Feed a list with the last value - jpa

I have theses entity and I do this query.
select r from RentAmount r Join r.lodger l join l.bailList b where r.unpaidBalance > 0 and (r.paymentDueDate > :date or r.paymentDueDate is null ) and b.paymentPeriod= order by r.rentAmountId")
Is there a way to feed Lodger.bailList only with the last bail or i would need to loop on every record to get this information?
#Entity
public class RentAmount {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long rentAmountId;
#OneToOne
private Lodger lodger;
}
#Entity
public class Lodger{
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long lodgerId;
#OneToOne(fetch = FetchType.LAZY, mappedBy="lodger")
private RentAmount rentAmount;
#OneToMany(cascade = {CascadeType.PERSIST, CascadeType.MERGE}, fetch = FetchType.LAZY, mappedBy = "lodger", orphanRemoval = true)
private List<Bail> bailList;
}
#Entity
public class Bail {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long bailId;
#Enumerated(EnumType.STRING)
private PaymentPeriodEnum paymentPeriod;
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumn(name = "lodger_id")
private Lodger lodger;
}

There are a few options:
One (Non JPA, Hibernate Only)
Ensure the collection is correctly ordered and mark it is as extra lazy. You will have access to the whole collection but accessing of individual items will not trigger a full load.
https://docs.jboss.org/hibernate/orm/3.3/reference/en/html/performance.html
"Extra-lazy" collection fetching: individual elements of the
collection are accessed from the database as needed. Hibernate tries
not to fetch the whole collection into memory unless absolutely
needed. It is suitable for large collections.
The mapping will look like:
#OneToMany(mappedBy = "lodger")
#LazyCollection(LazyCollectionOption.EXTRA)
#OrderBy("theRelevantProperty ASC")
private List<Bail> bailList;
public void getCurrentBail(){
//will only load this item from the database
return bailList.get(bailList.size() - 1);
}
Two (Non JPA, Hibernate Only.)
Use the #Where annotation to filter the collection so that while still #OneToMany, only one element will be accessible.
https://docs.jboss.org/hibernate/stable/annotations/reference/en/html_single/#entity-hibspec-collection
The mapping will look like:
#OneToMany(mappedBy = "lodger")
#Where(clause="some native sql which will filter to include onyl 1item"))
private List<Bail> bailList;
public void getCurrentBail(){
//will be the only item accessible
return bailList.get(0);
}
Three (JPA Compliant)
Would involve creating views at the database level. Various options in this area. If we are only ever interested in the current bail then this view would be similar to option 2 above. Simply point the Bail entity to this view rather than the concrete table:
#Entity
#Table(name = "vw_active_bail")
public class Bail {
}

Related

Why my foreign key is null when saving to h2 db, using JPA

What is the difference between these 2 codes. The 1st one shows null on my foreign key which is individualId. The 2nd one is not. Why?
//1st code:
#Entity
#JsonIgnoreProperties({ "hibernateLazyInitializer", "handler" })
public class Individual {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "INDIVIDUAL_ID")
private Long individualId;
#OneToMany(mappedBy="individual",cascade = CascadeType.ALL, fetch = FetchType.LAZY)
private List<Identification> identifications = new ArrayList<Identification>();
}
#Entity
public class Identification {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "IDT_ID")
private Long id;
#ManyToOne
#JoinColumn(name="individualId")
private Individual individual;
//second code
//replaced #OneToMany in the first code & then i just dont add #ManyToOne in the Identification Class and it works fine. Why?
#OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY)
#JoinColumn(name = "INDIVIDUAL_ID", referencedColumnName = "INDIVIDUAL_ID")
private List<Identification> identifications = new ArrayList<Identification>();
When i search for JPA tutorial in google the 1st code is the one that i always read. declare #OneToMany in the parent class and add mappedBy, declare #ManyToOne in the child class. But why the 2nd code works perfect than the 1st code? it just let me declare #OneToMany only in the parent class ?
In the class Identification the name of the #JoinColumn does not match any column in your class Individual. It must be the name of the column in the database, which is INDIVIDUAL_ID:
#JoinColumn(name="INDIVIDUAL_ID")

Will JPA eagerly fetch non-entity attributes?

I want to know if attributes such as Int or Varchar2 are fetched eagerly or lazily when creating a regular query.
#Entity
#Table(name = "ROOM")
public class Room implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue
#Column(name = "room_id")
private Integer id;
#Column(name = "number")
private String number;
#Column(name = "capacity")
private Integer capacity; //Will this be fetched eagerly???
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumn(name = "building_id")
private Building building;
...
...
...
}
Basically:
Room room = getRoomById(5); // select room from Room room where room.id = 5;
Integer roomCap = room.getCapacity(); //Will this create another query?
Or will it be inside the room object already?
The fetching strategies eager or lazy apply to relationships or associated entities where you want to load the data from another table and not to the columns that are part of the same entity or table. Columns or fields that belong to the same entity or table are fetched when you retrieve the entity and no separate query is fired.
when use lazy loading after data call on db after that you want to this object inside object your query go to db and execute db.
When you eager attribute get All element thats object

JPA -- Using the one-to-one dependency relationship on insertion

I have 2 entity classes with one-to-one dependencies on their primary keys:
The primary table:
#Entity
#Table(name = "tablePrimary")
#XmlRootElement
//...
public class TablePrimary implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Basic(optional = false)
#Column(name = "id")
private Integer id;
#Basic(optional = false)
#Column(name = "code")
private String code;
// set the dependency of table2 to this class
#OneToOne(cascade = CascadeType.ALL)
#PrimaryKeyJoinColumn
private Table2 table2inst;
// ...
} // end of class TablePrimary
The dependent table:
#Entity
#Table(name = "table2")
#XmlRootElement
//...
public class Table2 implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#Basic(optional = false)
#Column(name = "id")
private Integer id;
#Basic(optional = false)
#Column(name = "name")
private String name;
#MapsId
#OneToOne(mappedBy = "table2inst")
#JoinColumn(name = "id")
private TablePrimary tablePrimaryInst;
//...
} // end of class Table2
Whenever there is a row with say, id==55 in TablePrimary, there is
a row with the same id==55 in Table2 and vice-versa.
So in essence, these two tables are one table in logical level-- split into 2 physical tables for practicality.
When i'm inserting a row into the "logical" table,
i first am inserting to TablePrimary-- the primary table in the relationship,
getting the value of id==55 field of this new row i just inserted and inserting a row to
Table2 with that id value.
As part of this, i'm checking, just in case,
whether a row with id==55 is already in Table2.
Is there a better way of doing this?
Does JPA have a feature to make these two insertions to these two physical tables
by using the 1-1 dependency I configured on them-- without me having to do it "manually" in the code? Or a control feature on the id fields of the tables I set the dependency on?
If there is-- how is done? how does it handle the key value collision in the dependent table-- Table2?
A similar thing will come up on deletion. However, i'm not there yet, and might figure out out of this.
TIA.
You can take advantage of JPA cascading. You will have to define a cascade on the owning side (the one with the join column). If you have set the owning side of the relationship and persist the owning side, the inverse side will be persisted as well:
TablePrimary tp = new TablePrimary();
Table2 t2 = new Table2();
t2.setTablePrimaryInst(tp);
entityManager.persist(t2);
The 'mappedBy' element is supposed to be placed on the inverse side. You entities could look like this:
public class Table2 ...
#OneToOne(cascade=CascadeType.ALL)
#JoinColumn(name = "tp_id")
private TablePrimary tablePrimary;
public class TablePrimary...
#OneToOne(mappedBy="tablePrimary")
private Table2 table2;

JPA Query Many To One nullable relationship

I have the following entities and would like to seek help on how to query for selected attributes from both side of the relationship. Here is my model. Assume all tables are properly created in the db. JPA provider I am using is Hibernate.
#Entity
public class Book{
#Id
private long id;
#Column(nullable = false)
private String ISBNCode;
#ManyToOne(cascade = CascadeType.DETACH, fetch = FetchType.LAZY, optional = false)
private Person<Author> author;
#ManyToOne(cascade = CascadeType.DETACH, fetch = FetchType.LAZY, optional = true)
private Person<Borrower> borrower;
}
#Inheritance
#DiscriminatorColumn(name = "personType")
public abstract class Person<T>{
#Id
private long id;
#OneToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
private Info information;
}
#Entity
#DiscriminatorValue(PersonType.Author)
public class Author extends Person<Author> {
private long copiesSold;
}
#Entity
#DiscriminatorValue(PersonType.Borrower)
public class Borrower extends Person<Borrower> {
.....
}
#Entity
public class Info {
#Id
private long id;
#Column(nullable=false)
private String firstName;
#Column(nullable=false)
private String lastName;
......;
}
As you can see, the book table has a many to one relation to Person that is not nullable and Person that is nullable.
I have a requirement to show, the following in a tabular format -
ISBNCode - First Name - Last Name - Person Type
How can I write a JPA query that will allow me to select only attributes that I would want. I would want to get the attributes ISBN Code from Book, and then first and last names from the Info object that is related to Person Object that in turn is related to the Book object. I would not want to get all information from Info object, interested only selected information e.g first and last name in this case.
Please note that the relation between the Borrower and Book is marked with optional=true, meaning there may be a book that may not have been yet borrowed by someone (obviously it has an author).
Example to search for books by the author "Marc":
Criteria JPA Standard
CriteriaQuery<Book> criteria = builder.createQuery( Book.class );
Root<Book> personRoot = criteria.from( Book.class );
Predicate predicate = builder.conjunction();
List<Expression<Boolean>> expressions = predicate.getExpressions();
Path<Object> firtsName = personRoot.get("author").get("information").get("firstName");
expressions.add(builder.equal(firtsName, "Marc"));
criteria.where( predicate );
criteria.select(personRoot);
List<Book> books = em.createQuery( criteria ).getResultList();
Criteria JPA Hibernate
List<Book> books = (List<Book>)sess.createCriteria(Book.class).add( Restrictions.eq("author.information.firstName", "Marc") ).list();
We recommend using hibernate criterias for convenience and possibilities.
Regards,

eclipselink 2 OneToMany with one association table how to delete from one side

i have the following entity relationship:
SideA:
#Entity
#Table(name = "SideA")
public class SideA {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private long id;
#CascadeOnDelete
#OneToMany(fetch = FetchType.LAZY, mappedBy = "sideA", cascade=CascadeType.ALL)
private List<ABAssociation> association = new ArrayList<ABAssociation>();
}
Side B:
#Entity
#Table(name = "SideB")
public class SideB {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private long id;
#CascadeOnDelete
#OneToMany(fetch = FetchType.LAZY, mappedBy = "sideB", cascade=CascadeType.ALL)
private List<ABAssociation> association = new ArrayList<ABAssociation>();
}
ABAssociation:
#Entity
#Table(name = "ABAssociation")
public class ABAssociation {
#EmbeddedId
private ABAssociationPK pk = new ABAssociationPK();
#ManyToOne(cascade=CascadeType.MERGE)
#MapsId("aId")
private SideA sideA;
#ManyToOne(cascade=CascadeType.MERGE)
#MapsId("bId")
private SideB sideB;
}
ABAssociationPK:
#Embeddable
public class ABAssociationPK implements java.io.Serializable{
private long aId;
private long bId;
}
my problem is when i delete one side, the database delete the row in ABAssociation , but still stay in cache.
test code is like the follow:
SideA a = new SideA();
SideB b = new SideB();
entitymanager.persist(a);
entitymanager.persist(b);
ABAssociation ab = new ABAssociation()
ab.setSideA(a);
ab.setSideB(b);
entitymanager.persist(ab);
a.getABAssociationList().add(ab);
b.getABAssociationList().add(ab);
a = entitymanager.merge(a);
b = entitymanager.merge(b);
entitymanager.delete(a);
Since "a" was deleted, the relationship between "a" and "b" should be deleted too.
but when i check the "b.getABAssociationList().size()" it still there, even there is no rows in ABAssociation table in DB.
it this related to the share cache issue ?
In JPA you must maintain you object's relationships.
If you remove an object, you must first remove all references to it.
See,
http://en.wikibooks.org/wiki/Java_Persistence/Relationships#Object_corruption.2C_one_side_of_the_relationship_is_not_updated_after_updating_the_other_side
somewhat, yes. You need to remove B's reference to ABAssociation when ABAssociation gets deleted to maintain the cache with what is in the database. You might do this by using a preremove event on ABAssociation if you cannot do it in your application.
you can force update your list using evict() like this:
getEntityManager().getEntityManagerFactory().getCache().evict(ABAssociation.class);