I am new to XMPP and working on a group chat application similar to watsapp. The scenario is:
"User A creates a group chat adding users B, C and D to it. All members are online and they are chatting. Now D takes the app to background or kills the app. Now A removes D from the group. How user D will be notified that A has removed him from the group, when D comes back to the app ?
I am using ejabberd (15.11) with PostgreSQL and following the XMPP architecture. I am not sure if the answer is out there, so would like to get help here.
XMPP MUC specifications says in section 9.5: Modifying the Member List:
If a removed member is currently in a members-only room, the service
SHOULD kick the occupant by changing the removed member's role to
"none" and send appropriate presence to the removed member as
previously described. The service MUST subsequently refuse entry to
the user.
It means that the participant will only receive his own status change modification if it is present it the room when the event happen. If he is not online at that time, he can only know his credentials has been removed, because he cannot join the room anymore. In other words, in the current state of the specifications, there is no way to get that removal notification when user was not in the room when the removal happened. You can just infer he was removed because he cannot join the room again on next login.
There is nothing else defined in XEP-0045 Multi-User Chat to store membership event for offline participant and later delivery.
Related
I have a Role Type that multiple users are subscribed to recordCreation changes for.
It's easy to add new users to this CKQuerySubscription by using its subscriptionID, however the issue arises when I try to 'unsubscribe' one of the users from the subscription using the CKContainer.default().publicCloudDatabase.delete(withSubscriptionID:) method.
Rather than just stopping this device from receiving any further notifications, it deletes the subscription (for all other users as well).
So my question is: how do I remove one user from a CKQuerySubscription without deleting the subscription for other users who are also subscribed to it?
I am developing a mobile messaging app (ios) and I support the logout feature. I want to keep the latest conversation list when the users logs in back again. Because the local storage of the app gets cleaned once logout.
I am using MAM XEP-0313 sucessfully but I have not found an IQ to query the conversation list of a particular user.
For example:
chat
user_a -> user_b
user_c
user_d
user_f
user_a has had conversations with 4 users and he wants to logout of the app, when he comes back in he needs to get those last 4 conversation threads on his list.
What I do when a user messages another user is that I add them to my roster and have the logic of automatic subscription. So I was thinking to use the roster history logic to query this collection but I was also expecting the MAM module to have a more direct way..
I am using MongooseIM server
I understand your problem, the solution you have is probably the best one you can have with standard XEPs and their implementations.
The conversation list is actually sth missing in MAM spec or in general in XMPP. There are some works to define an extension to get you all the conversations where you have some unread messages (so called "unread sync"). Will this be enough for you or you would rather want to get some kind of "inbox". By "inbox" I mean a list of all recent conversations with unread messages count where there are some unread messages.
I am working on the chat application.
I want to implement the group user chat and I have successfully done that.
Now I want toad the functionality by which user can leave the group. I found leave the group but it seems like it's just making user unavailable but not removing user from the member list.
Is there any way by which user remove himself from the member list?
I have read the xep 0045 for it, in that there is a topic for existing the room which seems make user unavailable but not removing from member list.
http://xmpp.org/extensions/xep-0045.html#exit
If anyone has any idea how to do this please share it.
Leaving a room in XMPP (0045) is accomplished by sending an unavailable presence to that room (see XMPPRoom.leaveRoom() in the XMPPFramework) - that should remove them from the occupants of that room (we do this with our app regularly).
"Members list" - is a MUC feature for moderator use cases, it is not related to user. Just leave room as described in XEP, you no need to modify members list. In fact, you no need to add user in this list too, simple chat application should only tracks <presence> stanzas from and to room JID.
First from this question :
Asmack/openfire How do I keep a user permanently in groupchat room
I read that I cannot use MUC to keep the user persistent in the group, they'll automatically leave the group and can rejoin after they come online again, that concept is like IRC like what've been asked in here -> http://community.igniterealtime.org/thread/48020.
Then from the stackoverflow question I read about using pubsub, then I've done some research about pubsub and what I've got is pubsub can persist the user to be in the group even the user is offline but the message flow is more like one directional from the publisher to the subscriber (read-only).
So if I want to create a group chat application can I use pubsub and set all the member to become both publisher and subscriber? or is there any alternative solution?or my understanding of the pubsub and MUC is incorrect?
my goal is to create some group chat like in the whatsapp or blackberry messenger group.
Thanks.
You can make users permanent in Group chat in MUC by changing the following code of openfire.
File : src/java/org/jivesoftware/openfire/muc/spi/LocalMUCUser.java
change line 547-550:
// TODO Consider that different nodes can be creating and processing this presence at the same time (when
remote node went down)
removeRole(group);
role.getChatRoom().leaveRoom(role);
TO:
// TODO Consider that different nodes can be creating and processing this presence at the same time (when
remote node went down)
// TODO Dont remove user from group when they go offline.
//removeRole(group);
//role.getChatRoom().leaveRoom(role);
I am working on a social network that should allow members to chat with visitors on the site. The concept is simple.
Users who have registered signup get their own account with rosters
When a visitor comes to the home page of the social network, he can see some of the online members of the community
Now he should be able to initiate a chat with them, by clicking on their name.
I have already got members to chat with their roster mates. My question is, how can I get an anonymous user to chat with a member and exchange presence info with him?
I have successfully managed to create anonymous accounts, members accounts and even send messages from an anonymous user to other members. But I cant get presence information from anonymous-user to member or vice versa?
BTW, the chat is JS based.
You're trying to break the XMPP model. Presence is an opt-in permission based system. You ask me if you can see my presence, I say yes. Generally my client will then automatically ask you if I can see your presence, and your client says yes. That's what the roster is -- yes's and no's to presence subscription requests.
You can make chat rooms (MUC, multi user chat) that are anonymous, as well as do presence in them. It's not a roster, though. It's the closest to what you're describing without going into crazy-land with pubsub, and I don't know if you could even bend that tool far enough to have anonymous roster entries.