I have to take quite a few steps before I get into the file I need to be, which is why I'm trying to set up an alias in my terminal, that gets me to the file by running that alias.
The following steps are needed to arrive where I have to be:
cd Sites
vagrant ssh
cd /var/www/miniportal.billetten.dk/logs/
sudo -s
cd /etc/apache2/sites-available/
nano 25-av_miniportal.conf
Edit line 33 in that file (I guess it's possible to jump to that line)
I tried setting up an alias like this, but the problem is that it stops running the rest of the command after I SSH'd into Vagrant. if I manually exit Vagrant, it continues the command (and of course returns an error, because there is no such folder).
The question is: How do I make sure that everything from step 3 is executed AFTER step 2 is done logging in through SSH?
My ultimate goal is to set up an Apple Automator program that lets me put in a value that gets entered on line 33, but I'm fine with just an alias for now.
I know I asked this question a long time ago, but in the meantime I found a solution and forgot I had posted this question.
My alias in my .zshrc-file looks like this:
alias changeCust='ssh -t root#192.168.56.101 "nano +32 /etc/apache2/sites-enabled/25-av_miniportal.conf && service apache2 reload"'
In other words, it SSHs into vagrant as root (it asks for my password), nanos into a file on line 32 (or whatever line you need), then, when the file is saved, it reloads apache2 and the changes are applied.
Just use the below one and change the values.
alias AliasName='ssh -t root#your.ip.addres.here "nano +lineNumber /path/to/file"'
Related
I've been banging my head against a powershell shaped wall all day. For work reasons, I want to be able to upload a file from a windows machine to a remote linux box. There's some work to do before so I foolishly believed I could just drop in a call to SCP in my script. But it doesn't like it one bit:
Putting
scp api.zip ${user}#${currEnv}:/${uploadLocation}
where user is the remote login name, currEnv is the ip address and uploadLocation is /tmp (at least while I'm debugging)
in the code just causes the execution to hang completely - in fact the same thing happens if I run that command from the PS command line, even if I manually replace all the variables.
I tried replacing it with pscp which works better in that it actually connects, but then throws up the usual warning about this being the first time I've connected and should type 'y' to proceed (again, even from the command line iteself) - but that won't let me type anything in. I've also even tried using wsl scp ... to run it (don't tell the IT guy), but that also seems to hang - it shows me the server banner, but never gets to the bit where it should be asking for my remote password.
Am I missing something?
I am currently working in a remote environment which has a user with certain sudo permissions for which it does not require inputting any password.
Specifically it can perform some nginx commands without the need of a password, so far so good. The problem I face comes when I have a python script that takes care of checking for updates and if there are changes tries to reload nginx. As seen below
Popen(['sudo', 'nginx', '-T'], stdin=PIPE, stdout=PIPE, stderr=PIPE)
call(["sudo", "systemctl", "reload", "nginx.service"])
When the script reaches one of this steps a prompt pops up on the terminal asking for a password, which should not be necessary since the user running the script has the permissions to run the commands without inputting it.
Question: Is there maybe a way, without hardcoding the password in a variable, to tell the script to "inherit" the permissions of the user when I run it?
Some additional information:
If the script itself is invoked with sudo everything works, but sadly this is not an option and sudo should be used only for the specific parts that completely require it (nginx reloads)
Python version is 3.5
EDIT: Solved this thanks to a friend:
The solution was to add the 'shell=True' paramater to the Popen.
Popen('sudo nginx -T'], shell=True, stdin=PIPE, stdout=PIPE, stderr=PIPE)
The issue might be, that there is a mismatch in the sudoers nginx-path and the PATH variable used during script execution.
Try to either match the Popen call to the full PATH given in the sudoers file or adjust the PATH in the shell calling the Python script.
I'm trying to make a simple file so I can call it in SSH and it will start my minecraft server.
I tried making a batch file called start.bat with this code:
java -Xmx512M -Xmx512M -jar craftbukkit-1.2.5-R1.0.jar nogui
However, when I run it in SSH:
$ cd /Minecraft/server_1/
$ start.bat
The SSH returns that it is an invalid or unknown command. Is there any other way I can make a quick command/file to start my server? What file extensions would I use to get this working? It works if I paste that java command in SSH and run it, but I'd rather have a file.
The current working directory is not included in your PATH by default because it is a security risk on multiuser systems. (And a potential annoyance even on machines that are single user.) You would use ./start.bat to start the program.
Since you're using Windows naming conventions, I presume you also forgot to set the execution mode bit -- and you probably also forgot the shebang line at the top of the file.
Try this:
#!/bin/sh
java -Xmx512M -Xmx512M -jar craftbukkit-1.2.5-R1.0.jar nogui
Run chmod 500 on this file. (Strictly speaking, 555 could also work, if you didn't mind other people on the machine executing the file. But they don't need to, so don't let them.) See the chmod(1) manpage for more details on the modes -- 1 bits mean executable, 2 bits means writable, and 4 bits means readable -- thus, 5 is executable and readable.
Then, when you want to run the script, run it like this:
cd /Minecraft/server_1
./start.bat
Note the ./ -- that means the shell should start the search for the executable program in the current working directory. (It could be ./bin/start.bat if your current working directory had a bin subdirectory with a start.bat executable file.)
Is start.bat executable? Make sure you have #!/bin/sh as the first line of the file. Also the directory is probably not in in the path, so try this:
$ chmod 555 start.bat
$ ./start.bat
I am using a vpn service from certain server. I was given with a root account, and when I connect with a root account, the command line looks like below.
root#xa9g82:/etc/#
Then I used useradd to add an account called 'temp'
When I connected to the server with temp, then the command line only has a single character.
$
The user information is not shown, neither the path. Also, note that, in root's command line I can use tab to automatically complete the filename, however 'temp's command line inserts tab space, when I press tab. It is very inconvenient.
I am using Ubuntu 10.04. How can I resolve this issue?
I usually edit ~/.bashrc. Being root, you might want to change the system-wide preferences, at /etc/bash.bashrc. Personally, I changed some lines in ~/.bashrc to look like:-
# If this is an xterm set the title to user#host:dir
case "$TERM" in
xterm*|rxvt*)
## PS1="\[\e]0;${debian_chroot:+($debian_chroot)}\u#\h: \w\a\]$PS1" # default
PS1="\[\e]0;${debian_chroot:+($debian_chroot)}\h: \W\a\]$PS1" # How I like it
;;
*)
;;
esac
use prompt to set the prompt.... (man prompt...)
it depends on what shell you run each one has it's own tricks, but you can make it looks as you wish.
BASH
TCSH
It is likely that the default shell for root is set to /bin/sh, which does not provide many of the features that you may used to if you use a shell like bash. To check if this is the case, run the following command:
cat /etc/passwd | grep ^root
The last component of the line that this command outputs will be your shell (which, as stated previously, I'm guessing is /bin/sh). If this is not the shell you want (it probably isn't), then edit /etc/passwd (using nano or whatever editor you're most comfortable with) and change your shell to something more palatable, like /bin/bash. After doing this, you'll need to log out and then log back in.
Is it possible to have a Perl script run shell aliases? I am running into a situation where we've got a Perl module I don't have access to modify and one of the things it does is logs into multiple servers via SSH to run some commands remotely. Sadly some of the systems (which I also don't have access to modify) have a buggy SSH server that will disconnect as soon as my system tries to send an SSH public key. I have the SSH agent running because I need it to connect to some other servers.
My initial solution was to set up an alias to set ssh to ssh -o PubkeyAuthentication=no, but Perl runs the ssh binary it finds in the PATH instead of trying to use the alias.
It looks like the only solutions are disable the SSH agent while I am connecting to the problem servers or override the Perl module that does the actual connection.
Perhaps you could put a command called ssh in PATH ahead of the ssh which runs ssh as you want it to be run.
Alter the PATH before you run the perl script, or use this in your .ssh/config
Host *
PubkeyAuthentication no
Why don't you skip the alias and just create a shell script called ssh in a directory somewhere, then change the path to put that directory before the one containing the real ssh?
I had to do this recently with iostat because the new version output a different format that a third-party product couldn't handle (it scanned the output to generate a report).
I just created an iostat shell script which called the real iostat (with hardcoded path, but you could be more sophisticated), passing the output through an awk script to massage it into the original format. Then, I changed the path for the third-party program and it started working fine.
You could declare a function in .bashrc (or .profile or whatever) with that name. It could look like this (might break):
function ssh {
/usr/bin/ssh -o PubkeyAuthentication=no "$#"
}
But using a config file might be the best solution in your case.