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I have to read video frames one by one from image and store each frame in an array which I can further use. I guess there must be some loop which can do this work.
I am using:
video=VideoReader('sample.avi')
frm = read(video) % to get frame
but MATLAB gives error on read command and close automatically as shown in the attached image:
.
Can anyone help me please?
From the documentation:
v = VideoReader('xylophone.mp4');
while hasFrame(v)
video = readFrame(v);
end
or from the documentation of VideoReader.read
video = read(v,[1 Inf]);
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I want to define a vector y=[sin(1),sin(1/2),...,sin(1/1000)].
but I don't know how to do that. I defined
for i=1:1000
y(i)=sin(1/i);
end
but this does not work.
Just define the y as the following (and initialize to get the better performance):
y = zeros(1, 1000);
for i = 1:1000
y(i) = sin(1/i);
end
Also you can do it without for:
y = sin(1./(1:1000));
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I write this code but have error "Undefined function 'readframe' for input arguments of type 'VideoReader'"
How to I will solve? thank you.
v = VideoReader('filename.avi');
video = readframe(v,1);
figVid = figure();
axeVid = axes('Parent', figVid);
image(video, 'Parent', axeVid);
Actual Answer: The function is readFrame() not readframe().
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I watched a video titled "Writing a matlab program" and tried to use the syntax exactly, yet I still can't see how I've made an error...can you please help?
My code is simply
x= [-10:0.1:10];
y=2x^2-x + 1;
plot (x,y)
I'm getting a parse error at x and I have no idea what that means..
Matlab cannot parse 2x. Multiplication requires the * symbol. Either * or .* will work in this case.
Your next problem will be the use of ^ instead of .^ —this time you're going to have to include the dot. Google for "elementwise" operators in matlab to understand what difference the dot makes.
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I have tried the code from the link Ear Image Processing - Finding the point of intersection of line and curve in MATLAB
but seem to get an error as dist2s is undefined on matlab R2013a.Can anyone help me out
That's because you need to create the function (isn't defined by MatLab itself). Try saving this code in a file called dist2s.m and then setting the folder where it's located like current folder:
function out = dist2s(pt1,pt2)
out = NaN(size(pt1,1),size(pt2,1));
for m = 1:size(pt1,1)
for n = 1:size(pt2,1)
if(m~=n)
out(m,n) = sqrt( (pt1(m,1)-pt2(n,1)).^2 + (pt1(m,2)-pt2(n,2)).^2 );
end
end
end
return;
The code is provided in the same answer you refer to.
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When I am trying to use linspace in MATLAB I am getting the above error. How do I resolve it?
I am using linspace in a very simple statement:
t= linspace(0,8760,876);
Why don't you try to check internal matlab path? If you get that error is because Matlab cannot find the definition of the function. Thought it is weird as it is a basic function.
It's probably a path issue. Run restoredefaultpath.