I have the following data sample:
2001 1
2000 1
1974 1
2007 1
2007 2
2007 6
2007 3
1994 1
1986 1
2007 1
I want to sort the data by year and then plot the values. I wrote a code using for and find. However, using fprintf I got only the output in the command window, like this:
Ano-modelo 2009 | 88242 veiculos
Ano-modelo 2010 | 125822 veiculos
Ano-modelo 2011 | 132360 veiculos
Ano-modelo 2012 | 167984 veiculos
So, Is there some alternative way that, inside for loop, to create a matrix c = [year; sum_vehicles]?
My code is the following:
dados = dlmread('c:\experimental\frota_detran\frota-detran_total.dat');
ano = 1922:2015;
for i = ano
%procura somente os valores a cada ano
pro = find(dados(:,1)==i);
%lista somente os valores
qt = dados(pro,:);
%soma o ano modelo em questao
total = sum (qt(:,2));
%exibe os valores para cada ano modelo
fprintf('%s %d %s %d %s \n','Ano-modelo',i ,'|',total, 'veiculos');
end
Looks like you want the data sorted and aggregated:
[sorted ia ic] = unique(dados(:,1));
c = [sorted accumarray(ic, dados(:,2))];
Related
I have a GUI which has a lot of menus associated with radiobuttons. Menus or popmenus will be available to edit or select only if the radiobuttons next to them is selected.
Among these menus I have 2 popmenus associated to a radiobutton. In the first popmenu I have set up in the string 3 different choices and if I take choice 1 and 2 the second popmenu will propose a string with 5 choice. But if I select choice 3 in the second popmenu I have only it will change the string of the popmenu 2 and all the proposition will be different.
To do that I have a function which works but the only problem is that to see the change of string in the popmenu 2 I need to unselect and select again the radiobutton. Is there a way to refresh the popmenu 2 choices when I change the selection in popmenu 1?
function h0=exemple
%KGUI4N construction de la boite de dialogue pour KGEXEC4N
%CAVIAR2, © ALSTOM + OL 1999/12-2003/03
blanc=[1 1 1];
gris=blanc*0.75;
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%figure
h0=figure(...
'Units','characters',...
'DefaultUicontrolUnits','characters',...
'Color',gris,...
'IntegerHandle','off',...
'MenuBar','none',...
'Name','Norme harmonique',...
'NumberTitle','off',...
'Position',[100 30 110 25],...
'Resize','on',...
'Tag','NormeDlg',...
'WindowStyle','modal',...
'ToolBar','none');
%titre
uicontrol(h0,'Style','text',...
'BackgroundColor',gris,...
'HorizontalAlignment','center',...
'Position',[10 22 85 1],...
'String','Choix du gabarit à tracer en superposition sur les spectres');
%bouton OK
uicontrol(h0,...
'BackgroundColor',gris,...
'Callback','close(gcbf)',...
'Position',[27 0.5 16 2],...
'String','OK',...
'Tag','NormeOK');
%bouton annuler
uicontrol(h0,...
'BackgroundColor',gris,...
'Callback','close(gcbf)',...
'Position',[51 0.5 16 2],...
'String','Annuler');
%bouton aide
uicontrol(h0,...
'BackgroundColor',gris,...
'Position',[75 0.5 7 2],...
'String','?');
%Buttongroup1
bg = uibuttongroup('Visible','on',...
'BackgroundColor',gris);
%Aucune
ra(1) = uicontrol(bg,'Style','radiobutton',...
'BackgroundColor',gris,...
'Position',[5 19 30 1.7],...
'String','Aucun',...
'Tag','Norme0');
uicontrol(h0,'Style','text',...
'HorizontalAlignment','left',...
'BackgroundColor',gris,...
'Position',[35 19.35 7 1],...
'String','--',...
'Tag','Param0');
%IEEE519
ra(2) = uicontrol(bg,'Style','radiobutton',...
'BackgroundColor',gris,...
'Position',[5 17 30 1.7],...
'String','IEEE519 (2014)',...
'Tag','Norme519',...
'TooltipString','Param519-1');
prmsA{2} = uicontrol(h0,'Style','popupmenu',...
'BackgroundColor',blanc,...
'Position',[35 17 17 1.7],...
'String',['120V-69kV|70-161kV|162kV & +'],...
'Tag','Param519-1',...
'TooltipString','Niveau de tension considéré',...
'Value',1,...
'Enable','off');
prmsA{2}(2)=uicontrol(h0,'Style','popupmenu',...
'BackgroundColor',blanc,...
'Position',[53 17 18 1.7],...
'String','???',...
'Tag','Param519-2',...
'TooltipString','ISC/IL = courant de court-circuit sur courant maximum',...
'Value',1,...
'Enable','off');
set(bg,'SelectionChangeFcn',#(o,e)bgChangeFcn(o,e,prmsA))
movegui(h0,'center')
function bgChangeFcn(src,event,prms)
allprms = [prms{:}];
set(allprms,'Enable','off');
lbl=get(event.NewValue,'TooltipString');
if strcmp(lbl, 'Param519-1')
hno=[findobj(allprms,'Tag','Param519-1')
findobj(allprms,'Tag','Param519-2')];
Scr519(hno(1:2));
else
set(findobj(allprms,'Tag',lbl),'Enable','on');
end
function enable(h)
set(h,'Enable','on')
%%%%%%%%%%%%
function Scr519(h)
enable(h)
x=get(h(2),'Value');%n° ISC/IL en cours
switch get(h(1),'Value')
case {1,2}
if (x<1)||(x>5),x=1;end
ch='Iscr<20|20<Iscr<50|50<Iscr<100|100<Iscr<1k|1000<Iscr';
drawnow
case 3
if (x<1)||(x>3),x=1;end
ch='Iscr<25|25<Iscr>50|Iscr>=50';
drawnow
otherwise
error(kverranorm(6))
end
set(h(2),'String',ch,'Value',x)
The function that allow to update the popmenu string is the last one. It works but I would like to see the update without having to unselect and select the radiobutton.
I performed a Principal Component Analysis (PCA) in Stata.
My dataset includes eight financial indicators that vary across 9 countries.
For example:
* Example generated by -dataex-. To install: ssc install dataex
clear
input str7 Country double(Investment Profit Income Tax Repayment Leverage Interest Liquidity) int Year
"France" -.1916055239385184 .046331346724579184 .16438012750896466 .073106839282063 30.373216652548326 4.116650784492168 3.222219873614461 .01453109309122077 2010
"UK" -.09287803170279468 .10772082765154019 .19475363707485557 .05803923583546618 31.746409646181174 9.669982727208433 1.2958094802269167 .014273374324088752 2010
"US" -.06262935107629553 .08674901201182428 .1241593221865416 .13387194413811226 25.336612638526013 11.14330064161111 1.954785887176916 .008355601163285917 2010
"Italy" -.038025847122363045 .1523162032749684 .23885658237030563 .2057478638900476 31.02007902336988 2.9660938817562292 6.12544787693943 .011694993164234125 2010
"Germany" -.05454795914578491 .06287079763890834 .09347194572148769 .08730237262847926 35.614342337621174 12.03770488195981 1.1958205191308358 .012467084153714813 2010
"Spain " -.09133982259799572 .1520056836126315 .20905656056324853 .21054797530580743 30.133833346916546 2.0623245902645073 5.122615899157435 .013545432336873187 2010
"Sweden" -.05403262462960799 .20463787181576967 .22924827352771968 .05655833155565016 20.30540887860061 10.392313613725324 .8634381995636089 .008030624504967313 2010
"Norway " -.07560184571862992 .08383822093909514 .15469418498932822 .06569716455818478 29.568228705840234 14.383460621594622 1.5561013535825234 .012843159364225464 2010
"Algeria" -.0494187835163535 .056252436429004446 .09174672864585759 .08143181185307143 34.74103858167055 15.045254276254616 1.2074942921860699 .011578038401820303 2010
"France" -.03831442432584342 .14722819896988698 .22035417794604084 .12183886462162773 28.44763045286005 12.727100288710087 1.405629911115614 .011186908059399987 2011
"UK" -.05002189329928202 .16833493262244398 .2288402623558823 .04977050186975224 27.640103129372747 11.17376089844228 1.1764542835994092 .008386726178729322 2011
"US" -.0871005985124144 .10270482619857023 .1523559355903486 .06775742210623094 26.840586700880362 10.783899184031576 1.454011947763254 .013501919089967212 2011
"Italy" -.1069324103590126 -.5877872620957578 -.47469302172710803 .2004436360021364 23.133243742952658 5.3936761686065875 4.532771849692548 .012586313916956204 2011
"Germany" -.05851794344524515 .09960345907923154 .136805115392161 .1373407846168154 32.6182637042919 14.109738344526052 1.5077699357228835 .013200993625042274 2011
"Spain " -.10650743527105216 -.015785638597076792 .1808727613216441 .05038848927405154 28.22206251292902 10.839614113486853 1.5021425852392374 .012076771099482617 2011
"Sweden" -.09678946710644694 .11801761803893955 .18569993056826523 .1481844716617448 27.439283362903794 5.771154420635893 5.493437819181101 .013820243145673811 2011
"Norway " -.04263379351591438 .09931719473864983 .14469611775596314 .0796835513869996 26.68561168581991 14.06385602832082 1.5200488174887825 .01029136242440406 2011
"Algeria" -.04871983526465598 .2139061303228528 .2728647845448156 .056537570099712456 22.50263575072073 16.919641035094685 .7539881754626142 .009734650338902404 2011
end
I called my first component "indebtedness" and my second one "profitability", after rotation.
I have the same data for 2011, 2012, 2013, 2014 and so on. I want to use the matrix of weights Stata computed for 2010 and apply it to 2011, 2012, 2013 separately. My goal is to compare the indebtedness and the profitability between countries over time.
To do this, I use the estimate save and estimates use commands (Chapter 20 of Stata manual on estimates and the post-estimation PCA command help).
However, I can't understand what Stata is saving. Is it saving the scores computed for 2010 or the eigenvalues and eigenvectors?
This is the code I use:
tempfile pca
save `pca'
use `pca' if Year==2010
global xlist Investment Profit Income Tax Repayment Leverage Interest Liquidity
pca $xlist, components(2)
estimates save pcaest, replace
predict score
summarize score
use `pca' if Year==2011, clear
estimates use pcaest
predict score
summarize score
Does this method and code seem correct to you?
I'd also like to save the matrix of weights and create a new vector Z=b|1,1]*investment+....
Using your toy example for year 2010:
clear
input str7 Country double(Investment Profit Income Tax Repayment Leverage Interest Liquidity) int Year
"France" -.1916055239385184 .046331346724579184 .16438012750896466 .073106839282063 30.373216652548326 4.116650784492168 3.222219873614461 .01453109309122077 2010
"UK" -.09287803170279468 .10772082765154019 .19475363707485557 .05803923583546618 31.746409646181174 9.669982727208433 1.2958094802269167 .014273374324088752 2010
"US" -.06262935107629553 .08674901201182428 .1241593221865416 .13387194413811226 25.336612638526013 11.14330064161111 1.954785887176916 .008355601163285917 2010
"Italy" -.038025847122363045 .1523162032749684 .23885658237030563 .2057478638900476 31.02007902336988 2.9660938817562292 6.12544787693943 .011694993164234125 2010
"Germany" -.05454795914578491 .06287079763890834 .09347194572148769 .08730237262847926 35.614342337621174 12.03770488195981 1.1958205191308358 .012467084153714813 2010
"Spain " -.09133982259799572 .1520056836126315 .20905656056324853 .21054797530580743 30.133833346916546 2.0623245902645073 5.122615899157435 .013545432336873187 2010
"Sweden" -.05403262462960799 .20463787181576967 .22924827352771968 .05655833155565016 20.30540887860061 10.392313613725324 .8634381995636089 .008030624504967313 2010
"Norway " -.07560184571862992 .08383822093909514 .15469418498932822 .06569716455818478 29.568228705840234 14.383460621594622 1.5561013535825234 .012843159364225464 2010
"Algeria" -.0494187835163535 .056252436429004446 .09174672864585759 .08143181185307143 34.74103858167055 15.045254276254616 1.2074942921860699 .011578038401820303 2010
end
I get the following results:
local xlist Investment Profit Income Tax Repayment Leverage Interest Liquidity
pca `xlist', components(2)
Principal components/correlation Number of obs = 9
Number of comp. = 2
Trace = 8
Rotation: (unrotated = principal) Rho = 0.7468
--------------------------------------------------------------------------
Component | Eigenvalue Difference Proportion Cumulative
-------------+------------------------------------------------------------
Comp1 | 3.43566 .896796 0.4295 0.4295
Comp2 | 2.53887 1.23215 0.3174 0.7468
Comp3 | 1.30672 .750756 0.1633 0.9102
Comp4 | .555959 .472866 0.0695 0.9797
Comp5 | .0830926 .0181769 0.0104 0.9900
Comp6 | .0649157 .0526462 0.0081 0.9982
Comp7 | .0122695 .00975098 0.0015 0.9997
Comp8 | .00251849 . 0.0003 1.0000
--------------------------------------------------------------------------
Principal components (eigenvectors)
------------------------------------------------
Variable | Comp1 Comp2 | Unexplained
-------------+--------------------+-------------
Investment | 0.0004 -0.3837 | .6262
Profit | 0.3896 -0.3794 | .1131
Income | 0.4621 -0.1162 | .232
Tax | 0.4146 0.1236 | .3706
Repayment | -0.1829 0.4747 | .3131
Leverage | -0.4685 -0.2596 | .07464
Interest | 0.4580 0.2625 | .1045
Liquidity | -0.0082 0.5643 | .1913
------------------------------------------------
To see what items the pca command returns type:
ereturn list
scalars:
e(N) = 9
e(f) = 2
e(rho) = .7468162625387222
e(trace) = 8
e(lndet) = -13.76082122673546
e(cond) = 36.93476257313668
macros:
e(cmdline) : "pca Investment Profit Income Tax Repayment Leverage Interest Liquidity, components(2)"
e(cmd) : "pca"
e(title) : "Principal components"
e(marginsnotok) : "_ALL"
e(estat_cmd) : "pca_estat"
e(rotate_cmd) : "pca_rotate"
e(predict) : "pca_p"
e(Ctype) : "correlation"
e(properties) : "nob noV eigen"
matrices:
e(sds) : 1 x 8
e(means) : 1 x 8
e(C) : 8 x 8
e(Psi) : 1 x 8
e(Ev) : 1 x 8
e(L) : 8 x 2
functions:
e(sample)
One way to save the returned matrix containing the eigenvectors as variables for the next year is to create a copy of the matrix and load the 2011 data:
matrix A = e(L)
clear
input str7 Country double(Investment Profit Income Tax Repayment Leverage Interest Liquidity) int Year
"France" -.03831442432584342 .14722819896988698 .22035417794604084 .12183886462162773 28.44763045286005 12.727100288710087 1.405629911115614 .011186908059399987 2011
"UK" -.05002189329928202 .16833493262244398 .2288402623558823 .04977050186975224 27.640103129372747 11.17376089844228 1.1764542835994092 .008386726178729322 2011
"US" -.0871005985124144 .10270482619857023 .1523559355903486 .06775742210623094 26.840586700880362 10.783899184031576 1.454011947763254 .013501919089967212 2011
"Italy" -.1069324103590126 -.5877872620957578 -.47469302172710803 .2004436360021364 23.133243742952658 5.3936761686065875 4.532771849692548 .012586313916956204 2011
"Germany" -.05851794344524515 .09960345907923154 .136805115392161 .1373407846168154 32.6182637042919 14.109738344526052 1.5077699357228835 .013200993625042274 2011
"Spain " -.10650743527105216 -.015785638597076792 .1808727613216441 .05038848927405154 28.22206251292902 10.839614113486853 1.5021425852392374 .012076771099482617 2011
"Sweden" -.09678946710644694 .11801761803893955 .18569993056826523 .1481844716617448 27.439283362903794 5.771154420635893 5.493437819181101 .013820243145673811 2011
"Norway " -.04263379351591438 .09931719473864983 .14469611775596314 .0796835513869996 26.68561168581991 14.06385602832082 1.5200488174887825 .01029136242440406 2011
"Algeria" -.04871983526465598 .2139061303228528 .2728647845448156 .056537570099712456 22.50263575072073 16.919641035094685 .7539881754626142 .009734650338902404 2011
end
Then you can simply use the svmat command:
svmat A
list A* if _n < 9
+-----------------------+
| A1 A2 |
|-----------------------|
1. | .0003921 -.383703 |
2. | .3895898 -.3793983 |
3. | .4621098 -.1162487 |
4. | .4146066 .1235683 |
5. | -.1828703 .4746658 |
|-----------------------|
6. | -.4685374 -.2596268 |
7. | .457974 .2624738 |
8. | -.0081538 .5643047 |
+-----------------------+
EDIT:
Revised according to comments:
use X1, clear
local xlist Investment Profit Income Tax Repayment Leverage Interest Liquidity
forvalues i = 1 / 5 {
pca `xlist' if year == 201`i', components(2)
matrix A201`i' = e(L)
svmat A201`i'
generate B201`i'1 = (A201`i'1 * Investment) + (A201`i'1 * Profit) + ///
(A201`i'1 * Income) + (A201`i'1 * Tax) + ///
(A201`i'1 * Repayment) + (A201`i'1 * Leverage) + ///
(A201`i'1 * Interest) + (A201`i'1 * Liquidity)
generate B201`i'2 = (A201`i'2 * Investment) + (A201`i'2 * Profit) + ///
(A201`i'2 * Income) + (A201`i'2 * Tax) + ///
(A201`i'2 * Repayment) + (A201`i'2 * Leverage) + ///
(A201`i'2 * Interest) + (A201`i'2 * Liquidity)
}
I'm not really sure how to express it but I'm searching for unicode letters which are more than one visual latin letter.
I found this in Word so far:
DZ
Dz
dz
NJ
Lj
LJ
Nj
nj
Any others?
Here are some of the characters I've found. I'd first done this manually by looking at some probable blocks. However I've later written a Python script to do this automatically that you can find at the end of this answer
Digraphs
Two Glyphs
Digraph
Unicode Code Point
HTML
DZ, Dz, dz
DZ, Dz, dz
U+01F1 U+01F2 U+01F3
DZ Dz dz
DŽ, Dž, dž
DŽ, Dž, dž
U+01C4 U+01C5 U+01C6
DŽ Dž dž
IJ, ij
IJ, ij
U+0132 U+0133
IJ ij
LJ, Lj, lj
LJ, Lj, lj
U+01C7 U+01C8 U+01C9
LJ Lj lj
NJ, Nj, nj
NJ, Nj, nj
U+01CA U+01CB U+01CC
NJ Nj nj
Ligatures
Non-ligature
Ligature
Unicode
HTML
AA, aa
Ꜳ, ꜳ
U+A732, U+A733
Ꜳ ꜳ
AE, ae
Æ, æ
U+00C6, U+00E6
Æ æ
AO, ao
Ꜵ, ꜵ
U+A734, U+A735
Ꜵ ꜵ
AU, au
Ꜷ, ꜷ
U+A736, U+A737
Ꜷ ꜷ
AV, av
Ꜹ, ꜹ
U+A738, U+A739
Ꜹ ꜹ
AV, av (with bar)
Ꜻ, ꜻ
U+A73A, U+A73B
Ꜻ ꜻ
AY, ay
Ꜽ, ꜽ
U+A73C, U+A73D
Ꜽ ꜽ
et
🙰
U+1F670
🙰
ff
ff
U+FB00
ff
ffi
ffi
U+FB03
ffi
ffl
ffl
U+FB04
ffl
fi
fi
U+FB01
fi
fl
fl
U+FB02
fl
OE, oe
Œ, œ
U+0152, U+0153
Œ œ
OO, oo
Ꝏ, ꝏ
U+A74E, U+A74F
Ꝏ ꝏ
ſs, ſz
ẞ, ß
U+1E9E, U+00DF
ß
st
st
U+FB06
st
ſt
ſt
U+FB05
ſt
TZ, tz
Ꜩ, ꜩ
U+A728, U+A729
Ꜩ ꜩ
ue
ᵫ
U+1D6B
ᵫ
VY, vy
Ꝡ, ꝡ
U+A760, U+A761
Ꝡ ꝡ
There are a few other ligatures that are used for phonetic transcription but looks like Latin characters
Non-ligature
Ligature
Unicode
HTML
db
ȸ
U+0238
ȸ
dz
ʣ
U+02A3
ʣ
IJ, ij
IJ, ij
U+0132, U+0133
IJ ij
ls
ʪ
U+02AA
ʪ
lz
ʫ
U+02AB
ʫ
qp
ȹ
U+0239
ȹ
ts
ʦ
U+02A6
ʦ
ui
ꭐ
U+AB50
ꭐ
turned ui
ꭑ
U+AB51
ꭑ
https://en.wikipedia.org/wiki/List_of_precomposed_Latin_characters_in_Unicode#Digraphs_and_ligatures
Edit:
There are more letterlike symbols beside ℻ and ℡ like what the OP found in the comment:
℀ ℁ ⅍ ℅ ℆ ℔ ℠ ™
Longer letters are mainly from the CJK Compatibility block
U+XXXX
0
1
2
3
4
5
6
7
8
9
A
B
C
D
E
F
U+338x
㎀
㎁
㎂
㎃
㎄
㎅
㎆
㎇
㎈
㎉
㎊
㎋
㎌
㎍
㎎
㎏
U+339x
㎐
㎑
㎒
㎓
㎔
㎕
㎖
㎗
㎘
㎙
㎚
㎛
㎜
㎝
㎞
㎟
U+33Ax
㎠
㎡
㎢
㎣
㎤
㎥
㎦
㎧
㎨
㎩
㎪
㎫
㎬
㎭
㎮
㎯
U+33Bx
㎰
㎱
㎲
㎳
㎴
㎵
㎶
㎷
㎸
㎹
㎺
㎻
㎼
㎽
㎾
㎿
U+33Cx
㏀
㏁
㏂
㏃
㏄
㏅
㏆
㏇
㏈
㏉
㏊
㏋
㏌
㏍
㏎
㏏
U+33Dx
㏐
㏑
㏒
㏓
㏔
㏕
㏖
㏗
㏘
㏙
㏚
㏛
㏜
㏝
㏞
㏟
Among the 3-letter-like symbols are ㎈ ㎑ ㎒ ㎓ ㎔㏒ ㏕ ㏖ ㏙ ㎪ ㎫ ㎬ ㎭ ㏆ ㏿ ㍱... Probably the ones with most characters are ㎉ and ㎯
Unicode even have codepoints for Roman numerals. Here another 4-letter-like character can be found: Ⅷ
U+XXXX
0
1
2
3
4
5
6
7
8
9
A
B
C
D
E
F
U+215x
⅐
⅑
⅒
⅓
⅔
⅕
⅖
⅗
⅘
⅙
⅚
⅛
⅜
⅝
⅞
⅟
U+216x
Ⅰ
Ⅱ
Ⅲ
Ⅳ
Ⅴ
Ⅵ
Ⅶ
Ⅷ
Ⅸ
Ⅹ
Ⅺ
Ⅻ
Ⅼ
Ⅽ
Ⅾ
Ⅿ
U+217x
ⅰ
ⅱ
ⅲ
ⅳ
ⅴ
ⅵ
ⅶ
ⅷ
ⅸ
ⅹ
ⅺ
ⅻ
ⅼ
ⅽ
ⅾ
ⅿ
U+218x
ↀ
ↁ
ↂ
Ↄ
ↄ
ↅ
ↆ
ↇ
ↈ
↉
↊
↋
If normal numbers can be considered then there are some other code points for multiple digits like ⒆ ⒇ ⓳ ⓴ in enclosed alphanumerics
U+XXXX
0
1
2
3
4
5
6
7
8
9
A
B
C
D
E
F
U+246x
①
②
③
④
⑤
⑥
⑦
⑧
⑨
⑩
⑪
⑫
⑬
⑭
⑮
⑯
U+247x
⑰
⑱
⑲
⑳
⑴
⑵
⑶
⑷
⑸
⑹
⑺
⑻
⑼
⑽
⑾
⑿
U+248x
⒀
⒁
⒂
⒃
⒄
⒅
⒆
⒇
⒈
⒉
⒊
⒋
⒌
⒍
⒎
⒏
U+249x
⒐
⒑
⒒
⒓
⒔
⒕
⒖
⒗
⒘
⒙
⒚
⒛
⒜
⒝
⒞
⒟
U+24Ax
⒠
⒡
⒢
⒣
⒤
⒥
⒦
⒧
⒨
⒩
⒪
⒫
⒬
⒭
⒮
⒯
U+24Bx
⒰
⒱
⒲
⒳
⒴
⒵
Ⓐ
Ⓑ
Ⓒ
Ⓓ
Ⓔ
Ⓕ
Ⓖ
Ⓗ
Ⓘ
Ⓙ
U+24Cx
Ⓚ
Ⓛ
Ⓜ
Ⓝ
Ⓞ
Ⓟ
Ⓠ
Ⓡ
Ⓢ
Ⓣ
Ⓤ
Ⓥ
Ⓦ
Ⓧ
Ⓨ
Ⓩ
U+24Dx
ⓐ
ⓑ
ⓒ
ⓓ
ⓔ
ⓕ
ⓖ
ⓗ
ⓘ
ⓙ
ⓚ
ⓛ
ⓜ
ⓝ
ⓞ
ⓟ
U+24Ex
ⓠ
ⓡ
ⓢ
ⓣ
ⓤ
ⓥ
ⓦ
ⓧ
ⓨ
ⓩ
⓪
⓫
⓬
⓭
⓮
⓯
U+24Fx
⓰
⓱
⓲
⓳
⓴
⓵
⓶
⓷
⓸
⓹
⓺
⓻
⓼
⓽
⓾
⓿
and in Enclosed Alphanumeric Supplement
🅫, 🅪, 🆋, 🆌, 🆍, 🄭, 🄮, 🅊, 🅋, 🅌, 🅍, 🅎, 🅏
A few more:
Currency symbol group
₧ ₨ ₶ ₯ ₠ ₢ ₷
Miscellaneous technical group
⎂ ⏨
Control pictures (probably you'll need to zoom out to see)
U+XXXX
0
1
2
3
4
5
6
7
8
9
A
B
C
D
E
F
U+240x
␀
␁
␂
␃
␄
␅
␆
␇
␈
␉
␊
␋
␌
␍
␎
␏
U+241x
␐
␑
␒
␓
␔
␕
␖
␗
␘
␙
␚
␛
␜
␝
␞
␟
U+242x
␠
␡
␢
␣

␥
␦
Alchemical Symbols
🜀 🜅 🜆 🜇 🜈 🝪 🝫 🝬 🝛 🝜 🝝
Musical Symbols
𝄶 𝄷 𝄸 𝄹 𝄉 𝄊 𝄫
And there are the emojis 🔟 💤🆔🚾🆖🆗🔢🔡🔠 💯🆘🆎🆑™🔙🔚🔜🔝🔛📆🗓🔞
Vertical bars may be considered uppercase i or lowercase L (like your 〷 example which is actually the TELEGRAPH LINE FEED SEPARATOR SYMBOL) and we have
Vai syllable see ꔖ 0xa516
Large triple vertical bar operator ⫼ 0x2afc
Counting rod tens digit three: 𝍫 0x1d36b
Suzhou numerals 〢 〣
Chinese river 川
║ BOX DRAWINGS DOUBLE VERTICAL...
Here's the automatic script to find the multi-character letters
import unicodedata
for c in range(0, 0x10FFFF + 1):
d = unicodedata.normalize('NFKD', chr(c))
if len(d) > 1 and d.isascii() and d.isalpha():
print("U+%04X (%s): %s\n" % (c, chr(c), d))
It won't be able to find many ligatures like æ or œ because they're not considered orthographic ligatures and aren't decomposable in Unicode. Here's the result in Unicode 11.0.0 (checked with unicodedata.unidata_version)
U+0132 (IJ): IJ
U+0133 (ij): ij
U+01C7 (LJ): LJ
U+01C8 (Lj): Lj
U+01C9 (lj): lj
U+01CA (NJ): NJ
U+01CB (Nj): Nj
U+01CC (nj): nj
U+01F1 (DZ): DZ
U+01F2 (Dz): Dz
U+01F3 (dz): dz
U+20A8 (₨): Rs
U+2116 (№): No
U+2120 (℠): SM
U+2121 (℡): TEL
U+2122 (™): TM
U+213B (℻): FAX
U+2161 (Ⅱ): II
U+2162 (Ⅲ): III
U+2163 (Ⅳ): IV
U+2165 (Ⅵ): VI
U+2166 (Ⅶ): VII
U+2167 (Ⅷ): VIII
U+2168 (Ⅸ): IX
U+216A (Ⅺ): XI
U+216B (Ⅻ): XII
U+2171 (ⅱ): ii
U+2172 (ⅲ): iii
U+2173 (ⅳ): iv
U+2175 (ⅵ): vi
U+2176 (ⅶ): vii
U+2177 (ⅷ): viii
U+2178 (ⅸ): ix
U+217A (ⅺ): xi
U+217B (ⅻ): xii
U+3250 (㉐): PTE
U+32CC (㋌): Hg
U+32CD (㋍): erg
U+32CE (㋎): eV
U+32CF (㋏): LTD
U+3371 (㍱): hPa
U+3372 (㍲): da
U+3373 (㍳): AU
U+3374 (㍴): bar
U+3375 (㍵): oV
U+3376 (㍶): pc
U+3377 (㍷): dm
U+337A (㍺): IU
U+3380 (㎀): pA
U+3381 (㎁): nA
U+3383 (㎃): mA
U+3384 (㎄): kA
U+3385 (㎅): KB
U+3386 (㎆): MB
U+3387 (㎇): GB
U+3388 (㎈): cal
U+3389 (㎉): kcal
U+338A (㎊): pF
U+338B (㎋): nF
U+338E (㎎): mg
U+338F (㎏): kg
U+3390 (㎐): Hz
U+3391 (㎑): kHz
U+3392 (㎒): MHz
U+3393 (㎓): GHz
U+3394 (㎔): THz
U+3396 (㎖): ml
U+3397 (㎗): dl
U+3398 (㎘): kl
U+3399 (㎙): fm
U+339A (㎚): nm
U+339C (㎜): mm
U+339D (㎝): cm
U+339E (㎞): km
U+33A9 (㎩): Pa
U+33AA (㎪): kPa
U+33AB (㎫): MPa
U+33AC (㎬): GPa
U+33AD (㎭): rad
U+33B0 (㎰): ps
U+33B1 (㎱): ns
U+33B3 (㎳): ms
U+33B4 (㎴): pV
U+33B5 (㎵): nV
U+33B7 (㎷): mV
U+33B8 (㎸): kV
U+33B9 (㎹): MV
U+33BA (㎺): pW
U+33BB (㎻): nW
U+33BD (㎽): mW
U+33BE (㎾): kW
U+33BF (㎿): MW
U+33C3 (㏃): Bq
U+33C4 (㏄): cc
U+33C5 (㏅): cd
U+33C8 (㏈): dB
U+33C9 (㏉): Gy
U+33CA (㏊): ha
U+33CB (㏋): HP
U+33CC (㏌): in
U+33CD (㏍): KK
U+33CE (㏎): KM
U+33CF (㏏): kt
U+33D0 (㏐): lm
U+33D1 (㏑): ln
U+33D2 (㏒): log
U+33D3 (㏓): lx
U+33D4 (㏔): mb
U+33D5 (㏕): mil
U+33D6 (㏖): mol
U+33D7 (㏗): PH
U+33D9 (㏙): PPM
U+33DA (㏚): PR
U+33DB (㏛): sr
U+33DC (㏜): Sv
U+33DD (㏝): Wb
U+33FF (㏿): gal
U+FB00 (ff): ff
U+FB01 (fi): fi
U+FB02 (fl): fl
U+FB03 (ffi): ffi
U+FB04 (ffl): ffl
U+FB05 (ſt): st
U+FB06 (st): st
U+1F12D (🄭): CD
U+1F12E (🄮): WZ
U+1F14A (🅊): HV
U+1F14B (🅋): MV
U+1F14C (🅌): SD
U+1F14D (🅍): SS
U+1F14E (🅎): PPV
U+1F14F (🅏): WC
U+1F16A (🅪): MC
U+1F16B (🅫): MD
U+1F190 (🆐): DJ
How do I get the year (4 digits) when given a source code, I can only detect the day (29), but could not detect the year(1997). There is something wrong in my regexp checking.
age = regexp(CharData,'(\d{1,4})','match','once')
For example,
Registered On
March 29, 1997
Desired output: 1997
Error output: 29
for i = 1:2
data2=fopen(strcat('DATA\PRE-PROCESS_DATA\F22_TR\f22_TR_pdata_',int2str(i),''),'r')
CharData = fread(data2, '*char'); %read text file and store data in CharData
fclose(data2);
age = regexp(CharData,'(\d{4})','match','once')
end
file : f22_TR_pdata_1 --> Registered On
June 24, 1997
file : f22_TR_pdata_2 --> Registered On
March 29, 1997
Age: 1997
To only grab four digits
age = regexp(CharData,'(\d{4})','match','once')
Doing d{1,4} means look for numbers with a length between 1 and 4. Meaning, 1, 29, 123, 4444 would all match because their length is between 1 and 4
d{4} says, get me the number with exact length of 4. Meaning, 1997, 2001, 1800 would all match.
I'd like to construct a graph like the following which is done with excel:
I've entered my data into matlab using the following lines:
year = [1975 1976 1977 1978 1979 1980 1981 1982 1983 1984 1985 1986 1987 1988 1989 1990 1991 1992 1993 1994 1995 1996 1997 1998 1999 2000 2001 2002 2003 2004 2005 2006 2007 2008 2009 2010
]
fix_No = [-9.449167466 -11.19432509 -8.500517848 -5.644813211 -2.608063866 2.614370892 6.461752833 7.035549084 8.542521755 12.11070577 6.476900841 8.029225388 4.315820526 4.165349512 5.34593031 7.510812752 -2.629044124 -5.713139529 -8.626773532 -11.83226415 . -8.821345246 -6.396197293 -5.187823611 -1.79008821 3.34099288 5.545228048 7.013763711 6.580524638 4.256524275
]
fix_No_and_mean = [11.1610424 5.437315474 5.833032482 4.591658232 1.578021362 -1.572756298 -1.03351595 -2.250991302 -3.222969261 -5.734621837 . 12.96685642 10.95095066 10.2207684 5.654017602 1.753259697 -2.596143576 -7.155087995 -9.687001589 -8.700979283 -4.290434459 . 2.299711172 1.640802028 1.714407543 0.8360893 -0.425484303 -1.160053823 -0.858530711 0.123787867 0.782208621
]
In 1985 and 1996 the lines should be interrupted as in the excel graph. But how can I do this using Matlab? I've put a "." (point) where the interruptions should be but matlab doesn't accept points.
The lines for the construction of the graph look like this:
plot(year,fix_No, 'color', 'k', 'LineWidth',2, 'LineSmoothing','on')
line(year,fix_No_and_mean, 'color', 'r', 'LineWidth',2, 'LineSmoothing','on')
xlabel('year')
legend('fixed number', 'fixed number')
You Should put "NaN" instead of '.' ,i.e. in the places on the vectors fix_No_and_mean and fix_No that correspond to 1985 and 1996, put NaN.
This will plot different lines as in the figure you attached from excel.