I am using TestComplete with JScript testing a webpage that has elements that I declare as a variable to make it easier to test the element later. They all have a path like:
var check1 = Window.Panel(1).Panel(2).Panel(0).Panel(0).Panel(0).Panel(0).Panel(1).Panel(0).Label(0).Checkbox(0)
The elements are dynamic, so there is no telling how many there are when the test is run. I was hoping there was some way to loop through and declare the elements, but it would involve declaring the element like this:
var check1 = Window.Panel(1).Panel(2).Panel(0).Panel(0).Panel(0).Panel(0).Panel(1).Panel(0).Label(x).Checkbox(0)
where x is the counter variable. The problem is that TestComplete sees this as a literal path and does not recognize x as a variable.
Is there any way to do this with TestComplete using JScript? Or convert a string to an object? I think I can work with that, too.
My guess is that since you store the reference in variable check1, the variable x is updated but the x in variable check1 still holds it's original value (1).
Workaround
Keep the first part of the path static in the variable, then update x and assign it to the label.
var path = Window.Panel(1).Panel(2).Panel(0).Panel(0).Panel(0).Panel(0).Panel(1).Panel(0);
// path to the Checkbox
path.Label(x).Checkbox(0);
// or if you want to loop over it
for (var x = 0, len = 8; i < len; x += 1) {
if (path.Label(x).Checkbox(0).value === 'something') {
console.log('hooray!');
}
}
Related
I am completely new to Max and am struggling to understand how to use arrays and Javascript parameters.
I have one working js object that outputs an array:
var inlets = 1;
var outlets = 1;
function getRandomChordProgression()
{
outlet(0, [1,4,5]);
return [1,4,5];
}
And then later I want to use that array in another js object, that takes an array and an integer:
var inlets = 2;
var outlets = 1;
function getCurrentChord(chords, barNumber)
{
var chord = chords[barNumber % 3];
outlet(0, chord);
return chord;
}
I tried the below, but the js gets undefined inputs.
The first thing to notice is that in Max Msp, in order to assign a list to a single symbol, you need to use the "tosymbol" object. Even if lists are effectively considered mono dimensional arrays in Max Msp, in order to be understood by javascript they first need to be converted. Once the list is converted into a symbol, we can join it with the integer coming from the number box, pack it with the getCurrentChord message and feed it into the getCurrentChord.js object.
You will see that by converting a list into a symbol every character in the array, including the spaces, is seen as part of the array. So using your example, an array composed by 3 integers will have 5 positions occupied, from 0 to 4. In order to make this work, inside the second .js script the modulo operator needs to be set to 5 in order to have a maximum remainder of 4. This means that by setting the number box to 1 or 3 you will have an empty output. So you need to decide how and if to parse the input or the output in order to obtain only the values desired.
var inlets = 2;
var outlets = 1;
function getCurrentChord(chords, barNumber)
{
var chord = chords[barNumber % 5];
outlet(0, chord);
}
Hope that helps!
Why does for loop require var while for..in does not allow use of var?
for loop
for var index = 0; index < 10; i++ {
}
for..in loop
for index in "test" {
}
instead of:
for var index in "test" {
}
The Swift documentation sums it up pretty nicely:
index is a constant whose value is automatically set at the start of each iteration of the loop. As such, it does not have to be declared before it is used. It is implicitly declared simply by its inclusion in the loop declaration, without the need for a let declaration keyword.
In other words, the variable used in a for/in loop can only be a constant; thus, there's really no need to require that let be used.
The variable(s) used in a "traditional" for loop, however, can be variables or constants, so var or let is required. (Generally, they will be variables, but it is possible to use a constant in a for loop.) They can also be declared outside of the for loop (i.e., before it) and still used in the for loop. Because of this flexibility, you are required to declare it as a constant or variable.
The compiler expands for x in 0..<5 to the following:
var g = (0..<5).generate() {
while let x = g.next() {
// Use x in loop body
}
Every time around the loop, x is a freshly declared variable, the value of unwrapping the next result from calling next on the generator.
Now, that while can be rewritten in this fashion:
while var x = g.next() {
// use x here
}
I guess for this reason, for...in doesn't support the var syntax for declaring the loop counter so that it doesn't give you the wrong impression that x is mutable.
I have a situation in MATLAB where I want to try to assign a struct field into a new variable, like this:
swimming = fish.carp;
BUT the field carp may or may not be defined. Is there a way to specify a default value in case carp is not a valid field? For example, in Perl I would write
my $swimming = $fish{carp} or my $swimming = 0;
where 0 is the default value and or specifies the action to be performed if the assignment fails. Seems like something similar should exist in MATLAB, but I can't seem to find any documentation of it. For the sake of code readability I'd rather not use an if statement or a try/catch block, if I can help it.
You can make your own function to handle this and keep the code rather clear. Something like:
swimming = get_struct(fish, 'carp', 0);
with
function v = get_struct(s, f, d)
if isfield(s, f)
v = s.(f); % Struct value
else
v = d; % Default value
end
Best,
From what I know, you can't do it in one line in MATLAB. MATLAB logical constructs require explicit if/else statements and can't do it in one line... like in Perl or Python.
What you can do is check to see if the fish structure contains the carp field. If it isn't, then you can set the default value to be 0.
Use isfield to help you do that. Therefore:
if isfield(fish, 'carp')
swimming = fish.carp;
else
swimming = 0;
end
Also, as what Ratbert said, you can put it into one line with commas... but again, you still need that if/else construct:
if isfield(fish,'carp'), swimming = fish.carp; else, swimming = 0;
Another possible workaround is to declare a custom function yourself that takes in a structure and a field, and allow it to return the value at the field, or 0.
function [out] = get_field(S, field)
if isfield(S, field)
out = S.(field);
else
out = 0;
end
Then, you can do this:
swimming = get_field(fish, 'carp');
swimming will either by 0, or fish.carp. This way, it doesn't sacrifice code readability, but you'll need to create a custom function to do what you want.
If you don't like to define a custom function in a separate function file - which is certainly a good option - you can define two anonymous functions at the beginning of your script instead.
helper = {#(s,f) 0, #(s,f) s.(f)}
getfieldOrDefault = #(s,f) helper{ isfield(s,f) + 1 }(s,f)
With the definition
fish.carp = 42
and the function calls
a = getfieldOrDefault(fish,'carp')
b = getfieldOrDefault(fish,'codfish')
you get for the first one
a = 42
and the previous defined default value for the second case
b = 0
This question already has answers here:
How to concatenate a number to a variable name in MATLAB?
(5 answers)
Closed 1 year ago.
I would like to create a set of distinct variables in the form of e_1, e_2, e_3... The number of variables would depend on the value of k as shown below.
for i = 1:k
"create variable" = e_"i";
end
I will then want to call these variables; hence, I would need another loop that would be able to assign the correct value to each variable created before, or pull something out of the variable.
One option would be to do something like this:
kk = 10;
for ii=1:kk
eval(['e_' num2str(ii) '=[];'])
end
I got just the fix for you. Was just trying to do the same thing. Needed to be able to create an array with an infinate number of variables. Here's what I came up with. Well, I was adding 2 variables at a time, so it may be a little different than your version.
String[] parts;
String x = "";
String var = "";
int i = 0;
//to add variables
if(x.contains("-"){
x+="-"+var;
}
else{
x+=""+var;
}
then to get them, u just use.
if(x.contains("-")){
parts = x.split("-");
while(i<parts.length){
var=parts[i];
i++;
}
}
else if (x!=""){
var = x;
}
Changing the variables is a whole other story. I'll let your gifted mind figure that out. I don't need that part yet.
*hint, you're going to have to loop and put together the whole String back together with the new variables. Hope this helped. Felt like this was a new way of looking at it.
I am trying to cycle through a list of variables I have say 30+ and calculate the maximum and minimum value for each column in each variable. Save this in a new array and then export to excel.
My thoughts were to use the who function to create an array with the name of all variables which are present. Then cycling through each one using a for loop after working out the size of the array which was created. This works fine, however when I try and use the string to reference the array it does not work.
I will add in the code which I have written hopefully someone will be able to come up with an easy solution :).
variable_list = who
cell2 = input('What cell size do you want to look at? ');
STARTcell = input('What was the start cell size? ');
[num_variables, temp] = size(variable_list);
for va = 1:num_variables
variable = variable_list{va}
[max_value, max_index] = max(variable{cell2/STARTcell})
[min_value, min_index] = min(variable{cell2/STARTcell})
format_values{va} = vertcat(max_values, max_index, min_value, min_index);
end
The variables I am looking at are arrays which is why I use the cell2/STARTcell to reference them.
You need to use the eval() function to be able to get the value of a variable corresponding to a string. For example:
a = 1;
b = 2;
variable_list = who;
c = eval(variable_list{2});
results in c being 2. In your code, the following line needs to change from:
variable = variable_list{va}
to:
variable = eval(variable_list{va});
resulting in variable having the value of the variable indicated by the string variable_list{va}. If variable is of cell type, then you should be fine, otherwise you may have to revise the next two lines of code as well because it seems that you are trying to access the content of a cell.