Update Single Field on Domain Save - mongodb

The save() method seems to replace an entire document/record in my database. If I know the primary key of a document in my database, what is the best way in Grails for me to update a single field on that document without first querying the database using get()?
For instance, I don't like the following code because it executes two queries when all I want to do is to update myField.
def key = "foo"
def doc = MyDomain.get(key) // This is the query I want to eliminate
doc.myField = "bar"
doc.save()
In situations where I know the primary key, I want to simply update a single field, similarly to how Ruby on Rails leverages the ActionModel.update_attribute() method.
Even though my specific database is MongoDB, I think the question is applicable to any database, SQL or NoSQL. If the database supports the ability to update just a single field on one record via one query, using Grails can I avoid the extra get() query to retrieve a full record from the database?

Related

Is it possible to run a "dummy" query to see how many documents _would_ be inserted

I am using MongoDB to track unique views of a resource.
Everytime a user views a specific resource for the first time, a new view is logged in the db.
If that same user views the same resource again, the unique compound index on the collection blocks the insert of the duplicate.
For bulk inserts, with { ordered: false }, Mongo allows the new views through and blocks the duplicates. The return value of the insert is an object with an insertedCount property, telling me how many docs made it past the unique index.
In some cases, I want to know how many docs would be inserted before running the query. Then, based on the dummy insertedCount, I would choose to run the query, or not.
Is there a way to test a query and have it do everything except actually inserting the docs?
I could solve this by running some js serverside to get the answer I need. But I would prefer to let the db do those checks

want to use _id instead of id in waterline with mongodb

I have a case where I need to change the default referencing of primary key name id with _id for all the models in a given project I am working.
There is an express.js + mongoose setup which is in production. The data present in the database is directly referred by our users using mobile application. And the code of mobile application is very much aware of reading _id as the key in all the documents it receives in JSON.
Since sails uses waterline which has default key name as id and it maps to _id for mongodb, the underlying database will be used as it is, however on the middleware we are always reading it as id.
I have searched through the web and tried to have default id name as _id in the config/models.js, but the schema creation outputs an error stating _id, _id is used twice.
Production database, Waterline ... I recommend against actually changing your primary keys. Heck, I'd recommend against that kind of monkey-wrench if you were using a much more mature ORM.
Instead, I say, transform the key names in your action. e.g. in an action2, where you just return template variables at the end of a function:
r = await Model.findOne(where);
return {
_id: r.id, // <---- this bit <----
etc: r.etc
}
And then make a JSON structure as your view template.

Is it possible to delete a field with MongoEngine, without strict=False?

I've got a lot of data in MongoDB, which we access primarily via MongoEngine, and sometimes data first ended up in field F1, and then we later decided that field F2 is a better place for it, so we moved it over there, and stopped using F1.
That's convenient, but now we've got a bunch of stale (or useless) data in old F1 keys, and new documents are being created with empty F1 keys, for no reason.
While MongoDB being schemaless is convenient, I still appreciate the strict=True feature (which is on by default), and try to avoid turning it off except when absolutely necessary. I don't like turning off all the safety checks on a collection.
So is there any way to delete a field F1 from my MongoDB collection, without downtime, and without strict=False?
If I remove the field from my Document subclass first, MongoEngine will complain when it tries to load existing documents.
If I remove the field from my database first, MongoEngine will create it for any new records, until the model is updated.
Is there any way with MongoEngine to say "This is an old field. You can load it (or ignore it) if it's there, but don't create it for any new documents"?
If I remove the field from my database first, MongoEngine will create it for any new records, until the model is updated
It's only true if you explicitly write to that field or if the field has a default value set. Otherwise the field won't exist in MongoDB.
So as first step I suggest to remove the code that writes to that field and remove the default value (or set it to None). Then it's safe to remove the field from the database.
Below a small proof:
import mongoengine
class Foo(mongoengine.Document):
a = mongoengine.IntField()
b = mongoengine.ListField(default=None)
f = Foo().save()
type(f.a) # NoneType
type(f.b) # NoneType
And the database query:
> db.foo.findOne()
{ "_id" : ObjectId("56c49ae8ee8b341b4ea02fcb") }

Which is the best way to insert data in mongodb

While writing data to mongodb, we are checking if the data is present get the _id and using save update it else using insert add the data. Read save is the best way if you are providing _id in the query while saving it will update/insert based on if the _id is present in the db. Is the save the best method or is there any other way.
If you have all data available to save, just run update() each time but use the upsert functionality. Only one query required:
db.collection.update(
['_id' => $id],
$data,
['upsert' => true]
);
If your _id is generated by mongo you always know there is a record in the database and update is the one to use, but then again you could also save().
If you generated your id's (and thus don't know if it comes from the collection), this will always work without having to run an extra query.
From the documentation
db.collection.save()
Updates an existing document or inserts a new document, depending on its document parameter.
db.collection.insert()
Inserts a document or documents into a collection.
If you use db.collection.insert() in your case you will get duplication key error since it will try to insert new document which has same _id with an existing document. But instead of using save you should use the update method.

is there any way to restore predefined schema to mongoDB?

I'm beginner with mongoDB. i want to know is there any way to load predefined schema to mongoDB? ( for example like cassandra that use .cql file for this purpose)
If there is, please intruduce some document about structure of that file and way for restoring.
If there is not, how i can create an index only one time when I create a collection. I think it is wrong if i create index every time I call insert method or run my program.
p.s: I have a multi-threaded program that every thread insert and update my mongo collection. I want to create index only one time.
Thanks.
To create an index on a collection you need to use ensureIndex command. You need to only call it once to create an index on a collection.
If you call ensureIndex repeatedly with the same arguments, only the first call will create an index, all subsequent calls will have no effect.
So if you know what indexes you're going to use for your database, you can create a script that will call that command.
An example insert_index.js file that creates 2 indexes for collA and collB collections:
db.collA.ensureIndex({ a : 1});
db.collB.ensureIndex({ b : -1});
You can call it from a shell like this:
mongo --quiet localhost/dbName insert_index.js
This will create those indexes on a database named dbName on your localhost. It's worth noticing that if your database and/or collections are not yet created, this will create both the database and the collections for which you're adding the indexes.
Edit
To clarify a little bit. MongoDB is schemaless so you can't restore it's schema.
You can only create indexes and collections (by using createCollection helper).
MongoDB is basically schemaless so there is no definition of a schema or namespaces to be restored.
In the case of indexes, these can be created at any time. There does not need to be a collection present or even the required fields for the index as this will all be sorted out as the collections are created and when documents are inserted that matches the defined fields.
Commands to create an index are generally the same with each implementation language, for example:
db.collection.ensureIndex({ a: 1, b: -1 })
Will define the index on the target collection in the target database that will reference field "a" and field "b", the latter in descending order. This will happen even if the collection or even the database does not exist as yet, or in fact will establish a blank namespace in that case.
Subsequent calls to the same index creation method do not actually re-create the index. Where the same index is specified to one that already exists it is effectively skipped as a "no-operation".
As such, you can simply feed all your required index creation statements at application startup and anything that is not already present will be created. Anything that already exists will be left alone.