sed -i 's/$/\'/g'
sed -i "s/$/\'/g"
How to escape both $ and ' by 1 command?
This might work for you (GNU sed):
sed 's/$/'\''/' file
Adds a single quote to the end of a line.
sed 's/\$/'\''/' file
Replaces a $ by a single quote.
sed 's/\$$/'\''/' file
Replaces a $ at the end of line by a single quote.
N.B. Surrounding sed commands by double quotes is fine for some interpolation but may return unexpected results.
Use octal values
sed 's/$/\o47/'
Care to use backslash + letter o minus + octal number 1 to 3 digit
Just don't use single quotes to start the sed script?
sed "s/$/'/"
The /g at the end means to apply everywhere it's found on each stream (line) - you don't need this since $ is a special character indicating end of stream.
To add a quote at the end of a line use
sed -i "s/$/'/g" file
sed -i 's/$/'"'"'/g' file
See proof.
If there are already single quotes, and you want to make sure there is single occurrence at the end of string use
sed -i "s/'*$/'/g" file
sed -i 's/'"'*"'$/'"'"'/g' file
See this proof.
To escape $ and ' chars use
sed -i "s/[\$']/\\\\&/g" file
See proof
[\$'] - matches $ (escaped as in double quotes it can be treated as a variable interpolation char) or '
\\\\& - a backslash (need 4, that is literal 2 backslashes, it is special in the replacement), and & is the whole match.
I'm using sed to replace some strings in some of my files. I'm trying to match a string like "namespace Foo\BarBundle\Tests\blah\blah" with this pattern:
^\\(namespace\|use\\)\s\*Foo\BarBundle\Tests\\(.\*\\)$
But it's not working. The Complete command goes as follows:
sed -i -e "s/$pattern/\1 Tests\\Foo\BarBundle\2/g" <file_name>
Where $pattern is the pattern stated above. (which is the output from echo $pattern).
I've ran it on multiple files to no avail. Is there something wrong with the first pattern?
Use 3 backslashes \\\ to specify a regular backsplash \:
pattern="^\(namespace\|use\)\s*Foo\\\BarBundle\\\Tests\(.*\)$"
sed -e "s/$pattern/\1 Tests\\\Foo\\\BarBundle\2/g" <file_name>
The first two \\ become one in the shell which then escape the third one \ in sed
You have to use 4 backslashes if you want to match a single backslash - both in standard input and in the script.
How to search a pattern and remove the line using sed which contains special characters like "ranasnfs2:/SA_kits/prod"
I tried using a variable to hold the complete string and then recall the variable in sed command but it is not working.
echo $a
ranasnfs2:/SA_kits/prod
sed -i '/"$a"/d' test.txt
cat test.txt | grep -i SA
/SA_kits -rw,suid,soft,retry=4 ranasnfs2:/SA_kits/prod
You need to escape the slash character.
Use this for deleting lines which contain a /:
sed '/\//d' file
This question already has answers here:
Using different delimiters in sed commands and range addresses
(3 answers)
Closed 1 year ago.
I have a Visual Studio project, which is developed locally. Code files have to be deployed to a remote server. The only problem is the URLs they contain, which are hard-coded.
The project contains URLs such as ?page=one. For the link to be valid on the server, it must be /page/one .
I've decided to replace all URLs in my code files with sed before deployment, but I'm stuck on slashes.
I know this is not a pretty solution, but it's simple and would save me a lot of time. The total number of strings I have to replace is fewer than 10. A total number of files which have to be checked is ~30.
An example describing my situation is below:
The command I'm using:
sed -f replace.txt < a.txt > b.txt
replace.txt which contains all the strings:
s/?page=one&/pageone/g
s/?page=two&/pagetwo/g
s/?page=three&/pagethree/g
a.txt:
?page=one&
?page=two&
?page=three&
Content of b.txt after I run my sed command:
pageone
pagetwo
pagethree
What I want b.txt to contain:
/page/one
/page/two
/page/three
The easiest way would be to use a different delimiter in your search/replace lines, e.g.:
s:?page=one&:pageone:g
You can use any character as a delimiter that's not part of either string. Or, you could escape it with a backslash:
s/\//foo/
Which would replace / with foo. You'd want to use the escaped backslash in cases where you don't know what characters might occur in the replacement strings (if they are shell variables, for example).
The s command can use any character as a delimiter; whatever character comes after the s is used. I was brought up to use a #. Like so:
s#?page=one&#/page/one#g
A very useful but lesser-known fact about sed is that the familiar s/foo/bar/ command can use any punctuation, not only slashes. A common alternative is s#foo#bar#, from which it becomes obvious how to solve your problem.
add \ before special characters:
s/\?page=one&/page\/one\//g
etc.
In a system I am developing, the string to be replaced by sed is input text from a user which is stored in a variable and passed to sed.
As noted earlier on this post, if the string contained within the sed command block contains the actual delimiter used by sed - then sed terminates on syntax error. Consider the following example:
This works:
$ VALUE=12345
$ echo "MyVar=%DEF_VALUE%" | sed -e s/%DEF_VALUE%/${VALUE}/g
MyVar=12345
This breaks:
$ VALUE=12345/6
$ echo "MyVar=%DEF_VALUE%" | sed -e s/%DEF_VALUE%/${VALUE}/g
sed: -e expression #1, char 21: unknown option to `s'
Replacing the default delimiter is not a robust solution in my case as I did not want to limit the user from entering specific characters used by sed as the delimiter (e.g. "/").
However, escaping any occurrences of the delimiter in the input string would solve the problem.
Consider the below solution of systematically escaping the delimiter character in the input string before having it parsed by sed.
Such escaping can be implemented as a replacement using sed itself, this replacement is safe even if the input string contains the delimiter - this is since the input string is not part of the sed command block:
$ VALUE=$(echo ${VALUE} | sed -e "s#/#\\\/#g")
$ echo "MyVar=%DEF_VALUE%" | sed -e s/%DEF_VALUE%/${VALUE}/g
MyVar=12345/6
I have converted this to a function to be used by various scripts:
escapeForwardSlashes() {
# Validate parameters
if [ -z "$1" ]
then
echo -e "Error - no parameter specified!"
return 1
fi
# Perform replacement
echo ${1} | sed -e "s#/#\\\/#g"
return 0
}
this line should work for your 3 examples:
sed -r 's#\?(page)=([^&]*)&#/\1/\2#g' a.txt
I used -r to save some escaping .
the line should be generic for your one, two three case. you don't have to do the sub 3 times
test with your example (a.txt):
kent$ echo "?page=one&
?page=two&
?page=three&"|sed -r 's#\?(page)=([^&]*)&#/\1/\2#g'
/page/one
/page/two
/page/three
replace.txt should be
s/?page=/\/page\//g
s/&//g
please see this article
http://netjunky.net/sed-replace-path-with-slash-separators/
Just using | instead of /
Great answer from Anonymous. \ solved my problem when I tried to escape quotes in HTML strings.
So if you use sed to return some HTML templates (on a server), use double backslash instead of single:
var htmlTemplate = "<div style=\\"color:green;\\"></div>";
A simplier alternative is using AWK as on this answer:
awk '$0="prefix"$0' file > new_file
You may use an alternative regex delimiter as a search pattern by backs lashing it:
sed '\,{some_path},d'
For the s command:
sed 's,{some_path},{other_path},'
I'm using CMD on Windows Xp to replace special text with Sed. I'm using this command for replace special characters like $ or * :
sed -i "s/\*/123/g;" 1.txt
the previous command does not work because i have \, " and other special strings that sed use to make regex. The escape character ^ doesn't work well because sed no give me error but nothing change inside files.
To change this text "{\*)(//123/$$ i try use this command:
sed -i "s£"^"{^\^*)(//123/^$^$"£xx£g;" 1.txt £ is the delimiter, xx is new text..but nothing change
How i want to turn text like this? sed -i^/\\*$/$[{" ;" 1.txt into xx
This might work for you:
echo '"{\*)(//123/$$' | sed "s/[\"][{][\\][*][)][(][/][/]123[/][$][$]/xx/"
xx