How to get all documents with a find query where the queried array fields are exists in the document?
{
name: 'test1',
"array": [
{
"name": "100",
"subArray": [
"arr1"
]
},
{
"name": "200",
"subArray": [
"arr2",
"arr3"
]
}
]
}
If i use this query in the find({}) it gives back not only the good results:
$and: [
{'array.name': '100'}, {'array.subArray': 'arr1'},
{'array.name': '200'}, {'array.subArray': 'arr2'}
]
You need to use the $elemMatch operator. Your query should look like this:
$and: [
{ array: { $elemMatch: { name: '100', subArray: 'arr1' } } },
{ array: { $elemMatch: { name: '200', subArray: 'arr1' } } }
]
Related
I have following collection
[
{
"_id": ObjectId("57315ba4846dd82425ca2408"),
"myarray": [
{
"point": 5,
"userId": "570ca5e48dbe673802c2d035"
},
{
"point": 2,
"userId": "613ca5e48dbe673802c2d521"
},
{
"point": 4,
"userId": "570ca5e48dbe673802c2d045"
},
{
"point": 4,
"userId": "570ca5e48dbe473802c2d035"
}
]
}
]
I have a collection like above and I want to remove some objects inside array based on userID condition and after removing I have to update one field in mongo with size of array
I'm trying with the below query where removing array elements is working as excepted but array size is not updating properly
db.collection.update({
_id: ObjectId("57315ba4846dd82425ca2408")
},
{
$pull: {
"myarray": {
userId: {
$in: [
"570ca5e48dbe673802c2d035",
"613ca5e48dbe673802c2d521"
]
}
}
},
"$set": {
profilecount: {
$size: "$myarray"
}
}
})
to see result of query please click this link and run query https://mongoplayground.net/p/FtMk7ymacr3
One option is using an update with a pipeline:
db.collection.update({
_id: ObjectId("57315ba4846dd82425ca2408")
},
[{
$set: {
"myarray": {
$filter: {
input: "$myarray",
cond: {
$not: {
$in: [
"$$this.userId",
["570ca5e48dbe673802c2d035", "613ca5e48dbe673802c2d521"]
]
}
}
}
}
}
},
{$set: {profilecount: {$size: "$myarray"}}}
])
See how it works on the playground example
Here is the collection:
db.employees.insertMany([
{
"data": {
"category": [
{
"name": "HELLO",
"subcategory": [
"EDUCATION",
"ART",
]
},
{
"name": "HELLO",
"subcategory": [
"GG",
"ART",
]
},
{
"name": "HELLO",
"subcategory": [
"EDUCATION",
"SHORE",
]
}
]
}
},
{
"data": {
"category": [
{
"name": "HELLO",
"subcategory": [
"EDUCATION",
"HELLO",
]
}
]
}
},
{
"data": {
"category": [
{
"name": "HELLO",
"subcategory": [
"GG",
"ART",
]
}
]
}
}
]);
What I want is to locate the elements in 'category' with a 'subcategory' that contains 'EDUCATION' and replace 'EDUCATION' with another string, let's say 'SPORTS'.
I tried a couple of commands but nothing really did the job:
db.employees.updateMany({
"data.category.subcategory": "EDUCATION"
},
{
"$set": {
"data.category.$": {
"subcategory": "SPORTS"
}
}
})
What I saw is that it doesn't update the element by replacing it and it doesn't replace every element that meets the criteria.
Think that MongoDB Update with Aggregation Pipeline fulfills your scenario.
$set - Set data.category value.
1.1. $map - Iterate each element in data.category and return an array.
1.1.1. $mergeObjects - Merge the current document with the document with subcategory field from 1.1.1.1.
1.1.1.1 $map - Iterate each value from the subcategory array. With $cond to replace the word EDUCATION with SPORTS if fulfilled, else use existing value ($$this).
db.employees.updateMany({
"data.category.subcategory": "EDUCATION"
},
[
{
"$set": {
"data.category": {
$map: {
input: "$data.category",
in: {
$mergeObjects: [
"$$this",
{
subcategory: {
$map: {
input: "$$this.subcategory",
in: {
$cond: {
if: {
$eq: [
"$$this",
"EDUCATION"
]
},
then: "SPORTS",
else: "$$this"
}
}
}
}
}
]
}
}
}
}
}
]
Sample Mongo Playground
Here's another way to do it using "arrayFilters".
db.collection.update({
"data.category.subcategory": "EDUCATION"
},
{
"$set": {
"data.category.$[].subcategory.$[elem]": "SPORTS"
}
},
{
"arrayFilters": [
{ "elem": "EDUCATION" }
],
"multi": true
})
Try it on mongoplayground.net.
I have an array of objects and I want to check if there is an object that matches multiple properties. I have tried using $in and $and but it does not work the way I want it to.
Here is my current implementation.
I have an array like
"choices": [
{
"name": "choiceA",
"id": 0,
"l": "k"
},
{
"name": "choiceB",
"id": 1,
"l": "j"
},
{
"name": "choiceC",
"id": 2,
"l": "l"
}
]
I am trying to write aggregation code that can check if there is an object that contains both "id":2 and "l":"j" properties. My current implementation checks if there is an object containing the first property then checks if there is an object containing the second one.
How can I get my desired results?
Below, see my aggregation query. The full code is here
db.poll.aggregate([
{
"$match": {
"_id": 100
}
},
{
$project: {
numberOfVotes: {
$and: [
{
$in: [
2,
"$choices.id"
]
},
{
$in: [
"j",
"$choices.l"
]
}
]
},
}
}
])
The above query returns true yet there is no object in the array both of the properties id:2 and "l":"J". I know the code works as expected. How can I get my desired results?
You want to use something like $elemMatch
db.collection.find({
choices: {
$elemMatch: {
id: 2,
l: "j"
}
}
})
MongoPlayground
EDIT
In an aggregation $project stage I would use $filter
db.poll.aggregate([
{
"$match": {
"_id": 100
}
},
{
$project: {
numberOfVotes: {
$gt: [
{
$size: {
$filter: {
input: "$choices",
as: "choice",
cond: {
$and: [
{
$eq: [
"$$choice.id",
2
]
},
{
$eq: [
"$$choice.l",
"j"
]
}
]
}
}
}
},
0
]
}
}
}
])
MongoPlayground
I have a nested array structured like this
{
"_id": "5dff75968102f11e20ae888e",
"docID": "Employees",
"data": [
[
"234768237",
"Value1",
],
[
"234768238",
"Value2"
],
[
"234768239",
"Value3"
]
]
}
Inside the nested data array, first element is employee ID, Ex: 234768237.
I would want to pass an array of employee ID's and delete the matching ones, for ex : [234768237, 234768238]
What i have tried so far
let employeeIDArray = [234768237, 234768238];
collection.updateOne(
{ docID: "Employees" },
{
$pull: {
"data.$[]": { "0": { $each: employeeIDArray } }
}
}
);
You're close, try:
let employeeIDArray = [234768237, 234768238];
collection.updateOne(
{ docID: "Employees" },
{
$pull: {
"data": { $in: employeeIDArray }
}
}
);
The $each modifier is only available for $push and $addToSet actions, read more about it here.
EDIT:
For Nested Array use $pullAll instead of $pull like so:
collection.updateOne(
{ docID: "Employees" },
{
$pullAll: {
"data.$[]": employeeIDArray
}
});
If you are using MongoDB's latest version then you can use below query to update using aggregation pipeline:
collection.updateOne(
{ docId: "Employees" },
[ {
$set: {
data: {
$filter: {
input: "$data",
cond: { $in: [ { $arrayElemAt: [ "$$this", 0 ] }, [ "234768237", "234768238" ] ] } }
}
}
} ],
{ upsert: true }
)
I tried to filter the data using $elemmatch but it's not correctly working.
My Scenario
Prod Table
[
{
id:1.
product:[
{
id:1,
name:true
},
{
id:2,
name:true
},
{
id:3,
name:false
}
]
}
]
Query
db.Prod.find(
{"product.name": true},
{_id: 0, product: {$elemMatch: {name: true}}});
I got Output
[
{
id:1.
product:[
{
id:1,
name:true
}
]
}
]
Excepted Output
[
{
id:1.
product:[
{
id:1,
name:true
},
{
id:2,
name:true
}
]
}
]
How to achieve this Scenario and I referred this Link Retrieve only the queried element in an object array in MongoDB collection and I tried all the answers in this link mentioned. but Still it's not working can give an example query.
Hmm, you probably didn't try the aggregation provided in referenced link, 'cause it perfectly works.
db.collection.aggregate([
{
$match: {
"product.name": true
}
},
{
$project: {
product: {
$filter: {
input: "$product",
as: "prod",
cond: {
$eq: [
"$$prod.name",
true
]
}
}
}
}
}
])
Will output :
[
{
"_id": 1,
"product": [
{
"id": 1,
"name": true
},
{
"id": 2,
"name": true
}
]
}
]
Here's the example.
EDIT :
From the doc :
Usage Considerations
Both the $ operator and the $elemMatch operator project the first
matching element from an array based on a condition.
Considering this, you cannot achieve what you need with a find query, but only with an aggregation query.