List of all sub documents in array - mongodb

Question

Strangely I couldn't find the answer to that very simple question and I can't find a way to do it by myself with the doc.
This is an example schema
{
Test : [
{
foo:0,fighter:[]
},
{
foo:1,fighter:[]
},
{
food:2,fighter:[]
}
]
}
I want to be able to retrieve all the documents in Test
I've found that to retrieve the content of the first fighter you can just do :
Collection.find({_id: 0 , 'Test.foo': 0})
But what about getting the whole Test array ? or the whole fighter array ?
{ foo: 0, fighter: [ "john", "fitz", "gerald" ] }
{ foo: 1, fighter: [] }
{ food: 2, fighter: [] }
or just the whole figther ( foo 0 ) content
"john", "fitz", "gerald"
The only thing I've found would be Collection.findOne({_id: id}).Test , but it's not working , I'm getting
undefined " Test" method.

Answer 1

You will have to use projection for that. You can do something like this :
Collection.find({_id: 0}, { Test: { $elemMatch: { foo : 0 } } } )
This will give you the Test array, but with just one element, i.e. the first element that matches the criteria foo : 1
To get only the Test array and not the whole document use this :
Collection.find({_id: 0}, { Test: 1, _id: 0 } )
Also
You can find more about this here
Hope this helps.