmed by Dave DeLong).
Update for Swift 3:
func numberOfMondaysInMonth(_ month: Int, forYear year: Int) -> Int? {
var calendar = Calendar(identifier: .gregorian)
calendar.firstWeekday = 2 // 2 == Monday
// First monday in month:
var comps = DateComponents(year: year, month: month,
weekday: calendar.firstWeekday, weekdayOrdinal: 1)
guard let first = calendar.date(from: comps) else {
return nil
}
// Last monday in month:
comps.weekdayOrdinal = -1
guard let last = calendar.date(from: comps) else {
return nil
}
// Difference in weeks:
let weeks = calendar.dateComponents([.weekOfMonth], from: first, to: last)
return weeks.weekOfMonth! + 1
}

Actually your question is : How many Mondays are in a given month?
My approach is to calculate the first Monday for the month, this can be accomplished by setting the CalendarUnit WeekdayOrdinal to 1. Then get the number of total days and do some math.
Swift 1.2
func mondaysInMonth(month: Int, forYear year: Int) -> Int?
{
if 1...12 ~= month {
let calendar = NSCalendar(calendarIdentifier: NSCalendarIdentifierGregorian)!
let components = NSDateComponents()
components.weekday = 2 // Monday
components.weekdayOrdinal = 1
components.month = month
components.year = year
if let date = calendar.dateFromComponents(components) {
let firstDay = calendar.component(.CalendarUnitDay, fromDate: date)
let days = calendar.rangeOfUnit(.CalendarUnitDay, inUnit:.CalendarUnitMonth, forDate:date).length
return (days - firstDay) / 7 + 1
}
}
return nil
}
Swift 2
func mondaysInMonth(month: Int, forYear year: Int) -> Int?
{
guard 1...12 ~= month else { return nil }
let calendar = NSCalendar(calendarIdentifier: NSCalendarIdentifierGregorian)!
let components = NSDateComponents()
components.weekday = 2 // Monday
components.weekdayOrdinal = 1
components.month = month
components.year = year
if let date = calendar.dateFromComponents(components) {
let firstDay = calendar.component(.Day, fromDate: date)
let days = calendar.rangeOfUnit(.Day, inUnit:.Month, forDate:date).length
return (days - firstDay) / 7 + 1
}
return nil
}

Swift 2
The following code calculates the number of weeks in a month. It does not depend on what day the month started or ended.
func weeksInMonth(month: Int, year: Int) -> (Int)? {
let calendar = NSCalendar.currentCalendar()
let comps = NSDateComponents()
comps.month = month+1
comps.year = year
comps.day = 0
guard let last = calendar.dateFromComponents(comps) else {
return nil
}
// Note: Could get other options as well
let tag = calendar.components([.WeekOfMonth,.WeekOfYear,
.YearForWeekOfYear,.Weekday,.Quarter],fromDate: last)
return tag.weekOfMonth
}
// Example Usage:
if let numWeeks = weeksInMonth(8,year: 2015) {
print(numWeeks) // Prints 6
}
if let numWeeks = weeksInMonth(12,year: 2015) {
print(numWeeks) // Prints 5
}

Swift 4+:
//-- Get number of weeks from calendar
func numberOfWeeksInMonth(_ date: Date) -> Int {
var calendar = Calendar(identifier: .gregorian)
calendar.firstWeekday = 1
let weekRange = calendar.range(of: .weekOfMonth,
in: .month,
for: date)
return weekRange!.count
}
//-- Implementation
let weekCount = numberOfWeeksInMonth(Date)

Swift 4+:
Generate Date from your components:
let dateComponents = DateComponents.init(year: 2019, month: 5)
let monthCurrentDayFirst = Calendar.current.date(from: dateComponents)!
let monthNextDayFirst = Calendar.current.date(byAdding: .month, value: 1, to: monthCurrentDayFirst)!
let monthCurrentDayLast = Calendar.current.date(byAdding: .day, value: -1, to: monthNextDayFirst)!
Detect week number from date:
let numberOfWeeks = Calendar.current.component(.weekOfMonth, from: monthCurrentDayLast)

Related

How to round up date to midnight in Swift? [duplicate]

I'm trying to get the first and last day of the month in swift.
So far I have the following:
let dateFormatter = NSDateFormatter()
let date = NSDate()
dateFormatter.dateFormat = "yyyy-MM-dd"
let calendar = NSCalendar.currentCalendar()
let components = calendar.components([.Year, .Month, .Day, .Hour, .Minute, .Second], fromDate: date)
let month = components.month
let year = components.year
let startOfMonth = ("\(year)-\(month)-01")
But I'm not sure how to get the last date. Is there a built in method I'm missing? Obviously it has to take into account leap years etc.
Swift 3 and 4 drop-in extensions
This actually gets a lot easier with Swift 3+:
You can do it without guard (you could if you wanted to, but because DateComponents is a non-optional type now, it's no longer necessary).
Using iOS 8's startOfDayForDate (now startOfDay), you don't need to manually set the time to 12pm unless you're doing some really crazy calendar calculations across time zones.
It's worth mentioning that some of the other answers claim you can shortcut this by using Calendar.current.date(byAdding: .month, value: 0, to: Date())!, but where this fails, is that it doesn't actually zero out the day, or account for differences in timezones.
Here you go:
extension Date {
func startOfMonth() -> Date {
return Calendar.current.date(from: Calendar.current.dateComponents([.year, .month], from: Calendar.current.startOfDay(for: self)))!
}
func endOfMonth() -> Date {
return Calendar.current.date(byAdding: DateComponents(month: 1, day: -1), to: self.startOfMonth())!
}
}
print(Date().startOfMonth()) // "2018-02-01 08:00:00 +0000\n"
print(Date().endOfMonth()) // "2018-02-28 08:00:00 +0000\n"
You get the first day of the month simply with
let components = calendar.components([.Year, .Month], fromDate: date)
let startOfMonth = calendar.dateFromComponents(components)!
print(dateFormatter.stringFromDate(startOfMonth)) // 2015-11-01
To get the last day of the month, add one month and subtract one day:
let comps2 = NSDateComponents()
comps2.month = 1
comps2.day = -1
let endOfMonth = calendar.dateByAddingComponents(comps2, toDate: startOfMonth, options: [])!
print(dateFormatter.stringFromDate(endOfMonth)) // 2015-11-30
Alternatively, use the rangeOfUnit method which gives you
the start and the length of the month:
var startOfMonth : NSDate?
var lengthOfMonth : NSTimeInterval = 0
calendar.rangeOfUnit(.Month, startDate: &startOfMonth, interval: &lengthOfMonth, forDate: date)
For a date on the last day of month, add the length of the month minus one second:
let endOfMonth = startOfMonth!.dateByAddingTimeInterval(lengthOfMonth - 1)
Updated for Swift5:
extension Date {
var startOfDay: Date {
return Calendar.current.startOfDay(for: self)
}
var startOfMonth: Date {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.year, .month], from: self)
return calendar.date(from: components)!
}
var endOfDay: Date {
var components = DateComponents()
components.day = 1
components.second = -1
return Calendar.current.date(byAdding: components, to: startOfDay)!
}
var endOfMonth: Date {
var components = DateComponents()
components.month = 1
components.second = -1
return Calendar(identifier: .gregorian).date(byAdding: components, to: startOfMonth)!
}
func isMonday() -> Bool {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.weekday], from: self)
return components.weekday == 2
}
}
With Swift 3 & iOS 10 the easiest way I found to do this is Calendar's dateInterval(of:for:):
guard let interval = calendar.dateInterval(of: .month, for: Date()) else { return }
You can then use interval.start and interval.end to get the dates you need.
Swift 3
Many date example for :
Last 6 month,
last 3 month,
yesterday, last 7 day, last 30 day, previous month,
current month start & end, last month start & end date
let startDate = dateFormatter.string(from: Date().getThisMonthStart()!)
let endDate = dateFormatter.string(from: Date().getThisMonthEnd()!)
extension Date {
func getLast6Month() -> Date? {
return Calendar.current.date(byAdding: .month, value: -6, to: self)
}
func getLast3Month() -> Date? {
return Calendar.current.date(byAdding: .month, value: -3, to: self)
}
func getYesterday() -> Date? {
return Calendar.current.date(byAdding: .day, value: -1, to: self)
}
func getLast7Day() -> Date? {
return Calendar.current.date(byAdding: .day, value: -7, to: self)
}
func getLast30Day() -> Date? {
return Calendar.current.date(byAdding: .day, value: -30, to: self)
}
func getPreviousMonth() -> Date? {
return Calendar.current.date(byAdding: .month, value: -1, to: self)
}
// This Month Start
func getThisMonthStart() -> Date? {
let components = Calendar.current.dateComponents([.year, .month], from: self)
return Calendar.current.date(from: components)!
}
func getThisMonthEnd() -> Date? {
let components:NSDateComponents = Calendar.current.dateComponents([.year, .month], from: self) as NSDateComponents
components.month += 1
components.day = 1
components.day -= 1
return Calendar.current.date(from: components as DateComponents)!
}
//Last Month Start
func getLastMonthStart() -> Date? {
let components:NSDateComponents = Calendar.current.dateComponents([.year, .month], from: self) as NSDateComponents
components.month -= 1
return Calendar.current.date(from: components as DateComponents)!
}
//Last Month End
func getLastMonthEnd() -> Date? {
let components:NSDateComponents = Calendar.current.dateComponents([.year, .month], from: self) as NSDateComponents
components.day = 1
components.day -= 1
return Calendar.current.date(from: components as DateComponents)!
}
}
Swift 4
If you only need the ordinal day:
func lastDay(ofMonth m: Int, year y: Int) -> Int {
let cal = Calendar.current
var comps = DateComponents(calendar: cal, year: y, month: m)
comps.setValue(m + 1, for: .month)
comps.setValue(0, for: .day)
let date = cal.date(from: comps)!
return cal.component(.day, from: date)
}
lastDay(ofMonth: 2, year: 2018) // 28
lastDay(ofMonth: 2, year: 2020) // 29
This is the simplest way that I found (Swift 5+):
extension Date {
func getStart(of component: Calendar.Component, calendar: Calendar = Calendar.current) -> Date? {
return calendar.dateInterval(of: component, for: self)?.start
}
func getEnd(of component: Calendar.Component, calendar: Calendar = Calendar.current) -> Date? {
return calendar.dateInterval(of: component, for: self)?.end
}
}
Here is easiest solution:
extension Date {
func startOfMonth() -> Date {
let interval = Calendar.current.dateInterval(of: .month, for: self)
return (interval?.start.toLocalTime())! // Without toLocalTime it give last months last date
}
func endOfMonth() -> Date {
let interval = Calendar.current.dateInterval(of: .month, for: self)
return interval!.end
}
// Convert UTC (or GMT) to local time
func toLocalTime() -> Date {
let timezone = TimeZone.current
let seconds = TimeInterval(timezone.secondsFromGMT(for: self))
return Date(timeInterval: seconds, since: self)
}}
and then call these with your date instance:
print(Date().startOfMonth())
print(Date().endOfMonth())
2017...
First, get the month you need:
let cal = Calendar.current
let d = Calendar.current.date(byAdding: .month, value: 0, to: Date())!
// for "last month" just use -1, for "next month" just use 1, etc
To get the day-of-the-week for the first day of the month:
let c = cal.dateComponents([.year, .month], from: d)
let FDOM = cal.date(from: c)!
let dowFDOM = cal.component(.weekday, from: FDOM)
print("the day-of-week on the 1st is ... \(dowFDOM)")
// so, that's 1=Sunday, 2=Monday, etc.
To get the number of days in the month:
let r = cal.range(of: .day, in: .month, for: d)!
let kDays = r.count
print("the number of days is ... \(kDays)")
With Swift 3, you can choose one of the two following patters in order to retrieve the first and last days of a month.
#1. Using Calendar dateComponents(_:from:), date(from:) and date(byAdding:to:wrappingComponents:) methods
With this pattern, you first get the date of the first day of a month then add a month and remove a day from it in order to get the date of the last day of the month. The Playground code below shows how to set it:
import Foundation
// Set calendar and date
let calendar = Calendar.current
let date = calendar.date(byAdding: DateComponents(day: -10), to: Date())!
// Get first day of month
let firstDayComponents = calendar.dateComponents([.year, .month], from: date)
let firstDay = calendar.date(from: firstDayComponents)!
// Get last day of month
let lastDayComponents = DateComponents(month: 1, day: -1)
let lastDay = calendar.date(byAdding: lastDayComponents, to: firstDay)!
// Set date formatter
let dateFormatter = DateFormatter()
dateFormatter.locale = Locale(identifier: "en_UK")
dateFormatter.dateStyle = .long
dateFormatter.timeStyle = .long
// Print results
print(dateFormatter.string(from: date)) // Prints: 22 March 2017 at 18:07:15 CET
print(dateFormatter.string(from: firstDay)) // Prints: 1 March 2017 at 00:00:00 CET
print(dateFormatter.string(from: lastDay)) // Prints: 31 March 2017 at 00:00:00 CEST
#2. Using Calendar range(of:in:for:), dateComponents(_:from:) and date(from:) and methods
With this pattern, you get a range of absolute day values in a month and then retrieve the dates of the first day and last day of the month from it. The Playground code below shows how to set it:
import Foundation
// Set calendar and date
let calendar = Calendar.current
let date = calendar.date(byAdding: DateComponents(day: -10), to: Date())!
// Get range of days in month
let range = calendar.range(of: .day, in: .month, for: date)! // Range(1..<32)
// Get first day of month
var firstDayComponents = calendar.dateComponents([.year, .month], from: date)
firstDayComponents.day = range.lowerBound
let firstDay = calendar.date(from: firstDayComponents)!
// Get last day of month
var lastDayComponents = calendar.dateComponents([.year, .month], from: date)
lastDayComponents.day = range.upperBound - 1
//lastDayComponents.day = range.count // also works
let lastDay = calendar.date(from: lastDayComponents)!
// Set date formatter
let dateFormatter = DateFormatter()
dateFormatter.locale = Locale(identifier: "en_UK")
dateFormatter.dateStyle = .long
dateFormatter.timeStyle = .long
// Print results
print(dateFormatter.string(from: date)) // prints: 22 March 2017 at 18:07:15 CET
print(dateFormatter.string(from: firstDay)) // prints: 1 March 2017 at 00:00:00 CET
print(dateFormatter.string(from: lastDay)) // prints: 31 March 2017 at 00:00:00 CEST
In swift 3, if you put 0 to day component you can get the last day of the month. There's an example code:
public func isMoreDays(date: Date, asc: Bool)->Bool{
//components
var dayComponents = self.getDateComponents(date: date)
//asc is true if ascendant or false if descendant
dayComponents.day = asc ? 0 : 1
//plus 1 to month 'cos if you set up day to 0 you are going to the previous month
dayComponents.month = asc ? dayComponents.month! + 1 : dayComponents.month
//instantiate calendar and get the date
let calendar : Calendar = NSCalendar.current
let day = calendar.date(from: dayComponents)
//date comparison
if(day?.compare(date) == .orderedSame){
return false
}
return true
}
You can use the following extensions here :
let today = Date()
let startOfMonth = today.beginning(of: .month)
let endOfMonth = today.end(of: .month)

RelativeDateTimeFormatter returns one day less than expected [duplicate]

I'm wondering if there is some new and awesome possibility to get the amount of days between two NSDates in Swift / the "new" Cocoa?
E.g. like in Ruby I would do:
(end_date - start_date).to_i
You have to consider the time difference as well. For example if you compare the dates 2015-01-01 10:00 and 2015-01-02 09:00, days between those dates will return as 0 (zero) since the difference between those dates is less than 24 hours (it's 23 hours).
If your purpose is to get the exact day number between two dates, you can work around this issue like this:
// Assuming that firstDate and secondDate are defined
// ...
let calendar = NSCalendar.currentCalendar()
// Replace the hour (time) of both dates with 00:00
let date1 = calendar.startOfDayForDate(firstDate)
let date2 = calendar.startOfDayForDate(secondDate)
let flags = NSCalendarUnit.Day
let components = calendar.components(flags, fromDate: date1, toDate: date2, options: [])
components.day // This will return the number of day(s) between dates
Swift 3 and Swift 4 Version
let calendar = Calendar.current
// Replace the hour (time) of both dates with 00:00
let date1 = calendar.startOfDay(for: firstDate)
let date2 = calendar.startOfDay(for: secondDate)
let components = calendar.dateComponents([.day], from: date1, to: date2)
Here is my answer for Swift 2:
func daysBetweenDates(startDate: NSDate, endDate: NSDate) -> Int
{
let calendar = NSCalendar.currentCalendar()
let components = calendar.components([.Day], fromDate: startDate, toDate: endDate, options: [])
return components.day
}
I see a couple Swift3 answers so I'll add my own:
public static func daysBetween(start: Date, end: Date) -> Int {
Calendar.current.dateComponents([.day], from: start, to: end).day!
}
The naming feels more Swifty, it's one line, and using the latest dateComponents() method.
Here is very nice, Date extension to get difference between dates in years, months, days, hours, minutes, seconds
extension Date {
func years(sinceDate: Date) -> Int? {
return Calendar.current.dateComponents([.year], from: sinceDate, to: self).year
}
func months(sinceDate: Date) -> Int? {
return Calendar.current.dateComponents([.month], from: sinceDate, to: self).month
}
func days(sinceDate: Date) -> Int? {
return Calendar.current.dateComponents([.day], from: sinceDate, to: self).day
}
func hours(sinceDate: Date) -> Int? {
return Calendar.current.dateComponents([.hour], from: sinceDate, to: self).hour
}
func minutes(sinceDate: Date) -> Int? {
return Calendar.current.dateComponents([.minute], from: sinceDate, to: self).minute
}
func seconds(sinceDate: Date) -> Int? {
return Calendar.current.dateComponents([.second], from: sinceDate, to: self).second
}
}
I translated my Objective-C answer
let start = "2010-09-01"
let end = "2010-09-05"
let dateFormatter = NSDateFormatter()
dateFormatter.dateFormat = "yyyy-MM-dd"
let startDate:NSDate = dateFormatter.dateFromString(start)
let endDate:NSDate = dateFormatter.dateFromString(end)
let cal = NSCalendar.currentCalendar()
let unit:NSCalendarUnit = .Day
let components = cal.components(unit, fromDate: startDate, toDate: endDate, options: nil)
println(components)
result
<NSDateComponents: 0x10280a8a0>
Day: 4
The hardest part was that the autocompletion insists fromDate and toDate would be NSDate?, but indeed they must be NSDate! as shown in the reference.
I don't see how a good solution with an operator would look like, as you want to specify the unit differently in each case. You could return the time interval, but than won't you gain much.
Update for Swift 3 iOS 10 Beta 4
func daysBetweenDates(startDate: Date, endDate: Date) -> Int {
let calendar = Calendar.current
let components = calendar.dateComponents([Calendar.Component.day], from: startDate, to: endDate)
return components.day!
}
Swift 5. Thanks to Emin Buğra Saral above for the startOfDay suggestion.
extension Date {
func daysBetween(date: Date) -> Int {
return Date.daysBetween(start: self, end: date)
}
static func daysBetween(start: Date, end: Date) -> Int {
let calendar = Calendar.current
// Replace the hour (time) of both dates with 00:00
let date1 = calendar.startOfDay(for: start)
let date2 = calendar.startOfDay(for: end)
let a = calendar.dateComponents([.day], from: date1, to: date2)
return a.value(for: .day)!
}
}
Usage:
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "yyyy-MM-dd"
let start = dateFormatter.date(from: "2017-01-01")!
let end = dateFormatter.date(from: "2018-01-01")!
let diff = Date.daysBetween(start: start, end: end) // 365
// or
let diff = start.daysBetween(date: end) // 365
Here is the answer for Swift 3 (tested for IOS 10 Beta)
func daysBetweenDates(startDate: Date, endDate: Date) -> Int
{
let calendar = Calendar.current
let components = calendar.components([.day], from: startDate, to: endDate, options: [])
return components.day!
}
Then you can call it like this
let pickedDate: Date = sender.date
let NumOfDays: Int = daysBetweenDates(startDate: pickedDate, endDate: Date())
print("Num of Days: \(NumOfDays)")
Swift 5
Working, you need to set the time to be the same for both days, if you are off by seconds it will be wrong
func daysBetween(start: Date, end: Date) -> Int {
let start = Calendar.current.date(bySettingHour: 0, minute: 0, second: 0, of: start)!
let end = Calendar.current.date(bySettingHour: 0, minute: 0, second: 0, of: end)!
return Calendar.current.dateComponents([.day], from: start, to: end).day ?? 0
}
The things built into swift are still very basic. As they should be at this early stage. But you can add your own stuff with the risk that comes with overloading operators and global domain functions. They will be local to your module though.
let now = NSDate()
let seventies = NSDate(timeIntervalSince1970: 0)
// Standard solution still works
let days = NSCalendar.currentCalendar().components(.CalendarUnitDay,
fromDate: seventies, toDate: now, options: nil).day
// Flashy swift... maybe...
func -(lhs:NSDate, rhs:NSDate) -> DateRange {
return DateRange(startDate: rhs, endDate: lhs)
}
class DateRange {
let startDate:NSDate
let endDate:NSDate
var calendar = NSCalendar.currentCalendar()
var days: Int {
return calendar.components(.CalendarUnitDay,
fromDate: startDate, toDate: endDate, options: nil).day
}
var months: Int {
return calendar.components(.CalendarUnitMonth,
fromDate: startDate, toDate: endDate, options: nil).month
}
init(startDate:NSDate, endDate:NSDate) {
self.startDate = startDate
self.endDate = endDate
}
}
// Now you can do this...
(now - seventies).months
(now - seventies).days
This is an updated version of Emin's answer for Swift 5 that incorporates the suggestion to use noon instead of midnight as the definitive time for comparing days. It also handles the potential failure of various date functions by returning an optional.
///
/// This is an approximation; it does not account for time differences. It will set the time to 1200 (noon) and provide the absolute number
/// of days between now and the given date. If the result is negative, it should be read as "days ago" instead of "days from today."
/// Returns nil if something goes wrong initializing or adjusting dates.
///
func daysFromToday() -> Int?
{
let calendar = NSCalendar.current
// Replace the hour (time) of both dates with noon. (Noon is less likely to be affected by DST changes, timezones, etc. than midnight.)
guard let date1 = calendar.date(bySettingHour: 12, minute: 00, second: 00, of: calendar.startOfDay(for: Date())),
let date2 = calendar.date(bySettingHour: 12, minute: 00, second: 00, of: calendar.startOfDay(for: self)) else
{
return nil
}
return calendar.dateComponents([.day], from: date1, to: date2).day
}
Here is my answer for Swift 3:
func daysBetweenDates(startDate: NSDate, endDate: NSDate, inTimeZone timeZone: TimeZone? = nil) -> Int {
var calendar = Calendar.current
if let timeZone = timeZone {
calendar.timeZone = timeZone
}
let dateComponents = calendar.dateComponents([.day], from: startDate.startOfDay, to: endDate.startOfDay)
return dateComponents.day!
}
You could use the following extension:
public extension Date {
func daysTo(_ date: Date) -> Int? {
let calendar = Calendar.current
// Replace the hour (time) of both dates with 00:00
let date1 = calendar.startOfDay(for: self)
let date2 = calendar.startOfDay(for: date)
let components = calendar.dateComponents([.day], from: date1, to: date2)
return components.day // This will return the number of day(s) between dates
}
}
Then, you can call it like this:
startDate.daysTo(endDate)
There's hardly any Swift-specific standard library yet; just the lean basic numeric, string, and collection types.
It's perfectly possible to define such shorthands using extensions, but as far as the actual out-of-the-box APIs goes, there is no "new" Cocoa; Swift just maps directly to the same old verbose Cocoa APIs as they already exist.
I'm going to add my version even though this thread is a year old. My code looks like this:
var name = txtName.stringValue // Get the users name
// Get the date components from the window controls
var dateComponents = NSDateComponents()
dateComponents.day = txtDOBDay.integerValue
dateComponents.month = txtDOBMonth.integerValue
dateComponents.year = txtDOBYear.integerValue
// Make a Gregorian calendar
let calendar = NSCalendar(identifier: NSCalendarIdentifierGregorian)
// Get the two dates we need
var birthdate = calendar?.dateFromComponents(dateComponents)
let currentDate = NSDate()
var durationDateComponents = calendar?.components(NSCalendarUnit.CalendarUnitDay, fromDate: birthdate!, toDate: currentDate, options: nil)
let numberOfDaysAlive = durationDateComponents?.day
println("\(numberOfDaysAlive!)")
txtGreeting.stringValue = "Hello \(name), You have been alive for \(numberOfDaysAlive!) days."
I hope it helps someone.
Cheers,
Erin's method updated to Swift 3, This shows days from today (disregarding time of day)
func daysBetweenDates( endDate: Date) -> Int
let calendar: Calendar = Calendar.current
let date1 = calendar.startOfDay(for: Date())
let date2 = calendar.startOfDay(for: secondDate)
return calendar.dateComponents([.day], from: date1, to: date2).day!
}
This returns an absolute difference in days between some Date and today:
extension Date {
func daysFromToday() -> Int {
return abs(Calendar.current.dateComponents([.day], from: self, to: Date()).day!)
}
}
and then use it:
if someDate.daysFromToday() >= 7 {
// at least a week from today
}
easier option would be to create a extension on Date
public extension Date {
public var currentCalendar: Calendar {
return Calendar.autoupdatingCurrent
}
public func daysBetween(_ date: Date) -> Int {
let components = currentCalendar.dateComponents([.day], from: self, to: date)
return components.day!
}
}
Swift 3.2
extension DateComponentsFormatter {
func difference(from fromDate: Date, to toDate: Date) -> String? {
self.allowedUnits = [.year,.month,.weekOfMonth,.day]
self.maximumUnitCount = 1
self.unitsStyle = .full
return self.string(from: fromDate, to: toDate)
}
}
All answer is good. But for Localizations we need calculates a number of decimal days in between two dates. so we can provide the sustainable decimal format.
// This method returns the fractional number of days between to dates
func getFractionalDaysBetweenDates(date1: Date, date2: Date) -> Double {
let components = Calendar.current.dateComponents([.day, .hour], from: date1, to: date2)
var decimalDays = Double(components.day!)
decimalDays += Double(components.hour!) / 24.0
return decimalDays
}
Nice handy one liner :
extension Date {
var daysFromNow: Int {
return Calendar.current.dateComponents([.day], from: Date(), to: self).day!
}
}
Swift 3 - Days from today until date
func daysUntilDate(endDateComponents: DateComponents) -> Int
{
let cal = Calendar.current
var components = cal.dateComponents([.era, .year, .month, .day], from: NSDate() as Date)
let today = cal.date(from: components)
let otherDate = cal.date(from: endDateComponents)
components = cal.dateComponents([Calendar.Component.day], from: (today! as Date), to: otherDate!)
return components.day!
}
Call function like this
// Days from today until date
var examnDate = DateComponents()
examnDate.year = 2016
examnDate.month = 12
examnDate.day = 15
let daysCount = daysUntilDate(endDateComponents: examnDate)
extension Date {
func daysFromToday() -> Int {
return Calendar.current.dateComponents([.day], from: self, to: Date()).day!
}
}
Then use it like
func dayCount(dateString: String) -> String{
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MMM dd,yyyy hh:mm a"
let fetchedDate = dateFormatter.date(from: dateString)
let day = fetchedDate?.daysFromToday()
if day! > -1{
return "\(day!) days passed."
}else{
return "\(day! * -1) days left."
}
}
extension Date {
static func - (recent: Date, previous: Date) -> DateComponents {
var dateComponents = DateComponents()
dateComponents.year = Calendar.current.dateComponents([.day], from: previous, to: recent).year
dateComponents.month = Calendar.current.dateComponents([.month], from: previous, to: recent).month
dateComponents.day = Calendar.current.dateComponents([.day], from: previous, to: recent).day
dateComponents.hour = Calendar.current.dateComponents([.hour], from: previous, to: recent).hour
dateComponents.minute = Calendar.current.dateComponents([.minute], from: previous, to: recent).minute
dateComponents.second = Calendar.current.dateComponents([.second], from: previous, to: recent).second
return dateComponents
}
}
func completeOffset(from date:Date) -> String? {
let formatter = DateComponentsFormatter()
formatter.unitsStyle = .brief
return formatter.string(from: Calendar.current.dateComponents([.year, .month, .day, .hour, .minute, .second], from: date, to: self))
}
if you need year month days and hours as string use this
var tomorrow = Calendar.current.date(byAdding: .day, value: 1, to: Date())!
let dc = tomorrow.completeOffset(from: Date())
2017 version, copy and paste
func simpleIndex(ofDate: Date) -> Int {
// index here just means today 0, yesterday -1, tomorrow 1 etc.
let c = Calendar.current
let todayRightNow = Date()
let d = c.date(bySetting: .hour, value: 13, of: ofDate)
let t = c.date(bySetting: .hour, value: 13, of: todayRightNow)
if d == nil || today == nil {
print("weird problem simpleIndex#ofDate")
return 0
}
let r = c.dateComponents([.day], from: today!, to: d!)
// yesterday is negative one, tomorrow is one
if let o = r.value(for: .day) {
return o
}
else {
print("another weird problem simpleIndex#ofDate")
return 0
}
}
let calendar = NSCalendar.currentCalendar();
let component1 = calendar.component(.Day, fromDate: fromDate)
let component2 = calendar.component(.Day, fromDate: toDate)
let difference = component1 - component2
Swift 5.2.4 solution:
import UIKit
let calendar = Calendar.current
let start = "2010-09-01"
let end = "2010-09-05"
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "yyyy-MM-dd"
let firstDate = dateFormatter.date(from: start)!
let secondDate = dateFormatter.date(from: end)!
// Replace the hour (time) of both dates with 00:00
let date1 = calendar.startOfDay(for: firstDate)
let date2 = calendar.startOfDay(for: secondDate)
let components = calendar.dateComponents([Calendar.Component.day], from: date1, to: date2)
components.day // This will return the number of day(s) between dates

Working out the start and end of a day. Swift

I have a function to work out the start and end of a week which works as expected. I want to implement another function which works out the start and end of a single day. I have the code below however I get the following error:
Type of expression is ambiguous without more context.
public class Date {
let dateFormatter = NSDateFormatter()
let date = NSDate()
let calendar = NSCalendar.currentCalendar()
func calcStartAndEndDateForWeek(durationOccurance: Double) {
print("Calculating start and end for week")
let componentsWeek = calendar.components([.YearForWeekOfYear, .WeekOfYear], fromDate: date)
let startOfWeek = calendar.dateFromComponents(componentsWeek)!
print("start of Week = \(dateFormatter.stringFromDate(startOfWeek))")
let componentsWeekEnds = NSDateComponents()
componentsWeekEnds.weekOfYear = 1
let endOfWeek = calendar.dateByAddingComponents(componentsWeekEnds, toDate: startOfWeek, options: [])!
print("End of the week = \(dateFormatter.stringFromDate(endOfWeek))")
}
func calcStartAndEndDateForDay(durationOccurance: Double) {
print("Calculating start and end for day")
let componentsWeek = calendar.components([.Minutes, .Seconds], fromDate: date)
let startOfDay = calendar.dateFromComponents(componentsWeek)!
print("start day = \(dateFormatter.stringFromDate(startOfDay))")
}
init(){
dateFormatter.dateFormat = "dd-MM-yyyy"
}
}
We can create a more generic function using the methods on NSCalendar:
func rangeOfPeriod(period: NSCalendarUnit, date: NSDate) -> (NSDate, NSDate) {
let calendar = NSCalendar.currentCalendar()
var startDate: NSDate? = nil
// let's ask calendar for the start of the period
calendar.rangeOfUnit(period, startDate: &startDate, interval: nil, forDate: date)
// end of this period is the start of the next period
let endDate = calendar.dateByAddingUnit(period, value: 1, toDate: startDate!, options: [])
// you can subtract 1 second if you want to make "Feb 1 00:00:00" into "Jan 31 23:59:59"
// let endDate2 = calendar.dateByAddingUnit(.Second, value: -1, toDate: endDate!, options: [])
return (startDate!, endDate!)
}
Called as
print("\(rangeOfPeriod(.WeekOfYear, date: NSDate()))")
print("\(rangeOfPeriod(.Day, date: NSDate()))")
Putting it into your code:
public class Date {
let dateFormatter = NSDateFormatter()
let date = NSDate()
let calendar = NSCalendar.currentCalendar()
func rangeOfPeriod(period: NSCalendarUnit) -> (NSDate, NSDate) {
var startDate: NSDate? = nil
calendar.rangeOfUnit(period, startDate: &startDate, interval: nil, forDate: date)
let endDate = calendar.dateByAddingUnit(period, value: 1, toDate: startDate!, options: [])
return (startDate!, endDate!)
}
func calcStartAndEndDateForWeek() {
let (startOfWeek, endOfWeek) = rangeOfPeriod(.WeekOfYear)
print("Start of week = \(dateFormatter.stringFromDate(startOfWeek))")
print("End of the week = \(dateFormatter.stringFromDate(endOfWeek))")
}
func calcStartAndEndDateForDay() {
let (startOfDay, endOfDay) = rangeOfPeriod(.Day)
print("Start of day = \(dateFormatter.stringFromDate(startOfDay))")
print("End of the day = \(dateFormatter.stringFromDate(endOfDay))")
}
init() {
dateFormatter.dateFormat = "dd-MM-yyyy"
}
}
let myDate = Date()
myDate.calcStartAndEndDateForWeek()
myDate.calcStartAndEndDateForDay()
I was implementing something similar and went the following route:
extension Date {
static var startOfToday: Date? {
let date = Date()
guard !date.isStartOfDay else { return date }
return date
.zero(out: .second)?
.zero(out: .minute)?
.zero(out: .hour)?
.addingTimeInterval(-24 * 60 * 60)
}
private func zero(out: Calendar.Component) -> Date? {
return Calendar.current
.date(bySetting: out, value: 0, of: self)
}
private var isStartOfDay: Bool {
let cal = Calendar.current
let hours = cal.component(.hour, from: self)
let minutes = cal.component(.minute, from: self)
let seconds = cal.component(.second, from: self)
return hours == 0 && minutes == 0 && seconds == 0
}
}
Setting a component to zero will increment the next bigger component. So just setting the hour to zero will push the date to the next day at 00:00, unless of course the hour is already at zero. So to make it work for any date we have to zero out the seconds, minutes and hours (in that order). And to make sure we don't end up at the beginning of yesterday we first check if all values aren't already at zero.
I realize this is kinda hacky and probably not the best way to go about this, but it seems to work well enough for my use-case at least.
Getting the end of the day can be built on top of this by just adding another day.

How do I find the number of days in given month and year using swift

I want to find the total number days on given month and year.
Example: I want to find total number of days on year = 2015, month = 7
First create an NSDate for the given year and month:
let dateComponents = NSDateComponents()
dateComponents.year = 2015
dateComponents.month = 7
let calendar = NSCalendar.currentCalendar()
let date = calendar.dateFromComponents(dateComponents)!
Then use the rangeOfUnit() method, as described in
Number of days in the current month using iPhone SDK?:
// Swift 2:
let range = calendar.rangeOfUnit(.Day, inUnit: .Month, forDate: date)
// Swift 1.2:
let range = calendar.rangeOfUnit(.CalendarUnitDay, inUnit: .CalendarUnitMonth, forDate: date)
let numDays = range.length
print(numDays) // 31
Update for Swift 3 (Xcode 8):
let dateComponents = DateComponents(year: 2015, month: 7)
let calendar = Calendar.current
let date = calendar.date(from: dateComponents)!
let range = calendar.range(of: .day, in: .month, for: date)!
let numDays = range.count
print(numDays) // 31
Updated for Swift 3.1, Xcode 8+, iOS 10+
let calendar = Calendar.current
let date = Date()
// Calculate start and end of the current year (or month with `.month`):
let interval = calendar.dateInterval(of: .year, for: date)! //change year it will no of days in a year , change it to month it will give no of days in a current month
// Compute difference in days:
let days = calendar.dateComponents([.day], from: interval.start, to: interval.end).day!
print(days)
In extension format, using self to be able to return the number of days more dynamically (Swift 3).
extension Date {
func getDaysInMonth() -> Int{
let calendar = Calendar.current
let dateComponents = DateComponents(year: calendar.component(.year, from: self), month: calendar.component(.month, from: self))
let date = calendar.date(from: dateComponents)!
let range = calendar.range(of: .day, in: .month, for: date)!
let numDays = range.count
return numDays
}
}
Swift 5.0
func getDaysInMonth(month: Int, year: Int) -> Int? {
let calendar = Calendar.current
var startComps = DateComponents()
startComps.day = 1
startComps.month = month
startComps.year = year
var endComps = DateComponents()
endComps.day = 1
endComps.month = month == 12 ? 1 : month + 1
endComps.year = month == 12 ? year + 1 : year
let startDate = calendar.date(from: startComps)!
let endDate = calendar.date(from:endComps)!
let diff = calendar.dateComponents([Calendar.Component.day], from: startDate, to: endDate)
return diff.day
}
if let numberOfDays = getDaysInMonth(month: 1, year: 2015) {
print(numberOfDays)
}
Swift 2.0
func getDaysInMonth(month: Int, year: Int) -> Int
{
let calendar = NSCalendar.currentCalendar()
let startComps = NSDateComponents()
startComps.day = 1
startComps.month = month
startComps.year = year
let endComps = NSDateComponents()
endComps.day = 1
endComps.month = month == 12 ? 1 : month + 1
endComps.year = month == 12 ? year + 1 : year
let startDate = calendar.dateFromComponents(startComps)!
let endDate = calendar.dateFromComponents(endComps)!
let diff = calendar.components(NSCalendarUnit.Day, fromDate: startDate, toDate: endDate, options: NSCalendarOptions.MatchFirst)
return diff.day
}
let days = getDaysInMonth(4, year: 2015) // April 2015 has 30 days
print(days) // Prints 30
Swift 1.2
func getDaysInMonth(month: Int, year: Int) -> Int
{
let calendar = NSCalendar.currentCalendar()
let startComps = NSDateComponents()
startComps.day = 1
startComps.month = month
startComps.year = year
let endComps = NSDateComponents()
endComps.day = 1
endComps.month = month == 12 ? 1 : month + 1
endComps.year = month == 12 ? year + 1 : year
let startDate = calendar.dateFromComponents(startComps)!
let endDate = calendar.dateFromComponents(endComps)!
let diff = calendar.components(NSCalendarUnit.CalendarUnitDay, fromDate: startDate, toDate: endDate, options: NSCalendarOptions.allZeros)
return diff.day
}
let days = getDaysInMonth(4, 2015) // There were 30 days in April 2015
println(days) // Prints 30
In order to get number of days and all the dates on given month and year, try this.
func getAllDates(month: Int, year: Int) -> [Date] {
let dateComponents = DateComponents(year: year, month: month)
let calendar = Calendar.current
let date = calendar.date(from: dateComponents)!
let range = calendar.range(of: .day, in: .month, for: date)!
let numDays = range.count
let formatter = DateFormatter()
formatter.dateFormat = "yyyy MM dd"
formatter.timeZone = TimeZone(abbreviation: "GMT+0:00")
var arrDates = [Date]()
for day in 1...numDays {
let dateString = "\(year) \(month) \(day)"
if let date = formatter.date(from: dateString) {
arrDates.append(date)
}
}
return arrDates
}
Usage:
let arrDatesInGivenMonthYear = getAllDates(month: 1, year: 2018)
debugPrint(arrDatesInGivenMonthYear)
//Output: [2018-01-01 00:00:00 +0000, 2018-01-02 00:00:00 +0000, ... , 2018-01-31 00:00:00 +0000]
let numberOfDays = arrDatesInGivenMonthYear.count
debugPrint(numberOfDays)
//Output: 31
Swift 5
Another way to approach this:
extension Date {
func daysInMonth(_ monthNumber: Int? = nil, _ year: Int? = nil) -> Int {
var dateComponents = DateComponents()
dateComponents.year = year ?? Calendar.current.component(.year, from: self)
dateComponents.month = monthNumber ?? Calendar.current.component(.month, from: self)
if
let d = Calendar.current.date(from: dateComponents),
let interval = Calendar.current.dateInterval(of: .month, for: d),
let days = Calendar.current.dateComponents([.day], from: interval.start, to: interval.end).day
{ return days } else { return -1 }
}
}
here is the swift 4.0 version
func getTotalDate(){
// choose the month and year you want to look
var dateComponents = DateComponents()
dateComponents.year = 2018
dateComponents.month = 10
let calendar = Calendar.current
let datez = calendar.date(from: dateComponents)
// change .month into .year to see the days available in the year
let interval = calendar.dateInterval(of: .month, for: datez!)!
let days = calendar.dateComponents([.day], from: interval.start, to: interval.end).day!
print(days)
}
What about for a given year?
The following is printing the number of days in the date's month:
let range = userCalendar.range(of: .day, in: .year, for: Date())!
print("Days In Year: \(range.count)") // prints 31
... and not the number of days in the date's year as expected :/

Swift - Start day and end day of the week before previous week

Today is Friday 6 March. How to find that 16 Feb is the start day and 22 Feb is the end day of the week before previous week.
16 is for my country Bulgaria in USA will be 15 and 21 I use .currentCalendar()
Something like this should work:
let cal = NSCalendar.currentCalendar()
let components = NSDateComponents()
components.weekOfYear -= 1
if let date = cal.dateByAddingComponents(components, toDate: NSDate(), options: NSCalendarOptions(0)) {
var beginningOfWeek: NSDate?
var weekDuration = NSTimeInterval()
if cal.rangeOfUnit(.CalendarUnitWeekOfYear, startDate: &beginningOfWeek, interval: &weekDuration, forDate: date) {
let endOfWeek = beginningOfWeek?.dateByAddingTimeInterval(weekDuration)
print(beginningOfWeek) // Optional(2015-02-15 05:00:00 +0000)
print(endOfWeek) // Optional(2015-02-22 05:00:00 +0000)
}
}
A simpler Swift 2 alternative as an extension, derived from Martin R's answer for getting the end of the month:
extension: NSDate {
func startOfWeek(weekday: Int?) -> NSDate? {
guard
let cal: NSCalendar = NSCalendar.currentCalendar(),
let comp: NSDateComponents = cal.components([.YearForWeekOfYear, .WeekOfYear], fromDate: self) else { return nil }
comp.to12pm()
cal.firstWeekday = weekday ?? 1
return cal.dateFromComponents(comp)!
}
func endOfWeek(weekday: Int) -> NSDate? {
guard
let cal: NSCalendar = NSCalendar.currentCalendar(),
let comp: NSDateComponents = cal.components([.WeekOfYear], fromDate: self) else { return nil }
comp.weekOfYear = 1
comp.day -= 1
comp.to12pm()
return cal.dateByAddingComponents(comp, toDate: self.startOfWeek(weekday)!, options: [])!
}
}
Usage:
// Use 2 for Monday, 1 for Sunday:
print(NSDate().startOfWeek(1)!) // "2016-01-24 08:00:00 +0000\n"
print(NSDate().endOfWeek(1)!) // "2016-01-30 08:00:00 +0000\n"
To guard against DST and such, you should also implement an extension to force the time to 12 pm:
internal extension NSDateComponents {
func to12pm() {
self.hour = 12
self.minute = 0
self.second = 0
}
}
If anyone looking for swift 3 answer:
func startOfWeek(weekday: Int?) -> Date {
var cal = Calendar.current
var component = cal.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self)
component.to12am()
cal.firstWeekday = weekday ?? 1
return cal.date(from: component)!
}
func endOfWeek(weekday: Int) -> Date {
let cal = Calendar.current
var component = DateComponents()
component.weekOfYear = 1
component.day = -1
component.to12pm()
return cal.date(byAdding: component, to: startOfWeek(weekday: weekday))!
}
I set to 00:00:00 of that day
internal extension DateComponents {
mutating func to12am() {
self.hour = 0
self.minute = 0
self.second = 0
}
mutating func to12pm(){
self.hour = 23
self.minute = 59
self.second = 59
}
}
Swift 4+:
A very straightforward approach using mainly Calendar with the help of DateComponents:
Get Date
Go to previous week
Calendar.current.date(byAdding: .weekdayOrdinal, value: -1, to: aDate)
Get the current weekday
Calendar.current.component(.weekday, from: bDate)
Compute an offset from this weekday
Negative offset to reach the start of week
Positive offset to the reach end of the week
Use offset to go to the required date
Calendar.current.date(byAdding: .day, value: offset, to: bDate)
Solution:
extension Date {
var firstWeekdayOfLastWeek: Date? {
guard let previousWeek = Calendar.current.date(byAdding: .weekdayOrdinal,
value: -1, to: self)
else { return nil }
let offsetToFirstWeekday: Int = {
let currentWeekday = Calendar.current.component(.weekday, from: previousWeek)
guard currentWeekday > 0 else { return 0 }
return 1 - currentWeekday
}()
let result = Calendar.current.date(byAdding: .day,
value: offsetToFirstWeekday,
to: previousWeek)
return result
}
var lastWeekdayOfLastWeek: Date? {
guard let previousWeek = Calendar.current.date(byAdding: .weekdayOrdinal,
value: -1, to: self)
else { return nil }
let offsetToLastWeekday: Int = {
let currentWeekday = Calendar.current.component(.weekday, from: previousWeek)
return 7 - currentWeekday
}()
let result = Calendar.current.date(byAdding: .day,
value: offsetToLastWeekday,
to: previousWeek)
return result
}
}
Usage Example:
let formatter = DateFormatter()
formatter.dateStyle = .long
let date = Date()
//My current system date (as of time of writing)
print(formatter.string(from: currentDate)) //December 11, 2020
//Results (my system has Sunday as the start of the week)
print(formatter.string(from: date.firstWeekdayOfLastWeek!)) //November 29, 2020
print(formatter.string(from: date.lastWeekdayOfLastWeek!)) //December 5, 2020
Force unwrap is for example purposes only