Unity3D How to make object go away form mouse click position 2D - unity3d

Question

Im thinking about it two days. I still did not made any progress.
I wonder how to do that objects fly away from mouse click position in 2D view?
I tried like that:
pos = Input.mousePosition;
Vector3 realWorldPos = Camera.main.ScreenToViewportPoint(pos);
print("MOuse pos: " + realWorldPos);
//print(realWorldPos);
Vector3 velo = GetComponent<Rigidbody2D>().velocity;
if (realWorldPos.x < 0.5)
{
velo = new Vector3((realWorldPos.x * speed), velo.y);
}
else if(realWorldPos.x > 0.5)
{
velo = new Vector3((realWorldPos.x * speed) * (-1), velo.y);
}
if (realWorldPos.y < 0.5)
{
velo = new Vector3(velo.x, realWorldPos.y * speed);
}
else if (realWorldPos.y > 0.5)
{
velo = new Vector3(velo.x, (realWorldPos.y * speed) * (-1));
}
GetComponent<Rigidbody2D>().velocity = velo;
But it doesnt work as I want.
Is it possible to do this?

Answer 1

For this to work your Rigidbody2D must have Gravity Scale set to 0.
This is a simple test code that works for me, is placed on a sprite object:
public class PushPlayer : MonoBehaviour
{
public float pushPower = 50.0f;
Rigidbody2D rb;
void Start()
{
rb = GetComponent<Rigidbody2D>();
}
void Update()
{
if(Input.GetMouseButtonDown(0))
{
Vector3 dir = transform.position - Camera.main.ScreenToWorldPoint(Input.mousePosition);
dir = dir.normalized;
rb.AddForce(dir * pushPower, ForceMode2D.Force);
// as alternative:
rb.velocity = dir * pushPower;
}
}
}
You need to adjust the values a bit, also in the regidbody (like drag) to get it the way you want.
Edit:
transform.position - Camera.main.ScreenToWorldPoint(Input.mousePosition): calculate the directional vector from the mouse position to the player position (have a look a vector algebra if you are not familiar with this) which is the direction away from the click (in a straight line).
dir.normalized: this shortens the vector to a length (= magnitude) of 1 (again have a look at vectors) so it really is just a direction. You could omit this and reduce the factor, but doing it this way your factor equals the force you use.