in Specman e, is there a way go give messagef non-definitive message_tag? - specman

Question

I made 2 loggers, one for each thread like this(THREAD=2):
lsd_logger[THREADS] : list of message_logger is instance;
keep for each in lsd_logger {
soft it.tags == {appendf("DBG%d",index).as_a(message_tag)};
it.to_file == appendf("lsd%d.elog", index);
soft it.verbosity == HIGH;
it.to_screen == FALSE;
};
Now I have a checker that I want to sent a message to each logger according to the thread currently running, like this:
messagef(appendf("DBG%d",thread).as_a(message_tag), MEDIUM, "this is a message to logger %d",thread);
But I keep getting this error about how this is not a constant verbosity.
Is there a way to give the message_tag like this instead of creating a func to handle the printing?
Thank you,

Answer 1

No, this is impossible. The tag of the message must be hard-coded, thus it should be a constant tag, and not any expression that returns a tag.
You could possibly solve the issue by defining a method like this:
my_message() is {
case thread {
0: {
messagef(DBG0, MEDIUM, "this is a message to logger 0");
};
1: {
messagef(DBG1, MEDIUM, "this is a message to logger 1");
};
};
};
Then if you want to avoid writing this very long method with repeating code (which you even need to modify every time the number of threads changes), you can use a define as computed macro instead, such as:
define <my_message'action> "my_message" as computed {
items: list of string;
for i from 0 to THREADS-1 do {
items.add(appendf("%d: {messagef(DBG%d, MEDIUM, \"this is a message to logger %d\")}", i, i, i));
};
result = appendf("case thread { %s }", str_join(items, ";"));
};