Write a simulation of a funny game with a dice in MATLAB - matlab

Question

I am trying to write a code that simulates the following game:
Roll two dice and let x be the sum of them. If x=7 or x=11 then you win. Otherwise roll both dice again until you get x (in which case you win) or 7 or 11 (in which case you loose).
Imagine you have a two dice, then if in the first roll you get as the sum of both 7 or 11, you win, if not, then the sum could be other number, let's say 9, then you have to continue rollin both dice until you get again 9, if in that process you get 7 or 11 agiain you loose :)
Then I wrote the following code:
d1=floor(6*rand)+1;
d2=floor(6*rand)+1;
x=d1+d2;
while x~=7 & x~=11
d1=floor(6*rand)+1;
d2=floor(6*rand)+1;
x=d1+d2;
if x==x
disp('You win')
elseif x==7 | x==11
disp('You loose')
end
end
But it displays indefinitely the sentence "you win" and can't stop it, I know that this is because the condition "x==x" always evaluates true, but how can I fix that to have the simulation?
Thanks a lot in advance

Answer 1

Do you want to do re-rolls until you win? In that case you want to do the re-roll in your while-loop. Checking the same number over and over again is not going to be useful.
x=0;
wins=[7 11];
while min(x~=wins)
d1=floor(6*rand)+1;
d2=floor(6*rand)+1;
x=d1+d2
if max(x==wins)
disp('You win')
else
disp('You loose')
end
end

Answer 2

This should work:
x=0;
while x~=7 | x~=11
d1=floor(6*rand)+1;
d2=floor(6*rand)+1;
x=d1+d2;
if x==7 | x==11
disp(x)
disp('You win')
break
else
disp(x)
disp('You loose')
a = input('You want roll again (y/n)? ','s')
if strcmpi(a,'y')
else
break
end
end
end

Answer 3

added more of a game vibe to it, also added comments so you understand what I am doing
win1 = 7; %these values give you a win
win2 = 11;
lose1 = 0; %can't lose on first roll. this will be set later
lose2 = 0;
streak = 0;
%while game is still going on..
while true
newgame = input('Would you like to start a new game? Type YES or NO --> ','s'); %user inputs string
if strcmpi(newgame,'YES') %did user type YES?
game = true; % set games state to true to begin the game loop
firstroll=true; %first roll coming up
elseif strcmpi(newgame,'NO')
break; % end program by exiting outer loop
else %user didn't enter correctly so re-ask
continue;
end
while game
input('Press enter to roll dice'); %roll the dice
d1 = floor(6*rand)+1;
d2 = floor(6*rand)+1;
disp('You rolled:'); %display the dice
disp(d1);
disp(d2);
x=d1+d2;
if x==win1 || x==win2 % check for a win
streak=streak+1; %%add a win to your total
disp('WINNER!')
elseif x==lose1 || x==lose2
disp('YOU LOST!')
disp('streak:') %show how many games you won
disp(streak)
game = false; % end game state because you lost
%reset winning and losing numbers
win1=7;
win2=11;
lose1=0;
lose2=0;
streak = 0; %reset streak
elseif firstroll %ok, didn't win on the FIRST ROLL so lets set the NEW winning value and reroll
win1 = x; % we win if we roll the same value again
win2 = x;
lose1 = 7; % we lose if we roll a 7 or 11
lose2 = 11;
firstroll = false; % set firstroll false so it doesn't keep resetting the winning and losing values
continue;
end
end
end
disp('Thanks for playing!')

Answer 4

Because you change the rule after the first round, you specify the rule of the first round with an if statement and the rest of the game in the else statement. Moreover, you need to specify the value X in your code. Here I use 5 as an example. If there is no result after the first round, you role the dice again with the code d1=floor(6*rand)+1; d2=floor(6*rand)+1; x=d1+d2;, then determine whether you win or lose. If there is still no result, you will use a while loop to keep this going until there is a win or lose situation.
d1=floor(6*rand)+1;
d2=floor(6*rand)+1;
x=d1+d2;
first_sum = x % use another variable first_sum to hold the status of first roll
if x==7 || x==11
disp('You win')
else
d1=floor(6*rand)+1;
d2=floor(6*rand)+1;
x=d1+d2;
if x== 7 || x==11
disp('You lose')
elseif x == first_sum
disp('You win')
else
while x ~= first_sum && x~=11 && x~=7
d1=floor(6*rand)+1;
d2=floor(6*rand)+1;
x=d1+d2;
if x== 7 || x==11
disp('You lose')
elseif x == first_sum
disp('You win')
end
end
end
end
Or you can write this in a more succinct way. Since the else statement contains a structure like a do while loop(meaning do at least once and keep doing it if a certain condition is met), you can also code it like this :
d1=floor(6*rand)+1;
d2=floor(6*rand)+1;
x=d1+d2;
first_sum = x
if x==7 || x==11
disp('You win')
else
flag = true
while flag % The while loop will keep going until flag is set to false.
d1=floor(6*rand)+1;
d2=floor(6*rand)+1;
x=d1+d2;
if x== 7 || x==11
disp('You lose')
flag = false % If a result is reached, stop the while loop
elseif x == first_sum
disp('You win')
flag = false
end
end
end

Answer 5

d1=floor(6*rand)+1;
d2=floor(6*rand)+1;
x=d1+d2;
kk=1;
while x~=7 && x~=11
d1=floor(6*rand)+1;
d2=floor(6*rand)+1;
if kk ==1
tmp = d1+d2;
end
x=d1+d2;
if x==7 || x==11 && kk == 1
disp('You win')
elseif x==7 || x==11 && kk > 1
disp('You loose')
elseif x==tmp && kk>1
disp('You win')
else
disp('You loose')
end
kk = kk+1;
end
What is happening is that I introduced kk, which can be considered and iteration counter. Add that as an extra condition upon the winning condition. if statements then contain all the conditions you set, note that if kk==1 I save the sum in tmp, against which I check the second win condition.
Test run:
You loose
You loose
You loose
You win