I am working on implementing queue data structures using cell arrays in Matlab. I am trying to write functions to advance the queue by one, as well as search the queue for a specific item. At the moment the function looks like this (car types are the example data).
function q = createQueue()
q={};
q = enqueue(q,'Hilux');
q = enqueue(q,'E-Type');
q = enqueue(q,'Beetle');
q = enqueue(q,'Enzo');
q = enqueue(q,'Boxter');
q = dequeue(q)
q = searchQueue(q,'Boxter')
end
% Adds an item to the end of the queue. Returns the new queue.
function q = enqueue(q,item)
q{end+1} = item;
end
function [q item] = dequeue(q)
q{1} = {};
q{1} = q{2};
q{2} = q{3};
q{3} = q{4};
q{4} = q{5};
q{5} = {};
end
function answer = searchQueue(q, item)
for i = 1:length(q)
if q{i} == item
answer = fprintf('FOUND AT INDEX %d',i);
break
else
disp('-1')
end
end
end
Currently, the dequeue function leaves an empty cell, rather than removing the cell entirely. Is this able to be avoided? The searchQueue function also returns an error, and i am lost as to why. Thanks
Here's a rough first cut at it using matlab's object oriented capabilities. The reason for creating a class is to get reference semantics from the handle type, which allows for the dequeue/enqueue functions to modify the cell array directly, removing the need for reassignment.
I believe the code example below answers your main question about how to dequeue without leaving an empty cell (could be used without the OOP approach to the same effect).
To answer your question about what's wrong with your search: 1) the comparison q{i} == item gives you problems because == compares characters (which fails if there is a string size mismatch) whereas you wanted to use isequal(); 2) you wanted sprintf rather than fprintf; and 3) while not strictly wrong, the else in your loop happens on every item that doesn't match, which is probably not what you wanted.
classdef Queue < handle
properties
data = {}
end
methods
function q = Queue()
% TODO: do something in constructor if desired
end
function item = dequeue(q)
% TODO: bounds check
item = q.data(1);
q.data = q.data(2:end);
end
function enqueue(q,item)
q.data{end+1} = item;
end
function answer = search(q, item)
% TODO: check for multiple occurrences
answer = 'NOT FOUND';
for i = 1:length(q.data)
if isequal(q.data{i},item)
answer = sprintf('FOUND AT INDEX %d',i);
break
end
end
end
end
end
Related
I'm trying to exctract some data from a nested structure in a recursive manner. First, I know that this has a field (values) which repeats itself inside the nested structure. Secondly I know that the structure which has those values has only structures as fields. In the below code I've tried to acces the structure.values by searching if my current structure has a field named values. If it has, I put .values at the end of my structure name. If it doesn't have this field, I verify if all the fields are structures. If they are, it means that I will have to consider them further and to extract the values from each one. If the fields are not structures, it means that they are values and I save them into a new simplified structure. Example of fields that I want: S.values.model1.values.mission.values.(alt/list). Currently, with the below code I'm only able to get the values from one field and then I get an error and don't know how to approach further.
Code example:
clear all
clc
S=struct()
S.case='1';
S.type='A';
S.values.model1.case='2'
S.values.model1.type='C'
S.values.model1.values.mission.case='3'
S.values.model1.values.mission.type='D'
S.values.model1.values.mission.values.alt='none'
S.values.model1.values.mission.values.list=2
S.values.model1.values.mission.values.parameter=4
S.values.model1.values.phase.case='4'
S.values.model1.values.phase.type='A'
S.values.model1.values.phase.values.num='all'
S.values.model1.values.phase.values.eq=2
S.values.model1.values.phase.values.unit=4
S.values.model1.values.analysis.case='1'
S.values.model1.values.phase.type='A'
S.values.model1.values.phase.values.nump1.list='all'
S.values.model1.values.phase.values.nump1.table='four'
S.values.model1.values.phase.values.nump1.mean=0
S.values.model1.values.phase.values.nump2.list='none'
S.values.model1.values.phase.values.nump2.table='three';
S.values.model1.values.phase.values.nump2.mean=1
s=S.values.model1;
names=fieldnames(s);
nnames=numel(names);
newStruct={};
[valsi,newstructi]=extractValues(names,s,nnames,newStruct)
function [vals,newStruct]=extractValues(names,vals,nnames,newStruct)
if any(strcmp(names,'values'))
vals=vals.('values');
names=fieldnames(vals)
nnames=numel(names)
[vals,newStruct]=extractValues(names,vals,nnames,newStruct);
end
for j=1:nnames
value(j)=isstruct((vals.(names{j})));
end
if all(value)
for k=1:nnames
vals=(vals.(names{k}));
names=fieldnames(vals);
nnames=numel(names);
[vals,newStruct]=extractValues(names,vals,nnames,newStruct);
end
else
for j=1:nnames
value=(vals.(names{j}));
newStruct.(names{j})=value;
end
end
end
As it is known beforehand what fields are requested you can arrange the subsequent filed names in a cell array and use a loop to extract the value:
names = {'values', 'model1', 'values', 'mission', 'values', 'alt'};
out = S;
for name : names
out = out.(name{1});
end
So that is a loop version of using:
out = S.values.model1.values.mission.values.alt;
EDIT:
If you want to list all field names and all field values you can used these functions:
function out = names(s, p)
if isstruct(s)
out = {};
f = fieldnames(s);
for i = 1:numel(f)
s1 = s.(f{i});
p1 = [p '.' f{i}];
out = [out; names(s1, p1)];
end
else
out = {p};
end
end
function out = values(s)
if isstruct(s)
out = {};
f = fieldnames(s);
for i = 1:numel(f)
out = [out; values(s.(f{i}))];
end
else
out = {s};
end
end
Use them as:
n = names(S, 'S');
v = values(S);
I'm doing an introduction course in programing in matlab and python and I have only been coding for a short time, so I'm still on the basics.
In the problem that I'm trying to solve, we have been given a code that creates a linked list by the teacher.
classdef Elem < handle
%Elem A class realising a linked list.
properties
data
next = Elem.empty
end
methods
function node = Elem(value)
if (nargin > 0)
node.data = value;
end
end
function obj = insert(obj, value)
if(isempty(obj.next))
obj.next = Elem(value);
else
obj.next.insert(value);
end
end
% More methods go here
end
end
One of the questions is then to make a code that can insert a number before a number in the linked list.
To do this I have made this code.
function newlist=InsertBefore(list,newdata,dataBefore)
if ~isempty(list)
if list.data==dataBefore
newlist = Elem(newdata);
newlist.next = list;
elseif list.next.data==dataBefore
newlist=list;
newelem = Elem(newdata);
newelem.next = list.next;
newlist.next = newelem;
else
InsertBefore(list.next,newdata,dataBefore)
end
end
end
If I then write
linkedlist2=InsertBefore(LinkedList,4,12)
the function makes a new list with 4 in front of the 12 which is the first number in the list. so the "If" part of the code works fine. if I try doing the same thing with a number in the middle of the list it says.
Output argument "newlist" (and maybe others) not assigned during call to "InsertBefore".
I have tried many things but nothing has really worked perfect yet, so your help is much appreciated
Thanks
Lasse
SOLVED
Had to have
else
newlist = InsertBefore(list.next,newdata,dataBefore)
I have a segment of code where a composition of nested loops needs to be run at various times; however, each time the operations within the nested loops are different. Is there a way to make the outer portion (loop composition) somehow a functional piece, so that the internal operations are variable. For example, below, two code blocks are shown which both use the same loop introduction, but have different purposes. According to the principle of DRY, how can I improve this, so as not to need to repeat myself each time a similar loop needs to be used?
% BLOCK 1
for a = 0:max(aVec)
for p = find(aVec'==a)
iDval = iDauVec{p};
switch numel(iDval)
case 2
r = rEqVec(iDval);
qVec(iDval(1)) = qVec(p) * (r(2)^0.5 / (r(1)^0.5 + r(2)^0.5));
qVec(iDval(2)) = qVec(p) - qVec(iDval(1));
case 1
qVec(iDval) = qVec(p);
end
end
end
% BLOCK 2
for gen = 0:max(genVec)-1
for p = find(genVec'==gen)
iDval = iDauVec{p};
QinitVec(iDval) = QinitVec(p)/numel(iDval);
end
end
You can write your loop structure as a function, which takes a function handle as one of its inputs. Within the loop structure, you can call this function to carry out your operation.
It looks as if the code inside the loop needs the values of p and iDval, and needs to assign to different elements of a vector variable in the workspace. In that case a suitable function definition might be something like this:
function vec = applyFunctionInLoop(aVec, vec, iDauVec, funcToApply)
for a = 0:max(aVec)
for p = find(aVec'==a)
iDval = iDauVec{p};
vec = funcToApply(vec, iDval, p);
end
end
end
You would need to put the code for each different operation you want to carry out in this way into a function with suitable input and output arguments:
function qvec = myFunc1(qVec, iDval, p)
switch numel(iDval)
case 2
r = rEqVec(iDval); % see note
qVec(iDval(1)) = qVec(p) * (r(2)^0.5 / (r(1)^0.5 + r(2)^0.5));
qVec(iDval(2)) = qVec(p) - qVec(iDval(1));
case 1
qVec(iDval) = qVec(p);
end
end
function v = myFunc2(v, ix, q)
v(ix) = v(q)/numel(ix);
end
Now you can use your loop structure to apply each function:
qvec = applyFunctionInLoop(aVec, qVec, iDauVec, myFunc1);
QinitVec = applyFunctionInLoop(aVec, QinitVec, iDauVec, myFunc2);
and so on.
In most of the answer I've kept to the same variable names you used in your question, but in the definition of myFunc2 I've changed the names to emphasise that these variables are local to the function definition - the function is not operating on the variables you passed in to it, but on the values of those variables, which is why we have to pass the final value of the vector out again.
Note that if you want to use the values of other variables in your functions, such as rEqVec in myFunc1, you need to think about whether those variables will be available in the function's workspace. I recommend reading these help pages on the Mathworks site:
Share Data Between Workspaces
Dynamic Function Creation with Anonymous and Nested Functions
Is there a way to have one function that can return two different variables, but only one at a time AND knowing which one is returned in the function call?
example:
I have the following function in which only one of the outputs is valid (the other one would be [])
function [a,b] = AlternatingOutput (input)
if input == 1
return ONLY A
else
return ONLY B
end
end
and i call it in a script
[a,b] = AlternatingOutput (input)
i want a way to say the following (pseudocode):
if (function outputs a)
[a,~] = AlternatingOutput(input)
elseif (function outputs b)
[~,b] = AlternatingOutput(input)
end
the script is run in a loop, and later i need the newest Valid values for a and b, so i cannot overwrite one of the two with []
I do understand that I could just write a function that checks which variable will be output, but I was wondering if there is a more elegant way.
I hope I have made my question clear, and I hope someone can answer me :)
There is no way to tell if an output argument is actually used. You may check the number of output arguments using nargout and it would allow to distinguish between [a] = AlternatingOutput(input) and [~,b] = AlternatingOutput(input)
I don't know the full context of your problem, but maybe you can put all your variables into a struct? Simply pass this struct everytime you call the function and let it decide which variables to manipulate. (This might be slow in some programming languages, but not in matlab).
How about retuning a cell?
function [ ab ] = testfun( input )
if input
ab={'ax'};
else
ab={2};
end
end
No worries about what is in the cell.
thb you could return what ever you want, Matlab does not check the type anyways
If only one of the outputs from the function AlternatingOutput is valid, then you only need to return one output:
function [X] = AlternatingOutput(input)
if input == 1
X = A;
else
X = B;
end
end
To allocate the retured value to either a or b in the loop, put them into a cell:
C = {AlternatingOutput(1), AlternatingOutput(2)};
and then use input to determine which value is change. If input is either 1 or 2 you can just do
for counter = ...
input = mod(input,2)+1;
C{input}=AlternatingOutput(input);
end
If your function doesn't mind accepting more input variables, why not pass a and b as input:
function [a,b] = AlternatingOutput(a,b,input)
if input == 1
a = new_value_for_a;
% b retains its former value
else
% a retains its former value
b = new_value_for_b;
end
end
Then it can be easily called from your script in a loop:
for i= ...
[a,b] = AlternatingOutput(a,b,input);
...
...
end
I have data as a struct with several layers, for example:
data.A.B
The data I want to access is in layer B. But the problem is that field names in B can be different depending on where the data comes from. Therefore I can't just type:
data.A.B.myData
myData is itself a struct
I can use:
fieldnames(data.A)
to find the names, but this doesn't help my much. I would have to write code sections for every possible field name that can occur at this level. And that's just what i trying to avoid.
Is there a way to get down to the data I have (myData) without knowing the field names of B?
Traditionally, you can loop over the fieldnames and perform the search of myData at a specific sub-structure of the struct. However, if you don't know which sub-structure you need to search, then you can perform a recursive algorithm. Below is an example. It will return the first match of myData in the struct or an empty matrix if no match found. The code can be improved to find all matches of myData.
function S2=getmyfield(S1,queriedField)
if isstruct(S1)
% Get all fieldnames of S1
fieldArray=fieldnames(S1);
% Find any match with the queried field. You can also use isfield().
% If there is a match return the value of S1.(queriedField),
% else perform a loop and recurse this function.
matchTF=strcmp(queriedField,fieldArray);
if any(matchTF)
S2=S1.(fieldArray{matchTF});
return;
else
S2=[];
i=0; % an iterator count
while isempty(S2)
i=i+1;
S2=getmyfield(S1.(fieldArray{i}),queriedField);
end
end
else
S2=[];
end
end
Cheers.
You just need a recursive function that checks fieldnames at each level for the structure.
This is roughly what you need (it could be improved to supply the path to the found field).
function [ value, found ] = FindField( rootStruct, fieldName )
%FindField - Find a field with a structure
value = [];
found = 0;
if isstruct( rootStruct )
fields = fieldnames(rootStruct);
for fi=1:length(fields)
if strcmp(fields{fi}, fieldName )
value = rootStruct.(fieldName);
found = true;
return;
end
[value, found ] = FindField( rootStruct.(fields{fi}), fieldName );
if found
return;
end
end
end
end
Usage example:
a.b = 1;
a.b.c = 2;
a.b.d = struct('Index',1,'Special',2);
FindField(a,'d')
ans =
Index: 1
Special: 2