I need to check whether a wav file in Matlab work folder exists ou not. If it does, I need to load the file into a variable (file in my case), i use this code but it doesn't work.
if strcmp(file,'\n')==0
file='test.wav';
elseif findstr(file,'.')==''
file=strcat(file,'.wav');
end
[TestWave,Fs] = audioread(file);
You don't say if you are trying to find a particular .WAV file, or just any .WAV file...
If you just want to know if a particular file (of any kind) exists, use the exist() function. It returns value 2 if a file exits:
myFileName = 'test.wav';
myDirectory = 'c:\temp';
filepath = fullfile(myFileName,myDirectory);
if exist(filepath,'file') == 2
[TestWave,Fs] = audioread(file);
end
Otherwise, just search for the files you need using dir():
myDirectory = 'c:\temp';
wildcard = '*.wav';
theseFiles = dir(fullfile(myDirectory,wildcard));
for i = 1:length(theseFiles)
thisFilePath = fullfile(myDirectory,theseFiles(i).name);
[TestWave,Fs] = audioread(thisFilePath); % Load this file
% Do something with the loaded file...
end
Related
I have a folder origin_training with subfolders like FM, folder1, folder2, ... . I can get the list of image files in .png format into a cell called FM.
FM_dir = fullfile(origin_training, 'FM');
FM = struct2cell(dir(fullfile(FM_dir, '*.png')))';
My goal is to match the names in my folder with the images in my cd, and make a new folder FM with the images from cd. Image names in the two paths are identical. I can do that with:
% mother_folder = '...' my current directory
filenames = FM(:,1);
destination = fullfile(mother_folder, 'FM', FM(:,1));
cellfun(#copyfile,filenames, destination);
This is really slow. Takes minutes even for small amounts of images (~30).
My current directory has ~ 10000 images (the ones that correspond to FM, folder2, folder3, ...). What am I missing here?
An alternative would be to create a shell command and execute it. Assuming FM contains full paths for each file, or relative paths from the current directory, then:
FM_dir = fullfile(origin_training, 'FM');
destination = fullfile(mother_folder, 'FM');
curdir = cd(FM_dir);
FM = dir('*.png');
cmd = ['cp ', sprintf('%s ',FM.name), destination];
system(cmd);
cd(curdir);
If you're on Windows, replace 'cp' by 'copy'.
Note that here we're not creating a shell command per file to be copied (presumably what copyfile does), but a single shell command that copies all files at once. We're also not specifying the name for each copied file, we specify the names of the files to be copied and where to copy them to.
Note also that for this to work, mother_folder must be an absolute path.
I somehow put my code into a function and now it works at expected speed. I suspected that cd had to do with the low speed so I am only passing the full directories as character vectors.
The same approach works for my purpose or with a slight modification to just copy from A to B. As now, it works to match files in A to those on B and copy to B/folder_name
function [out] = my_copyfiles(origin_dir, folder_name, dest_dir, extension)
new_dir = fullfile(origin_dir, folder_name);
% Get a cell with filenames in the origin_dir/folder_name
% Mind transposing to have them in the rows
NEW = struct2cell(dir(fullfile(new_dir, extension)))';
dest_folder = fullfile(dest_dir, folder_name);
% disp(dest_folder)
if ~exist(dest_folder, 'dir')
mkdir(dest_folder)
end
%% CAUTION, This is the step
% Use names from NEW to generate fullnames in dest_dir that would match
filenames = fullfile(dest_dir, NEW(:,1));
destination = fullfile(dest_folder, NEW(:,1));
% if you wanted from origin, instead run
% filenames = fullfile(new_dir, NEW(:,1));
% make the copies
cellfun(#copyfile,filenames, destination);
%Save the call
out.originDir = new_dir;
out.copyFrom = dest_dir;
out.to = dest_folder;
out.filenames = filenames;
out.destination = destination;
end
I have a folder with 10 subfolder each has about 100 different files including text files and different extension images. I just need to copy the image files with JPG extension and move it to another single folder.
I am using this code:
clear all
clc
M_dir = 'X:\Datasets to be splitted\Action3\Action3\'% source directory
D_dir = 'X:\Datasets to be splitted\Action3\Depth\'
files = dir(M_dir);% main directory
dirFlags = [files.isdir];
subFolders = files(dirFlags);%list of folders
for k = 1 :length(subFolders)
if any(isletter(subFolders(k).name))
c_dtry = strcat(M_dir,subFolders(k).name)
fileList = getAllFiles(c_dtry)%list of files in subfolder
for n1 = 1:length(fileList)
[pathstr,name,ext] = fileparts(fileList{n1})% file type
%s = dir(fileList{n1});
%S = s.bytes/1000;%file size
Im = imread(fileList{n1});
%[h,w,d] = size(Im);%height width and dimension
if strcmp(ext,'.jpg')|strcmp(ext,'.JPG')%)&S>=50&(write image dimension condition))% here you need to modify
baseFileName = strcat(name,ext);
fullFileName = fullfile(D_dir, baseFileName); % No need to worry about slashes now!
imwrite(Im, fullFileName);
else
end
end
end
end
But the code is stopped with an error when a text file being processed.
The error says:
Error using imread>get_format_info (line 491)
Unable to determine the file format.
Error in imread (line 354)
fmt_s = get_format_info(fullname);
Error in ReadFromSubFolder (line 16)
Im = imread(fileList{n1});
Thanks
Your code is reading the data before you check the extension
Im = imread(fileList{n1});
is before
if strcmp(ext,'.jpg')|strcmp(ext,'.JPG')
edit
For finding files which end 'vis' you can usestrcmp
strcmp ( name(end-2:end), 'vis' )
For completeness you should also check that name is longer than 3 char.
Here is a relatively simpler solution using dir and movefile or copyfile depending on whether you want to move or copy:
%searching jpg files in all subdirectories of 'X:\Datasets to be splitted\Action3\Action3'
file = dir('X:\Datasets to be splitted\Action3\Action3\**\*.jpg');
filenames_with_path = strcat({file.folder},'\',{file.name});
destination_dir = 'X:\Datasets to be splitted\Action3\Depth\';
%mkdir(destination_dir); %create the directory if it doesn't exist
for k=1:length(filenames_with_path)
movefile(filenames_with_path{k}, destination_dir, 'f'); %moving the files
%or if you want to copy then: copyfile(filenames_with_path{k}, destination_dir, 'f');
end
I'm recording a sound and using wavwrite to save the wav file, but I need to save it in a specific folder in C:, such as in c:\Users\soundwav.
Here is an excerpt from my wavwrite code:
data(:,s)=getdata(ai,44100);
y = [y; data]
format shortg
c = clock;
fix(c);
a=num2str(c);
year=strcat(a(1),a(2),a(3),a(4),a(5));
month=strcat(a(19),a(20));
day=strcat(a(34),a(35));
hour=strcat(a(48),a(49));
min=strcat(a(63),a(64));
sec=strcat(a(74),a(75));
name=strcat(year,'-',month,'-',day,'-',hour,'-',min,'-',sec);
wavwrite(data,name);
You need to cd the path while saving it. I have included a line that concatenates the full path with name variable and then saves it.
data(:,s)=getdata(ai,44100);
y = [y; data]
format shortg
c = clock;
fix(c);
a=num2str(c);
year=strcat(a(1),a(2),a(3),a(4),a(5));
month=strcat(a(19),a(20));
day=strcat(a(34),a(35));
hour=strcat(a(48),a(49));
min=strcat(a(63),a(64));
sec=strcat(a(74),a(75));
name=strcat(year,'-',month,'-',day,'-',hour,'-',min,'-',sec);
name = strcat('c:\Users\soundwav\', name);
wavwrite(data,name);
To select the folder in which to save your file, you can use uigetdir which allows you to select the folder; then you can add to it the filename you've built.
directoryname = uigetdir
You can also specify a starting folder
directoryname = uigetdir('c:\user\')
name = strcat(directoryname, '\', name);
Hope this helps.
I need to extract the first value of the following code:
3.43099,70.8539,91.701,FAIL
The file has the '.sol' extension, but it can be read in notepad or Matlab.
I just want to know how to to read in all *.sol files in a folder and how to write the extracted value in a text file.
Thanks a lot, i would be grateful.
NEW
ita='"';
for i=1:size(z,2)
word_to_replace=input('Replace? ','s');
tik=input('Replacement? ','s');
coluna=input('Column? ');
files = dir('*.txt');
for i = 1:numel(files)
if ~files(i).isdir % make sure it is not a directory
contents = fileread(files(i).name);
fh = fopen(files(i).name,'w');
val=num2str(z(i,coluna));
word_replacement=strcat(tik,val,ita);
contents = regexprep(contents,'word_to_replace','word_replacement');
fprintf(fh,contents); % write "replaced" string to file
fclose(fh) % close out file
end
end
end
Many thanks
File extension does not make a difference as to what MATLAB can "read", use the fileread command to load in the file and parse its contents. You can then split on commas, since it looks like it is comma separated
files = dir('*.sol');
fh = fopen('outFile.txt','w');
for i = 1:numel(files)
if ~files(i).isdir % make sure it is not a directory
contents = fileread(files(i).name);
parts = regexp(contents,',','Split');
fprintf(fh,[parts{1},'\n']);
end
end
fclose(fh)
This should do what you want. It will find all files in the current directory with the .sol extension, loop through all of them, grab the first value, and write it out to a text file.
Find and replace
Finding and replacing is relatively simple as well. You can do the same looping, read the file contents, run a replacement, and then rewrite that out to the same file.
files = dir('*.sol');
for i = 1:numel(files)
if ~files(i).isdir % make sure it is not a directory
contents = fileread(files(i).name);
fh = fopen(files(i).name,'w'); % open handle to same file just read for overwriting
contents = regexprep(contents,'toReplace','replacement'); % do string replacement
fprintf(fh,contents); % write "replaced" string to file
fclose(fh) % close out file
end
end
What is the best way to figure out the size of a file using MATLAB? The first thought that comes to mind is size(fread(fid)).
Please see the dir function as stated above.
Please note that the dir function works on files and not on directories only.
>> s = dir('c:\try.c')
s =
name: 'try.c'
date: '01-Feb-2008 10:45:43'
bytes: 20
isdir: 0
datenum: 7.3344e+005
You can use the DIR function to get directory information, which includes the sizes of the files in that directory. For example:
dirInfo = dir(dirName); %# Where dirName is the directory name where the
%# file is located
index = strcmp({dirInfo.name},fileName); %# Where fileName is the name of
%# the file.
fileSize = dirInfo(index).bytes; %# The size of the file, in bytes
Or, since you are looking for only one file, you can do what Elazar said and just pass an absolute or relative path to your file to DIR:
fileInfo = dir('I:\kpe\matlab\temp.m');
fileSize = fileInfo.bytes;
Use the fact that MatLab has access to Java Objects:
myFile = java.io.File('filename_here')
flen = length(myFile)
If you don't want to hardcode in your directory, you can use the built in pwd tool to find the current directory and then add your file name to it. See example below:
FileInfo = dir([pwd,'\tempfile.dat'])
FileSize = FileInfo.bytes
The question seems to indicate that fopen/fread/.. is used. In this case, why not seeking to the end of the file and reading the position?
Example:
function file_length = get_file_length(fid)
% extracts file length in bytes from a file opened by fopen
% fid is file handle returned from fopen
% store current seek
current_seek = ftell(fid);
% move to end
fseek(fid, 0, 1);
% read end position
file_length = ftell(fid);
% move to previous position
fseek(fid, current_seek, -1);
end
Matlab could have provided a shortcut..
More on ftell can be found here.
This code works for any file and directory (no need for absolute path) :
dirInfo=dir(pwd);
index = strcmp({dirInfo.name},[filename, '.ext']); % change the ext to proper extension
fileSize = dirInfo(index).bytes
Easy way to find size of file is:
enter these cammands
K=imfinfo('filename.formate');
size_of_file=K.FileSize
and get size of file.