TSQL: Inserting missing records into table - tsql

I am stuck at this T-SQL query.
I have table below
Age SectioName Cost
---------------------
1 Section1 100
2 Section1 200
1 Section2 500
3 Section2 100
4 Section2 200
Lets say for each section I can have maximum 5 Age. In above table there are some missing Ages. How do I insert missing Ages for each section. (Possibly without using cursor). The cost would be zero for missing Ages
So after the insertion the table should look like
Age SectioName Cost
---------------------
1 Section1 100
2 Section1 200
3 Section1 0
4 Section1 0
5 Section1 0
1 Section2 500
2 Section2 0
3 Section2 100
4 Section2 200
5 Section2 0
EDIT1
I should have been more clear with my question. The maximum age is dynamic value. It could be 5,6,10 or someother value but it will be always less than 25.

I think I got it
;WITH tally AS
(
SELECT 1 AS r
UNION ALL
SELECT r + 1 AS r
FROM tally
WHERE r < 5 -- this value could be dynamic now
)
select n.r, t.SectionName, 0 as Cost
from (select distinct SectionName from TempFormsSectionValues) t
cross join
(select ta.r FROM tally ta) n
where not exists
(select * from TempFormsSectionValues where YearsAgo = n.r and SectionName = t.SectionName)
order by t.SectionName, n.r

You can use this query to select missing value:
select n.num, t.SectioName, 0 as Cost
from (select distinct SectioName from table1) t
cross join
(select 1 as num union select 2 union select 3 union select 4 union select 5) n
where not exists
(select * from table1 where table1.age = n.num and table1.SectioName = t.SectioName)
It creates a Cartesian product of sections and numbers 1 to 5 and then selects those that doesn't exist yet. You can then use this query for the source of insert into your table.
SQL Fiddle (it has order by added to check the results easier but it's not necessary for inserting).

Use below query to generate missing rows
SELECT t1.Age,t1.Section,ISNULL(t2.Cost,0) as Cost
FROM
(
SELECT 1 as Age,'Section1' as Section,0 as Cost
UNION
SELECT 2,'Section1',0
UNION
SELECT 3,'Section1',0
UNION
SELECT 4,'Section1',0
UNION
SELECT 5,'Section1',0
UNION
SELECT 1,'Section2',0
UNION
SELECT 2,'Section2',0
UNION
SELECT 3,'Section2',0
UNION
SELECT 4,'Section2',0
UNION
SELECT 5,'Section2',0
) as t1
LEFT JOIN test t2
ON t1.Age=t2.Age AND t1.Section=t2.Section
ORDER BY Section,Age
SQL Fiddle
You can utilize above result set for inserting missing rows by using EXCEPT operator to exclude already existing rows in table -
INSERT INTO test
SELECT t1.Age,t1.Section,ISNULL(t2.Cost,0) as Cost
FROM
(
SELECT 1 as Age,'Section1' as Section,0 as Cost
UNION
SELECT 2,'Section1',0
UNION
SELECT 3,'Section1',0
UNION
SELECT 4,'Section1',0
UNION
SELECT 5,'Section1',0
UNION
SELECT 1,'Section2',0
UNION
SELECT 2,'Section2',0
UNION
SELECT 3,'Section2',0
UNION
SELECT 4,'Section2',0
UNION
SELECT 5,'Section2',0
) as t1
LEFT JOIN test t2
ON t1.Age=t2.Age AND t1.Section=t2.Section
EXCEPT
SELECT Age,Section,Cost
FROM test
SELECT * FROM test
ORDER BY Section,Age
http://www.sqlfiddle.com/#!3/d9035/11

Related

How to use WHERE with virtual column name added with UNION?

SELECT '1000000' AS number
UNION ALL
SELECT '541' AS number
UNION ALL
SELECT '-500' AS number
UNION ALL
SELECT '100' AS number
UNION ALL
SELECT number, 'biggest' AS result
WHERE number = 1000000
How to make this work? My task is to find the biggest number from those that I added.
SELECT '1000000' AS number
UNION ALL
SELECT '541' AS number
UNION ALL
SELECT '-500' AS number
UNION ALL
SELECT '100' AS number
UNION ALL
SELECT number, 'biggest' AS result
WHERE number = 1000000
How to make this work? My task is to find the biggest number from those that I added.
You need to wrap the query in a derived table to be able access a column alias
select *
from (
SELECT 1000000 AS number
UNION ALL
SELECT 541 AS number
UNION ALL
SELECT -500 AS number
UNION ALL
SELECT 100 AS number
)
WHERE number = 1000000
But to find the highest number, you can use an order by and limit:
select *
from (
SELECT 1000000 AS number
UNION ALL
SELECT 541 AS number
UNION ALL
SELECT -500 AS number
UNION ALL
SELECT 100 AS number
)
order by number desc
limit 1
Alternatively you can also simplify this by using a VALUES clause:
select *
from (
values (1000000),(541),(-500),(100)
) as t(number)
order by number desc
limit 1
you can use common table expresssion with FETCH as given below:
WITH CTE_Number AS (
SELECT 1000000 AS number
UNION ALL
SELECT 541 AS number
UNION ALL
SELECT -500 AS number
UNION ALL
SELECT 100 AS number
)
SELECT Number,'Biggest' as result
FROM CTE_Number
ORDER BY Number DESC
FETCH FIRST ROW ONLY;

Remove duplicate with separate column check TSQL

I have 2 tables having same columns and permission records in it.
One columns named IsAllow is available in both tables.
I am getting records of both tables in combine using UNION
But want to skip similar records if IsAllow = 0 in any one column - I don't want those records. But UNION returns all records and am getting confused.
Below are columns
IsAllow, UserId, FunctionActionId
I tried union but it gives both records. I want to exclude IsAllow = 0 in either table.
Sample data table 1
IsAllow UserId FunctionActionId
1 2 5
1 2 8
Sample data table 2
IsAllow UserId FunctionActionId
0 2 5 (should be excluded)
1 2 15
You can try this:
;with cte as(select *, row_number()
over(partition by UserId, FunctionActionId order by IsAllow desc) rn
from
(select * from table1
union all
select * from table2) t)
select * from cte where rn = 1 and IsAllow = 1
Version2:
select distinct coalesce(t1.UserId, t2.UserId) as UserId,
coalesce(t1.FunctionActionId, t2.FunctionActionId) as FunctionActionId,
1 as IsAllow
from tabl1 t1
full join table2 t2 on t1.UserId = t2.UserId and
t1.FunctionActionId = t2.FunctionActionId
where (t1.IsAllow = 1 and t2.IsAllow = 1) or
(t1.IsAllow = 1 and t2.IsAllow is null) or
(t1.IsAllow is null and t2.IsAllow = 1)

T-SQL End of Month sum

I have a table with some transaction fields, primary id is a CUSTomer field and a TXN_DATE and for two of them, NOM_AMOUNT and GRS_AMOUNT I need an EndOfMonth SUM (no rolling, just EOM, can be 0 if no transaction in the month) for these two amount fields. How can I do it? I need also a 0 reported for months with no transactions..
Thank you!
If you group by the expresion month(txn_date) you can calculate the sum. If you use a temporary table with a join on month you can determine which months have no records and thus report a 0 (or null if you don't use the coalesce fiunction).
This will be your end result, I assume you are able to add the other column you need to sum and adapt for your schema.
select mnt as month
, sum(coalesce(NOM_AMOUNT ,0)) as NOM_AMOUNT_EOM
, sum(coalesce(GRS_AMOUNT ,0)) as GRS_AMOUNT_EOM
from (
select 1 as mnt
union all select 2
union all select 3
union all select 4
union all select 5
union all select 6
union all select 7
union all select 8
union all select 9
union all select 10
union all select 11
union all select 12) as m
left outer join Table1 as t
on m.mnt = month(txn_date)
group by mnt
Here is the initial working sqlfiddle

Merging tables in t-sql

I have a table holding periods and prices, something like this
itemid periodid periodstart periodend price
1 1 2011/01/01 2011/05/01 50.00
1 2 2011/05/02 2011/08/01 80.00
1 3 2011/08/02 2011/12/31 50.00
Now I have a second table that can hold single dates or periods
itemid periodid periodstart periodend price
1 8 2011/07/01 2011/07/17 70.00
Now, how can I do a query that would return the following result?
itemid periodid periodstart periodend price
1 1 2011/01/01 2011/05/01 50.00
1 2 2011/05/02 2011/06/30 80.00 ****
1 8 2011/07/01 2011/07/17 70.00 ***
1 2 2011/07/18 2011/08/01 80.00 ****
1 3 2011/08/02 2011/12/31 50.00
EDIT -- Highlight the fact that the merge is modifying the dates around it
How about something like
select
t1.itemid,t1.periodid,t1.periodstart, coalesce(dateadd(d,-1,t2.periodstart),t1.periodend) as periodend, t1.price
from t1
left outer join t2 on t1.periodstart < t2.periodstart and t1.periodend>t2.periodstart and t1.itemid=t2.itemid
union
select
t2.itemid,t2.periodid,t2.periodstart, t2.periodend, t2.price
from t1
inner join t2 on t1.periodstart < t2.periodstart and t1.periodend>t2.periodstart and t1.itemid=t2.itemid
union
select
t1.itemid,t1.periodid,dateAdd(d,1,t2.periodend), t1.periodend, t1.price
from t1
inner join t2 on t1.periodstart < t2.periodend and t1.periodend>t2.periodend and t1.itemid=t2.itemid
order by periodstart
Use a Union?
Select itemid, periodid,periodstart, periodend,price FROM table1
UNION
SELECT itemid, periodid,periodstart, periodend,price FROM table2
Are you trying to do some sort of join though? the result set doesn't match the two tables you supplied.
Are you accounting for entries that line up or are you just trying to combine the rows?
if the latter, you could just do a Union
Select itemid, periodid, periodstart, periodend, price
From Table1
Union
Select itemid, periodid, periodstart, periodend, price
From Table2

Simplified cross joins?

Let's sat I have a Table 'A' with rows:
A
B
C
D
Is there a simple way to do a cross join that creates
A 1
A 2
A 3
A 4
...
D 1
D 2
D 3
D 4
without creating a second table?
Something like:
SELECT *
FROM A
CROSS JOIN (1,2,3,4)
something like that should work, i guess
select * from A cross join (select 1 union all select 2 union all select 3 union all select 4) as tmp
you will create a second table, but you won't persist it.
The following would work for a table of any size (though I only tested it against 6 rows). It uses the ranking functions available in SQL Server 2005 and up, but the idea should be adaptible to any RDBMS.
SELECT ta.SomeColumn, cj.Ranking
from TableA ta
cross join (select row_number() over (order by SomeColumn) Ranking from TableA) cj
order by ta.SomeColumn, cj.Ranking
You should be able to achieve this via
select * from A cross join
(select 1
union all
select 2
union all
select 3
union all
select 4)