Using If statement to check against 3 possibilities - swift

Question

I am wanting to compare three randomly generated numbers to see if any two of them are equal. I have an if statement that works but I would really like to combine the two else if statements into one if possible. I am thinking there has to be some way to use or but its only a binary operator. is there a way to use ? and make a ternary argument in one else if statement?
if aRand == bRand && bRand == cRand{
resultLabel.text = "3 out of 3"
} else if
(aRand == bRand || aRand == cRand) {
resultLabel.text = "2 out of 3"
} else if
(bRand == cRand) {
resultLabel.text = "2 out of 3"
} else {
resultLabel.text = "No Match"
}

Answer 1

Actually it's
if aRand == bRand || aRand == cRand || bRand == cRand
Here a swiftier expression
let rand = (aRand, bRand, cRand)
switch rand {
case let (a, b, c) where a == b && b == c : resultLabel.text = "3 out of 3"
case let (a, b, c) where a == b || a == c || b == c : resultLabel.text = "2 out of 3"
default : resultLabel.text = "No match"
}

Answer 2

Shorter way:
if (aRand == bRand && bRand == cRand) {
resultLabel.text = "3 out of 3"
} else if (aRand == bRand || bRand == cRand || aRand == cRand) {
resultLabel.text = "2 out of 3"
} else {
resultLabel.text = "No Match"
}

Answer 3

If I understand your algorithm correctly, you can avoid if altogether:
let aRand = 0
let bRand = 1
let cRand = 1
let allValues = [aRand, bRand, cRand]
let uniqueValues = Set(allValues)
let text: String
if (uniqueValues.count == allValues.count) {
text = "No match"
} else {
text = String(format: "%i out of %i", allValues.count - uniqueValues.count + 1, allValues.count)
}
print(text)
This will work for any number of values.