PowerShell - Extracting the Metadata of of files and grid viewing it - powershell

Question

Please see the following code:
# import .NET 4.5 compression utilities
Add-Type -As System.IO.Compression.FileSystem;
$zipArchives = Get-ChildItem "*.zip";
foreach($zipArchive in $zipArchives)
{
$archivePath = $zipArchive.FullName;
$archive = [System.IO.Compression.ZipFile]::OpenRead($archivePath);
try
{
foreach($archiveEntry in $archive.Entries)
{
if($archiveEntry.FullName -notmatch '/$')
{
$tempFile = [System.IO.Path]::GetTempFileName();
try
{
[System.IO.Compression.ZipFileExtensions]::ExtractToFile($archiveEntry, $tempFile, $true);
$windowsStyleArchiveEntryName = $archiveEntry.FullName.Replace('/', '\');
Select-String -pattern "<dc:title>.*</dc:title>" -path (Get-ChildItem $tempFile) | Select-Object #{Name="Path";Expression={Join-Path $archivePath (Split-Path $windowsStyleArchiveEntryName -Parent)}}
#Select-String -pattern "<dc:title>.*</dc:title>" -path (Get-ChildItem $tempFile) | Select-Object Matches
#Select-String -pattern "<dc:subject>.*</dc:subject>" -path (Get-ChildItem $tempFile) | Select-Object Matches
#Select-String -pattern "<dc:date>.*</dc:date>" -path (Get-ChildItem $tempFile) | Select-Object Matches
}
finally
{
Remove-Item $tempFile;
}
}
}
}
finally
{
$archive.Dispose();
}
}
It's a modified version of code that I found on the internet and helped me to find strings inside zip files.
My intention now is to extract metadata from zip files using this code.
I don't understand how can I display the two types of information in separate lines. If you run the script with only one Select-String... pipeline line active, the code works as expected. If you activate (uncomment) the second Select-String... pipeline line, the second type of information (the <dc:title> value) is not displayed and instead there is a blank line.
Please help me:
1) How can I also display the dc:title value using the Select-String | Select-Object mechanism that I used in the code.
2) How can I output all the data in a table format, so the table would look something like this:
* ZIP Filename * DC Title *
* zipfile01.zip * Bla Bla 01 *
* zipfile02.zip * Bla Bla 02 *
* zipfile03.zip * Bla Bla 03 *
This format of output would be the most usable for me.

Answer 1

The console "view" for pipeline-objcts is created based on the first object (which only have a Path-property). The second object is missing a Path-property which is why you see a blank line. If you had commented out the first Select-String ..-line (that shows Path), then the second line would work.
Objects sent through the pipeline should have the same set of properties so avoid using select-object with different property-sets. Ex:
.....
$tempFile = [System.IO.Path]::GetTempFileName();
try
{
[System.IO.Compression.ZipFileExtensions]::ExtractToFile($archiveEntry, $tempFile, $true);
[System.IO.Compression.ZipFileExtensions]::
$windowsStyleArchiveEntryName = $archiveEntry.FullName.Replace('/', '\');
Select-String -pattern "<dc:title>(.*)</dc:title>" -path (Get-ChildItem $tempFile) | Select-Object #{n="Zip FileName";e={$zipArchive.Name}}, #{Name="DC Title";Expression={ $_.Matches.Groups[1].Value}}
}
finally
{
Remove-Item $tempFile;
}
.....
To output all the metadata, you should create an object that includes all the values. Ex:
$tempFile = [System.IO.Path]::GetTempFileName();
try
{
[System.IO.Compression.ZipFileExtensions]::ExtractToFile($archiveEntry, $tempFile, $true);
[System.IO.Compression.ZipFileExtensions]::
$windowsStyleArchiveEntryName = $archiveEntry.FullName.Replace('/', '\');
#Avoid multiple reads
$content = Get-Content $tempFile
New-Object -TypeName psobject -Property #{
"Zip Filename" = $zipArchive.Name
"DC Title" = if($content -match '<dc:title>(.*)</dc:title>') { $Matches[1] } else { $null }
"DC Subject" = if($content -match '<dc:subject>(.*)</dc:subject>') { $Matches[1] } else { $null }
"DC Date" = if($content -match '<dc:date>(.*)</dc:date>') { $Matches[1] } else { $null }
}
}
finally
{
Remove-Item $tempFile;
}
....
Ex. output
Zip Filename DC Subject DC Title DC Date
------------ ---------- -------- -------
test.zip Subject O M G 5/18/2016
If you really want to force separate views (will get ugly), then you need to send he objects to | Out-Default to create a new view every time, ex:
Select-String -pattern "<dc:title>.*</dc:title>" -path (Get-ChildItem $tempFile) | Select-Object #{Name="Path";Expression={Join-Path $archivePath (Split-Path $windowsStyleArchiveEntryName -Parent)}} | Out-Default

Answer 2

i know it's not the answer you were looking for, but as a temporary workaround, you may be able to combine the two commands into one like this
Select-String -pattern "<dc:title>.*</dc:title>" -path (Get-ChildItem $tempFile) | Select-Object Matches, #{Name="Path";Expression={Join-Path $archivePath (Split-Path $windowsStyleArchiveEntryName -Parent)}}