How about the approximation capability of a convolutional neural network? - neural-network

Globally, a deep CNN is a series of compositions of linear function and sigmoid function. So how about its approximation capability?

Given enough neurons, neural networks can approximate any function.
Here is a nice, visual proof.

Related

Supervised Neural Networks

I am reading a lot of articles about neural networks and I found very different information. I understand that the supervised neural network can be also regression and classification. In both cases I can use the sigmoid function but what is the difference?
A single-layer neural network is essentially the same thing as linear regression. That's because of how neural networks work: Each input gets weighted with a weight factor to produce an output, and the weight factors are iteratively chosen in such a way that the error (the discrepancy between the outputs produced by the model and the correct output that should be produced for a given input) is minimised. Linear regression does the same thing. But in a neural network, you can stack several of such layers on top of each other.
Classification is a potential, but by far not the only, use case for neural networks. Conversely, there are classification algorithms that don't use neural networks (e.g. K-nearest neighbours). The sigmoid function is often used as an activation function for the last layer in a classifier neural network.

Why do we need biases in the neural network?

We have weights and optimizer in the neural network.
Why cant we just W * input then apply activation, estimate loss and minimize it?
Why do we need to do W * input + b?
Thanks for your answer!
There are two ways to think about why biases are useful in neural nets. The first is conceptual, and the second is mathematical.
Neural nets are loosely inspired by biological neurons. The basic idea is that human neurons take a bunch of inputs and "add" them together. If the sum of the inputs is greater than some threshold, then the neuron will "fire" (produce an output that goes to other neurons). This threshold is essentially the same thing as a bias. So, in this way, the bias in artificial neural nets helps to replicate the behavior of real, human neurons.
Another way to think about biases is simply by considering any linear function, y = mx + b. Let's say you are using y to approximate some linear function z. If z has a non-zero z-intercept, and you have no bias in the equation for y (i.e. y = mx), then y can never perfectly fit z. Similarly, if the neurons in your network have no bias terms, then it can be harder for your network to approximate some functions.
All that said, you don't "need" biases in neural nets--and, indeed, recent developments (like batch normalization) have made biases less frequent in convolutional neural nets.

Step function versus Sigmoid function

I don't quite understand why a sigmoid function is seen as more useful (for neural networks) than a step function... hoping someone can explain this for me. Thanks in advance.
The (Heaviside) step function is typically only useful within single-layer perceptrons, an early type of neural networks that can be used for classification in cases where the input data is linearly separable.
However, multi-layer neural networks or multi-layer perceptrons are of more interest because they are general function approximators and they are able to distinguish data that is not linearly separable.
Multi-layer perceptrons are trained using backpropapagation. A requirement for backpropagation is a differentiable activation function. That's because backpropagation uses gradient descent on this function to update the network weights.
The Heaviside step function is non-differentiable at x = 0 and its derivative is 0 elsewhere. This means gradient descent won't be able to make progress in updating the weights and backpropagation will fail.
The sigmoid or logistic function does not have this shortcoming and this explains its usefulness as an activation function within the field of neural networks.
It depends on the problem you are dealing with. In case of simple binary classification, a step function is appropriate. Sigmoids can be useful when building more biologically realistic networks by introducing noise or uncertainty. Another but compeletely different use of sigmoids is for numerical continuation, i.e. when doing bifurcation analysis with respect to some parameter in the model. Numerical continuation is easier with smooth systems (and very tricky with non-smooth ones).

Neural network converges more slowly with htan

I implemented a neural network with sigmoid and hyperbolic tangent activation functions. One thing I have noticed is that sigmoid converges much faster than htan. They both converge and I have checked my code and am confident no coding bugs exist. Are neural networks using sigmoid naturally faster than htan, or might I be doing something wrong?

Why do sigmoid functions work in Neural Nets?

I have just started programming for Neural networks. I am currently working on understanding how a Backpropogation (BP) neural net works. While the algorithm for training in BP nets is quite straightforward, I was unable to find any text on why the algorithm works. More specifically, I am looking for some mathematical reasoning to justify using sigmoid functions in neural nets, and what makes them mimic almost any data distribution thrown at them.
Thanks!
The sigmoid function introduces non-linearity in the network. Without a non-linear activation function, the net can only learn functions which are linear combinations of its inputs. The result is called universal approximation theorem or Cybenko theorem, after the gentleman who proved it in 1989. Wikipedia is a good place to start, and it has a link to the original paper (the proof is somewhat involved though). The reason why you would use a sigmoid as opposed to something else is that it is continuous and differentiable, its derivative is very fast to compute (as opposed to the derivative of tanh, which has similar properties) and has a limited range (from 0 to 1, exclusive)