I got 3 lists with grades ranging from 0-100 represting 3 different tests.
each list has an equal number of indxes (represting participates).
For example- the 1st indexes in the lists- list1,list2 and list3, are the grades of the first particiapte in the 3 different tests.
I need to make a new group (named group1) that select evey 3rd participate, starting from the first, and than calculate the avarage of this group scores.
i'll appriciate any help!!
Hopefully instead of three 'lists' you are actually using a 3 column matrix for this? e.g.
testScores = [20 48 13;
85 90 93;
54 50 56;
76 80 45
...]
From here it is trivial to select every third participant:
testScores(1:3:end, :)
and then to find the mean:
mean(testScores(1:3:end,:),2)
Related
To be generic the issue is: I need to create group means that exclude own group observations before calculating the mean.
As an example: let's say I have firms, products and product characteristics. Each firm (f=1,...,F) produces several products (i=1,...,I). I would like to create a group mean for a certain characteristic of the product i of firm f, using all products of all firms, excluding firm f product observations.
So I could have a dataset like this:
firm prod width
1 1 30
1 2 10
1 3 20
2 1 25
2 2 15
2 4 40
3 2 10
3 4 35
To reproduce the table:
firm=[1,1,1,2,2,2,3,3]
prod=[1,2,3,1,2,4,2,4]
hp=[30,10,20,25,15,40,10,35]
x=[firm' prod' hp']
Then I want to estimate a mean which will use values of all products of all other firms, that is excluding all firm 1 products. In this case, my grouping is at the firm level. (This mean is to be used as an instrumental variable for the width of all products in firm 1.)
So, the mean that I should find is: (25+15+40+10+35)/5=25
Then repeat the process for other firms.
firm prod width mean_desired
1 1 30 25
1 2 10 25
1 3 20 25
2 1 25
2 2 15
2 4 40
3 2 10
3 4 35
I guess my biggest difficulty is to exclude the own firm values.
This question is related to this page here: Calculating group mean/medians in MATLAB where group ID is in a separate column. But here, we do not exclude the own group.
p.s.: just out of curiosity if anyone works in economics, I am actually trying to construct Hausman or BLP instruments.
Here's a way that avoids loops, but may be memory-expensive. Let x denote your three-column data matrix.
m = bsxfun(#ne, x(:,1).', unique(x(:,1))); % or m = ~sparse(x(:,1), 1:size(x,1), true);
result = m*x(:,3);
result = result./sum(m,2);
This creates a zero-one matrix m such that each row of m multiplied by the width column of x (second line of code) gives the sum of other groups. m is built by comparing each entry in the firm column of x with the unique values of that column (first line). Then, dividing by the respective count of other groups (third line) gives the desired result.
If you need the results repeated as per the original firm column, use result(x(:,1))
In jasper i have one requirement like, sum all the data of the column based on another column. I know how to show sum of all the data in the column. But please suggest me for this requirement.
Emp-Category Emp-Id Salary
---------------------------------------
Cate - A 1 128
2 50
3 89
total 267
Cate - B 4 123
5 50
6 100
total 273
Total Expenses 540
So there will be many number of categories, which will be getting from database.
Please suggest me how to do this approach.
In that case, you can use groups...
You can refer to the link below for tutorial :)
http://www.tutorialspoint.com/jasper_reports/jasper_report_groups.htm
Still new to the programing game but I need a little help! I'm not exactly sure how to describe what I want to do but I'll give it my best shot. I have a set of numbers produced by an algorithm I've put together. e.g. :
....
10 10 10
11 11 11
12 1 2
13 3 4
14 12 13
15 6 7
16 5 15
17 8 9
....
Essentially what I want to do is assign these index numbers to groups. Lets say I start with the number 14 in the first column. It is going to belong to group 1, so I label it in a new column in row 14 "1" for group one. The second and the third column show other index numbers that are grouped with the index 14. So I use a code like:
FindLHS = find(matrix(:,1)==matrix(14,2));
and
FindRHS = find(matrix(:,1)==matrix(14,3));
so clearly this will produce the results of
FindLHS = 12
FindRHS = 13
I will then proceed to label both 12 and 13 as belonging to group "1" as I did for 14
now my problem is I want to do this same procedure for both 12 and 13 of finding and labelling the indexs for 12 and 13 being (1,2) and (3,4). Is there a way to repeat that code for both idx of 1,2,3 and 4? because the real dataset has over 5000 data points in it...
Do you understand what I mean?
Thanks
James
All you really want to do is find wherever matrix(:,1) contains one of the numbers you've already found, include the numbers in the second and third columns into your group list (presuming they aren't already there), and stop when that list stops growing, right? This may not be the most efficient way of doing it but it gives you the basic idea:
while ~(numel(oldnum)==numel(num))
oldnum = num;
idx = ismember(matrix(:,1),oldnum)
num = unique(matrix(idx,:))
end
Output:
num =
1
2
3
4
12
13
14
Now if your first column is literally just your numbers 1 through 5000 in order, you don't need to even find the index, you can just use your number list directly.
To do this for multiple groups you would just need an outer loop that stores the information for each group, then picks out the next unused number. I'm presuming that your individual groups are consistent so that no matter which of those numbers you pick you end up with the same result - e.g. starting at 2 or 14 gives you the same result (if not, it becomes more complex).
I'm just beginning with Report Builder and I am trying to get an average of the value of one field if another field equals a number.
Example:
A table that contains a series of book reviews by different reviewers identified by number:
Reviewer Score
1 95
2 85
3 77
3 99
1 87
What I want is to get a reviewer's overall average score. So i would like to get an average of all scores filtering out the other reviewers.
I have been at this for a couple hours now and I don't think I am even close...
=Avg(iif(reviewer="1",score,Nothing))
I have used this successfully in my report.
Suppose I have an array age=[16 17 25 18 32 89 43 55] which holds the ages of a certain list of people. I also have a second array called groups=[1 1 2 1 3 2 1 4] denotes to which group each person belongs, i.e the person whose age is 55 is the only person in group 4, there are three people in group 1 etc.
I want to calculate the combined sum of ages in each group. That is, the result I want to get in this case is an array of 4 elements, it's first entry containing the sum of ages of people belonging to group #1 (16+17+18+43), second entry containing the sum of ages of people belonging to group #2 (23+89) etc.
I know of course how to do this with a for loop, but is it possible to do this using some variation of sum or something similar, so as to tap into matlab's vector optimization?
The code in #Ismail's answer is fine, but you could also try this:
>> accumarray(groups', age')
ans =
94
114
32
55
I find it hard to get an appreciation from the documentation exactly what accumarray can do in its full generality, but this is a great example of a simple usage. It's worth learning how to use it effectively, as once you've worked it out it's very powerful - and it will be a lot faster (when used on a larger example) than arrayfun.
You can use arrayfun and unique as follows:
arrayfun(#(x) sum(age(groups==x)), unique(groups))