I want to have a string that counts down from current time to alarm time.
I've manage to figer out how to get the current time and how to set the alarm time.
The problem I'm having is that when I take current time - alarm time it gives me a numer witch I then need to format back to a hh:mm:ss string.
i've got this.
set alarmHour to 23
set alarmMinute to 00
set theDate to the current date
set the hours of theDate to alarmHour
set the minutes of theDate to alarmMinute
set the seconds of theDate to 0
theDate
set countdown to theDate - (current date)
set ss to countdown / 60
at this point it gives me 22.283333333333 witch i now need to convert to hh:mm:ss and then put them into a sting that give me 00:22:00
UPDATE:
in swift you have % you can use
countDownTime = (formatterInteger - timeControlInteger)
let interval = Int(countDownTime)
let seconds = interval % 60
let minutes = (interval / 60) % 60
let hours = (interval / 3600)
but how to you do this in applescript?
Answer to second question:
is there a way to format strings like in swift? like
String(format:"%02d",absHour) – Mathias Halén
Yes, but you need to use the Satimage.osax scripting addition, available for free at:
Satimage AppleScript Additions
Satimage strftime() -- Date/Time Format Function
strftime v : format a date using a specification string like in the C
function strftime.
strftime date or list of date
into string : the formatting string. To obtain ISO 8601 dates, use
"%FT%TZ" or "%GW%V-%uT%TZ" (using the 'with GMT' parameter)
[GMT boolean] : if true, output date as GMT. Default: false, the ouput
date is local.
→ string : the formatted date
EXAMPLE: strftime (current date) into “%x” RETURNS: 07/22/14
"%a, %b %d, %Y" RETURNS: Tue, Jul 22, 2014
set d to current date
-- some ISO 8601 formats:
strftime d into "%FT%T%z"
-- "2007-01-15T16:10:56+0100"
strftime d into "%GW%V-%uT%T%z"
-- "2007W03-1T16:10:56+0100"
--if you need to store the date d as UTC:
strftime d into "%FT%TZ" with GMT
-- "2007-01-15T15:10:56Z"
strftime d into "%a, %b %d, %Y %H:%M:%S %z"
-- "Mon, Jan 15, 2007 16:10:56 +0100"
Related
It's possible to set the current date in the gnuplot title?
Something like...
set title "date of execution = datetime()"
Thanks in advance.
Alexandre.
Use strftime and time(0) to add a time/data to your title, e.g.:
set title "data of execution ".strftime("%a %b %d %H:%M:%S %Y", time(0))
Alternatively, if it doesn't have to be in the title you can also use
set timestamp
The accepted answer is correct. Unfortunately, both time(0) and timestamp are UTC. You need to manually convert UTC to your local time zone. For example:
fmt = '%Y-%m-%d # %H:%M:%S'; # Format used for printing out time
time_diff=8*60*60; # Seconds between local time zone and UTC
curr_time_utc = time(0); # Get UTC time
curr_time_pdt = curr_time_utc - time_diff; # Adjust to local time zone
print "Current time (UTC): ".strftime(fmt, curr_time_utc);
print "Current time (PDT): ".strftime(fmt, curr_time_pdt);
I just added 8 hours in seconds to time to adjust for my Timezone of +8. 8x60x60 = 28800
set title "Last Run: " .strftime("%a %b %d %H:%M", time(0)+28800)
Works a treat.
Bj
I want to get the date and time in GNU Octave and print it to screen. What is the best way to do this?
I've checked the Octave documentation, but I don't see a function to print out YYYY-MM-DD HH:MM:SS with a one liner simple command.
http://www.gnu.org/software/octave/doc/interpreter/Timing-Utilities.html
Get the date and time in Octave:
Number of seconds since epoch as integer:
time()
ans = 1.3482e+09
The date(), now() and datestr(...) builtin methods:
date()
ans = 20-Sep-2012
datestr(now(), 'yyyy-mm-dd');
ans = 2022-07-04
str2num(datestr(now(), 'yyyymmddHHMMSS'))
ans = 20220704165727
Add/Subtract days/months interval from now:
datestr(addtodate(now(), -20, 'days'), 'yyyy-mm-dd')
ans = 2022-06-14
datestr(addtodate(now(), -20, 'month'), 'yyyy-mm-dd')
ans = 2020-11-04
Format date/time as string with strftime
strftime ("%r (%Z) %A %e %B %Y", localtime (time ()))
ans = 09:52:42 PM (EDT) Thursday 20 September 2012
Get yyyy-mm-dd hh:mm:ss format
strftime ("%Y-%m-%d %H:%M:%S", localtime (time ()))
ans = 2012-09-20 21:56:07
Sources:
https://octave.sourceforge.io/octave/function/datestr.html
https://octave.sourceforge.io/octave/function/strftime.html
I can't get my head around how formatting a datetime variable inside a string works in PowerShell.
$startTime = Get-Date
Write-Host "The script was started $startTime"
# ...Do stuff...
$endTime = Get-Date
Write-Host "Done at $endTime. Time for the full run was: $( New-TimeSpan $startTime $endTime)."
gives me the US date format while I want ISO 8601.
I could use
$(Get-Date -Format u)
but I want to use $endTime to make the calculation of the timespan correct.
I have tried all permutations of $, (, ), endTime, -format, u, .ToString(...) and .ToShortDate(), but the one that works.
"This is my string with date in specified format $($theDate.ToString('u'))"
or
"This is my string with date in specified format $(Get-Date -format 'u')"
The sub-expression ($(...)) can include arbitrary expressions calls.
Microsoft Documents both standard and custom DateTime format strings.
You can use the -f operator
$a = "{0:D}" -f (get-date)
$a = "{0:dddd}" -f (get-date)
Spécificator Type Example (with [datetime]::now)
d Short date 26/09/2002
D Long date jeudi 26 septembre 2002
t Short Hour 16:49
T Long Hour 16:49:31
f Date and hour jeudi 26 septembre 2002 16:50
F Long Date and hour jeudi 26 septembre 2002 16:50:51
g Default Date 26/09/2002 16:52
G Long default Date and hour 26/09/2009 16:52:12
M Month Symbol 26 septembre
r Date string RFC1123 Sat, 26 Sep 2009 16:54:50 GMT
s Sortable string date 2009-09-26T16:55:58
u Sortable string date universal local hour 2009-09-26 16:56:49Z
U Sortable string date universal GMT hour samedi 26 septembre 2009 14:57:22 (oups)
Y Year symbol septembre 2002
Spécificator Type Example Output Example
dd Jour {0:dd} 10
ddd Name of the day {0:ddd} Jeu.
dddd Complet name of the day {0:dddd} Jeudi
f, ff, … Fractions of seconds {0:fff} 932
gg, … position {0:gg} ap. J.-C.
hh Hour two digits {0:hh} 10
HH Hour two digits (24 hours) {0:HH} 22
mm Minuts 00-59 {0:mm} 38
MM Month 01-12 {0:MM} 12
MMM Month shortcut {0:MMM} Sep.
MMMM complet name of the month {0:MMMM} Septembre
ss Seconds 00-59 {0:ss} 46
tt AM or PM {0:tt} ““
yy Years, 2 digits {0:yy} 02
yyyy Years {0:yyyy} 2002
zz Time zone, 2 digits {0:zz} +02
zzz Complete Time zone {0:zzz} +02:00
: Separator {0:hh:mm:ss} 10:43:20
/ Separator {0:dd/MM/yyyy} 10/12/2002
Instead of using string interpolation you could simply format the DateTime using the ToString("u") method and concatenate that with the rest of the string:
$startTime = Get-Date
Write-Host "The script was started " + $startTime.ToString("u")
Is there a Matlab code that transfer the date ( day,month,year) from gregorian
to Hijri (Islamic) calendar and also from hijri to gregorian calendar,
Let's assume that we want to change the gregorian date:
Friday, 18 / 11 / 2011
to the Hijri date which is Friday 22 / 12 / 1432
Thanks
If you are on Windows, you could use the .NET Framework from inside MATLAB.
Here is a function to convert Gregorian dates to Hijri (based on an article on CodeProject):
function out = GregToHijri(str, frmtIn, frmtOut)
% English (US) and Arabic (Saudi Arabia) cultures
enCult = System.Globalization.CultureInfo('en-US',false);
enCult.DateTimeFormat.Calendar = System.Globalization.GregorianCalendar();
arCult = System.Globalization.CultureInfo('ar-SA',false);
arCult.DateTimeFormat.Calendar = System.Globalization.HijriCalendar();
% parse using supplied input format
dt = System.DateTime.ParseExact(str, frmtIn, enCult.DateTimeFormat);
% convert datetime as formatted string
out = char( dt.ToString(frmtOut, arCult.DateTimeFormat) );
end
Tested on your input:
>> GregToHijri('Friday, 18/11/2011', 'dddd, dd/MM/yyyy', 'dd/MM/yyyy')
ans =
22/12/1432
I took this piece from an unencrypted .DAT file:
Code:
00 e1 27 17 6f e6 69 c0
Which translates to 63,374,851,375,000,000 in decimal. The units for the number are microseconds.
And this huge number cannot bypass the 1st January 1970 00:00:00 format; such a format that most converters use today.
So, yes. Is there such a converter that uses the 1st January of the year 1 format? Or how shall I make one?
And by the way, a timestamp is both date and time.
Thanks in advance!
You do not say what language are you using, if it is a .NET language, you can use: http://msdn.microsoft.com/en-us/library/z2xf7zzk.aspx for that constructor the input is in nanoseconds (are you sure that your number is in milliseconds and not in nanoseconds?).
If you are sure it is in milliseconds, the conversion to nanoseconds should be easy: 1 millisecond = 1 000 000 nanoseconds.
But I have the feeling that those are nanoseconds and not milliseconds...
Now that you have told us that it is in microseconds:
C# Example from decimal to yyyy dd MM hh:mm:ss
long microseconds = 63370738175000000;
long ticks = microseconds * 10;
DateTime timestamp = new DateTime(ticks);
Console.WriteLine(timestamp.ToString("yyyy dd MM hh:mm:ss"));
It prints:
2009 20 02 02:49:35
The other way around from yyyy dd MM hh:mm:ss to decimal
String dateString = "2009 20 02 02:49:35";
DateTime timestamp = DateTime.ParseExact(dateString, "yyyy dd MM hh:mm:ss",CultureInfo.CurrentCulture);
long ticks = timestamp.Ticks;
long microseconds = ticks / 10;
Console.WriteLine(microseconds);
It prints:
63370694975000000
And if you want it in hexadecimal just write:
Console.WriteLine(microseconds.ToString("X"));
Then it will print:
E1234FB3278DC0
If you want the answer in another programming language, please add that to you question.
In JAVA in order to convert microseconds into java.sql.Timestamp:
public static Timestamp getTimestampFromMicros(long pMicros) {
long millis = TimeUnit.MICROSECONDS.toMillis(pMicros);
long shaaritInMicros = pMicros - TimeUnit.MILLISECONDS.toMicros(millis);
Timestamp ts = new Timestamp(millis);
long nanos = ts.getNanos() + TimeUnit.MICROSECONDS.toNanos(shaaritInMicros);
ts.setNanos((int)nanos);
return ts;
}
Use below Java code to covert microseconds to date and time,
long msec = microseconds * 1/1000;
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
dateFormat.format(msec);
Which will returns,
2016-01-27 03:41:12