Trying to unwind two or more arrays in OrientDB - orientdb

Question

I'm using OrientDB's UI/Query tool to analyze some graph data, and I've spent a couple of days unsuccessfully trying to unwind two arrays.
The unwind clause works just fine for one array but I can't seem to get the output I'm looking for when trying to unwind two arrays.
Here's a simplified example of my data:
#class | amt | storeID | customerID
transaction $4 1 1
transaction $2 1 1
transaction $6 1 4
transaction $3 1 4
transaction $2 2 1
transaction $7 2 1
transaction $8 2 2
transaction $3 2 2
transaction $4 2 3
transaction $9 2 3
transaction $10 3 4
transaction $3 3 4
transaction $4 3 5
transaction $10 3 5
Each customer is a document with the following information:
#class | customerID | State
customer 1 NY
customer 2 NJ
customer 3 PA
customer 4 NY
customer 5 NY
Each store is a document with the following information:
#class | storeID | State | Zip
store 1 NY 1
store 2 NJ 3
store 3 NY 2
Assuming I did not have storeID (nor wanted to create it), I want to recover a flattened table with the following distinct values: name of the store, city, account numbers, and the sum of spent.
The query would hopefully generate something like the table below (for a given depth value).
State | Zip | customerID
NY 1 4
NY 1 5
NY 2 1
NY 2 4
NJ 3 1
NJ 3 2
NJ 3 3
I've tried various expand/flatten/unwind operations but I can't seem to get my query to work.
Here's the query I have that recovers the State and Zip as two arrays and flattens the customerID:
SELECT out().State as State,
out().Zip as Zip,
customerID
FROM ( SELECT EXPAND(IN())
FROM (TRAVERSE * FROM
( SELECT FROM transaction)
)
) ;
Which yields,
State | Zip | customerID
[NY, NY, NJ, NJ] [1,1,2,2] 1
[NY, NY, NJ, NJ] [1,1,2,2] 1
[NY, NY, PA, PA] [1,1,3,3] 4
[NY, NY, PA, PA] [1,1,3,3] 4
... .... ....
Which is not what I'm looking for. Can someone provide a little help on how I can flatten/unwind these two arrays all together?

Answer 1

I tried your case with this structure (based on your example):
I used this queries to retrieve State, Zip and customerID (not as array):
Query 1:
SELECT State, Zip, in('transaction').customerID AS customerID FROM Store
ORDER BY Zip UNWIND customerID
----+------+-----+----+----------
# |#CLASS|State|Zip |customerID
----+------+-----+----+----------
0 |null |NY |1 |1
1 |null |NY |1 |1
2 |null |NY |1 |4
3 |null |NY |1 |4
4 |null |NY |2 |4
5 |null |NY |2 |4
6 |null |NY |2 |5
7 |null |NY |2 |5
8 |null |NJ |3 |1
9 |null |NJ |3 |1
10 |null |NJ |3 |2
11 |null |NJ |3 |2
12 |null |NJ |3 |3
13 |null |NJ |3 |3
----+------+-----+----+----------
Query 2:
SELECT inV('transaction').State AS State, inV('transaction').Zip AS Zip,
outV('transaction').customerID AS customerID FROM transaction ORDER BY Zip
----+------+-----+----+----------
# |#CLASS|State|Zip |customerID
----+------+-----+----+----------
0 |null |NY |1 |1
1 |null |NY |1 |1
2 |null |NY |1 |4
3 |null |NY |1 |4
4 |null |NY |2 |4
5 |null |NY |2 |4
6 |null |NY |2 |5
7 |null |NY |2 |5
8 |null |NJ |3 |1
9 |null |NJ |3 |1
10 |null |NJ |3 |2
11 |null |NJ |3 |2
12 |null |NJ |3 |3
13 |null |NJ |3 |3
----+------+-----+----+----------
EDITED
In the following example, with the query you'll be able to retrieve the average and the total spent for every storeID (based on each customerID):
SELECT customerID, storeID, avg(amt) AS averagePerStore, sum(amt) AS totalPerStore
FROM transaction GROUP BY customerID,storeID ORDER BY customerID
----+------+----------+-------+---------------+-------------
# |#CLASS|customerID|storeID|averagePerStore|totalPerStore
----+------+----------+-------+---------------+-------------
0 |null |1 |1 |3.0 |6.0
1 |null |1 |2 |4.5 |9.0
2 |null |2 |2 |5.5 |11.0
3 |null |3 |2 |6.5 |13.0
4 |null |4 |1 |4.5 |9.0
5 |null |4 |3 |6.5 |13.0
6 |null |5 |3 |7.0 |14.0
----+------+----------+-------+---------------+-------------
Hope it helps