I seem to be struggling to find the right way of deleting a document. I.e. should I be using remove() or delete_one() for example and also what is the canonical method of deleting by id, which is a string.
I.e. should I be using the following:
mongo.db.xxx.delete_one({'_id': { "$oid" : str(_id) } })
or can I use another format?
mongo.db.xxx.remove({'_id': { "$oid" : str(_id) } })
mongo.db.xxx.remove({'_id': ObjectId(_id) })
What is the canonical form?
remove is deprecated in the 3.x release of pymongo, so the current canonical form would be to use delete_one:
from bson.objectid import ObjectId
result = mongo.db.xxx.delete_one({'_id': ObjectId(_id)})
The call returns a DeleteResult in which you can inspect the deleted_count field to see if it found a document to delete
You can simply do:
result = mongo.db.xxx.delete_one({})
Related
I have a document like below:
"application" : "test",
"QA1" : {
"url" : "https://google.co.in",
"db" : {
"userName" : "user",
"password" : "pswd"
}
}
I want to retrieve the value "https://google.co.in" by calling the key "url".
While using the below shell command, I am able to retrieve the value as expected.
db.getCollection('Application_Data').findOne({"application":"test"}).QA1.url
But when I convert it to java code, it is throwing me null pointer exception:
cursor = collection.find(Filters.eq("application","test")).iterator();
while (cursor.hasNext()) {
value=cursor.next().get("QA1.url").toString();
break;
}
I also tried with projection like below to get the required values:
cursor = collection.find(Filters.and(Filters.eq("application","test"))).projection(Projections.fields(Projections.include("QA1.url"),Projections.excludeId())).iterator();
while (cursor.hasNext()) {
System.out.println(cursor.next().get("QA1").toString());
}
This is giving me the output as below:
Document{{url=https://google.co.in}}
It is still not giving me the exact value. Appreciate your help on this.
Mongodb Documents are nested. So say, in your example, when you do cursor.next().get("QA1"), you get the Document under "QA1" property.
So the way to achieve what you want is
cursor.next().get("QA1").get("url"). That, with proper error handling (think exceptions).
A better way to do what you want is to use a mapper like spring-data-mongodb that would map the JSON response of mongodb into a java object for you automatically.
You need to use the Document class's getEmbedded method to extract the nested field's value.
while (cursor.hasNext()) {
Document doc = cursor.next();
System.out.println(doc.toJson());
String urlValue = doc.getEmbedded(Arrays.asList("QA1","url"), String.class);
System.out.println(urlValue); // output below
}
The result is as expected - a string: https://google.co.in
suppose I have the following datastructure:
var user = {_id: 'foo', age: 35};
var post = {_id: '...', author: {$ref: user, $id: 'foo'},...};
How can I query all posts which references user[foo]? I tried the following but not work:
db.post.find('author._id': 'foo');
var u = db.user.find({_id: 'foo'});
db.post.find('author': u);
neither can I find the answer from the official document and google!
Anyone has any idea?
Got it:
db.post.find({'author.$id': 'foo'})
This db.post.find('author.$id': 'foo') has missing the {}, so the correct sentence is:
db.post.find({'author.$id': 'foo'})
Also this can be achieved with:
db.post.find({'author': DBRef("user", ObjectId('foo'))})
But is more compact and practical the first way.
You can use the .$id reference but it will ignore any indexes on those fields.
I would suggest ignoring that method unless you are querying it directly via the terminal or want to look up something quickly. In using large collections you will want to index the field and query it using the below method.
If you want to use an index query using the following:
db.post.find('author' : { "$ref" : 'user', "$id" : 'foo' , "$db" :'database_name' })
If foo is an object id
db.post.find('author' : { "$ref" : 'user', "$id" : ObjectId('foo') , "$db" :'database_name' })
You can create an index on author by
db.post.ensureIndex( {'author' : 1 } );
For anyone looking for a Java solution to this then if you are using mongojack its really easy:
collection.find(DBQuery.is("user", new DBRef(user.getId(), User.class)));
Where collection is a JacksonDBCollection.
In mongoengine you should just use the instance of the referenced object. It should have the ID set.
Suppose the author is the Author document instance. So using this:
Post.objects(author__eq=author)
you can go through all posts of this author.
Post.author should be defined as ReferenceField
Using Mongo 2.4.1 version
This is how you do it on command line for OLA collection where #DBRef dbrefName
db.OLA.find({"dbrefName.someFieldValue" : "Personal"});
Exact query
db.OLA.find({"dbrefName.$id" : ObjectId("1234")});
I've found this question answered for C# and Perl, but not in the native interface. I thought this would work:
db.theColl.find( { _id: ObjectId("4ecbe7f9e8c1c9092c000027") } )
The query returned no results. I found the 4ecbe7f9e8c1c9092c000027 by doing db.theColl.find() and grabbing an ObjectId. There are several thousand objects in that collection.
I've read all the pages that I could find on the mongodb.org website and didn't find it. Is this just a strange thing to do? It seems pretty normal to me.
Not strange at all, people do this all the time. Make sure the collection name is correct (case matters) and that the ObjectId is exact.
Documentation is here
> db.test.insert({x: 1})
> db.test.find() // no criteria
{ "_id" : ObjectId("4ecc05e55dd98a436ddcc47c"), "x" : 1 }
> db.test.find({"_id" : ObjectId("4ecc05e55dd98a436ddcc47c")}) // explicit
{ "_id" : ObjectId("4ecc05e55dd98a436ddcc47c"), "x" : 1 }
> db.test.find(ObjectId("4ecc05e55dd98a436ddcc47c")) // shortcut
{ "_id" : ObjectId("4ecc05e55dd98a436ddcc47c"), "x" : 1 }
If you're using Node.js:
var ObjectId = require('mongodb').ObjectId;
var id = req.params.gonderi_id;
var o_id = new ObjectId(id);
db.test.find({_id:o_id})
Edit: corrected to new ObjectId(id), not new ObjectID(id)
Even easier, especially with tab completion:
db.test.find(ObjectId('4ecc05e55dd98a436ddcc47c'))
Edit: also works with the findOne command for prettier output.
You Have missed to insert Double Quotes.
The Exact Query is
db.theColl.find( { "_id": ObjectId("4ecbe7f9e8c1c9092c000027") } )
If you are working on the mongo shell, Please refer this : Answer from Tyler Brock
I wrote the answer if you are using mongodb using node.js
You don't need to convert the id into an ObjectId. Just use :
db.collection.findById('4ecbe7f9e8c1c9092c000027');
this collection method will automatically convert id into ObjectId.
On the other hand :
db.collection.findOne({"_id":'4ecbe7f9e8c1c9092c000027'}) doesn't work as expected. You've manually convert id into ObjectId.
That can be done like this :
let id = '58c85d1b7932a14c7a0a320d';
let o_id = new ObjectId(id); // id as a string is passed
db.collection.findOne({"_id":o_id});
I think you better write something like this:
db.getCollection('Blog').find({"_id":ObjectId("58f6724e97990e9de4f17c23")})
Once you opened the mongo CLI, connected and authorized on the right database.
The following example shows how to find the document with the _id=568c28fffc4be30d44d0398e from a collection called “products”:
db.products.find({"_id": ObjectId("568c28fffc4be30d44d0398e")})
I just had this issue and was doing exactly as was documented and it still was not working.
Look at your error message and make sure you do not have any special characters copied in. I was getting the error
SyntaxError: illegal character #(shell):1:43
When I went to character 43 it was just the start of my object ID, after the open quotes, exactly as I pasted it in. I put my cursor there and hit backspace nothing appeared to happen when it should have removed the open quote. I hit backspace again and it removed the open quote, then I put the quote back in and executed the query and it worked, despite looking exactly the same.
I was doing development in WebMatrix and copied the object id from the console. Whenever you copy from the console in WebMatrix you're likely to pick up some invisible characters that will cause errors.
In MongoDB Stitch functions it can be done using BSON like below:
Use the ObjectId helper in the BSON utility package for this purpose like in the follwing example:
var id = "5bb9e9f84186b222c8901149";
BSON.ObjectId(id);
For Pythonists:
import pymongo
from bson.objectid import ObjectId
...
for row in collectionName.find(
{"_id" : ObjectId("63ae807ec4270c7a0b0f2c4f")}):
print(row)
To use Objectid method you don't need to import it. It is already on the mongodb object.
var ObjectId = new db.ObjectId('58c85d1b7932a14c7a0a320d');
db.yourCollection.findOne({ _id: ObjectId }, function (err, info) {
console.log(info)
});
Simply do:
db.getCollection('test').find('4ecbe7f9e8c1c9092c000027');
I am new to MongoDB. I have a collection called person. I'm trying to get all the records without an _id field with this query:
db.person.find({}{_id:0})
but the error is
syntax error: unexpected {
but if i write
db.person.find()
it works perfectly.
Consider following documents inserted in person collection as
db.person.insert({"name":"abc"})
db.person.insert({"name":"xyz"}
If you want to find exact matching then use query as
db.person.find({"name":"abc"})
this return only matched name documents
If you want all names without _id then use projeciton id query as
db.person.find({},{"_id":0})
which return
{ "name" : "abc" }
{ "name" : "xyz" }
According to Mongodb manual you have little wrong syntax, you forgot to give comma after {}
Try this :
db.person.find({}, { _id: 0 } )
I have recently changed one of my fields from object to array of objects.
In my production I have only 14 documents with this field, so I decided to change those fields.
Is there any best practices to do that?
As it is in my production I need to do it in a best way possible?
I got the document Id's of those collections.like ['xxx','yyy','zzz',...........]
my doc structure is like
_id:"xxx",option1:{"op1":"value1","op2":"value2"},option2:"some value"
and I want to change it like(converting object to array of objects)
_id:"xxx",option1:[{"op1":"value1","op2":"value2"},
{"op1":"value1","op2":"value2"}
],option2:"some value"
Can I use upsert? If so How to do it?
Since you need to create the new value of the field based on the old value, you should retrieve each document with a query like
db.collection.find({ "_id" : { "in" : [<array of _id's>] } })
then iterate over the results and $set the value of the field to its new value:
db.collection.find({ "_id" : { "in" : [<array of _id's>] } }).forEach(function(doc) {
oldVal = doc.option1
newVal = compute_newVal_from_oldVal(oldVal)
db.collection.update({ "_id" : doc._id }, { "$set" : { "option" : newVal } })
})
The document structure is rather schematic, so I omitted putting in actual code to create newVal from oldVal.
Since it is an embedded document type you could use push query
db.collectionname.update({_id:"xxx"},{$push:{option1:{"op1":"value1","op2":"value2"}}})
This will create document inside embedded document.Hope it helps