Pattern Matching String Split $ - scala

Question

Hello currently I have the following string:
"STRING$INTEGER$STRING$STRING"
How can I pattern match that in scala?
Currently I know that I can use .split, but that produces a Array[String] my regex is flawed I could match everything against (.*) but that will handle the second as a String but it's an int, is there a way to have
data match {}

Answer 1

You can indead use a regex, but everything you match will be a String.
val format = """(\w+)\$(\d+)\$(\w+)\$(\w+)""".r
"hello$5$foo$bar" match {
case format(s1, i, s2, s3) => // i is a String
val n = i.toInt
}
You could also create an extractor which could use the regex above or split.
object Format {
def unapply(string: String) = string.split("""\$""") match {
case Array(s1, i, s2, s3) =>
Try(i.toInt).toOption.map(i => (s1, i, s2, s3))
}
}
"hello$5$foo$bar" match {
case Format(s1, i, s2, s3) => i + 5 // i is an Int
}
// Int = 10

Answer 2

Your question is plenty unclear, but I guess you might need something like this?
val string = "STRING$INTEGER$STRING$STRING"
val regex = """(\w+)\$(\w+)\$(\w+)\$(\w+)""".r
string match {
case regex(s1, i, s2, s3) =>
s"$s1, $i, $s2, $s3"
case _ =>
"error"
}
|> res0: String = STRING, INTEGER, STRING, STRING

Answer 3

To separate a string val s = "abc$123$foo$bar" by $ consider
val xs = s.split("\\$")
xs: Array[String] = Array(abc, 123, foo, bar)
To collect all the integer values in the resulting array consider for instance
xs.flatMap( s => scala.util.Try(s.toInt).toOption )
res: Array[Int] = Array(123)
were we try to convert each string into an integer value; in case of failure it delivers a None which is flattened out.