Back when current view controller is not presented by segue. Swift - swift

Question

I am trying to present VC2 from VC1 without using segue. It works. Then, I tried to use self.navigationController?.popViewControllerAnimated(true) to back but it does not work. I am wondering what is the code I should use to back from VC2 to VC1. Below code is in appDelegate.
AppDelegate
let storyboard = UIStoryboard(name: "Main", bundle: nil)
let VC2 = storyboard.instantiateViewControllerWithIdentifier("VC2") as! VC2
let navController = UINavigationController(rootViewController: VC2)
self.topViewController()!.presentViewController(navController, animated: false, completion: nil)
func topViewController(base: UIViewController? = UIApplication.sharedApplication().keyWindow?.rootViewController) -> UIViewController? {
if let MMDrawers = base as? MMDrawerController {
for MMDrawer in MMDrawers.childViewControllers {
return topViewController(MMDrawer)
}
}
if let nav = base as? UINavigationController {
return topViewController(nav.visibleViewController)
}
if let tab = base as? UITabBarController {
if let selected = tab.selectedViewController {
return topViewController(selected)
}
}
if let presented = base?.presentedViewController {
return topViewController(presented)
}
return base
}
VC2
#IBAction func backButtonTapped(sender: AnyObject) {
print(self.navigationController?.viewControllers) // print([<MyAppName.VC2: 0x12f147200>])
self.navigationController?.popViewControllerAnimated(true)
}

Answer 1

Here is the Flow of your navigation :
Current Screen - Presenting A New Screen (Which itself embed within a navigation controller with vc2) so Popviewcontroller won't work .
If you present any viewcontroller then popviewcontroller wont work rather use dismissviewcontroller to come out previous screen .
Use This :
self.dismissViewControllerAnimated(true, completion: {})
Solved!
Thanks.