how I can use a method search for generate a query like this SEARCH(name) select * from person where name like '% name %' and how I set this method to filter a gridview? I only see the option for startwith and endwith
CFQL supports the concatenation operation, so you can use the following CFQL method:
SEARCH(Name) WHERE Name LIKE '%' + #Name + '%'
If you edit your model directly in XML, you have to escape the character %:
<cf:method name="SearchSample" body="SEARCH(Name) WHERE Name LIKE '%%' + #Name + '%%'" />
Formal grammar of CodeFluent Query Language (CFQL)
Related
I have a problem I can't seem to figure out. I am trying to extract capacity from a product description. It is always between two values, "," and "oz." however there could be other commas included in the description that are not part of what I'm trying to extract. Example value is , 15 oz., or , 2 oz.,
I'm trying to find values that have the oz in them and are between two commas and I have been completely unsuccessfully. I've tried many things, but here is the latest that I have tried today and I'm just getting an error.
SELECT SUBSTRING(
FullDescription,
CHARINDEX(',', FullDescription),
CHARINDEX('oz.',FullDescription)
- CHARINDEX(',', FullDescription)
+ Len('oz.')
)
from CatalogManagement.Product
Since the backwards pattern ,.zo is more recognisable, I'd go with the REVERSE function
Sample values:
"something, something more, 18oz., complete"
"shorter, 12oz., remainder"
"there is no capacity, in this, value"
"a bit more, 14oz, and some followups, maybe"
SELECT REVERSE(
SUBSTRING (
REVERSE(FullDescription),
CHARINDEX(',.zo', REVERSE(FullDescription)) + 1,
CHARINDEX(',', REVERSE(FullDescription), CHARINDEX(',.zo', REVERSE(FullDescription)) + 1) - CHARINDEX(',.zo', REVERSE(FullDescription)) - 1
)
)
FROM CatalogManagement.Product
WHERE FullDescription LIKE '%oz.,%'
You might use XML-splitting together with a XQuery predicate:
DECLARE #tbl TABLE(ID INT IDENTITY, YourString VARCHAR(MAX));
INSERT INTO #tbl VALUES('Here is one with an amount, 1 oz., some more text')
,('Here is one with no amount, some more text')
,('a, 10 oz.')
,('b, 20oz., no blank between oz and the number')
,('30oz., starts with the pattern, no leading comma');
SELECT t.*
,A.oz.value('.','nvarchar(max)') oz
FROM #tbl t
CROSS APPLY(SELECT CAST('<x>' + REPLACE((SELECT t.YourString AS [*] FOR XML PATH('')),',','</x><x>') + '</x>' AS XML)
.query('/x[contains(text()[1],"oz.")]')) A(oz);
The idea in short:
We use some string methods to replace commas with XML tags and to cast your string to XML. each fragment is placed within a decent <x> element.
We use a predicate to return just the fragments containing "oz.".
You can filter easily with
WHERE LEN(A.oz.value('.','nvarchar(max)'))>0
I try to create advanced search to my database.
I want to do something like that: if the user type for search = overf**w
and I have in my database an cloumn that his value = overflow - show him.
this my code:
$name = str_replace('*', '_', $name);
SELECT name FROM table WHERE name LIKE CONCAT('%', ?, '%')
its not working, I dont know what the problem.
You can't use LIKE in this situation, you need to use REGEXP() to do a wildcard search. Replace * or ** with .*. To only return names that starts with the given value use ^ at the beginning of the regular expression
SELECT name
FROM actors
WHERE name REGEXP('^overf.*w')
I don't know php but your $name parameter should be set like this (in pseudo code)
$name = '^' + replace($name, '**', '.*')
So I have a in my Postgresql:
TAG_TABLE
==========================
id tag_name
--------------------------
1 aaa
2 bbb
3 ccc
To simplify my problem,
What I want to do is SELECT 'id' from TAG_TABLE when a string "aaaaaaaa" contains the 'tag_name'.
So ideally, it should only return "1", which is the ID for tag name 'aaa'
This is what I am doing so far:
SELECT id FROM TAG_TABLE WHERE 'aaaaaaaaaaa' LIKE '%tag_name%'
But obviously, this does not work, since the postgres thinks that '%tag_name%' means a pattern containing the substring 'tag_name' instead of the actual data value under that column.
How do I pass the tag_name to the pattern??
You should use tag_name outside of quotes; then it's interpreted as a field of the record. Concatenate using '||' with the literal percent signs:
SELECT id FROM TAG_TABLE WHERE 'aaaaaaaa' LIKE '%' || tag_name || '%';
And remember that LIKE is case-sensitive. If you need a case-insensitive comparison, you could do this:
SELECT id FROM TAG_TABLE WHERE 'aaaaaaaa' LIKE '%' || LOWER(tag_name) || '%';
A proper way to search for a substring is to use position function instead of like expression, which requires escaping %, _ and an escape character (\ by default):
SELECT id FROM TAG_TABLE WHERE position(tag_name in 'aaaaaaaaaaa')>0;
I personally prefer the simpler syntax of the ~ operator.
SELECT id FROM TAG_TABLE WHERE 'aaaaaaaa' ~ tag_name;
Worth reading through Difference between LIKE and ~ in Postgres to understand the difference.
`
In addition to the solution with 'aaaaaaaa' LIKE '%' || tag_name || '%' there
are position (reversed order of args) and strpos.
SELECT id FROM TAG_TABLE WHERE strpos('aaaaaaaa', tag_name) > 0
Besides what is more efficient (LIKE looks less efficient, but an index might change things), there is a very minor issue with LIKE: tag_name of course should not contain % and especially _ (single char wildcard), to give no false positives.
SELECT id FROM TAG_TABLE WHERE 'aaaaaaaa' LIKE '%' || "tag_name" || '%';
tag_name should be in quotation otherwise it will give error as tag_name doest not exist
Here is my query that results in a syntax error:
SELECT *
FROM account_invoice,sale_order
WHERE sale_order.name LIKE %account_invoice.origin%
The account_invoice.origin field contains the text of sale_order.name, plus other text as well, so I need to match sale_order.name string anywhere in the account_invoice.origin string.
I'm using PostgreSQL 8.4.
Try this
SELECT *
FROM account_invoice,sale_order
WHERE sale_order.name LIKE '%' || account_invoice.origin || '%'
% needs single quote because the pattern is a string.
|| is the operator for concatenation.
I have a table like this:
ID text_1 text_2 text_3
12 some text some more even more
I need it to be put it to be put to one string so it comes out like
some text\n\nsome more\n\neven more
Now I know that \n is something else in TSQL but I can't remember what, maybe CHAR(13).
Anyone know to archive this?
This query will return the string you want:
SELECT text_1 + '\n\n' + text_2 + '\n\n' + text_3
FROM myTable
If you want a line break character you will indeed need to use CHAR(13) and for a line feed CHAR(10), in a similar manner:
SELECT text_1 + CHAR(13) + CHAR(10) + text_2 + CHAR(13) + CHAR(10) + text_3
FROM myTable
As #Adam Robinson comments, if the text_x fields are of type TEXT or NTEXT you will need to convert them first.