Elegant Handling of Scala Future[Either]] - scala

Question

I have a type whose shape is like this:
val myType: Future[Either[MyError, TypeA]] = // some value
I know that I could pattern match on this and get to the Right or Left type, but the problem is that I would have to nest my pattern matching logic. I'm looking for much more elegant way of handling this? Any suggestions?

Answer 1

If you encode your MyError as an exception, you don't need the Either anymore and can simply patternMatch against the completion, or use a recoverWith to map it to another type:
myType.onComplete {
case Success(t) =>
case Failure(e) =>
}
To map your existing Either types you could do something like this:
case class MyException(e: MyError) extends Exception
def eitherToException[A](f: Future[Either[MyError,A]]): Future[A] = {
f.flatMap {
case Left(e) => Future.failed(MyException(e))
case Right(x) => Future.successful(x)
}
}
val myType2 = eitherToException(myType)
Alternatively, if MyError and TypeA are under your control, you could create a common super type and pattern match against that:
sealed trait MyResult
final case class MyError() extends MyResult
final case class TypeA() extends MyResult
myType.map {
case MyError() => ...
case TypeA() => ...
}

Answer 2

You can create custom extractor objects:
object FullSuccess {
def unapply[T](x: Try[Either[MyError, T]]) = x match {
case Success(Right(x)) => Some(x)
case _ => None
}
}
object PartSuccess {
def unapply[T](x: Try[Either[MyError, T]]) = x match {
case Success(Left(err)) => Some(err)
case _ => None
}
}
And
val myType: Future[Either[MyError, TypeA]] = // some value
myType.onComplete {
case FullSuccess(x) => ... // equivalent to case Success(Right(x))
case PartSuccess(x) => ... // equivalent to case Success(Left(x))
case Failure(e) => ...
}