Bit of a weird one I hope someone can help out with.
In leaflet, once the user has entered a lat/lng and added a point to the map I want to be able to also add a 10km square around that point.
I've tried looking around for a calculation to find the corners of the square x Km away but haven't dug anything up. But surely there's an easier way!
Does anyone have any thoughts? It'd be lovely to just say L.polygon then pass in a centre point and a square size.
Thanks,
Tayler
Initialize a L.Circle on your desired latitude/longitude with a radius of 5000 meters, grab the boundaries and use them to initialize a L.Rectangle:
new L.Rectangle(new L.Circle([0, 0], 5000).getBounds())
Related
I have a historical city map that I want to display using Leaflet.
I like to set the coordinates of this image to reflect the real world, e.g so I can click on the image and get the real coordinates.
I guess I can just make it an overlay to a real map, but there must be a better solution just define at what coordinates of the corners of the image.
For this image, the approx real world coordinates is NW: 60.34343, 18.43360, SE: 60.33761, 18.44819
My code, so far, is here:
http://stage1876.xn--regrund-80a.se/example3.html
Any ideas how to proceed? It feels like it there should be an easy way to do this?
Any help would be so appreciated!
EDIT: The implementation (so far) with tiles are optional. I could go for a one image-map as well.
Seems like a simple question, but I have been tearing my hair out for hours now.
I have a series of files ie.
kml_image_L1_0_0.jpg
kml_image_L2_0_0.jpg
kml_image_L2_0_1.jpg
kml_image_L2_1_0.jpg
kml_image_L2_1_1.jpg
etc. However just plotting them on the leaflet map surface understandibly puts the images at 0,0 on the earths surface, and the 0 zoom level inferred by the files should really be about 15 or so.
So I want to specify the latitude and longitude where the images should originate , and what zoom level they should start at. I have tried bounds (which doesn't display anything) and I have tried playing with offsetting the zoom level.
I need this because a user needs to click on an offline map to specify where they are and I need the GPS coordinates.
I also have a KML file but it seems to be of more help for plotting vector data on the map.
Any help is much appreciated, cheers.
If I understand correctly, the "kml_image_Lz_x_y.jpg" images that you have are actually tiles, with zoom, horizontal and vertical indices in their file name?
And your issue is that they use (z,x,y) numbers as if they started from the top-most level (zoom 0, single tile for entire world), but in fact they are just a small portion of the pyramid of tiles?
And you cannot use them as is because you still want to get actual geographic coordinates (latitude, longitude), which would be totally wrong if you used the tiles as if they were showing the entire world?
In that case, you have several options as workarounds:
The most simple and reliable would probably be to simply write a small script to rename all your tiles to their true (z,x,y) numbers.
Another option would be to modify the (z,x,y) numbers before they are written in the tile src attribute, and apply the appropriate offset (constant for z, scaled by z for x and y). That should probably happen in L.TileLayer.getTileUrl() method.
Good luck! :-)
Maybe I'm asking this too soon in my research, but I'd better know if this is possible sooner than later.
Imagine I have the following square printed on a paper on top of a table:
The table is brown, so it does not match with any of the colors in the square. Is there a way for me, from a common iPhone camera (non-stereo view), to figure out the distance and angle from which Im looking at the square in the table?
In the end what I'm looking for is being able to draw a 3D square on top of this one using the camera image, but I'm not sure if I am going to be able to figure out the distance and position of the object in space using only a 2D image. Any hints are well appreciated.
Short answer: http://weblog.bocoup.com/javascript-augmented-reality
Big answer:
First posterize, Then vectorize, With the vectors in your power you may need to do some math tricks to define, based on the vectors position, the perspective and then the camera position.
Maybe this help:
www.pixastic.com/lib/docs/actions/posterize/
github.com/selead/cl-vectorizer
vectormagic.com/home
autotrace.sourceforge.net
www.scipy.org/PyLab
raphaeljs.com/
technabob.com/blog/2007/12/29/video-games-get-vectorized/
superuser.com/questions/88415/is-there-an-open-source-alternative-to-vector-magic
Oughta be possible. Scan the image for the red/blue/yellow pattern, then do edge detection to figure out how warped the squares are (they'll be parallelograms in anything but straight-on view). Distance would depend on the camera's zoom setting and scan resolution. But basically you'd count how many pixels are visible in each of the squares, run that past the camera's specs and you should be able to determine a rough distance.
I have a series of nature reserves that need to be plotted, as polygon overlays, on a map using the coordinates contained within KML data. I’ve found a tutorial on the Apple website for displaying KML overlays on map instances.
The problem is that the reserves vary in size greatly - from a small pond right up to several hundred kilometers in size. As a result I can’t use the coordinates of the center point to find the nearest reserves. Instead I need to calculate the nearest point of the reserves polygon to find the nearest one. With the data in KML - how would I go about trying to achieve this?
I've only managed to find one other person ask this and no one had replied :(
Well, there are a couple different solutions depending on your needs. The higher the accuracy required, the more work required. I like Phil's meanRadius parameter idea. That would give you a rough idea of which polygon is closest and would be pretty easy to calculate. This idea works best if the polygons are "circlish". If the polygon are very irregular in shape, this idea loses it's accuracy.
From a math standpoint, here is what you want to do. Loop through all points of all polygons. Calculate the distance from those points to your current coordinate. Then just keep track of which one is closest. There is one final wrinkle. Imagine a two points making a line segment that is very long. You are located one meter away from the midpoint of the line. Well, the distance to these two points is very large, while, in fact you are very close to the polygon. You will need to calculate the distance from your coordinate to every possible line segment which you can do in a variety of manners which are outlined here:
http://www.worsleyschool.net/science/files/linepoint/distance.html
Finally, you need to ask yourself, am I in any polygons? If you're 10 meters away from a point on a polygon, but are, in fact, inside the polygon, obviously, you need to consider that. The best way to do that is to use a ray casting algorithm:
http://en.wikipedia.org/wiki/Point_in_polygon#Ray_casting_algorithm
I am wondering if there is a way to translate the underlying matrix of a layer much like you can in ActionScript3.
In AS3 I can get the transform of a layer and shift it to, let's say, make the center of the layer the anchor point, rather than the upper-left corner.
The reason I ask is because I am trying to rotate a layer (containing a square) along a diagonal axis. I thought it might be easy if I could rotate the matrix by 45 degrees, then I could just rotate around the X-axis and be done.
But I cannot figure out how to do that.
Any help, greatly appreciate, as always.
Cheers,
Chris
Use a CGAffineTransform.
Edit:
I am afraid I don't know what you mean by "rotating an object along a diagonal axis". What you most likely need to do is to concatenate two or more transforms.
See figure 5-8 in Quartz 2D programming Guide The concatenation of two transforms creates the appearance of the image rotating around its lower left corner.